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Posts by henry

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ALGEBRA PLZ HELP!1
L = 2in * 12ft/1n = 24 ft. W = 1.75in * 12ft/1n =

Math
10/35 = 8/W. W = ?.

Math
Length = 12 cm. Width = 1/1.414 * 12cm = 8.49 cm. Area = L * W.

math
65%/35% * 20Litres. = 37.1 Litres.

Physics
Va = 65mi/h * 1600m/mi * 1h/3600s = 28.9 m/s. F1 = (Vs+Vp)/(Vs-Va) * Fa. F1 = (330+0)/(330-28.9) * 500 = 548.0 Hz. F2 = (330-0)/(330+28.9) * 500 = 459.7 Hz. F1-F2 = 548 - 459.7 = 88.3 Hz. = Total shift in freq.

math
P = Po(1+r)^n. Po = 200 r = (9%/12)/100% = 0075/mo. n = 1comp./mo. * 24mo = 24 Compounding periods. P = 200(1.0075)^24 = $239.28

FINANICIAL
Po = 46,000/(1.0755)^12 = $19,205.82

FINANICIAL
P = Po(1+r)^n = 46,000. r = 7.55%/100% = 0.0755. n = 1comp./yr. * 12yrs. = 12 Compounding periods. Po = ?.

Physics
h = 0.5g*t^2 = 2.4-0.91. 4.9t^2 = 1.49. t1 = 0.551 s. d1 = Xo*t1 = 22.3 * 0.551 = 12.3 m. = Distance from back line to net. 0.5g*t2^2 = 2.4. 4.9t2^2 = 2.4, t2 = 0.70 s. to fall to gnd. d2 = Xo*t2 = 22.3 * 0.7 = 15.6 m. = Maximum distance travelled. a. Yes. b. d = 12.3 + 6.4 = ...

algerba
X pennies, and Y nickels. Eq1: 1x + 5y = 920 cents. Eq2: 5x + 1y = 2680 cents. -5x - 25y = -4600 +5x + 1y = 2680 Sum: -24y = -1920 Y = 80 nickels. In Eq1, replace Y with 80: x + 5*80 = 920, X = 520 Pennies.

MATH
Po = 46,000/(1.0755^12) = $19,205.82 = Amt. invested now.

math algebra
A = P*e^rt. P = $2,000 rt = 0.0475/yr. * 30yrs. = 1.425. A = ?.

Math
W = -(40*Cos30+60*Cos(theta)). -40*sin30 + 60*sin(theta) = 0. 60*sin(theta) = 40*sln30, sin(theta) = 2/3 * sin30 = 0.3333, theta = 19.5o W = -(40*Cos30+60*Cos19.5) = -91.2 N.

physics
6.28rad/rev * 2rev = 12.56 rad. 12.56rad/24h * 1h/3600s = 1.45*10^-4 rad/s.

physics
M*g = 30, g = 30/M.

physics
d = 0.5g*t^2.

Science
d = 0.5a*t^2 = 1500 m. 2.5*t^2 = 1500, t = 24.5 s.

physics
Range = Vo^2*sin(2A)/g.

Physics
See previous post.

Science Physics
See previous post: Wed, 11-30-16, 11:53 AM.

Science, physics
You have 2 vectors: one pointing north and one pointing west. Vr = -6 + 15i = 16.2km/h[-68.2o] = 16.2km/h[68.2o] N. of W.

Science
KE = 0.5M*V^2. KE = 0.5M*(V/2)^2 = 0.5M*V^2/4. So KE is reduced by a factor of 4(divided by 4).

physics
a. Vm - 2i = 4.2. Vm = 4.2 + 2i = 4.65m/s[25.6o] N. of E. = Velocity and Heading. b. Vm = 4.65m/s[25.6o]. c. d = Vm*t = 800. t = 800/Vm = 800/4.65 = 172 s.

Algebra
When B^2-4AC < 0, No real solutions. When B^2-4AC = 0, One real solution. When B^2-4AC > 0, Two real solutions.

Algebra
1. X = (-B +- Sqrt(B^2-4AC))/2A. X = (-0.8 +- sqrt(0.64+2.96))/-0.04 = -27.43, and 67.43. Solution: X = 67.43. 2. 0 = 5x^2+2x-12. B^2 - 4AC = 4 - (-240) = 244. Two solutions. 3. -8x^2 - 8x - 2 = 0. B^2-4AC = 64 - 64 = 0. One solution.

consumers math
Ar = Ab-I = Ab - Ab*r*t. Ar = 290 - 290*(0.16/360)*90, Ar = 290 - 11.60 = $278.40 = Amt. received(proceeds). I = $11.60.

precalculus
See previous post: Tue, 11-29-16, 3:33 PM.

Math
1. When X = 5, Y = 3*5 = 15. Since Y varies directly with X, Y will ALWAYS be 3 times X: Y = 3x. 2. Slope-Intercept Form: Y = (-2/3)x - 1. Multiply both sides by 3: 3y = -2x - 3, Add 2x to both sides: 2x + 3y = -3,

pre-calculus
A. 1rev/5.4min * 6.28rad/rev = 1.16 rad/min. B. Circumference = pi*2r = 3.14 * 78 = 245.0 feet. 5.6ft/s * 6.28rad/245ft. = 0.144 rad/s. C. 0.9rad/3s = 0.3rad/s.

math
See previous post: Tue, 11-29-16, 5:38 PM.

maths
a. 4.8kg/(0.25kg/pk.) = 19.2 or 19 packets. b. 250g/pk. * 0.2pk. = 50 g.

pre calculus
Eq2 was obtained by multiplying both sides of Eq1 by 2. Therefore, the two Eqs are identical. So we have an infinite number of solutions.

pre calculus
Eq2 was obtained by multiplying both sides of E

science
Circumference = pi*2r = 3.14 * 0.5 = 1.57 m. Vo = 72,000m/3600s * 6.28rad/1.57m = 80 rad/s. d = 20rev * 6.28rad/rev = 125.6 rad. V^2 = Vo^2 + 2a*d. V = 0, Vo = 80 rad/s, d = 125.6 rad, a = ?. "a" will be negative.

Science
Are you sure the time is only o.5 s.?

Math
Eq1: Vm - Vc = 15. Eq2: 0.5Vm + Vc = 12. Sum: 1.5Vm = 27, Vm = 18 mi/h. In Eq1, replace Vm with 18 and solve for Vc.

Math
d1 = d2. (Vp+Vw)*t1 = (Vp-Vw)t2. (150+Vw)*2 = (150-Vw)*3. Vw = ?.

physics
See Related Questions: Thu, 7-21-16, 1:58 AM.

History
The space is between the words the and act

History
The purpose of the act was to provide land to railroad companies so that a transcontinental railroad could be built.

History
Fill in the blank The purpose of the act was to provide land to railroad companies so that a transcontinental railroad could be built.

History
Yes

History
What are 2 things the railroad supplied from the west to other parts of the world ? What technology was used to show that the railway was complete ?

precalculus
Law of Sine: a/sin A = b/sin B. 9.4/sin150 = 4.8/sin B 9.4*sin B = 4.8*sin150, 9.4*sin B = 2.4, sin B = 0.25532, B = 14.8o. A+B+C = 180o. 150 + 14.8 + C = 180, C = 15.2o. a/sin A = c/sin C. c = ?.

physics
b. KE1 = 0.5M1*V1^2 + 0.5M2*V2^2, KE1 = 500*25^2 + (1000*15i^2), KE1 = 312,500 + 225,000 = 537,500 J. = KE before collision. KE2 = 0.5M1*V + 0.5M2*V. KE2 = 500*13^2 + 1000*13^2 = 253,500 J. = KE after collision. KE1-KE2 = KE lost after collision.

physics
a. M1V1 + M2V2 = M1V + M2V. 1000*25 + 2000*15i = 1000V + 2000V, 25,000 + 30,000i = 3000V, Divide by 1,000: 25 + 30i = 3V, V = 13m/s[50.2o] N. of E.

Physics
Correction: F = -1250 N.

Physics
V^2 = Vo^2 + 2a*d = 200^2. 300^2 + 2a*0.2 = 40,000, 0.4a = 40,000-90,000 = -50,000, a = -125,000 m/s^2. F = M*a = 0.01 * (-125000) = -11250 N. Resisting the bullet.

Physics , static fluids
Di/Dw = (920kg/m^3)/(1000kg/m^3) = 0.92 = 92% below the surface. 1.0-0.92 = 0.08 = 8% exposed.

Physics
F = 15 N.?. F = M*a, a = F/M = 15/14 = 1.07 m/s^2. V = Vo + a*t = 0 + 1,07*8 = 8.56 m/s.

Physics
Fr = 50N.[0o] + 30[30o]. X = 50 + 30*Cos30 = 76.0 N. Y = 30*sin50 = 15 N. Tan A = Y/X = 15/76 = 0.19737. A = 11.2o Fr = X/Cos A = 76/Cos11.2 = 77.5 N.]11.2o] N. of E.

physics
See previous post.

physics
M*g = 20 * 9.8 = 196 N. = Wt. of body. Fp = 196*sin30 = 98 N. = Force parallel to the incline. Fp-40 = M*a. 98-40 = M*a, a = 58/M = 58/20 = 2.9 m/s^2.

Physics
V = Vo + a*t = 2.0 rad/s. 0 + a*1.96 = 2.0, a = 1.02 rad/s^2. d = 0.5a*t^2 = 0.51*1.96*2 = 1.96 rad. (360deg./6.28rad) * 1.96rad = 112.4 deg. .

Maths Ratio and Proportion
Q1. (10/5)875 + (5/7)875 = 2375.

Maths Ratio and Proportion
Q2. 30,000L = 3cm. L = 1*10^-4 cm. Q3. 10/30 * 510 = 170 words.

Physics
Correction: A. PE = M*g*h Joules.

Physics
B. PE = M*g*h Joules. B. KE = PE = C. V^2 = Vo^2 + 2g*h = 0 + 19.6*10 = 196, V = 14 m/s.

Physics
V^2 = Vo^2 + 2a*d = 0. 400^2 + 2a*0.12 = 0, 160,000 + 0.24a = 0, a = -666,667 m/s^2. F = M*a = 0.03 * (-666,667) = -20,000 N.

Math grade 5, two-part problem
Adeline has X pens. Lisa has 2x/3 pens. A. (2x/3 + 16)/x = 2/1. 2x/3 + 16 = 2x 2x + 48 = 6x, X = 12. B. 2/3 * 12 = 8 pens. (8+16)/(12-6) = 24/6 = 4/1.

Science Physics
Disp. = X/Cos25.6 = 34.7km[25.6o].

Science Physics
Disp. = 20km[150o]+40km[0o]+10km[30o]. X = 20*Cos150+40+10*Cos30 = 31.3 km. Y = 20*sin150+10*sin30 = 15 km. Tan A = Y/X = 15/31.3 = 0.47923. A = 25.6o = Direction.

Physics
r/2 + r/2 + r = 2r = 2 in parallel + 2 in parallel + 1 in series.

Physics
r/2 + 3r = r/2 + 6r/2 = 7r/2 = 2 in parallel and 3 in series. r/3 + 2r = r/3 + 6r/3 = 7r/3 = 3 in parallel and 2 in series.

physics
See previous post.

physics
10 to 15 m/s: KE1 = 0.5M*V1^2 = 0.5M*10^2 = 50M. KE2 = 0.5M*V2^2 = 0.5M*15^2 = 113M. KE2-KE1 = 113M - 50M = 63M. = Change in KE. 15 to 20 m/s: KE1 = 0.5M*15^2 = 113M. KE2 = 0.5M*20^2 = 200M. 200M - 113M = 87M. = Change in KE.

Physics
V = Vo + g*t. Vo = 20 m/s, g = 9.8 m/s^2, t = 5 s, V = ?.

Physics
V^2 = Vo^2 + 2a*d. 0 = 300^2 + 2a*0.05, a = -900,000 m/s^2. V = Vo + a*t. 0 = 300-900,000t, t = ?.

Math
An angle ? satisfies the relation csc ? cos ? = -1. A) Use the definition of the reciprocal trigonometric ratios to express the left side in terms of sin ? and cos ?. B) What is the relation between sin ? and cos ? for this angle? C) Determine two possible values for ?. - ...

physics
Fr = F1+F2 = 10N[80o] + 3.5N[10o]. X = 10*Cos80 + 3.5*Cos10 = 5.18 N. Y = 10*sin80 + 3.5*sin10 = 10.5 N. Fr = = sqrt(x^2+y^2) = (5.18^2+10.5^2) = 11.7 N, = Resultant force. Fr = M*a = 11.7, a = 11.7/M = 11.7/0.5 = 22.14 m/s^2.

Math
Rate no. 1 = r mi/h. Rate no. 2 = r+2 mi/h. r*t = 2, t = 2/r. (r+2)*t = 3 (r+2)2/r = 3, 2 + 4/r = 3, 4/r = 1, r = 4 mi/h. (r+2) = 4+2 = 6 mi/h.

science
Exp. = 0.5cm/m * 100m = 50 cm.

physic
L = 120 cm, W = 80 cm, h = 40 cm. V = 120*80*40 = 384,000 cm^3. M = V*D = 384,000cm^3 * 19.3g/cm^3 = 7.41*10^6 g = 7410 kg.

physics
Note: 39.48 = (2pi)^2.

physics
T^2 = 39.48 * L/g = 1^2 = 1. L/g = 1/39.48, L = g/39.48 = 9.8/39.48 = 0.248 m. On The Moon: T^2 = 39.48*L/g = 39.48*0.248/1.63 = 6.0, T = 2.45 s.

Maths
1st number = X. 2nd number = X+1. (x+1) + x(x+1) = x+1 + x^2+x = x^2 + 2x + 1 = (x+1)(x+1) = (x+1)^2.

Physics
Fap = Force applied. Fap*d = 80 J. Fap*1 = 80, Fap = 80 N. Fap = M*a. a = Fap/M. = 80/2 = 40 m/s^2.

Physics
T = 136s/100cycles. = 1.36 s./cycle. T^2 = 39.48*L/g = (1.36)^2. L/g = 0.0468, g = 0.50/0.0468 = 10.7 m/s^2.

Physics
Ws = 1200 Lbs. Fp = 100*Cos30 = 86.6 Lbs. = Force parallel with the surface. Fn = 1200-100*sin30 = 1150 Lbs. = Normal force. Fk = u*Fn = u*1150 Lbs. Fp-u*Fn = Ws*a. u*Fn = Fp-Ws*0, u*Fn = Fp, u = Fp/Fn = 86.6/1150 = 0.075.

Physics
D = Vo*t + 0.5a*t^2. D = 1*10 + 0.05*10^2 = 15 rad. D = 15rad/(6.28rad/rev.) = 2.39 rev.

Physics
V^2 = Vo^2 + 2a*d. V = 0, Vo = 200 m/s, d = 0.045 m., a = ?.

Physics
C = pi*2r = 3.14 * 4 = 12.56 m. = circumference. Arc = (20/360) * 12.56m = 0.698 m.

Physics
F = M*a.

Math
P = Po(1+r)^n. First Year: Po = $100,000. r = 0.08/yr. * 0.5yrs. = 0.04. n = 2comp./yr. * 1yr. = 2 compounding periods. P = 100000(1.04)^2 = $108,160. Last Two Years: Po = 108,160. r = 0.12/yr. * 0.25yrs. = 0.03/qtr. n = 4comp./yr. * 2yrs. = 8 compounding periods. P = ?.

physics
M*g = 38.5, M = 38.5/g = 38.5/9.8 = 3.93 kg. = Wt. of fluid displaced. Density = M/V = 3.93kg/0.00735m^3 = 534.5 kg/m^3.

Physics
R = E/I = 40/5 = 8 Ohms. I = E/R = 120/8 = 15A.

electronics and circuits
I1 = Vs/(Rw1+RL1) = 4/(1+15) = 0.25A. = Current thru RL1. VL1 = I1*RL1 = 0.25 * 15 = I2 = (Vs/(Rw2+RL2) = VL2 = I2*RL2 =

electronics and circuits
I = V/r = 2/10 = 0.2A. Rbat = V/I = (4-2)/0.2 = 10 Ohms.

physics
See previous post: Thu, 11-17-16, 6:05 AM.

math
Salary = $X. X-x/4 = 3x/4. 3x/4-(1/4)3x/4 = 3x/4-3x/16 = 12x/16-3x/16 = 9x/16. 9x/16-(1/9)9x/16 9x/16-(1/9)9x/16 = 9x/16-x/16 = 8x/16 = x/2. x/2 = 3400, X = $6800.

Physics
See previous post: Fri, 11-18-16, 12:26 AM.

Physics
See previous post: Fri, 11-16-16, 12:26 AM.

Physics
See previous post.

Physics
V = (55-25)g * 1cm^3/g = 30 cm^3. Da = M/V = (48-25)g/30cm^3 = 0.767 g/cm^3 = Density of alcohol.

Maths
V = Vo + g*t. Vo = 0, g = 9.8 m/s^2, t is greater 0, but less than 1.5 s.

Maths
1. h = 0.5g*t^2 = 4.9*1.5^2 = 2. V^2 = Vo^2 + 2g*h. Vo = 0, g = 9.8 m/s^2, V = ?.

Physics
M*g = 40 * 9.8 = 392 N. = Wt. of child. Fp = 392*sin35 = 224.8 N. = Force parallel to the incline. V^2 = Vo^2 + 2a*d = 2.5^2. 0 + 2a*4 = 6.25, a = 0.781 m/s^2. Fp-Fk = M*a. Fk = Fp-M*a = 224.8-40*0.781 = 193.6 N.

physics
c. F = 24.5N/m * 0.05m = 1.23 N.

physics
M*g = 0.5 * 9.8 = 4.9 N. = Wt. of object. a. k = F/d = 4.9N./(0.45-0.25)m = 24.5 N/m. b. 24.5N./m * (0.50-0.25)m = 6.125 N. 6.125 - 4.9 = 1.23 N. addition wt.

Algebra
Eq1: 5x - 4y = 10. Eq2: 2x + 8y = 4. Multiply Eq1 by 2 and add the Eqs: 10x - 8y = 20. +2x + 8y = 4. Sum: 12x = 24,m X = 2. In Eq2, replace x with 2: 2*2 + 8y = 4. Y = 0. M1 = -A/B = -5/-4 = 1.25. M2 = -2/8 = -0.25.

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