Tuesday
October 21, 2014

Posts by henry


Total # Posts: 9,313

physics
Vo = 136km/h = 136,000m/3600s=37.78 m/s V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a d = (0-(37.78^2))/-500 = 2.85 m.
June 8, 2014

Math Personal Finance
See previous post.
June 8, 2014

Math Personal Finance
P = Po(1+r)^n = 2000 r = (6%/12)/100% = 0.005 n = 12comp/yr. * 5yrs. = 60 compounding periods. Po(1.005)^60 = 2000 Po = 2000/(1.005^60) = $1482.74=Initial deposit or present value.
June 8, 2014

Math Personal Finance
P=Po(1+r)^n. Calculate int. for 1 year. r = (5%/12)/100% = 0.00417 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 1yr. = 12 Compounding periods. P = 7000(1.00417)^12 = $7358.13 I = P-Po = 7358.13 - 7000 = $358.13 APY = (I/Po)*100% = (358.13/7000)*100% = 5.116%
June 8, 2014

Engg Mechanics
Block A: 200*sin30 = 100 N. = Force parallel to the plane. Fn = 200*cos30 = 173.2 N. = Normal force Block B: 100*sin30 = 50 N. = Force parallel to the plane. Fn = 100*cos30 = 86.6 N. = Normal force. P = Wa+Wb = 200 + 100 = 300 N.
June 8, 2014

electronics
Given: i = 6 mA. t = ? 1. Locate 6 mA on the y-axis. 2. Draw a hor. line from 6 mA to the curve. 3. Draw a ver. line from the intersection of the hor. line and curve to the x-axis. 4.Read the time, t , at the intersection of the ver. line and x-axis. Note: When t is given, ...
June 8, 2014

physics
a. The force of static friction decreases. b. The force of friction increases. The max. possible value of the force of friction increases. The max. angle at which block will slide decreases.
June 8, 2014

Physics
Upward: a = g = -9.8 m/s^2(slowing down) Highest point: a = g = -9.8 m/s^2. Downward: a = g = 9.8 m/s^2. The data shows that the acceleration due to gravity is present during the entire flight of the object. If g goes to zero, the object would not come down.
June 8, 2014

Physics
a. V^2 = Vo^2 + 2g*d V^2 = 4.9^2 + 19.6*21 = 435.61 V = 20.87 m/s. b. V = Vo + g*t t = (V-Vo)/g = (20.87-4.9)/9.8 = 1.63 s.
June 7, 2014

physics
a. False.
June 7, 2014

Science
2. Slower object: KE = 0.5m*V^2. Faster object: KE = 0.5m*(2V)^2 = 0.5m*4*V^2. 0.5m*4V^2/0.5m*V^2 = 4 Times. 3. KE = 0.5m*V^2 9. MA = 20/100 10. W = F*d. d = 0.
June 7, 2014

Physics
a. Vo=36mi/h * 1600m/mi * 1h/3600s=16 m/s. V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a d = (0-256)/-10 = 25.6 m. b. d = 0-1024)/-10 = 102.4 m.
June 7, 2014

MULTIPLY. WRITE EACH PRODUCT IN SCIENTIFIC NOTATIO
post.
June 6, 2014

MULTIPLY. WRITE EACH PRODUCT IN SCIENTIFIC NOTATIO
24. (3*10^6)(2*10^12) = 6*10^(6+12)=6*10^18 26. (6*10^9)(5*10^4) = 30*10^(9+4) = 30*10^13 = 3*10^14
June 6, 2014

MULTIPLY. WRITE EACH PRODUCT IN SCIENTIFIC NOTATIO
34. 5^10/5^7 = 5^(10-7) = 5^3 36. 76^11/76^5 = 76^(11-5) = 76^6
June 6, 2014

electronics
Rt = R2*R3/R1 = 2.11k R2*8.2k/2.2k = 2.11k 3.727R2 = 2.11k R2 = 0.566k = 566 ohms. NOTE: I'm assuming that Rt = 2.11k at 0oC.
June 6, 2014

physics
Yes, when an object is DROPPED, the initial velocity is 0. When an object is THROWN up or down, the initial velocity is not 0. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*7 = 137.2 V = 11.71 m/s.
June 5, 2014

Math
1. ) = 30 + 0.1(x-200) F(x) = 30 + 0.1x - 20 The above Eq is valid for all real values of X that are equal to or greater than 200: X => 200. When x = 200 minutes, the cost would be $30. None of the given choices meets this requirement. 2. Cost = 30 + 0.1x - 20 = $100 0.1x...
June 5, 2014

math
See previous post: Fri,5-23-14,12:35 PM.
June 5, 2014

electrical circuit instrumentation
R1 = 6 ohms. R2 = 8 ohms. Re=R1*R2/(R1+R2) = 6*8/(6+8)=3.429 ohms = Equivalent resistor. I1 = E/R1 = 36/6 = 6 Amps. I2 = E/R2 = 36/8 = 4.5 Amps. I = I1+I2 = 6 + 4.5 = 10.5 Amps. P1 = E^2/R1 = 36^2/6 = 216 Watts. P2 = E^2/8 = 36^2/8 = 162 Watts. P = P1+P2 = 216 + 162 = 378 ...
June 5, 2014

mechanical physics
Incomplete.
June 5, 2014

Physics
1. h = 0.5g*t^2 = 6 m. 4.9t^2 = 6 t^2 = 1.224 Tf = 1.107 s. = Fall time. d = Xo * Tf = 24 m. Xo * 1.107 = 24 Xo = 21.7 m/s = Initial velocity. 2. Fg = m*g = Force of gravity = Wt. of car. Fk = u*Fg = Force of kinetic friction. Fn = Fap-Fk = Net force. Fap = Force applied.
June 5, 2014

science
1. V = Vo + g*t = 30 - 10*2 = 10 m/s. 2. hmax = (V^2-Vo^2)/2g hmax = (0-(30)^2)/-20 = 3. V = Vo + g*Tr = 0 @ hmax. Tr = -Vo/g = -30/-10 = 3 s. = Rise time.
June 3, 2014

math
I=2.37*10^-5 watts/cm^2=Sound Intensity level. Io =10^-16 W/cm^2 = Reference sound Intensity level. db = 10*Log(I/Io) db = 10*Log(2.37*10^-5/10^-16) = 114
June 3, 2014

physics
Fx = 100*Cos37 = 79.86 N. Wb = m*g = 10kg * 9.8N/kg = 98 N. = Weight of buggy. a=(Fx-Fk)/m = (79.86-60)/10=1.99 m/s^2
June 3, 2014

physics
d1 = d2 25t = 0.5a*t^2 25 = 0.5a*t 0.002t = 25 t = 12,500 s. = 3.5 h.
June 3, 2014

physics
d = 300km[135o] V1 = 300km[135o]/0.75h = 400 km/h[135o] without wind. Vp + Vw = 400o[135] Vp + 80[-90o] = 400[135] Vp = 400[135] - 80[-90] Vp=400*cos135+i400*sin135 - (80*Cos(-90)+i80*sin(-90)) Vp = -282.84+i282.84 - (0-i80) Vp = -282.84 + i362.84 = 460km[128o] = Velocity and ...
June 3, 2014

Algebra 1 (Reiny)
1. T = T1*T2/(T1+T2) = 2*3/(2+3)=1.2 h. 2. H = 0.4 * 300 = 120 mL in current solution. W = 0.6 * 300 = 180 mL of water in current solution. W/(W+H) = 0.7 W/(W+120) = 0.7 W = 0.7W + 84 0.3W = 84 W = 280 mL of water in new solution. 280-180 = 100 mL of water added to new solution.
June 3, 2014

geometry
A1 = 150o = Minor Arc. A2 = 360-150 = 210o = Major Arc. X = (A2-A1)/2 = (210-150)/2 = 30o=Angle formed by 2 tangents. a
June 3, 2014

College Algebra
Length = L units. Width = (2L-2) units. A = L(2L-2) = 82cm^2 2L^2 - 2L - 82 = 0 L^2 - L - 41 = 0 Use Quadratic formula: L = 6.92 cm. Width = 2L - 2 = 2*6.92 - 2 = 11.84 cm. The diagonal divides the rectangle into 2 congruent rt. triangles. D^2 = L^2 + W^2 = 6.92^2 + 11.84^2=...
June 2, 2014

College Algebra ..Please help
1. Width = W ft. Length = (W+20) ft. A = W*(W+20) = 8,000 Ft^2 W^2 + 20W - 8000 = 0 C=-8,000 = -80*100. Sum = -80+100=20=B. (w+100)(w-80) = 0 w+100 = 0, W = -100 w-80 = 0, W = 80 Ft = Width. w+20 = 80+20 = 100 Ft = Length. 2. A = L*W = 16, L = 16/W. Eq2: L^2 + W^2 = 68 In Eq2...
June 2, 2014

LOOK AT THE GIVEN TRIANGLES??
a. P1 = (4x+2) + (7x+7) + (5x-4)=16x + 5 P2 = (x+3) + (x+7) + (2x-5) = 4x+5 b. P1-P2 = (16x+5) - (4x+5) = 16x+5 - 4x-5 = 12x.
June 2, 2014

physics
d = 3.6 + 0.5 = 4.1 miles. T1 = 3.6/9 + 12/60 = 0.6 hr. To travel 4.1 miles from starting point. V1 = d/T1 = 4.1/0.6 = 6.83 mi/h. V2=9.0 mi/h. when returning to starting point. V = (V1+V2)/2 = (6.83+9.0)/2 = 7.92 mi/h = Average velocity for entire trip.
June 2, 2014

physics
T^2 = 4pi^2(L/g) = 3.4^2 39.48(2.87/g) = 11.56 113.3/g = 11.56 11.56g = 113.3 g = 9.80 m/s^2
June 2, 2014

Kirr
P = Po(1+r)^n = $25,000 r = (1.825%/365)/100% = 5*10^-5 = Daily % rate expressed as a decimal. n = 365Comp./yr. * 4yrs. = 1460 Compounding periods. Po(1.00005)^1460 = 25000 Po = 25,000/1.00005^1460 = $23,240.
June 2, 2014

algebra math!
9pts/6wks = 1.5 Points/week.
June 1, 2014

physics
Wb = m*g = 40kg * 9.8N/kg = 392 N. = Weight of box. Fk=u*(Wb-F*sin31)=0.45(392-173*sin31) = 136.3 N.= Force of kinetic friction. Fn=F*CosA-Fk = 173*cos31 - 136.3 = 12 N. = Net force. a = Fn/m = 12/40 = 0.30 m/s^2.
June 1, 2014

Physics
hmax = L*sin A = 5*sin40 = 3.21 m. At top of incline: KE + PE = mg*hmax-Fk*L 0 + PE = mg*3.21-10*5 PE = mg*3.21-50. At bottom of incline: KE + PE = mg*3.21-50 KE + 0 = mg*3.21-50 KE = mg*3.21-50 = 35 J. m*9.8*3.21-50 = 35 31.5m-50 = 35 31.5m = 85 m = 2.7 kg. = Mass of box.
May 30, 2014

physics
V = Vo + g*Tr = 0 at max. ht. Tr = -Vo/g = -40/-9.8 = 4.08 s. = Rise time. T = 4.08-1 = 3.08 s. h1 = Vo*t + 0.5g*t^2 h1 = 40*3.08 - 4.9*3.08^2 = 76.7 m. h2 = 40*4.08 - 4.9*4.08^2 = 81.6 m. h2-h1 = 81.6-76.7 = 4.93 m. = Distance traveled in the last second.
May 30, 2014

physics
h = Vo*t + 0.5g*t^2 h = 0 + 5*3^2 = 45 m. = Height of object above gnd. (45-1)/4m = 11th floor.
May 30, 2014

physics
V^2 = Vo^2 + 2a*d V^2 = 0 + 10*10 = 100 V = 10 m/s.
May 30, 2014

algebra
I = 2.42*10^-5 Watts/cm^2. = Sound intensity. Io = 10^-16 Watts/cm^2 = Reference sound intensity. dB = 10^Log(2.42*10^-5/10^-16) = 114.
May 29, 2014

physics
h = L*sin A = 5.5*sin30 = 2.75 m. Fn = mg*Cos A = 66*Cos 30 = 57.16 N. = Normal force = Force perpendicular to the ramp. Fk = u*Fn = 0.22 * 57.16 = 12.57 N. = Force of kinetic friction. KE + PE = mg*hmax-Fk*L KE + PE = 66*2.75-12.57*5.5 = 112.4 J. 0 + PE = 112.4 PE = 112.4 J. ...
May 29, 2014

physics
1. W = Fk*d 25 * 12 Joules. 2. W = 175 * 12 Joules. 3. Wn = (175*12)-(25*12)
May 29, 2014

Physics
a. X = 45 N. Y = -22 N. F^2 = 45^2 + (-22)^2 = 2,509 F = 50.09 N. b. d = 22m/s * 3s = 66 m. Work = F*d = 50.09 * 66 = 3306 Joules.
May 29, 2014

Physics! Help
F1 + F2 = 96.2N.[55.4o] + 11.6N.[41.2o] X = 96.2*cos55.4 + 11.6*cos41.2=63.35 N
May 29, 2014

ALGERBRA
What are the "2 ways?" Perhaps some punctuation would help.
May 29, 2014

Physics
F = m*a = 1350 N. Impulse=m*V = m*(a*T) = 1350*6.2*10^-3= 8.37 kg-m/s.
May 29, 2014

Physics
D=2m[270o] + 16m[180o] + 24m[90o]+36m[180o]. Add the two 180o vectors directly: D = 2[270o] + 52[180o] + 24[90o] X = 2*cos270+52*cos180+24*cos90 = -52 m. Y = 2*sin270+52*sin180+24*sin90 = 22 m. D^2 = (-52)^2 + 22^2 = 3188 D = 56.5 m.
May 29, 2014

Physics
a. d = V*T = 420 m. (12.5-2.70) * T1 = 420 T1 = 420/(12.5-2.70) = 42.9 s. b. T2 = 420/(12.5+2.7) = 27.6 s. T = T1+T2 = 42.9 + 27.6 = 70.5 s. c. T1 = 420/12.5 = 33.6 s. T2 = T1 = 33.6 s. T = 33.6 + 33.6 = 67.2 s.
May 29, 2014

physics
V=100mi/h * 1600m/mi * 1h/3600s = 44.44m/s V = Vo + a*t = 0 a = -Vo/t = -44.444/10^-3=-44,444 m/s^2 F = m*a = 0.145 * (-44,444) = - 6444 N.
May 28, 2014

physics
Da = 69.5*T Db = 84.3*T B will have to travel 394 m(0.394km) farther than A to catch up: Db = Da + 0.394km 84.3 * T = 69.5 * T + 0.394 84.3T-69.5T = 0.394 14.8T = 0.394 T = 0.02662 h. = 1.60 Min. to catch up.
May 28, 2014

math
Slope = Tan A = Y/X = 1/6 A = 9.46o
May 27, 2014

math
Slope = Y/x = 16 Y/3 = 16 Y = 48 m.
May 27, 2014

physics
W = F*d*cos A = 457 * 6.2 * Cos 8 = 2806 J.
May 26, 2014

college physics
mgh2 - mgh1 = mg(h2-h1) = mg(3.1) = 64.7*9.8(3.1) = 1966 Joules.
May 26, 2014

college physics
a. Always negative.
May 26, 2014

Physics
The force of the golf club acts in parallel with the motion of the ball which is 28o. So my answer is 1650 N. @ 28o. Since they did not ask for the direction of the force, I did not include the angle. Your answer is not the full force acting on the ball; it is the hor. ...
May 26, 2014

Physics
a=(V-Vo)/t a = (55-0)/1.5*10^-3=36670 m/s^2 F = m*a = 0.045 * 36,670 = 1650 N.
May 26, 2014

Business mat
7x + 3 = 7x + b b = 7x-7x+3 = 3
May 24, 2014

Math
Eq1: Y = x^2+3x-4 Eq2: Y = 2x+2 In Eq1, replace Y with 2x+2 and solve for X: 2x+2 = x^2+3x-4 x^2+3x-2x = 2+4 x^2+x = 6 x^2+x-6 = 0 C = -6 = -2*3. (x-2)(x+3) = 0 x-2 = 0, X = 2. x+3 = 0, X = -3. Solution: X = -3, and 2.
May 23, 2014

math
1. Y = 4x + 12 = $44. 4x = 44-12 = 32 X = 8 Months = Oct. of same yr. 2.C 3. 8 < x + 3 X > 8-3 X > 5. 7 > 5 Answer = b = 7.
May 23, 2014

Math
Bought X boxes. Sold (x-5) boxes. Cost = $Y per box Selling price = $(y+0.1) per box. P = $6 * 1.25 = 7.50 = Sale price. (x-5)(y+0.1) = 7.50 xy + 0.1x - 5y - 0.5 = 7.5 Eq1: xy + 0.1x - 5y = 8 Eq2: xy = $6.00 Y = 6/x In Eq1, replace Y with 6/x: 6 + 0.1x - 30/x = 8 0.1x - 30/x...
May 23, 2014

math
Martin is X yrs. old. Joan is (x-3) yrs. old. 4x/5 = x-3 Multiply both sides by 5: 4x = 5x-15 X = 15 (4/5) * 15 = 12 yrs. = Joan's age.
May 23, 2014

math
Answer = b.
May 23, 2014

math
I = 2.42*10^-5 watts/cm^2 = Intensity. Io = 1*10^-16 watts/cm2 = Reference. db = 10*Log(I/Io) db = 10*Log(2.42*10^-5/1*10^-16) db = 10*Log(2.42*10^11) = 114.
May 23, 2014

math
Thu sales = $X Sat sales = $2X Other 4 days = $X/2 X/(x+2X+X/2) = X/(3 1/2)x = X/(7x/2) = x * 2/7x = 2/7.
May 23, 2014

physics
KE = 0.5m*V^2 = 900,000 J. 0.5*2000*V^2 = 900,000. Solve for V in m/s.
May 21, 2014

Algerbra 2
V = Vo - Vo*r*T V = 16,400 - 16,400*0.24*2 = $8528
May 21, 2014

Math
Do you mean: A(7,3.-4), B(-3,1,0). If so, X = (7+(-3))/2 = 2. Y = (3+1)/2 = 2. Z = (-4+0)/2 = -2. (x,y,z) = (2,2,-2).
May 21, 2014

Math
See previous post.
May 21, 2014

Math
C(h,k), P(x,y). x - h = x+5 x-x-h = 5 -h = 5 h = -5 y-k = y-2 y-y-k = -2 -k = -2 k = 2 C(-5,2). r = sqrt(9) = 3 Units.
May 21, 2014

math
-15-(-4) + (-12) + -8 -9 = -15 + 4 -12 -17 = -44 + 4 = -40.
May 21, 2014

Science
B. 1.
May 21, 2014

Science
1d. 2a.
May 20, 2014

Math
Incomplete.
May 20, 2014

Science
W = F*d = 200 * 45.5
May 19, 2014

physics
T^2 = 4pi^2(L/g) = (2.45)^2 39.48(1.25/g) = 6.00 6g = 49.35 g = 8.23 m/s^2
May 19, 2014

Math
csc R = 13/12 = 1/sin R 1/Sin R = 13/12 sin R = 12/13 = Y/r. X^2 + Y^2 = r^2 X^2 + 12^2 = 13^2 X^2 = 13^2 - 12^2 = 25 X = 5. Tan T = Y/X = 12/5
May 19, 2014

Algebra
Tan A = 5.67 A = 80 Degrees.
May 19, 2014

Geometry
A(0,0), B(a,0). AB is a hor. line, because Y is constant. AB = a - 0 = a. D(0,b), C(a,b). DC is a hor. line. DC = a - 0 = a. AB = DC, Because quantities that are = to the same or = quantities are = to each other. A(0,0), D(0,b). AD is a Vertical line, because X is constant. AD...
May 19, 2014

algebra
h max = ho + (V^2-Vo^2)/2g h max = 80 + (0-(64^2))/-64 = 144 Ft above gnd.
May 19, 2014

maths
Multiply numerator and denominator by 2^-(1-n): 1/2^(1-n) = 2^-(1-n)/1 = 2^(-1+n) = 2^(n-1)
May 19, 2014

maths
a. 16 = 2^4 b. 2^m/8 = 2^m/2^3 = 2^(m-3)
May 19, 2014

Algebra
P = Po(1+r)^n P = $25,000 Po = ? = Initial principal. r = (8%/2)/100% = 0.04 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 3.5yrs. = 7 Compounding periods. P = Po(1.04)^7 = 25,000 Po = 25,000/1.04^7 = $18,997.95 Down.
May 19, 2014

Physics
a = (V-Vo)/t = (-46-30)/5*10^-3 = -15.2*10^3 m/s^2. F = m*a = 0.15 * (-15,200) = -2280 N.
May 18, 2014

Math
a. Bal = 739.65 - 0.05*739.65 + 179.39 = $882.06 b. P min = 0.05 * 882.06
May 18, 2014

math
Ab = Ab = (W*L)/2 = (6*9)/2 = 27 in^2 = Area of the base. V = (Ab*h)/3 = (27*4)/3 = 36 in^3.
May 18, 2014

math
As = 2(L*h) + 2(W*h) + 2(L*W) As = 2(2*12) + 2(9*12) + 2(2*9) =
May 18, 2014

math
I don't know how they came up with $5100; perhaps you should double check that number. In a discounted loan, the discounted amount(Int.) is paid up-front by deducting it from the amount borrowed: Ab = $2,000 = Amount borrowed = Face value. Ar = Amount received by borrower...
May 18, 2014

physics
Vo = 12m/s[50o] Xo = 12*Cos50 = 7.71 m/s. Yo = 12*sin50 = 9.19 m/s. Tr = -Yo/g = -9.19/-9.8 = 0.938 s. Tf = Tr = 0.938 s. = Fall time. Tr+Tf = 0.938 + 0.938 = 1.876 s. = Time to return to launching height. Range=Xo * (Tr+Tf) = 7.71 * 1.876=14.46m D max = 14.46 + 8m/s * 1.876s ...
May 17, 2014

physics
Incomplete.
May 17, 2014

Physics
P = (0.45m/3.6m) * 1s. = 0.125 s. = The period of the wave. Freq. = 1/P = 1/0.125 = 8 Cycles/s = 8 Hz.
May 17, 2014

Physics
d=V*T = 3*10^8 * (1.9*10^-3/2) = 2.85*10^5 m.
May 17, 2014

Geometry
As = 2*(W*h)) + 2*(L*h) + 2(L*W) a. As = Al + 2*(L*W) = 992 Ft^2 Al + 2*(20*12) = 992 Al = 992 - 480 = 512 Ft^2.=Lateral area. b. Al = 2(W*h) + 2(L*h) = 512 Ft^2 2(12*h) + 2(20*h) = 512 Solve for h.
May 17, 2014

physics
Circumference = pi*2r = 3.14 * 80 = 251.3 cm. = 2.513 m. V=300rev/min * 2.513m/rev * 1min/60s = 12.57 m/s. = Linear speed. Va = 12.57m/s * 6.28rad/2.513m=31.4rad/s = Angular speed.
May 17, 2014

physics
X = 100N Y = 100N Tan A = Y/X = 100p/100 = 1.0 A = 45o = Direction. Fr = X/Cos A = = 100/Cos45=141.4N[45o]= Resultant force. a=Fr/m=141.4[45o]/100kg=1.414m/s^2[45o].
May 16, 2014

math
Ans: D
May 15, 2014

Pre cal
1. AB+BC = 200km[110o] + 100km[37o] X = 200*cos110 + 100*cos37 = 11.46 km. Y = 200*sin110 + 100*sin37 = 248.1 km. D^2 = X^2 + Y^2 = (11.46)^2+(248.1)^2 = 61,685 D = 248.4 km 2. V = 530mph[N25oW] = 530mph[115o] CCW.
May 15, 2014

Pre cal
1. An airplane flies 200 km on course 110 degrees from point A to point B. At point B the pilot changes course to 37 degrees. The plane then flies 100 km to point C. Find the magnitude of the net displacement from A to C. 2. A plane is flying on a bearing of 25 degrees west of...
May 15, 2014

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