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March 30, 2017

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Posts by henry

Total # Posts: 13,363

Physics
Fr = 5.9[28o] + 5[90o]. X = 5.9*Cos28 = 5.2Units. Y = 5*sin28 + 5*sin90 = 7.35 Units. Fr = sqrt(x^2+y^2) = Tan A = Y/X = 7.35/5.2 = 1.41346, A = 54.7o = The direction.
February 12, 2017

Math
1. x + y = 9. 2xy = 40, xy = 20, X = 20/y. x + y = 9. 20/y + y = 9, Multiply by Y: 20 + y^2 = 9y, y^2 - 9y + 20 = 0, (x-4)(x-5) = 0, Y = 4, and 5. x + y = 9. Solution set: (x,y)=(4,5),(5,4). So the numbers are 4, and 5. 2. 1st number = X. 2nd number = x+4. x^2 + (x+4)^2 = 208...
February 12, 2017

Physics
Vo = 5m/s[60o]. Xo = 5*cos60 = 2.5 m/s. Yo = 5*sin60 = 4.33 m/s. 1. Y = Yo + g*t. 0 = 4.33 - 9.8t, t = ?. 2. Y^2 = Yo^2 + 2g*h. 0 = 4.33^2 - 19.6h, h = ?. 3. Range = Vo^2*sin(2A)/g. Range = 5^2*sin(120)/9.8 =
February 12, 2017

science
The Elasticity of the balloon. The balloon can be stretched beyond its' normal size and can return to normal if the elastic limit is not exceeded.
February 11, 2017

physics
a. (185+182+183+182+182+184+183)/7 =
February 11, 2017

Physics
I drew out image of the situation but still need help. Can someone help with this problem about swinging on wrecking ball when at 1st: wrecking ball is in line with birdbath when at a peak in its trajectory, and in line with front door at the lowest point in the trajectory. ...
February 11, 2017

math
M*g = 35 * 9.8 = 343 N. = wt. of carton. Fp = 343*sin40 = 220.5 N. = Force parallel to the incline. Fn = 343*cos40 = 262.8 N. = Normal force. Fp-Fs = M*a. 220.5 - Fs = 35*0, Fs = 220.5 N. = Force of static friction.
February 11, 2017

math
Correction: 326 = 0.816T2, T2 = 400 N.
February 11, 2017

math
60o W. of N. = 150o CCW from +x-axis. 45o E. of N. = 45o CCW from +x-axis. The system is in equilibrium: 326*cos150 = -T2*cos45. 326 = 0.742T2, T2 = 400 N. Fb = -(T1*sin150+T2*sin45). Fb = -(326*sin150+400*sin45) = -446 N. = 446 N. Downward. M*g = 446. M = 446/g = 446/9.8 = 46...
February 11, 2017

Physics
While swinging on the wrecking ball, a student notices that, at first, the wrecking ball is in line with her birdbath when it is at a peak in its trajectory, and in line with her front door at the lowest point in the trajectory. However, since drag is acting against the ...
February 10, 2017

Physics
I was able to figure out mass of ball = to 720kg and velocity of ball and her is 1.90m/s
February 10, 2017

Physics
While swinging on the wrecking ball, a student notices that, at first, the wrecking ball is in line with her birdbath when it is at a peak in its trajectory, and in line with her front door at the lowest point in the trajectory. However, since drag is acting against the ...
February 10, 2017

Slopes
m = (7-4)/(-5-0) = -0.6 Y = mx + b. 4 = -0.6*(6) + b, b = 7.6. Eq: Y = -0.6x + 7.6
February 9, 2017

Math
r = 226mi/2h = 113 mi/h. d = r*t =
February 9, 2017

Math
csc A = 4/3. sin A = 3/4, x^2 + 9 = 16, X = sqrt7 = 7^(1/2). Cot A = sqrt7/3. sin A + sin A * cot^2 A = 3/4 + 3/4*(7^(1/2))^2 = 3/4+3/4*7 = 24/4 = 6.
February 9, 2017

Finance
My answer is unsecured debt.
February 8, 2017

math
Income/wk. = $12/wash * XWASHES = $12X. Cost/wk. = ($12/h*40h)2 + $450/wk. = $1410. Profit/wk. = 12x - 1410 = $3.25/wash * xwashes. = $3.25x. Profit/wk. = 12x - 1410 = 3.25x, X = 161.14 or 162 Washes.
February 8, 2017

algebra
Vp*t = 1600. Vp*5 = 1600, Vp = 320 mi/h. in still air. (Vp-Vw)*5.5 = 1600. 5.5Vp - 5.5Vw = 1600. 5.5*320 - 5.5Vw = 1600, Vw = ?.
February 7, 2017

Physics
8 - 5 = 3 N. M*g = 3, M = 3/9.8 = 0.306 kg = Mass of water displaced. V*D = 306 grams. V*1 = 306, V = 306 cm^3. volume of water displaced = volume of candle holder. M*g = 8 N. M = 8/g = 8/9.8 = 0.816 kg = Mass of candle holder. D = 816g/306cm^3 = 2.67 g/cm^3.
February 7, 2017

Science
F = M*G = 500 * 10 = 5000 N. P = F*d/(t*0.4) = 5000*80/(10*0.4) = 100,000 Watts.
February 7, 2017

Science
F = M*a. a = F/M. = 15,000/500.
February 7, 2017

Physics
2. F4 =-(F1*sin90+F2*sin170+F3*sin34.8)F4 = -(70 + 8.68 + 34.2) = -113 N. = 113 N. Downward.
February 6, 2017

Physics
F1 = 70N[90o]. F2 = 50N[170o], CCW from +x-axis. F3 = 60N[Xo]. 1. The hor. component of F2 and F3 must be equal and opposite: F3*Cos X = -F2*Cos170. 60*Cos X = -50*Cos170, Cos X = 0.82067, X = 34.8o. 2.
February 6, 2017

Physics
F1 = 70N[90o]. F2 = 50N[170o], CCW from +x-axis. F3 = 60N[Xo]. F3*Cos X = -F2*Cos170. 60*Cos X = -50*Cos170, Cos X = 0.82067, X = 34.8o.
February 6, 2017

Physics
V = 1000mi/2wks * 1wk./7days * 1day/24h = 2.98 mi/h.
February 6, 2017

Physics
a. V = Vo + a*t. -45 = 36 + a*0.002, a = ? F = M*a. b. V = Vo + a*t. 45[30o] = 36 + a*0.002, 39 + 22.5i = 36 + a*0.002, 3 + 22.5i = a*0.002, a = 1500 + 11,250i = 11,350 m/s^2[82.4o]. F = M*a = 0.15 * 11,350[82.4o] = 1,702N[82.4o]. Magnitude = 1,702 N.
February 6, 2017

math
I don't see the scale.
February 6, 2017

Physics
Range = Vo^2*sin(2A)/g. Range = 65^2*sin(2*37)/9.8 = 414.4 m.
February 5, 2017

Physics
V = Vo + a*t. 55 = 70 + a*25, a = ?.
February 5, 2017

Physics
V = 68mi/72min * 60min/h =
February 5, 2017

Physics
V^2 = Vo^2 + 2g*h. 0 = 69^2 - 19.6h, h = ?. V = Vo + g*t. 0 = 69 - 9.8t, t = ?.
February 5, 2017

physics
V^2 = vo^2 + 2g*h. V^2 = 0 + 19.6*27, V = 23 m/s.
February 5, 2017

Math
(x-2)/x > 1/2. 2x-4 > x, X > 4. Let x = 5. (5-2)/5 = 3/5.
February 5, 2017

math
A diagram of the problem: 1. Draw a rectangle with the longest sides hor. 2. Draw a hor. line through the ver. sides to form two rectangles. 3. Label the ver. sides of the lower rectangle h1(15m) and the ver. sides of the top rectangle h2. 4. Draw a diagonal from the upper ...
February 4, 2017

math
Tan 17 = h1/d. Tan 17 = 15/d, d = 49.1 m. = Distance between the buildings. Tan32 = h2/d. Tan32 = h2/49.1, h2 = 30.7 m. = ht. from window of 1st bldg. to top of 2nd bldg. h = h1+h2 = 15 + 30.7 = 45.7 m. = ht. of 2nd bldg.
February 4, 2017

Math
Yes! -9(x-63) = x + (-49) = x-49.
February 4, 2017

PHYSICS
A window washer pulls herself upward using the bucket-pulley apparatus.. Part A) How hard must she pull downward to raise herself slowly at constant speed? The mass of the person plus the bucket is 80 kg . Part B) If she increases this force by 16 %, what will her acceleration...
February 4, 2017

physics
The cable supporting a 2150-kg elevator has a maximum strength of 2.2×104 N . What maximum upward acceleration can it give the elevator without breaking?
February 4, 2017

Physics
1. V^2 = Vo^2 + 2a*d. (3*10^6)^2 = 0 + 2a*0.15, a = ?. 2. F = M*a, a = F/M = 4.9/0.5 =
February 3, 2017

maths
(75+82+90+X)/4 = 85. X = ?.
February 3, 2017

physics
See previous post.
February 3, 2017

physics
V = pi*r^2*(h2-h1). V = 3.14*6^2*(135-120) = 1696 cm^3.
February 3, 2017

Algebra
1. (3,2), (1,-4) m = (y2-y1)/(x2-x1) = (-4-2)/(1-3) = -6/-2 = 3. 2. (-2,4), (-4,6). m = (6-4)/(-4-(-2)) = 2/-2 = -1. 3. (7,4), (-5,-2). m = (-2-4)/(-5-7) = -6/-12 = 1/2. Y = mx + b 4 = (1/2)7 + b, b = 1/2. Y = (1/2)x + 1/2. 4. (1,4), (2,-8). m = (-8-4)/(2-1) = -12, Y = mx + b...
February 1, 2017

Math
3pizzas/4bro. = 3/4 Pizza/bro.
January 31, 2017

Physics
V1 = a1*t1 = 1.76 * 20 = 35.2 m/s. d1 = 0.5a1*t1^2 = 0.88*20^2 = V2 = V1 + a*t = 35.2 - 5.93*5 = 5.55 m/s. The 5-second deceleration is not enough to bring the car to a full stop. d2 = V1*t + 0.5a*t^2. d2 = 35.2*5 - 0.5*5.93*5^2 = d = d1+d2 =
January 31, 2017

algebra
14x -3 y to the negative 4 / 2x5 y to the negative 2 how do you do this
January 31, 2017

math
1. I = Po*r*t = 1200*(0.105/12)*3. 2. P = Po + Po*r*t. P = 1200 + 1200*0.0775*2 = 3. 100%-20% = 80% financed. Po = 0.80 * 69,500 =
January 31, 2017

Math
4. 30/80 = 6/16. Not 6/18.
January 30, 2017

Math
1. 4/20 = 1/5. Not 1/6.
January 30, 2017

math
a. 1957 total CDs. X pop CDs. x-256 hip-hop CDs. (x-256)/3 country CDs. x + (x-256) + (x-256)/3 = 1957. Multiply both sides by 3 and solve for x. c. Country CDs/3.
January 30, 2017

Physics
V2 = V1 + a*t. 60 = 0 + a*4, a = 15 m/s^2. d = V1*t + 0.5a*t^2. V1 = 0, t = 4 s., a = 15 m/s^2, d = ?.
January 30, 2017

physics
Mb*V1 + Ma*V2 = Mb*V3 + Ma*V4. 5*3 - 10*3 = 5*V3 + 10*2, -15 = 5V3 + 20, V3 = -7 m/s = 7 m/s to the left.
January 30, 2017

Science
Incomplete.
January 29, 2017

Science
A. d = Vo*t + 0.5a*t^2. d = 0 + 1*30^2 = B. V = a*t.
January 29, 2017

physics
Tan A = (-3.50)/116.5 = -0.030043, A = -1.72o = 1.72o S. of E. Tan1.72 = d/153, d = 4.59 m.
January 29, 2017

Physics
Range = Vo^2*sin(2A)/g. 2.4 = 7^2*sin(2A)/9.8. A = 14.7o. = Minimum launching angle. Max. range occurs at 45o: Range = 7^2*sin(2*45)/9.8 = 5 m., max. Range of launch angles = 14.7 t0 45o.
January 28, 2017

algebra
t = 4/8 * 32h =
January 28, 2017

physics
2. Continued. d = V*t, V = 3*10^5 km/s, t = ?.
January 28, 2017

physics
1. 10^56/10^35 = 2. d = 3.3AU * 1.499*10^8km/AU =
January 28, 2017

Pre Cal
A ) B + C = 180. A + 62 + 48 = 180, A = 70o. sinB/b = sinA/a. b = ?.
January 27, 2017

biology
1)Can you suggest reasons why a phylogeny based on molecular evidence and a phylogeny based on morphology and other evidence might not be exactly the same? 2) Zoologist worldwide are sequencing a mitochondrial gene CO1 (cyctochrome c oxidase subunit), which is found in all ...
January 27, 2017

Physics
M*g = 300 * 9.8 = 2940 N. = Wt. of furniture. Fk = Force of kinetic friction. F1 = 45 N. F2 = 80*Cos25 = 72.5 N. F1+F2 - Fk = M*a. Fk = ?.
January 27, 2017

Physics
a. V = Vo + a*t. V = 0, Vo = 15 m/s, t = 0.3 s., a = ?. a will be negative. b. F = M*a. F will be negative.
January 27, 2017

physics
F = 2N/0.2cm * 2cm = 20 H. Work = F*d.
January 26, 2017

math
X tickets sold. x/6 children's tickets. 40 seniors tickets. X/2 adult tickets. x/6 + 40 + x/2 = X. x/6 + 40 + 3x/6 = x, 4x/6 - x = -40, -2x/6 = -40, X = 120. x/6 = 120/6 = 20. x/2 = 120/2 = 60 2*20 + 3*40 + 6*60 = $520 Collected.
January 26, 2017

math
Correction: Ignore the "10".
January 26, 2017

math
10 100ft^2/2 = 50 ft^2/sq. s^2 = 50, s = 7.071 ft. 7.071ft/side * 8sides = 56.57 ft = total required. But we have only 56 ft.
January 26, 2017

math
At = Ag + Arg. At = 6 + Arg, We need to know the dimensions of the area surrounding the rose garden. Then we could calculate At, the total area which leaves only one unknown(Arg), the area of the rose garden.
January 26, 2017

Science
d = V*t.
January 26, 2017

Math
Flour/Milk = Y/X = 5/4. a. Yes. b. Y/X = 5/4, Y/14 = 5/4, Y = ?.
January 25, 2017

Math
See previous post: Wed, 1-25-17, 8:22 P.M.
January 25, 2017

physics
Disp. = -34i + 117 + 64.5i + 28.5 = 145.5 + 30.5i. Magnitude = sqrt(145.5^2+30.5^2) =
January 25, 2017

Math
Wed.: d = r*t1 = 50mi/h * (43/60)h = 35.83 mi. Thu.: t2 = d/r = 35.83/68 = 0.527 h. = 31.6 min. t1-t2 = 43-31.6 = 11.4 min = Time saved.
January 25, 2017

Physics
40m/1min = 40m/60s = 0.667 m/s.
January 25, 2017

Math
5/20 = 1/4. A. = 1/4. D. 25/10 = 1/4.
January 24, 2017

physics
The positive and negative plates of a parallel-plate capacitor have an area of 1.05 cm by 1.05 cm. Their surface charge densities are +1.00×10-6 C/m2 and -1.00×10-6 C/m2, respectively. A proton moving parallel to the plates enters the middle of the space between ...
January 24, 2017

science
The system is in equilibrium: 30o W. of N. = 120o CCW. T1*Cos120 = -T2*Cos60. T1 = T2. T1*sin120 + T2*sin60 = -(-10) = 10. T2*sin120 + T2*sin60 = 10, 0.866T2 + 0.866T2 = 10, T2 = 5.77 N. T1 = T2 = 5.77 B.
January 24, 2017

applied mechanics
Vo = 72000m/3600s = 20 m/s. V = Vo + a*t = 0. 20 + a*5 = 0, a = -4 m/s^2. V^2 = Vo + 2a*d. V = 0, Vo = 20 m/s, a = -4 m/s^2, d = ?.
January 24, 2017

Algebra
K = (M2-M1)/(d2-d1) = (30-12)/(18-15) = 6 kg/cm . d = (12kg/6kg) * 1cm = 2 cm. L + 2 = 15, L = 13 cm.
January 24, 2017

Science
F = m*g in Newtons(N). Work = F*d in Joules.
January 24, 2017

Math
Assuming simple interest: P = Po + I = Po + Po*r*t. P = 6500 + 6500*0.09*4 = 6500 + 2340 = $8840 = Total amt. paid. I = P=Po =
January 24, 2017

Math
a. d = r*t. b. t = d/t. Eq1: t1 + t2 = 4 1/3 h. = 13/3 h. Eq2: 60t1 + 90t2 = 350 km. Solve the 2 Eqs simultaneously: -60t1 - 60t2 = -260 +60t1 + 90t2 = 350 sum: 30t2 = 90, t2 = 3 h. t1 + 3 = 13/3, t1 = 4/3 = 1 1/3 h. d1 = 60 * 4/3 = d2 = 90 * 3 =-
January 24, 2017

Geometry
As = 2pir^2 + pi*2r*h. As = (6.28*8^2) + (3.14*16*24) = 1608 m^2.
January 23, 2017

Math
a. 3:05, and 3:10. b. 5:00, and 6:05. c. 10:00, and 11:00.
January 23, 2017

Maths
c = X cm. a = x+20 cm. b = x+20 + 50 cm. a + b + c = 270. x+20 + x+20+50 + x = 270. X = ?. b = x+20+50.
January 23, 2017

physics
T = 2pi*sqrt(L/g). pi = 3.14., L = 1.25 m., g = 9.8 m/s^2.
January 23, 2017

math
a = b. x+2y = -2x+6y+1. Eq1: 3x-4y = 1. a + b + c = 28. x+2y -2x+6y+1 + 4y = 28. Eq2: -x+12y = 27. Add Eq1 and Eq2, solve for X, and Y: +3x - 4y = 1 -3x + 36y = 81(3*Eq2). sum: +32y = 82, Y = 41/16. In Eq1, replace Y with 41/16, and solve for X: 3x - 4*41/16 = 1, X = 15/4. X...
January 22, 2017

Mathematics
1. P1 = Po + Po*r*t. P1 = 12,500 + 12,500*0.12*3 = 2. P2 = Po(1+r)^n. Po = 12,500, r = 0.10. n = 1comp./yr. * 3yrs. = 3 compounding periods. P1-P2 =
January 22, 2017

math
Eq1: 4x + 2y = -2. m1 = -A/B = -4/2 = -2. m2 = m1 = -2. P2 = (-5,-7). Y = mx + b = -7, -2x + b = -7, b = -7+2x = -7 + 2(-5) = -17. Eq2:Y = -2x - 17.
January 20, 2017

physical science
Fr = -300 + 150 = -150 N. = 150 N. to the left.
January 20, 2017

math
C = pi*D = 3.14 * 25 = 78.5 in. 5,280ft/mi * 12in/ft. * 360o/78.5in * 295mi =
January 19, 2017

Math
The altitude(ht.) bisects the vertical angle and the base: 118/2 = 59o. Tan(90-59) = h/5. h = ?.
January 19, 2017

Math
Concentration = 6*120mg/60mls =
January 18, 2017

Physical Science.
Displacement is the straight-line distance from the end point to the starting point. The path traveled might not be a straight line. Displacement =< Distance traveled.
January 18, 2017

Algebra
T = T1*T2/(T1+T2) = 16*15/(16+15) =
January 18, 2017

Math
B.
January 18, 2017

math
0nes place = 9. tens place = X. hundreds place = X+1. x + x+1 = 11. X = 5. 659 blocks.
January 18, 2017

Algebra 2
2 People: 60boxes/10min . = 6 boxes/min. 6 People: (6/2) * 6 = 18 boxes/min. T = 120boxes * 1min/18boxes = 6.67 min.
January 18, 2017

dynamics
V1 = 400m/20s = 20 m/s. V2 = 400m/30s = 13.33 m/s. a = (V2-V1)/(T2-T1) = (13.33-20)/(30-20) = -0.667 m/s^2. V2 = V1 + 2a*d. 13.33 = 20 - 2*0.667*d. d = ?.
January 18, 2017

physics
a. M1*V1 + M2*V2 = 2.9*5.4 - 1.5*1.4 = 13.6
January 17, 2017

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