Saturday
July 4, 2015

Posts by henry


Total # Posts: 10,681

Algebra
x = -1/3 x + 1/3 = 0 x = 3/7 x - 3/7 = 0 (x+1/3)(x-3/7) = 0 x^2 - 3x/7 + x/3 - 1/7 = 0 Multiply by 21: 21x^2 -9x + 7x - 3 = 0 21x^2 - 2x - 3 = 0
April 17, 2015

Algebra
Use same procedure as previous problem.
April 17, 2015

Algebra
x^2 - 2x + 2 = 0 X = (-B +- sqrt(B^2-4AC))/2A X = (2 +- sqrt(4-8))/2 X = (2 +- sqrt(-4))/2 X = (2 +- sqrt(4(-1))/2 X = (2 +- 2sqrt(-1)/2 X = (2 +- 2i)/2 = 1 +- i = 1+i, and 1-i. Check: (1+i)^2 - 2(1+i) + 2 = 1 + 2i - 1 - 2 -2i + 2 = 0
April 17, 2015

Algebra
(x+2)^2 + (x-7)(x-2) = 16 x^2 + 4x + 4 + x^2 - 2x -7x + 14 = 16 2x^2 - 5x + 18 = 16 2x^2 - 5x + 2 = 0 A*C = 2*2 = 4 = (-1)*(-4). Choose the pair of factors whose sum = B 2x^2 - (x+4x) +2 = 0 (2x^2-x) - (4x-2) = 0 x(2x-1) - 2(2x-1) = 0 (2x-1)(x-2) = 0 2x-1 = 0 2x = 1 X = 1/2 x-...
April 17, 2015

Help with Psychology
To help Karen overcome her fear of thunderstorms, a behavior therapist asks her to relax and imagine watching light rain with distant thunder. The therapist is using... a) client-centered therapy b) cognitive therapy c) systematic desensitization d) aversive conditioning ** ...
April 17, 2015

Physics
db = 10*Log W/Wo = 100 10*Log W/10^-12 = 100 Log W/10^-12 = 10 Log W - Log 10^-12 = 10 Log W = 10 + Log 10^-12 = 10-12 = -2 W = 10^-2 = 0.01 Watts.
April 17, 2015

physics
D = 5 + 10[30o] X = 5 + 10*Cos30 = 13.66 m. Y = 10*sin30 = 5 m. D = sqrt(X^2+Y^2) = sqrt(13.66^2 + 5^2) = 14.5 m.
April 17, 2015

Math
F = M*a = 0.04 * 2.5 = 0.1 N. a = F/M = 0.1/0.050 = 2.0 m/s^2
April 16, 2015

exponential equations
See previous post: Tue, 4-7-15, 7:04 AM.
April 16, 2015

Physics
h = 0.5g*t^2 g = 9.8 m/s^2. h = 0.75 m. Solve for t(Fall time). V^2 = Vo^2 + 2g*h Vo = 0 Solve for V. Dx = Xo*t Xo = 1.50 m/s t = Fall time. Solve for Dx
April 16, 2015

math
One Solution: Add to verify. -3x + 2y = 4 3x + 2y = 4 No Solution: Multiply Eq1 by (-1) and add. -3x + 2y = 4 -3x + 2y = 6 Infinite Solutions: Multiply Eq1 by 3 and compare. -3x + 2y = 4 -9x + 6y = 12
April 16, 2015

College Physics
See Related Questions: Thu, 8-26-14, 5:07 PM.
April 16, 2015

math
= 0.36603
April 16, 2015

physics
2nd Cable Direction = 30o E. of N.
April 15, 2015

physics
a = Fx/M = 15*Cos15/M
April 15, 2015

physics
V^2 = Vo^2 + 2a*d V = 0 Vo = 27 m/s d = 578 m. Solve for a. It will be negative. F = M*a
April 15, 2015

physics
M*g = 741 M = 741/g = 741/9.8 = 75.6 kg M*g = 5320 N. g = 5320/M = 5320/75.6 = 70.4 m/s^2
April 15, 2015

Math
Correction: You probably want the multiplication done without converting to base 10. I can't show it clearly here But it is long-hand multiplication. 1111 0101 0011110 0111100 1001011= Product = 75 base 10.
April 15, 2015

Math
1111 * 101 (1*2^3+1*2^2+1*2^1+1*2^0)*(1*2^2+0*2^1+1*2^0) = (8+4+2+1)*(4+0+1) = (15) * (5) = 75
April 15, 2015

Physics
a = F/M = 8/0.5 = 16 m/s^2 V^2 = Vo + 2a*d Vo = 0 a = 16 m/s^2 d = 4 m. Solve for V(m/s).
April 15, 2015

math
6*(1.2 * 1.2 * 1.2) = 6(1.2^3) = 10.37 in^3.
April 15, 2015

angles
ABD = ABC - DBC = 71 - 45 = 26
April 15, 2015

Physics
Vo = 7 m/s V = 3 m/s t = 8 s. V = Vo + a*t Solve for a. It should be negative. d = Vo*t + 0.5a*t^2 Solve for d.
April 15, 2015

physics
Wt. = M*g Newtons.
April 15, 2015

Science
Momentum = M*V
April 14, 2015

Physics
Y^2 = Yo^2 + 2g*h = 0 Yo^2 = -2g*h = -2*(-9.8)*10,000 = 196,000 Yo = 443 m/s.=Ver. component of initial velocity. Vo = Yo/sin60 = 443/sin60 = 512 m/s = Initial velocity = Speed at which the cannon is fired.
April 14, 2015

math analysis
Plane #1: d1 = 140mi/h[38o] * 2h = 280mi/h[38o] Plane #2: d2 = 180mi/h[350o] * 2h = 360mi[350] d = d2-d1 = 360[350o] - 280[38o] X = 360*Cos350 - 280*Cos38 = 134 mi Y = 360*sin350 - 280*sin38 = -235 mi D^2 = X^2 + Y^2 = 134^2 + (-235)^2 = 73,181 D = 270.5 Miles apart.
April 14, 2015

Science
1. Amplitude and wavelength. 4. Freq. 8. The freq. 9. To transmit signals.
April 14, 2015

Physics
See previous post: Sat, 4-11-15, 4:23 AM.
April 14, 2015

physics
Work = F*h = Mg*h = 400*9.8 * 60 = 235,200 J. = Output energy. Input energy = Output/Eff. = 235,200/0.8 = 294,000 J.
April 14, 2015

Allegbra
Use Quadratic Formula and get: 11.24
April 13, 2015

Science
For a given power output, the higher the voltage the lower the current. The lower current means less I^2*R loss. P = E*I = 100 * 10 = 1000 W. P = 1000 * 1 = 1000 W. Note: When E is increased to 1000 volts, the current is reduced to 1A.
April 13, 2015

physics
Fb = 80 kHz = Freq. emitted by the bat. Fh = 78 kHz = Freq. heard. Vs = 343 m/s = Velocity of sound in air. a. The bat is moving away. b. Fh = (Vs-Vr)/(Vs+Vb) * Fb = 78 kHz (343-0)/(343+Vb) * 80 = 78 Solve for Vb, the velocity of the bat.
April 13, 2015

science
M1*V1 + M2*V2 = M1*V + M2*V 40*2 + 4*0 = 40V + 4V 44V = 80 V = 1.82 m/s.
April 13, 2015

Physics
Incomplete.
April 12, 2015

Maths help
See previous post: Sat, 4-11-15, 4:23 AM.
April 12, 2015

Maths help
See previous post: Sat, 4-11-15, 4:24 AM.
April 12, 2015

CIRCUIT
E = 3 + 7 +V3 = 12 Solve for V3
April 12, 2015

Physic
P = 75 + 25 = 100 W., Total. P = 120 * I = 100 I = 100/120 = 0.833A R = E/I = 120/0.83333 = 144 Ohms.
April 12, 2015

Physic
See previous post: Thu, 4-9-15, 4:55 AM.
April 12, 2015

Physic
E = 120 V. R1 = 4.8k R2 = ? R1+R2 = 4(R1*R2)/(R1+R2) (R1+R2)^2 = 4(R1*R2) R1^2+2R1*R2+R2^2 = 4R1*R2 23.04+9.6R2+R2^2 = 19.2R2 R2^2 - 9.6R2 + 23.04 = 0 Use Quadratic formula R2 = 4.8k Check: Parallel Connection P1 = E^2/2.4k = 120^2/2.4k = 6,000 mW = 6 W. Series connection P2...
April 12, 2015

Math, Circuits
R1 = 3,000 Ohms = 3k Ohms R2 = 0.5k R3 = 10k I = 15 mA V1 = I*R1 = 15mA * 3k = 45 V.
April 12, 2015

CIRCUITS
Rt = R1+R2+R3 = 20k + 20k + 20k = 60k Ohms. = Total resistance. I = E/Rt = 120/60k = 2 mA(milliamps). V1 = V2 = V3 = I*R1 = 2 * 20k = 40 Volts Therefore, the voltage across each resistor is 40 Volts.
April 12, 2015

Science
M*g = 7 N. M = 7/g = 7/9.8 = 0.71 kg a = (Fap-Ff)/M = 1.4-1)/0.71=0.56 m/s^2 V = Vo + a*t = 0 + 0.56*4 = 2.24 m/s
April 11, 2015

MATHSS
Eq1: R1 + R2 = 1600 Ohms. Eq2: R2 = 2R1 - 560 Ohms. In Eq1, replace R2 with 2R1-560 R1 + 2R1-560 = 1600 3R1 = 2160 R1 = 720 Ohms In Eq1, replace R1 with 720 Ohms. 720 + R2 = 1600 R2 = 880 Ohms
April 11, 2015

MATHSS
Theta = 4 Rad. Wo = 3.2? Rad/s a = 0.6rad/s^2 Theta = Wo*t + 0.5a*t^2 = 4 rads. 3.2t + 0.5*0.6t^2 = 4 0.3t^2 + 3.2t - 4 = 0 Use Quadratic Formula. t = 1.13 s (Wo = 3.2 rad/s). t = 0.125 s (Wo = 32 rad/s).
April 11, 2015

Mathematics
Leslie: 4.5Laps/0.75h = 6 Laps/h Kala: 3.5Laps/0.75h = 4.67 Laps/h 6Laps/h - 4.67Laps/h = 1.33 Laps/h. Therefore, Leslie can run 1.33 more laps in 1 hr. than Kayla.
April 10, 2015

PHYSICS
Impulse = M*V = 3 * 2 = 6
April 10, 2015

Physics
Vr = 14 * pi*r^2 * h = 3.14*(0.295/2)^2 * 6.5 = 6.22 m^3 = Volume of the raft. Vr*Dr = 6.22m^3 * 600kg/m^3 = 3732 kg = Mass of the raft. Vw*Dw = 6.22m^3 * 1000kg/m^3 = 6220 kg = Mass of the water displaced. 6220 - 3732 = 2488 kg can be added to the raft. 2488kg * 1person/75kg...
April 9, 2015

Maths
a. X stamps, Total. 124 stamps, Australia 0.3x stamps, France 0.3x-12 stamps, Japan X = 124 + 0.3x + 0.3x-12 0.4x = 112 X = 280 b. 280 + n = 1.25*280 = 350 n = 70 Stamps from Lisa's aunt. (0.3x+n)/350 = (84+70)/350 = 0.44 = 44% from France.
April 9, 2015

Physics
a. Fr = 10N[60o]CCW + 15N[0o] X = 10*Cos60 + 15 = 20 N. Y = 10*sin60 = 8.7 N. Q1. Tan A = Y/X = 8.7/20 = 0.433 A = 23.4o N. of E. Fr = X/Cos A = 20/Cos23.4=21.8 N.[23.4o] N. of E. = 23.4o CCW b. Equilibrant: X = -20 Y = -8.7 Q3. Tan A = Y/X = -8.7/-20 = 0.433 A = 23.4o S. of W...
April 9, 2015

Physic
R1 = 1.4k Ohms R2 = 2.5k Ohms R3 = 3.7k Ohms P1 max = I1^2*R1 = 500 mW I1^2*1.4 = 500 I1^2 = 357.14 I1 = 18.9mA, max = Total current. Req. = R1 + (R2*R3)/(R2+R3) = 1.4 + (2.5*3.7)/(2.5+3.7) = 1.4 + 1.49 = 2.89k Ohms E max = I1*Req = 18.9 * 2.89 = 54.6 V. =
April 9, 2015

math
b. h = Vo*t + 0.5g*t^2 Vo = 192 Ft/s g = -32Ft/s^2 h = 432 Ft. Solve for t(Use Quadratic formula). c. h max = -(Vo^2)/2g = -(192^2)/-64 = 576 Ft. d. V = Vo + g*Tr = 0 Tr = -Vo/g = -192/-32 = 6 s. = Rise time Tf = Tr = 6 s. = Fall time. Tr+Tf = 6 + 6 = 12 s. to hit gnd.
April 9, 2015

math
h = Vo*t + 0.5g*t^2 Vo = 192Ft/s t = 10 s. g = -32Ft/s^2 Solve for h.
April 9, 2015

Physics
M*g = 330 * 9.8 = 3234 N. = Wt. of sled. Fp = 3234*sin6 = 38 N. = Force parallel to the incline. Fn = 3234*Cos6 = 3216 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.135 * 3216 = 434.2 N. = Force of kinetic friction. a = (Fap-Fk)/M = (1780-434)/330 = 4.08 m/s^...
April 9, 2015

Physics
Vo = 101km/h = 101,000m/3600s = 28.1 m/s = Initial velocity. See Related Questions: Tue, 10-28-14, 2:33 AM.
April 9, 2015

math
P = Po - Po*r*t = 11,090.41 120,000 - 120,000*r*12 = 11,090.41 -1,440,000r = 11,090.41 - 120,000 r = 0.0756 = 7.56% per annum
April 8, 2015

Physics
M*g = 59.9 * 9.8 = 587 N. = Wt. of girl and sled. Fp = 587*sin30 + 131 = 424.5 N. = Force parallel to the incline. Fn = 587*Cos30 = 508.4 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.217 * 508.4 = 110.3 N. = Force of kinetic friction. a=(Fp-Fk)/M = (424.5-...
April 8, 2015

DPS PHYCIS
Fr = 10[30] + 10[60o] X = 10*Cos30 + 10*Cos60 = 13.66 Units Y = 10*sin30 + 10*sin60 = 13.66 Units Fr = sqrt(X^2+Y^2)
April 8, 2015

Physics
Wavelength=V*P = V*(1/F) = V*(1/3.8) = 0.48 m. V/3.8 = 0.48 V = 1.82 m/s
April 8, 2015

Physics
1. V = 3400rev/min * 6.28rad/rev * 1min/60s = 356 rad/s V = Vo + a*t V = 356 rad/s Vo = 0 t = 50 s. Solve for a(rad/s^2).
April 7, 2015

physics
M1*V1 + M2*V2 = M1*V + M2*V 15*5 + 3*V2 = 15*1.5 + 3*1.5 3V2 = 27 - 75 = -48 V2 = -16 m/s = 16 m/s to the left.
April 7, 2015

Physics
a. V = Vo + a*t V = 51.5 m/s Vo = 41.5 m/s a = 2.65 m/s^2 Solve for t. b. Same procedure and answer as part a.
April 7, 2015

Grambling
a. D = 4.58 + 6.25i - 8.65 - 1.84i = -4.07 + 4.41i, Q2 D = sqrt(4.07^2+4.41^2) km. b. Tan A = Y/X = 4.41/-4.07 = -1.08354 A = -47.3o = 47.3o N. of W.
April 7, 2015

Grambling
V^2 = Vo^2 + 2a*d V = 11.4 m/s Vo = 83.8 m/s d = 750 m. Solve for a. It should be negative.
April 7, 2015

Physics
h = 6.03*sin21.5 = 2.21 m. V^2 = Vo^2 + 2g*h = 4.87^2 + 19.6*2.21 V = Final velocity Vo = 4.87 m/s g = 9.8 m/s^2 Solve for V.
April 7, 2015

Physics
PE max = Mg*h-Fk*h = 0.5*M*V^2 M = 98.5 kg g = 9.8 m/s^2 h = 4 m V = 1.81 m/s. Solve for Fk. Divide both sides by M, and solve for Fk
April 7, 2015

math help
Tank #1 = T min. Tank #2 = (T+60) min. T*(T+60)/(T+T+60) = 40 min (T^2+60T)/(2T+60) = 40 T^2+60T = 80T+2400 T^2 - 20T - 2400 = 0 Use Quadratic Formula. T = 60 min. T + 60 = 60 + 60 = 120 min.
April 7, 2015

Please help asap science
A. Ri = 0.4 + 0.4 = 0.8 Ohms B. I = E/(Ri+Rm+Ra+Rb) = 24/6.95 = 3.45A
April 7, 2015

Physics
D. P = 12 * 1.4 = 16.8W. = Greatest energy consumption.
April 6, 2015

geometry
2x+5 + 5x-79 + 122 = 180 7x = 180 + 79 = 259 X = 37 m<YWZ = 5x-79 = 5*37 - 79 = 106o
April 6, 2015

physics
a. 5000 Watts = 5,000 J/s = 5000 Joules every second.
April 6, 2015

Physics
a. Circumference = pi * 2r = 3.14 * 0.9 = 2.83 m. Arc = 2.83m/360o * 170o = 1.33 m. b. V = 0.25rad/s * 2.83m/6.28rads = 0.113 m/s. c. If the velocity is constant, the acceleration is zero.
April 6, 2015

physics
Max ht. occurs at 45o. Vo = 4m/s[45o] Yo = 4*sin45 = 2.83 m/s = Ver. component of initial velocity. Y^2 = Yo^2 + 2g*h Y = 0 Yo = 2.83 m/s. g = 9.8 m/s^2 Solve for h.
April 6, 2015

physics
See previous post: Mon. 4-6-15, 8:58 AM.
April 6, 2015

physics
V = Vo + a*t = 30 m/s 0 + a*20 = 30 a = 1.5 m/s^2 d = 0.5a*t^2 = 0.5*1.5*10^2 = 75 m.
April 6, 2015

Physics
V = g*t V = 20*1 = 20 m/s. V = 20*2 = 40 m/s. V = 20*3 = 60 m/s. Increase = 20 m/s with each second.
April 5, 2015

math
(1/2)/3 = 1/2 * 1/3 = 1/6 of the Half- pie. 1/2 * 1/6 = 1/12 of the whole pie.
April 4, 2015

physics
Momentum before the collision=Momentum after the collision: M1*V1 + M2*V2 = M1*V + M2*V 0.075*80 + 13*0 = 0.075*V + 13*V 6 + 0 = 13.075V V = 0.459 m/s
April 4, 2015

physics
M!*V1 + M2*V2 = M1*V + M2*V 0.075*80 + 13*0 = 0.075*V + 13*V 6 + 0 = 13.075V
April 4, 2015

Physics
M*g = 13 N. = Wt. of puck. M = 13/g = 13/9.8 = 1.33 kg. Fn = 13*cos37 = 10.4 N. Fk = u*Fn = 0.08 * 10.4 = 0.831 N. sin37 = h/3 h = 3*sin37 = 1.81 m. PE = Mg*h - Fk*d = 13*1.81 - 0.831*3 = 21.04 J. At bottom of ramp: KE = PE = 0.5*M*V^2 = 21.04 J. 0.5*1.33*V^2 = 21.04 V^2 = 21....
April 3, 2015

Physics
V^2 = Vo^2 + 2a*d = 0 + 2a*2pi = 4a*pi V = 2*sqrt(pi*a) = 2*1.772*sqrt a = 3.54*sqrt a
April 3, 2015

math
Sam has X stamps. Jill has (576-X) Stamps. X-x/7 = 6x/7 = Sam's bal. 576-x + x/7 = 576 - 6x/7 = Jill's bal. 1/4(576-6x/7) = 144 - 6x/28 3/4(576-6x/7) = 432 - 9x/14 = Jill's new bal. 6x/7 + 144-6x/28 = 144 + 24x/28-6x/28 = 144 + 9x/14 = Sam's new bal. Jill's...
April 2, 2015

Physics
M*g = 475 * 9.8 = 4655 N. P = F*d/t = Mg * d/t = 4655 * 10/24 = 1940 J/s = = 1940 W. = 1.94 kW
April 2, 2015

math help`
Any pair of parallel lines will have equal slopes. I don't know what you mean by "some is always -1".
April 2, 2015

math
Multiply Eq1 by -2 and add the Eqs: -4x + 6y = 4 +4x + y = 24 Sum: 7y = 28 Y = 4 In Eq1, replace Y with 4 and solve for X
April 2, 2015

algebra
d1 = d2 60 + 60t = 80t 20t = 60 t = 3 h.
April 2, 2015

Physics
When t = 0, X = 0-0 +6 = 6 m. When t = 3 s., X = 3^2 - 4*3 + 6 = 3 m. d = 6-3 = 3 m.
April 2, 2015

physics
See previous post: Wed, 4-1-15, 6:39 AM.
April 2, 2015

Physics
If they were wired in series, All lights will go out when one bulb burns out. Therefore, they are connected in parallel.
April 2, 2015

Physics 101
Correction: a = (Fp-Fk)/M = (122.6-63.65)/25 = 2.36 m/s^2
April 2, 2015

Physics 101
M*g = 25 * 9.8 = 245 N. = Wt. of the box Fp = 245*sin30 = 122.5 N. = Force parallel to the incline. Fn = 245*Cos30 = 212.2 N. = Force perpendicular to the incline. Fk = u*Fn = 0.30 * 212.2 N. = 63.65 N. = Force of kinetic friction. a = (Fp-Fk)/M*sin30 = (122.5-63.65)/12.5 = 4....
April 2, 2015

Finances
a. P = Po(1+r)^n Po = $600 r = 1.5%/100 = 0.015 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 2yrs. = 24 Compounding periods. Solve for P. Monthly Payment = P/24 a. Simple Interest: P = Po + Po*r*t = 600 + 600*0.015*24 Solve for P. Monthly payment = P/24 b. Same ...
April 1, 2015

Physic
V = Vo + a*t V = 6.5 m/s Vo = 0 t = 22 s. Solve for a. d = 0.5a*t^2 t = 22 s. Solve for d
April 1, 2015

Physic
V = Vo + a*t v = 22 m/s Vo = 5 m/s t = 18 s. Solve for a.
April 1, 2015

Physic
M*g = 637 N. g = 9.8 m/s^2 M = Mass in kg Solve for M.
April 1, 2015

Geometry
X = 3-2.5 = 0.5 m. Y = 1.5 m. Tan A = Y/X = 1.5/0.5 = 3.0 A = 71.57o Tan 71.57 = h/3 Solve for h.
April 1, 2015

math
See previous post: Tue, 3-31-15, 5:18 PM.
April 1, 2015

physics
M*g = 150 N = Wt. of the boy = Normal force(Fn). Fk = u*Fn = 0.05 * 150 = 7.5 N. = Force of kinetic friction. Fap-Fk = M*a Fap-7.5 = M*0 = 0 Fap = 7.5 N. = Force applied.
April 1, 2015

algebra
V = Vo + g*t = 128 - 32*2 = 64 Ft/s after 2 s. V = 128 - 32*4 = 0 After 4 s. Vavg = (0+4)/2 = 2 Ft/s
April 1, 2015

  1. Pages:
  2. <<Prev
  3. 1
  4. 2
  5. 3
  6. 4
  7. 5
  8. 6
  9. 7
  10. 8
  11. 9
  12. 10
  13. 11
  14. 12
  15. 13
  16. 14
  17. 15
  18. Next>>

Members