Friday

February 12, 2016
Total # Posts: 11,506

**physics**

Momentum = m*V = 0.1 * 500
*November 13, 2014*

**physics**

M = 4.5 kg h = 1500cm = 15 m. F = 1861N/m * 0.12m = 223.32 N. a = F/m = 223.32/4.5 = 49.63 m/s^2 V2^2 = V1^2 + 2a*h=0 + 99.25*15=1488.8 V2 = 38.6 m/s = Speed of block.
*November 12, 2014*

**Freshman Algebra**

Private plane: 500km/h * 1h = 500km Head-start. d1 + d2 = 2100 km 500+500t + 700t = 2100 1200t = 2100-500 = 1600 t = 4/3 = 1 1/3 Hours(1:20 PM).
*November 12, 2014*

**Physics (Work Problem)**

a. Work = Fx * d = 50*Cos30 * 10 = 433 J
*November 12, 2014*

**physics**

Correct!
*November 12, 2014*

**Physics**

g/2^2 = g/4.
*November 12, 2014*

**Physics**

F = 110N[45o] Fx = 110*Cos45 = 77.78 N.
*November 12, 2014*

**Science**

T = 1/F = 1/0.5 = 2 s. = Period = Time between crests. WL = V*T = 6 m. V * 2 = 6 V = 3 m/s.
*November 12, 2014*

**Physics**

a. d1 = 0.5a*t^2 = 0.5*1.3*5.9^2=22.63 m V1 = a*t = 1.3 * 5.9 = 7.67 m/s. V = V1 + a*t = 7.67 - 1.7*1.6 = 4.95 m/s b. d1 = 0.5a*t^2 = 0.5*1.3*5.9^2=22.63 m d2 = (V^2-V1^2/2a = (4.95^2-(7.67^2))/-3.4 = 10.1 m. d = d1+d2 = 22.63 + 10.1 = 32.73 m
*November 12, 2014*

**physics**

d = 4.3*10^-6cm/s * 3600s/h * 8760h/yr. * 6.4yrs. = 868 cm.
*November 11, 2014*

**math**

Your problem would be easier to under- stand if you proof-read it and show punctuations.
*November 11, 2014*

**Math**

Log2(x+4) = Log2(x^2+2) x + 4 = x^2 + 2 x - x^2 = 2 - 4 -x^2 + x = -2 -x^2 + x + 2 = 0 Multiply both sides by -1: x^2 - x - 2 = 0 -2 = -2*1. Sum = -2 + 1 = -1 = B. x+(-2)) = 0 x-2 = 0 X = 2 x+1 = 0 X = -1 Solution: X = -1, and 2.
*November 11, 2014*

**physics**

Work = Fx*d = 148*Cos35 * 2 = 242.5 N.
*November 11, 2014*

**physics**

Wt. = (1.61/9.8) * 54.3N. = 8.92 N.
*November 11, 2014*

**physics**

KE = m*V^2/2 2KE = m*V^2 m = 2KE/V^2 m*V^2 = 2KE V^2 = 2KE/m V = Sqrt(2KE/m)
*November 11, 2014*

**physics**

d = 0.5a*t^2 = 122.1 m. 2.4*t^2 = 122.1 t^2 = 50.875 t = 7.13 s. V = a*t = 4.8 * 7.13 = 34.2 m/s.
*November 10, 2014*

**physics**

h = 0.5*t^2 = 125 m. 4.9t^2 = 125 t^2 = 25.51 Tf = 5.05 s. = Fall time. Dx = Xo * Tf = 144m/s * 5.05s = 727 m. From the cliff.
*November 10, 2014*

**Math**

10yds * 36in/yd. = 360 In. 360in * 1ribbon/6in. = 60 Ribbons.
*November 10, 2014*

**Math**

It could mean 12 squared = 12*12 = 12 raised to the 2nd power = 144.
*November 10, 2014*

**math**

1/5x^(-1/2) = x^(1/2)/5.
*November 10, 2014*

**maths**

See previous post: Sun, 11-9-14, 11:00 AM.
*November 10, 2014*

**math**

Length = L Width = L/3 P = 2L + 2L/3 = 40 cm. Solve for L.
*November 10, 2014*

**physics**

Vo = 58.2km/h = 58200m/3600s. = 16.2 m/s a = u*g = 0.155 * -9.8 = -1.52 m/s^2. V^2 = Vo^2 + 2a*d = 0 d = -(Vo^2)/-2a = -(16.2^2)/-3.04 = 86.3 m.
*November 10, 2014*

**physics**

Tf = Tr = 5.8/2 = 2.9 s. Tr = Rise time. Tf = Fall time. h = 0.5g*Tf^2
*November 9, 2014*

**Math**

Incomplete.
*November 9, 2014*

**Check my physics answer**

When the arrow points toward the negative x axis.
*November 9, 2014*

**physics**

m*g = 75.95 N. = Wt. of the box. Fp = 75.95*sin29.7 = 37.63 N. = Force parallel to the ramp. a = (Fp-Fk)/m a = (37.63-5.88)/7.75 = 4.1 m/s^2 V^2 = Vo^2 + 2a*d = 0 + 8.2*3.11 = 25.5 V= 5.05 m/s = Xo = Initial hor. velocity. h = 0.5g*t^2 = 0.84 m. 4.9*t^2 = 0.84 t^2 = 0.171 Tf...
*November 9, 2014*

**Physics**

Vo = 22 m/s. u = 0.68 a = u*g = 0.68 * -9.8 = -6.66 m/s^2. V = Vo + a*t = 0 t = -Vo/a = -22/-6.66 = 3.30 s.
*November 9, 2014*

**physics**

m*g = 65 * 9.8 = 637 N. = Force of skier. Fp = 637*sin15 = 164.9 N. = Force parallel to the incline. Fn = 637*cos15 = 615.3 N. = Normal force = Force perpendicular to the incline. Fk = u*Fn = 0.25 * 615.3 = 153.8 N. = Force of kinetic friction. a = (Fap-Fp-Fk)/m. Fap = 500 N...
*November 9, 2014*

**physics 1**

Incomplete.
*November 9, 2014*

**Algebra 2**

+3x + 3y - z = -3 -2x - 3y + 2z = 3 x - 6y + 3z = 0 Eq1: 3x + 3y - z = -3 Eq2: -2x - 3y + 2z = 3 Sum: x + 0 + z = 0 z = -x Eq2: -2x - 3y + 2z = 3 Eq3: x - 6y + 3z = 0 Multiply Eq2 by 6 and Eq3 by (-3): -12x - 18y + 12z = 18 -3x + 18y - 9z = 0 Sum: -15x + 0 + 3z = 18 Replace z ...
*November 9, 2014*

**physical science**

a = (Fap-Ff)/M = (40-24)/8 = 2 m/s^2.
*November 9, 2014*

**maths**

(3/8+2/8) * 128 = (5/8) * 128 = 80 cards given away.
*November 9, 2014*

**Physics**

M*g = 178 N. Vo = 0.5 m/s. Ramp = 3m[24o] Fp = 178*sin24 = 72.4 N. = Force parallel to the ramp. M*g = 178 M = 178/g = 178/9.8 = 18.16 kg = mass of box. a = Fp/M = 72.4/18.16 = 3.99 m/s^2.
*November 9, 2014*

**Math**

Incomplete.
*November 9, 2014*

**Physics test review**

h = 30.1 m. Dx = 66.8 m. 1. h = Yo*t + 0.5g*t^2 = 30.1 0 + 4.9t^2 = 30.1 t^2 = 6.143 Tf = 2.48 s. = Fall time or time in motion. 2. Dx = Xo*Tf = 66.8 Xo * 2.48 = 66.8 Xo = 27 m/s. = Initial velocity. 3. X = Xo = 27 m/s = X component of velocity just before it hits gnd. 4. Y^2...
*November 8, 2014*

**word problem math b**

Posts = 4 + (2*L/10) + (2*W/10)
*November 7, 2014*

**Math**

16pi/5 = 16*180/5 = 576o = 1.6 Rev. A = 0.6Rev * 360o/Rev = 216o, Q3. In Q3, A - Ar = 180o 216 - Ar = 180 Ar = 36o = Reference angle. Ar = (36o/360o) * 2pi = 2pi/10 Radians. Notes: In Q2, A + Ar = 180o In Q4, A + Ar = 360o
*November 7, 2014*

**math**

Tot. Funds=16*$1.00 + 5*5.00 + 5*10.00 + 3*20.00 + 4*0.05 + 20*0.10 + 16*0.25 + 66.00 + 53.75 Deposit = Tot. funds - 50.00
*November 7, 2014*

**physics**

Incomplete.
*November 7, 2014*

**physics**

False. The force of kinetic friction is smaller.
*November 7, 2014*

**CAL- derivative **

Find the derivative; y= x^3(5x-1)^4 So this is my answer y'=2x(5x-1)^3 + 10x + x(5x-1) Please correct me if my answer is wrong.
*November 7, 2014*

**Algebra**

10*Log(2.50*10^5/10^-16) = 10*Log(2.50*10^21) = 214 db.
*November 7, 2014*

**physics**

Vo = 1630 m/s[86o] Yo = 1630*sin86 = 1626 m/s. Y = Yo + g*Tr = = 0 @ max Ht. Tr = -Yo/g = -1626/-9.8 = 166 s. = 2.77 Min. Tf = Tr = 2.77 min. = Fall time. Tr + Tf = 2.77 + 2.77 = 5.54 Min. = Time in flight.
*November 6, 2014*

**physics**

d = 7.6 m. h = 0.5g*t^2 = 3.3 m. Solve for t. Xo = d/t m/s = Initial Hor. velocity
*November 6, 2014*

**science**

a = F/m = 85/5 = 17 m/s^2. V = Vo + a*t = 14 + 17*20 = 354 m/s.
*November 6, 2014*

**math**

Tan20 = h/d = 50/d d = 50/Tan20 = 137.4 m.
*November 6, 2014*

**science.**

The law of conservation of momentum says it will be the same.
*November 6, 2014*

**physics**

V^2 = Vo^2 + 2g*h Vo = 0 2g = 19.6 m/s^2 h = 35 m. Solve for V.
*November 6, 2014*

**Math, Please Help!**

X student tickets sold. (723-X) Non-student tickets sold. 3x + 5(723-X) = $2,815. Solve for X.
*November 6, 2014*

**Physics**

A. m*g = 19kg * 9.8N/kg = 186.2 N. = Force of the suitcase. u = a/g, a = u*g = 0.54 * 9.8 = 5.29 m/s^2 Fn = mg-F*sin41.3 = 186.2-0.66F = Normal force. F*Cos41.3-.54(186.2-0.66F) = 19*5.29 0.751F - 100.5 + 0.356F = 100.5 1.107F = 201 F = 181.6 N. = Force applied. Fn = 186.2 - 0...
*November 6, 2014*

**nqwiliso s.s.s.**

Fr = 30 + 25 + (-40) = 15 N.,Headed East
*November 6, 2014*

**Pre Algebra**

Sqrt(25) + (-9) = -4 = A Whole number.
*November 6, 2014*

**physics**

(1rev/0.4s) * 60s./min = 150 RPM.
*November 6, 2014*

**physics**

F = m*g = 1*9.8 = 9.8 N k = F/d = 9.8N/0.012m = 816.7 N/m.
*November 6, 2014*

**Math**

1. Log(9/300) = Log 9 - Log 300 2. Log2(4^2*3^4) = Log2(4^2) + Log2(3^4) = Log2(16) + Log2(81)
*November 6, 2014*

**Science**

F1+F2 = m*a = 0.750 * 0.450 = 0.3375 N. Fi-F2 = 0.750 * 0.240 = 0.18 N. Eq1: F1 + F2 = 0.3375 Eq2: F1 - F2 = 0.1800 Sum: 2F1 = 0.5175 F1 = 0.25875 N. In Eq1, replace F1 with 0.25875 0.25875 + F2 = 0.3375 F2 = 0.3375 - -0.25875 = 0.07875 N.
*November 6, 2014*

**physics**

See previous post: Thu, 11-7-14, 6:30 AM.
*November 6, 2014*

**physics**

See previous post: Thu, 11-7-14, 6:30 AM.
*November 6, 2014*

**physics**

d = V*T = 3.50 km T = 3.50/V = 3.50/25 = 0.14 h. T = 3.50/40 = 0.0875 h. 0.14 - 0.0875 = 0.0525 h = 3.15 Min. gained.
*November 6, 2014*

**phisics**

Fap = mg*sin45 = 36 N. m = 36/g*sin45 = 5.2 kg Fap = Force applied.
*November 6, 2014*

**algebra**

3.65V^2 + 0.0875V^2/0.09 = 62.7 3.65V^2 + 0.9722V^2 = 62.7 4.622V^2 = 62.7 V^2 = 13.56 V = 3.68
*November 5, 2014*

**physics**

Fd = (Vs+Vd)/(Vs-Va)*Fa = 1050 Hz. (340+0)/(340-Va) * 980 = 1050 Divide both sides by 980: 340/(340-Va) = 1.0714 364.29-1.0714Va = 340 -1.0714Va = 340-364.29 = -24.29 Va = 22.7 m/s. = Velocity of the ambulance. Vs = Velocity of sound. Vd = Velocity of the detector.
*November 5, 2014*

**algebra**

V^2 = Vo^2 + 2g*h = 0 + 64*203 = 12,992 V = 114 Ft/s.
*November 5, 2014*

**Algebra**

V = 8*sqrt(h) = 8*sqrt(203) = 114 Ft/s.
*November 5, 2014*

**physics**

V^2 = Vo^2 + 2g*h = 0 + 19.6*(10-5) = 98 V = 9.90 m/s @ 5 m above the surface. V^2 = 0 + 19.6*10) = 196 V = 14 m. Just before striking the surface.
*November 5, 2014*

**science**

Incomplete.
*November 5, 2014*

**physics**

Vo = 10 m/s. V = 5 m/s. d = 150 m. a = ? a. V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d = b. d = (V^2-Vo^2)/2a. V = 0, Vo = 5 m/s.
*November 5, 2014*

**Physics**

Incomplete.
*November 4, 2014*

**Algebra**

F(x) = Y = -x^2 + 6x + 6 = 0 Use Quadratic Formula. (X, Y) = (-2, 0), (8, 0).
*November 4, 2014*

**Precalculus**

Do you mean e^2x - 1 = e^4 or e^(2x-1) = e^4. I will assume the 2nd Eq. (2x-1)*Ln e = 4*Ln e (2x-1)*1 = 4*1 2x-1 = 4 2x = 5 X = 5/2 = 2.5
*November 4, 2014*

**physics**

a. a = (V-Vo)/t. V = 510 m/s Vo = 0 t = 2.37 s. b. a = (V-Vo)/t V = 0 Vo = 510 m/s. t = 3.15 s. Note: Acceleration when braking will be negative.
*November 4, 2014*

**physics**

V^2 = Vo^2 + 2g*h. Vo = 0 @ top of hill. V^2 = 2g*h. Solve for V.
*November 4, 2014*

**physics**

V^2 = Vo^2 + 2g*h = 0 + 19.6*2000 = 3920 V = 62.6 m/s. KE = 0.5m*V^2 = 50*62.6^2 = 195,938 J.
*November 4, 2014*

**physics**

m*g = 180kg * 9.8N/kg = 1764 N. PE = mg*h = 8000 J @ top of hill. h = 8000/mg = 8000/1764 = 4.54 m.
*November 4, 2014*

**Math**

(40/360) * 2p1 = 2pi/9 Radians.
*November 4, 2014*

**Science**

a = (Fap-Ff)/m = (25-6)/1.5 =
*November 4, 2014*

**Physics**

A vector quantity shows magnitude and direction: 50 m/s @ 45o. Magnitude = 50 m/s. Direction = 45 Degrees.
*November 4, 2014*

**physics**

F1+F2+F3 = 72.7N[0o] + 79.9N[45o] + 103N[315o]. X = 72.7 + 79.9*Cos45 + 103*Cos315=202 N Y = 79.9*sin45 + 103*sin315 = -16.33 N. F^2 = X^2 + Y^2 = 202^2 + (-16.33) = 41,071 F = 203 N. = Resultant force. Tan A = Y/X = -16.33/202 = -0.08084 A = -4.62o = 4.62o S. of E. = Direction.
*November 3, 2014*

**science**

1. The DF increases: DF = PW/PRF. 2. The PRF increases: PRF = 1/PRP. 4. When WL decreases, the PRF increases. The increase in PRF decreases the DF. PRF = V/WL
*November 3, 2014*

**physics**

A = (27.1-9.1)*7.7*10^-4 * 5 = 0.0693 Gal.
*November 3, 2014*

**science**

incomplete.
*November 3, 2014*

**Physics**

D = 4.19*Cos10.4
*November 3, 2014*

**Physics**

D = 4.19*sin10.4 =
*November 3, 2014*

**physics**

a. m*g = 1.0*10^4 N. m = 1.0*10^4/g = 1.0*10^4/9.8 = 1020 kg. Fp = 1.0*10^4*sin34 = 5592 N. = Force parallel to the hill. a = Fp/m = 5592/1020 = 5.48 m/s^2. b. V^2 = Vo^2 + 2a*d = 0 + 10.96*28 = 307 V = 17.5 m/s.
*November 2, 2014*

**Physics**

Vo = 20m/s[50o] Xo = 20*cos50 = 12.9 m/s Yo = 20*sin50 = 15.3 m/s. V = Vo + g*Tr = 0 @ max Ht. Tr = -Yo/g = -15.3/-9.8 = 1.56 s. = Rise time. h = Yo*Tr + 0.5g*Tr^2 h max = 15.3*1.56 - 4.9*1.56^2=11.9 m. h = 0.5g*t^2 = 11.9-3.04 = 8.90 m. 4.9t^2 = 8.90 t^2 = 1.82 Tf = 1.35 s...
*November 2, 2014*

**physics**

Vo = 50m/s[30o] Xo = 50*Cos(30) = 43.3 m/s. Yo = 50*sin(30) = 25 m/s. h = Yo*t + 0.5g*t = 59 m. 25t + 4.9t^2 = 50 4.9t^2 + 25t - 50 = 0 Use Quadratic Formula. Tf = 1.54 s. = Fall time. Dx = Xo * Tf = 43.3m/s * 1.54s = 66.7 m. From the cliff. Y = Yo + g*t = 25 + 9.8*1.54 = 40.1...
*November 2, 2014*

**Physics**

a. Fr = 328N[35o] + 464N[13o] X = 328*Cos35 + 464*Cos13 = 721 N. Y = 328*sin35 + 464*sin13 = 293 N. Fr^2 = X^2 + Y^2 = 721^2 + 293^2 = 605,690. Fr = 778 N. = Resultant force. b. a = F/m = 778/2950 = 0.264
*November 2, 2014*

**Physics**

Maximum power transfer occurs when the resistance of the load is equal to the internal resistance of the source: R = r.
*November 2, 2014*

**physics**

Vo = 0 V = 6,000rad/min = 6,000rad/60s = 100 rad/s. a = (V-Vo)/t = (100-0)/4 = 25 rad/s^2
*November 2, 2014*

**Physics**

a. D = Vo*t = 190rad/s * 13s = 2470 rad b. D = 300rad/s * 13s = 3900 Rad. c. a = (V-Vo)/t = (300-190)/13 = 8.46 rad/s^2. D = Vo*t + 0.5a*t^2 D = 190*13 + 4.23*13^2 = 3185 Rad.
*November 1, 2014*

**physics**

Multiply your answer by 100 to convert to cm.
*November 1, 2014*

**physics**

d = 0.5g^t^2. g = 9.8 m/s^2, t = 0.29 s. Solve for d.
*November 1, 2014*

**Physics**

Momentum = m1*V1-m2*V2 = 0.062*9-0.006*4 = 0.558 - 0.024 = 0.534 m1*V = 0.534 0.062*V = 0.534 V = 8.61 m/s.
*October 31, 2014*

**Physics**

Fr = F1 + F2 + F3 + F4 = 0 100N[37o] + 200N[270] + 250N[200] + F4=0 X = 100*Cos37+200*Cos270+250*Cos200 = -155 N. Y = 100*sin37+200*sin270+250*sin200 = -225 N. Tan Ar = Y/X = -225/-155 = 1.45161 Ar = 55.44o = Reference angle. A = 55.44 + 180 = = 235.4o F1+F2+F3 = Y/sin A = -...
*October 31, 2014*

**Physics**

a.m2*V2-m1*V1 = 0.250*10[71o]-0.250*28.4[58.8o] = 2.50[71o] - 7.1[58.8o] X = 2.50*Cos71 - 7.1*Cos58.8 = -2.86 Y = 2.50*sin71 - 7.1*sin58.8 = -3.71 M^2=X^2 + Y^2 = (-2.86)^2 + (-3.71)^2 = 21.9 M = 4.68 = Magnitude of change in momentum. b. Tan Ar = Y/X = -3.71/-2.86 = 1.29720 ...
*October 31, 2014*

**Physics**

(m1+m2)*V = m1*V1 (1424+1424)*V = 1424*11 2848V = 15,664 V = 5.5 m/s.
*October 31, 2014*

**Science Physics**

a. Vw = L*W*h = 85 *30 * (15-3) = 30,600 Ft^3. b. 30,600Ft^3 * 62.4Lbs/Ft^3 = 1.909,440 Lbs. = 955 Tons = Wt. of water displaced. Load = 955 - 160 = 795 Tons.
*October 31, 2014*

**Algebra 1B**

Width = W in. Length = (2W + 4) in. V = L * W * h = 2720 n^3. (2W+4) * W * 17 = 2720 2W^2+4W)*17 = 2720 34W^2 + 68W - 2720 = 0 W^2 + 2W - 80 = 0 -80 =-8*10. (W-8)(W+10) = 0 W-8 = 0 W= 8 W+10 = 0 W = -10 Use positive value of W: W = 8.
*October 31, 2014*

**physics**

T^2 = 4*pi^2*(L/g) T^2 = 39.48(0.65/9.8). Solve for T.
*October 31, 2014*