Thursday

August 21, 2014

August 21, 2014

Total # Posts: 8,916

**dynamics**

See 10:35am post.
*July 22, 2013*

**Dynamics**

Ek = 0.5m*V^2 *h - = 750 * 6^2 = 27,000 J. Wt. = Fg = 1500kg * 9.8N/kg = 14,700 N. Ep = Fg * h = 27000-Fk*d 14700*5*sin20 = 27000-Fk*5 25138.5 = 27000-5Fk 5Fk = 27000-25138.5 = 1861.5 Fk = 372 N.
*July 22, 2013*

**dynamics**

V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g h = (0-625)/-19.6 = 31.89 m. NOTE: V = 0 @ max. Ht.
*July 22, 2013*

**general physics**

Di + Db = Dsw 917 + Db = 1025 kg/m^3 Db = 108 kg/m^3 = Density of the bear. Mass of bear = 6.76m^3*108kg/m^3=730 kg Wt. of bear = 730kg * 9.8N/kg = 7154 N.
*July 20, 2013*

**science**

CORRECTION: Ek = 84.672 J.
*July 20, 2013*

**science**

V^2 = Vo^2 + 2g*d Vo^2 = V^2-2g*d Vo^2 = 0-(-19.6*1.2 = 23.52 Vo = 4.85 m/s. Ek = 0.5m*Vo^2 = 3.6*(4.85)^2 = 11.76 J. vo^2
*July 20, 2013*

**MATH**

h = 125-5t^2 = 0 -5t^2 + 125 = 0 t^2 - 25 = 0 (t+5)(t-5) = 0 t = -5 t = 5 s. V = g*t = 9.8 * 5 = 49 m/s.
*July 19, 2013*

**physics**

Vs = 25 m/s = Velocity of the source. F = 260 Hz(NOT 26Hz). Fo = 240 Hz. Vr = Velocity of the receiver(person) F = (V+Vr)/(V-Vs)*Fo = 260 Hz. (V+0)/(V-25)*240 = 260 240V/(V-25) = 260 240V = 260V - 6500 -20V = -6500 V = 325 m/s.
*July 17, 2013*

**Math**

P = (Po*r*t)/(1-(1+r)^-t) Po = $81,000. r = (9%/12)/100% = 0.0075 = Monthly % rate expressed as a decimal. t = 25yrs. * 12mo/yr. = 300 Months. Plug the above values into the given Eq and get: P = $203,924.72 Monthly Payments = P/t Monthly Int. = (P-Po)/t. Monthly Prin. = (P/t...
*July 17, 2013*

**physics/science**

See previous post.
*July 17, 2013*

**physhcs**

Xc = 1/W*C = 1/314.2*3*10^-6 = 1061 Ohms Z = R-jXc = 500 -j1061 = 1173[-64.8o]. 1. I = V/Z=12/1173[-64.8o]=0.01023[64.8] 2. Vc= I * Xc = 0.01023[64.8]*1061[-90o]= 10.85 Amps.[-25.2o] 3. A = -25.2o 4. P = I^2*R = (0.01023)^2 * 500= 0.0523 W. 5. Pf = cosA = cos(-64.8) = 0.426
*July 17, 2013*

**phys ics**

b. V = (0.243/0.335) * 28m/s = 20.3 m/s.
*July 16, 2013*

**physics**

Circumference=pi*2r=3.14*0.67=2.1=2.1 m. Va = 24.1m/s * 6.28rad/2.1m=72.1 rad/s.
*July 16, 2013*

**physics**

d = 0.5g*t^2 = 5.95 m. 4.9t^2 = 5.95 t^2 = 1.21 s. t = 1.10 s. 2.55rev/s * 1.1s = 2.8 revs.
*July 16, 2013*

**physics**

a. 28.9rad/s * 1rev/6.28rad = 4.60 rev/s. t = (13.6/4.60) * 1s = 3.0 s. b. V = Vo + at = 0 When @ rest. 28.9 + a*3 = 0 3a = -28.9 a = -9.63 rad/s^2.
*July 16, 2013*

**physics**

a. d = 2870rev * 6.28rad/rev = 18,024 rad. t = 18,024rad/131rad/s = 138 s. V = Vo + a*t = 131 rad/s Vo + 0.170*138 = 131 Vo = 131-23.4 = 108 rad/s. b. t = 138 s.
*July 16, 2013*

**physics**

V = Vo + at = 4.4 rad/s. 0 + 4.2t = 4.4 t = 4.4/4.2 = 1.05 s.
*July 16, 2013*

**physics**

d1 + d2 = 2pi rads = A complete circle. V1t + V2t = 2pi 2.46*10^-3 + 7.91*10^-3 = 6.28 10.37*10^-3t = 6.28 t = 606 s.
*July 16, 2013*

**Math**

See previous post.
*July 16, 2013*

**Math**

See previous post.
*July 16, 2013*

**Math**

Eq1: x^2 + y^2 = 34 Eq2: x + y = 2 x + y = 2 Y = 2 - x In Eq1, replace Y with 2 - x. x^2 + (2-x)^2 = 34 x^2 + 4 - 4x + x^2 = 34 2x^2 -4x + 4 = 34 2x^2 -4x - 30 = 0 Divide both sides by 2: x^2 - 2 - 15 = 0 (x+3)(x-5) = 0 x+3 = 0 X = -3. Y = 2- x = 2-(-3) = 5 x-5 = 0 X = 5. Y = ...
*July 16, 2013*

**physics**

Wt. = (6.0/1.0)^2 * 45.8 = 1649 N.
*July 16, 2013*

**Elementary mechanics**

My answer is the Rise Time or time to reach max. height. R = Vo*cosA * (Tr+Tf) Tr = Tf. Therefore, R = Vo*cosA * 2Tr. Tr = Rise time. Tf = Fall time. Vo*cosA = Hor. component of initial velocity.
*July 15, 2013*

**Physics**

Circumference=pi*D = 3.14 * 41=128.8 cm= 1.288 m. Vo = (86rev/min)*1min/60s*1.288m/rev = 1.85 m/s. V = (342/86) * 1.85 = 7.34 m/s a=(V-Vo)/t = (7.34-1.85)/3.4=1.61 m/s^2 d =Vo*t + 0.5*a*t^2 d=1.85*3.4 + 0.5*1.61*(3.4)^2= 15.6 m.
*July 14, 2013*

**physics**

Wt. = Fg = m*g = 60kg * 9.8N/kg=588 N.= Wt. of skier. Fp=588*sin35 = 337 N.=Force parallel to incline. Fv = 588*cos35 = 482 N. = Force perpendicular to incline. Fk = u*Fv = 0.08 * 482 = 38.5 N. = Force of kinetic friction. d =h/sinA = 2.5/sin35 = 4.36 m. Ek + Ep = Ekmax - Fk*d...
*July 14, 2013*

**Physics**

Wt. = m*g = 10kg * 9.8N/kg = 98 N. = Wt. of the luggage. F = 98N.[60o] = Force of luggage. Fp = 98*sin60 = 84.9 N. = Force parallel to incline. Fv=98*cos60 = 49 N.=Force perpendicular to incline = Normal. a. Work=mg * h = 98 * 6.5sin60= 552 J. b. Work = -98 * 6.5sin60 = -552 J...
*July 14, 2013*

**physics**

Density of water = 1000kg/m^3. V = 3m * 0.20m * 0.05m = 0.03 m^3=Vol. of board. 1 - (350/1000) = 0.65 = 13/20.
*July 13, 2013*

**Physics**

Impulse = m*V1-m*V2 Impulse = 2.4*2.5 - 2.4*1.5 = 2.4kgm/s
*July 13, 2013*

**Elementary mechanics**

F1 = 100[170o] F2 = 100[50o] X = 100*cos170+100*cos50o = -34.2 N. Y = 100*sin170+100*sin50 = 94 N. tan Ar = Y/X = 94/-34.2 = -2.74838 Ar = -70o = Reference angle. A = -70+180 = 110o Fr = X/cosA = -34.2/cos110 = 100N.[110o]
*July 12, 2013*

**Trigonometry**

Draw a picture of the situation: 1.Draw ver. line AC with A on the bottom. 2. Add point D on line AC. 3. Draw a hor. line from A to the left. Label it AB. Now we have a rt angle. 4. Draw hyp. BC. 5. Draw hyp. BD. <ABC = <ABD + <DBC = 61.5o 56.33 + <DBC = 61.5 <...
*July 11, 2013*

**Physics**

T^2 = 4*pi^2(L/g) 1a. Longer. A smaller g increases the ratio of L/g which increases the period. 1b. Unchanged. The mass is not included in the Eq. 1c. Shorter. The ratio of L/g decreases which decreases the period. 1d. Unchanged. The ratio of L/g remains the same. Therefore, ...
*July 10, 2013*

**science**

The 100W bulb.
*July 10, 2013*

**Physics**

Wc = m*g = 1650kg * 9.8N/kg = 16,170 N.= Wt. of car. k = 16,170N./3.5m. = 4620 N/m.
*July 8, 2013*

**Physics**

Wc = m*g = 1840kg * 9.8N/kg = 18032 N. = Wt. of car. Fc = 18,032N[12.5o] = Force of the car. Fp = 18,032*sin12.5 = 3903 N. = Force parallel to incline. F-Fp = m*a = m*0 = 0 F-3903 = 0 F = 3903 N. Parallel to the incline Work = F*d = 3903 * 14 = 54,642 J.
*July 8, 2013*

**physics**

g = 9.8/6 = 1.633333 m/s^2 on moon. d = o.5g*t^2 = 50 m. 0.5*1.63333*t^2 = 50 0.81666t^2 = 50 t^2 = 61.22 t = 7.82 s.
*July 8, 2013*

**physics**

b. Fn = m*a a = Fn/m = (940-521)/95.9 = 4.37m/s^2. V = Vo + a*t = 0 Vo = -a*t = -(-4.37*1.63) = 7.1 m/s.
*July 8, 2013*

**physics**

Wp = m*g = 95.9kg * 9.8N/kg = 940 N. = Wt. of player. a. Fk = 0.554 * 940 = 520.7 N.
*July 8, 2013*

**physics**

CORRECTION: b. hmax = 3 + 0.141 = 3.141 m.
*July 8, 2013*

**physics**

a. V^2 = Vo^2 + 2g*h h(up) = (V^2-Vo^2)/2g. h(up) = (0-2.76)/-19.6 = 0.141 m. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6(0.141+3) = 61.6 V = 7.85 m/s. b. 0.141 m.
*July 8, 2013*

**math**

See previous post: 7:09pm.
*July 8, 2013*

**Physics**

d = 0.5g*t^2 = 122.5 m. 4.9t^2 = 122.5 t^2 = 25 t = 5 s. = Fall time. d = r*t = 122.5 m. 343t = 122.5 t = 0.357 s. T = 5 + 0.357 = 5.357 s.
*July 8, 2013*

**physics**

a. Y^2 = Yo^2 + 2g*h = 0 @ max. ht. Yo^2 = -2g*h = 19.6 * 21.8 = 427.28 Yo = 20.7 m/s. = Ver. component of initial velocity. Yo = 51.2*sin A = 20.7 m/s. sinA = 20.7/51.2 = 0.40373 A = 23.8o. Vo = 51.2[23.8o] Xo = 51.2*cos23.8 = 46.8 m/s. = Hor. component of initial velocity. V...
*July 8, 2013*

**physics**

F = m*g = 0.662 * 9.8 = 6.49 N. a. Work=F*d=6.49 * (6.32-1.82)=29.2 J. b. PE = mg*h = 6.49 * 6.32 = 41.0 J. c. PE = 6.49 * 1.82 = 11.81 J. d. 11.81 - 41 = -29.2 J.
*July 8, 2013*

**physics**

V^2 = Vo^2 + 2g.h Vo^2 = V^2-2g.h Vo^2 = 0-(-19.6)*190sin13 = 837.7 Vo = 28.9 m/s
*July 8, 2013*

**physics**

CORRECTION: Vo^2 = 9.8*190/sin26 = 4247.54 Vo = 65.2 m/s.
*July 8, 2013*

**physics**

D = Vo^2*sin(2A)/g = 190 m. Vo^2*sin(26)/9.8 = 190 Vo^2 = 190/sin26 = 433.4 Vo = 20.8 m/s.
*July 8, 2013*

**MATH**

P(t) = 20(4t+3)/(2t+5) a. Population in 1990: Let t =0. Solve for P and get 12,000. Population in 2000: Let t = 10. P = 34,400. Population in 2010: Let t = 20. P=36,889. Therefore the population is growing. b. Replace P with 50 and solve for t. You should get -9.5 years. The ...
*July 8, 2013*

**physics**

V^2 = Vo^2 + 2a*d a=(V^2-Vo^2)/2 a = ((2.1)^2-0)/19.2=0.230 m/s^2 Fn = m*a (Fap-Fk) = m*a (29-Fk) = 17*0.230 29-Fk = 3.91 Fk = 29-3.91 = 25.1 N. Ws = m*g = 17kg * 9.8N/kg = 167 N. = Wt. of sled. u = Fk/Ws = 25.1/167 = 0.150 = Coefficient of kinetic friction.
*July 8, 2013*

**physics**

Wc = m * g = 1310kg * 9.8N/kg = 12838 N. Fp = 12338*sin9.12o = 2035 N. = Force parallel to road. Fv = 12838*cos9.12 = 12676 N. = Force perpendicular to road. = The normal. Work = Fn * D = 155,00 J. Fn * 337 = 155000 Fn = 460 N. = Net force. Fn = F-Fp-Fk = 460 N. F-2035-541 = ...
*July 8, 2013*

**physics**

a. F*cos23.2-48.5 = m*a = m*0 = 0 Fcos23.2 = 48.5 F = 48.5/cos23.2 = 52.8 N. b. Work = F*d = 52.8 * 34 = 1795 Joules. c. Work = Fk * d = 48.5 * 34 = 1649 J.
*July 8, 2013*

**math**

-16x^2 + 160t The max. point on the parabola is the vertex: t = Xv = -B/2A = -160/-32 5 s hmax. = Yv = -16*5^2 + 160*5 = 400 Ft. V(5,400).
*July 8, 2013*

**Geometry**

1. A = 400cm * 2cm = 800 cm^2. 2. A = (3.5^2) = 3. A = pi*r^2 = 3.14 * (9/2)^2 =
*July 8, 2013*

**algebra1 HELP PLEASE**

Let y = 0. x^2-7 = 0 x^2 = 7 X = =+-sqrt 7
*July 8, 2013*

**algebra1 HELP PLEASE**

h1(t) = 100 - 0.5*32*t^2. h1 = 100 - 16t^2 = 0 @ gnd. level. 16t^2 = 100 t^2 = 6.25 t = 2.50 s. h2(t) = 210 - 0.5*32*t^2 h2 = 210 - 16t^2 = 0 @ gnd. level. 16t^2 = 210 t^2 = 13.125 t = 3.62 s.
*July 8, 2013*

**physics**

See previous post,4:21 PM.
*July 7, 2013*

**Finance**

2. Increases with every payment and completely repays the loan with the last payment.
*July 7, 2013*

**physics**

Vo = 17m/s[25o] Xo = 17*cos25 = 15.4 m/s. Yo = 17*sin25 = 7.2 m/s. Y = Yo + g*t = 0 @ max. Ht. Tr = -Yo/ g = -7.2/-9.8 = 0.73 s. = Rise time. Tf = Tr = 0.73 s. = Fall time. D = Xo*(Tr+Tf) = 15.4 * 1.46 = 22.5 m. V=(D-12)/(Tr+Tf)=(22.5-12)/1.46=7.19m/s
*July 7, 2013*

**physics**

F = m*a V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = ((350)^2-0)/1.7 = 72,059 m/s^2 F = 0.004 * 72059 = 288 N.
*July 6, 2013*

**physics**

Please clarify your problem.
*July 6, 2013*

**phy**

1. Fn = m*a 40*cos37-Fk = 5 * 3 31.9-Fk = 15 Fk = 31.9-15 = 17 N. 3. a = Fn/m a = (250*cos37-8)/20 = 9.58 m/s^2.
*July 6, 2013*

**math**

The bar means the 2nd 89 REPEATS continuously.
*July 5, 2013*

**physics**

A = 5.0km[135o] B = 7.0km[315o] D = A+B D=(5.0*cos135+7.0*cos315)+i(5.0*sin135+ 7.0*sin315 D = (-3.54+4.95) + i(3.54-4.95) D = 1.41 - i1.41 = 2km[-45o]=2km[45o S of E]. NOTE: The cosine function was used to find the hor. components; the sine function was used to find the ver. ...
*July 4, 2013*

**physics**

A = 100m[0o] B = 200m[270o] C = 50m[3i5o] D = A+B+C D=(100+200*cos270+50*cos315+i(sin270+50*sin315) D = (100+0+35.4) + i(-200-35.4) D = 135.4 - i235.4 = 272m[-60o] = 272m [60o S. of E.].
*July 4, 2013*

**Physics**

A = 3m/s * 20s = 60m[180o]. B = 100m[270o]. C = 2m/s * 20s = 40 m[0o]. D = (A+B)-C A+B = (60*cos180+100*cos270)i(60*sin180+ 100*sin270) A+B = (-60+0) + i(0-100) A+B = -60 - i100 = -116.5[59o] A+B = 116.5[59+180] = 116.5m[239o]. D = (A+B)-C = 116.5[239] - 40 D = -60 - i100 - 40...
*July 4, 2013*

**math 2**

m1 = -A/B = 6/2 = 3. m2 = -12/-4 = 3. The Eqs have equal slopes. Therefore, they are parallel and do not intersect. So there are NO solutions.
*July 4, 2013*

**contemporary math**

P = Po(1+r)^n. P = $50,000 r = (8%/4)/100% = 0.02 = Quarterly % rate expressed as a decimal. n = 4comp./yr * 5.5yrs. = 22 Compounding periods. Plug the above values into the given Eq and solve for Po.
*July 4, 2013*

**Math**

Substitution.
*July 4, 2013*

**Math**

Substitution.
*July 4, 2013*

**math**

See previous post: Mon,7-1-13,10:49 PM.
*July 3, 2013*

**math**

Correction: A =(8/4)^2 * 18 = 72 Ft^2 = Area of the base. V = A*h = 72 * 8 = 576 Ft^3. OR V = (8/4)^3 * 72Ft^3 = 576 Ft^3.
*July 3, 2013*

**math**

18Ft^2*h1 = 72Ft^3 h1 = 72Ft^3/18Ft^2 = 4 Ft. A = (8Ft/4Ft) * 18Ft^2 = 36 Ft^2 = Area of the base. V = A*h = 36Ft^2 * 8Ft = 288 Ft^3.
*July 3, 2013*

**Gen. physics**

V^2 = Vo^2 + 2ad = 0 a = -Vo^2/2d = -(6.4)^2/29 = -1.41 m/s^2
*July 2, 2013*

**physics**

a. V = Vo + g*t = 17 m/s. Vo = 17-g*t = 17-(-9.8*2.2) = 38.56 m/s. b. V = 38.56 -9.8*4.4 = -4.56 m/s. The negative sign means the rock is on its' way down.
*July 2, 2013*

**gen physics**

See Related Questions: Thu,6-27-13,6:00am.
*July 2, 2013*

**gen physics**

A = 71[180o]. B = 71[270o]. a. A+B=(71*cos180+71*cos270)+i(71*sin180+71*sin270) A+B = (-71+0) + i(0-71) A+B = -71 - i71 = -100.4]45o] or 100.4[45o+180o] = 100.4[225o]. Since the resultant is in Q3, 45o is the reference angle. b. A-B=(71*cos180-71*cos270)-i(71sin180-71sin270) A...
*July 2, 2013*

**Algebra**

x(3y) = y(3x) = 3(xy) = 3*y*x.
*July 2, 2013*

**49PM.ath**

See Related Questions: Mon,7-1-13,10:
*July 1, 2013*

**math**

P = Po(1+r)^n. Po = $42,000 r = 11%/100% = 0.11 n = 1comp./yr. * 19yrs = 19 Compounding periods. Plug the above values into the given Eq and solve for P.
*July 1, 2013*

**algebra 1 NEED NOW!!! PLEASE HELPPP**

Since the parabola opens downward, the vertex is the max. point on the curve. Y = -12x^2 + 48x 1. h = Xv = -B/2A = -48/-24 = 2 Seconds. 2. k = Yv = -12*2^2 + 48*2 = 48 Ft. V(x,y)= (2,48). 3. Tr = Tf = 2 s. T = 2 + 2 = 4 s. Tr = Rise time. Tf = Fall time.
*July 1, 2013*

**business math**

See Mon,7-1-13,10:49PM post.
*July 1, 2013*

**Mathematics**

What is 72ten?
*July 1, 2013*

**finance**

D = 10000-0.15*10000 = $8500.
*June 30, 2013*

**Physics**

F = m*a a = V-Vo)/t = (34.4-0)/42 = 0.819 m/s^2. F = 3.6*0.819 = 2.95 N.
*June 30, 2013*

**MATH**

A(-1,-2),P(x,y),B(9,3). x-(-1) = 4(9-x) x+1 = 36-4x 5x = 35 X = 7. y-(-2) = 4(3-y) y+2 = 12-4y 5y = 10 Y = 2. P(7,2).
*June 30, 2013*

**Physics**

V = 6.48*cos9.54 = 6.39 m/s.
*June 30, 2013*

**Physics**

See previous post.
*June 30, 2013*

**Physics**

a=(V-Vo)/t = (26.5-0)/0.55 = 48.2 m/s^2. F = m*a = 929.4 * 48.2 = 44,780 N.
*June 30, 2013*

**Discrete Math**

CORRECTION:BCD should be BCDA
*June 30, 2013*

**Discrete Math**

8 different passwords were formed: ABCD BCD CDAB DABC. DCBA CBAD BADC ADCB
*June 30, 2013*

**math**

Move the decimal 8 places to the right. 7.5*10^8 = 750,000,000
*June 30, 2013*

**math**

1. P = Po(1+r)^n. Po = $500,000. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 5yrs. = 20 Compounding periods. Plug the above values into the given Eq. and solve for P. 2. P = Po(1+r)^n. r = APR = (8%/100% = 0.08 n = 1comp./yr. * 5yrs. = 5...
*June 29, 2013*

**trig**

X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.
*June 28, 2013*

**physics**

See Related Questions: Thu,6-27-13,6:ooAM.
*June 28, 2013*

**Business Math**

P = Po(1+r)^n. Po = 50000 r = (1.6%/2)/100% = 0.008 = Semi-APR. n = 2comp./yr. * 5yrs = 5yrs = 10 Compounding periods. Plug the above values into the given Eq and solve for P.
*June 27, 2013*

**Business Math**

P = Po(1+r)^n P = $27,500 Po = Initial investment. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. n = 12comp/yr. * 3yrs = 36 Compounding periods. P = Po(1.005)^36 = 27500 Po = 27500/(1.005)^36 = $22,980.
*June 27, 2013*

**Business Math**

APY = The interest for 1 year divided by the initial investment: APY = (I/Po)*100%.
*June 27, 2013*

**Business Math**

CORRECTION: n = 4Comp./yr. * 1yr. = 4 Compounding periods.
*June 27, 2013*

**Business Math**

P = Po(1+r)^n. Po = $1,000,000. r = (8%/4)/100% = 0.02 = Quarterly % .rate expressed as a decimal. n 4Comp./yr. * 8trs = 32 Compounding periods. Plug the above values into the given Eq and solve for P. I = P-Po.
*June 27, 2013*

**Business Math**

P = Po(1+r)^n. Po = $7700. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs = 20 Compounding periods. Plug the above values into the given Eq and get: P = $10,370.78
*June 27, 2013*

**physics**

Vo = 85m/s[45o]. Xo = 85*cos45 = 60.1 m/s. Yo = 85*sin45 = 60.1 m/s. Tr = (Y-Yo)/g = (o-60.1)/-9.8 = 6.1 s. = Rise time. h = Yo*t + 0.5g*t^2 h = 60.1*6.1 - 4.9*(6.1)^2 = 184.3 m. d = Yo*t + 0.5g*t^2=184.3 + 120=304.3m 0 + 4.9t^2 = 304.3 t^2 = 62.1 Tf = 7.9 s. = Fall time. d =...
*June 27, 2013*

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