Saturday
February 6, 2016

Posts by henry

Total # Posts: 11,478

math
Assume 5 cm is measured on the drawing. d = 5cm * 3m/1cm = 15 m. = Actual distance.
October 22, 2015

math
(2/3)/6 = 2/3 * 1/6 = 2/18 = 1/9 cup.
October 22, 2015

physics
M*g = 1000 * 9.8 = 9800 N. Fp = 9800*sin33 = 5337 N. = Force parallel to the incline. a = Fp/M = 5337/1000 = 5.34 m/s^2.
October 22, 2015

sri krishna
3-4-5 triangle with each side multiplied by 4: hyp. = 20 = 5*4. 3*4 = 12. 4*4 = 16. So X = 4. so
October 22, 2015

Math
3/4 * M = 48. M = 4/3 * 48 = $64.
October 22, 2015

Physics
a. Vf = Vo + g*Tr = 0. Tr = -Vo/g = -15/-9.8 = 1.53 s. = Rise time. b. h1 = Vo*Tr + 0.5g*Tr^2 = Ht. above the roof. g = -9.8 m/s^2. h = h1 + 20. c. h = 0.5g*Tf^2. h = h1 + 20. g = 9.8 m/s^2. Tf = Fall time. Tf = ? Tr + Tf = Total flight time. d. Vf^2 = Vo^2 + 2g*h. Vo = 0. g...
October 22, 2015

Physics
Need more INFO.
October 22, 2015

math
d = 5days * 2(13/2)mi/day = 65 Miles. 65mi/4gal. = 16.25 mi/gal.
October 21, 2015

math
144/32 = 4 R16 = 4 Thirty-two inch pieces with 16 inches left.
October 21, 2015

math
(3 2/3)/2/3 = (11/3)/2/3 = 11/3 * 3/2 = 33/6 = 5 3/6 = 5 1/2 or 5 pieces.
October 21, 2015

physics
Yf^2 = Yo + 2g*h = 0. Yo = -2g*h = -2*(-9.8)*0.449 = 8.8 m/s. Yo = Vo*sin3.40 = 8.8 m/s. Vo = 8.8/sin3.4 = 148 m/s.
October 21, 2015

math
Sole X necklaces. Sold 3x watches. 4*x + 7*3x = $300. X = ?.
October 21, 2015

Physics- PLEASE HELP!!
Hannah and Tammy please show how you arrive at your answer.
October 21, 2015

maths
1 - (2/5 + 1/3) = 15/15 -(6/15 + 5/15)= 15/15 - 11/15 = 4/15 Left.
October 21, 2015

physics
D = 26km[90o] + 62km[60o]. X = 62*Cos60 = 31km. Y = 26 + 62*sin60 = 79.7 km. Q1. Tan A = Y/X = 79.7/31 = 2.57076. A = 68.7o = Direction. D = Y/sin A = 79.7/sin68.7 = 85.5 km[68.7o].
October 21, 2015

Quick physics check
Fr = 60[135o]CCW + 5[330o]CCW. X = 60*Cos135 + 5*Cos330 = -38.1 N. Y = 60*sin135 + 5*sin330 = 39.9 N. Q2. Tan A = Y/X = 39.9/-38.1 = -1.04794. A = -46.3o = 46.3o N. of W. = Direction. Fr=Sqrt(X^2 + Y^2)=Sqrt(38.1^2 + 39.9^2) = 55.2 N. = Resultant force.
October 21, 2015

Physics
M*g = 9990 N., M = 9990/9.8 = 1019 kg. V = 64.87 mi/h * 1600m/mi * 1h/3600s. = 28.83 m/s. KE = 0.5M*V^2 = 0.5*1019*(28.83)^2 = 423,481 J. PE = Mg*h = KE. 9990*h = 423,481. h = ?
October 21, 2015

physics 11
X = -2.7 m/s. Y = 1.3 m/s. Q2. a. Tan A = Y/X = 1.3/-2.7 = -0.48148. A = -25.7 m/s = 25.7o N. of W. = 64.3o W. of N. = Direction. Vr = Sqrt(X^2 + Y^2) = Sqrt(2.7^2+1.3^2)= 3.0 m/s = Resultant velocity. Dr = Sqrt(20^2 + 41.5^2) = 46.1 m. = Resultant distance. Dr = Vr*T = 46.1 m...
October 20, 2015

Physics
1. Vf^2 = Vo^2 + 2a*d Vo = 0. Vf = ?. 2. d = 0.5a*t^2.
October 20, 2015

College Physics
Wc = M*g = 1670 * 9.8 = 16,366 N. N/m = 16,366N./6.5m.
October 20, 2015

physcial science
D.
October 20, 2015

Physics
See previous post: Tue, 10-20-15, 11:26 AM.
October 20, 2015

Physics
See previous post: Tue,10-20-15, 11.26 AM.
October 20, 2015

Physics. Appreciate the help I can get.
a = (F-Fk)/M = (720-320)/400 = 1.0 m/s^2 A. d = Vo*t + 0.5a*t^2. Vo = 5 m/s. t = 6 s. d = ?. B. Work = F*d. C. Power = Work/t in J/s = Watts.
October 20, 2015

NFCS
Change = a*t = 0.219m/s^2 * 11.2s. =
October 20, 2015

Physics 101
Increase = (39-10)C*9.8*10^-6/C * 250 m. = 0.071 m.
October 20, 2015

math
Kim has X decals. 2x/3 on 5 cars. Remaining = x - 2x/3 = 1x/3. 2/5 * 1x/3 = 2x/15 decals on 2 bikes. Remaining = 6. 2x/3 + 2x/15 + 6 = X. 10x + 2x + 90 = 15x. 15x-12x = 90. 3x = 90. X = 30 = Total decals. 2x/3 = 60/3 = 20 Decals on 5 cars. 20decals/5cars = 4 decals/car.
October 20, 2015

AP physics
Vf^2 = Vo^2 + 2a*d = 0. a = -(Vo^2)/2d = -(10^2)/50 = -2.0 m/s^2 F = M*a = 60 * (-2.0)=-120 N. Retarding force.
October 20, 2015

Physics 101 help (dumb it down please)
M1*V1 + M2*V2 = M1*V + M2*V. M1 = 12,000 kg, V1 = 22 m/s. M2 = 1200 kg, V2 = 16 m/s. V = ?.
October 20, 2015

PHYSICS
Vf = 50.4km/h = 50400m/3600s = 14 m/s. a = (Vf-Vo)/t = (. Vo = 0. d = 0.5a*t^2.
October 19, 2015

Physics
M*g = 1600 * 9.8 = 15,680 N. Fp = 15,680*sin20 = 5363 N. Fn = 15,680*Cos20 = 14,734 N. Fk = u*Fn = 0.09 * 14,734 = 1326 N. Fw-Fp-Fk = M*a = M*0 = 0. Fw = Fp+Fk = 5363 + 1326 = 6689 N. = Force of the winch. Power = Fw * V = 6689 * 1.21 = 8094 J/s. = 8094 Watts.
October 19, 2015

algebra
-5(3-Q) + 4 = 5Q - 11. -15+5Q + 4 = 5Q - 11. 5Q - 5Q = -11 + 15 - 4. 0 = 0. Infinite solutions.
October 19, 2015

Physics
h = 0.5g*t^2 = 1.70 m. g = 9.8 m/s^2. t = ?.
October 19, 2015

phPhysical Science
Disp. = -16 + 20 = 4 km. V = 4km/(5+6)hrs. = 0.364 km/hr., East.
October 19, 2015

AP physics
h = 30*sin12 = 6.24 m. Vf^2 = Vo^2 + 2g*h = 0 + 19.6*6.24 = 122.3. Vf = 11.1 m/s.
October 18, 2015

physics
Yf = Yo + g*t = 12 - 10*2.4 = -12 m/s. Vf = sqrt(9^2 + 12^2) = 15 m/s.
October 18, 2015

Physics
Distance = 10 + 15 = 25 m. X = -10 m. Y = -15 m. Q3. Tan A = Y/X = -15/-10 = 1.50. A = 56.3o S. of W. = 236.3o CCW. Displacement = -15/sin236.3 = 18 m[236.3o] CCW.
October 18, 2015

math
b. 36cookies/2hr. = 18 Cookies/hr. T = 120Cookies * 1hr/18Cookies = 6.67 hrs.
October 18, 2015

Physics
Wb = M*g = 10 * 9.8 = 98 N. = Normal force, Fn. Fs = Force of static friction. Fap-Fs = M*a. 8 - Fs = M*a = M*0 = 0. Fs = 8 N. Fs = u*Fn = 8 N. u = 8/Fn = 8/98 = 0.082.
October 18, 2015

physics
Wc = M*g = 1.3 * 9.8 = 12.74 N. Fp = 12.74*sin25 = 5.38 N. = Force parallel to the incline. a. Fap-Fp = M*a. Fap-5.38 = M*0 = 0. Fap = 5.38 N. = Force applied.
October 18, 2015

Physics
M*g = 2.9 * 9.8 = 28.4 N. = Wt. of the brick = Normal force, Fn. Fk = u*Fn = 0.33 * 28.4 = 9.38 n. = Force of kinetic friction. Fap-Fk = M*a. Fap-9.38 = M*0 = 0. Fap = 9.38 N.
October 17, 2015

maths
5 yrs. ago: Amreen was X yrs. old. Juhi was 3x yrs. old. 10 years later: Amreen is x+10 yrs. old. Juhi is 3x+10 yrs. old. (3x+10) = 2(x+10). 3x + 10 = 2x + 20. X = 10. Amreen = x+10 = 10 + 10 = 20 yrs. old. Juhi = 3x+10 = 3*10 + 10 = 40 yrs. 0ld.
October 17, 2015

Science
1. False. The forces are balanced. 2. Air resistance. 7. Size of an object.
October 17, 2015

physics
M*g = 82 * 9.8 = 803.6 N. = Wt. of crate. = Normal force, Fn. Fk = u*Fn = 0.3 * 803.6 = 241 N. = Force of kinetic friction. F-Fk = M*a. 314-241 = 82*a. 82a = 73. a = 0.890 m/s^2. Vf^2 = Vo^2 + 2a*d. Vo = 0. Vf = ?.
October 16, 2015

PHYSICS
See previous post: Fri, 10-16-15, 12:41 AM.
October 16, 2015

physics
a. h = 0.5g*Tf^2. h = 414.1 m. g = 9.8 m/s^2. Tf = ? = Fall Time. Dx = Xo*Tf. Dx = 95.3 m. Xo = ? = Initial hor. speed. b. Y = Yo + g*Tf. Yo = 0. Y = ? = Ver. component of total velocity. Speed = Sqrt(Xo^2 + Y^2).
October 16, 2015

physics
Fo = (340+Vo)/(340-Vs1)*Fs1. Fo = (340+0)/(340-20) * 500 = 531.25 Hz. = The freq. heard by the observer. Fo = (340+0)/(340-23) * 500 = 536.28 Hz. Fb = 536.28 - 531.25 = 5.028 Hz = Beat freq. Note: The Freq. of S1 and S2 are equal, but their velocities are different. Therefore...
October 16, 2015

Physics
Dx = Vo^2*sin(2A)/g. Vo = 11 m/s. A = 30o g = 9.8 m/s^2. Dx = ?
October 16, 2015

Physics
a. h = 0.5g*t^2. g = 9.8 m/s^2. h = 1.05 m. t = ? b. Dx = Xo*t. Xo = 1.90 m/s. t = Value calculated in part a.
October 15, 2015

physics
Dx = Vo^2*sin(2A)/g = 44. m. Vo^2*sin(68)/9.8 = 44. Vo^2*0.0946 = 44. Vo^2 = 465.1. Vo = 21.6 m/s. at 34o below the hor. Xo = Vo*Cos A = 21.6*Cos34 = 17.9 m/s. Dx = 17.9*T = 44. T = 2.46 s. = Time in air.
October 15, 2015

physics
Vo = 15 m/s. Yf^2 = Yo^2 + 2g*h. Yf = 0. g = -9.8 m/s^2. h = 2 m. Yo = ?. sin A = Yo/Vo. A = ?
October 15, 2015

Physics
Vo = 120m/s[25o]. Xo = 120*Cos25 = 108.8 m/s. Yo = 120*sin25 = 50.71 m/s. Yf = Yo + g*Tr = 0 at max h. Tr = -Yo/g = 50.71/-9.8 = 5.17 s. = Rise time. Tf = Tr = 5.17 s. = Fall time. a. T = Tr + Tf = Time of Flight. b. Range = Xo*T. c. h max = Yo*Tr + 0.5g*Tr^2. g = -9.8 m/s^2.
October 15, 2015

physics
Wb = M*g = 330 * 9.8 = 3234 N. Fp = 3234*sin A = Force parallel to the incline. Fn = 3234*Cos A = Force perpendicular to the incline. Fs=u*Fn = 0.25 * 3234*Cos A = 809*Cos A = Force of static friction. Fp-Fs = M*a. 3234*sin A-8o9*Cos A = M*0 = 0. 3234*sin A = 809*Cos A. Divide...
October 15, 2015

Physis
h = 0.5g*t^2.
October 15, 2015

Algebra 2
If you mean: (x-3)/x = 3/5. Multiply Eq by 5x: 5x-15 = 3x. 5x - 3x = 15. 2x = 15. X = 7.5.
October 13, 2015

Algebra 2
x - 3/x = 3/5. Multiply Eq by 5x: 5x^2 - 15 = 3x. 5x^2 - 3x -15 = 0. Use Quad. Formula. X = -1.46, and 2.06.
October 13, 2015

Algebra 2
In Eq2, replace Y with 5: x - 5 = 2. X = 7. (x, y) = (7, 5).
October 13, 2015

college algebra
V = Vo + g*Tr = 0 at max h. Tr = -Vo/g = -108/-32 = 3.375 s. = Rise time. Tf = Tr = 3.375 s. = Fall time. A. T = Tr+Tf B. h = Vo*t + 0.5g*t^2 = 180 Ft. 108t - 16t^2 - 180 = 0. -16t^2 + 108t - 180 = 0. Use Quad. Formula. t = 3.0 s.
October 13, 2015

algebra
V = 460mi/1h = 460 mi/h. Or V = 920mi/2h = 460 mi/h. Or V = 1380mi/3h = 460 mi/h. Or V = 1840mi/4h = 460 mi/h. Get it? d = V*T = 5060 miles. 460*T = 5060. T = 11 h.
October 13, 2015

Science
A. M*V
October 13, 2015

Science
A. m*V.
October 13, 2015

Revolution and frequency i need help physics
P = 15min/60rev = 0.25 min./rev. F = 1/P = 1/0.25 = 4 rev./min. Or F = 60rev/15min. = 4 rev/min.
October 13, 2015

math
2. Cr = 2pi. C = 2pi/r. Not equivalent.
October 13, 2015

science
d = 600 + 420 = 1020 km.
October 13, 2015

Algebra
2.28*10^-8 = 0.0000000228. 7^-2 = 1/7^2 = 1/49. I'm not sure what they want here.
October 13, 2015

Math
3.56*10^-5 = 0.0000356
October 13, 2015

physics
M*g = 16.5 * 9.8 = 161.7 N. = Wt. 0f cart. a. F*Cos27.9-Fk = M*a. 0.884F - 48.1 = M*0 = 0. 0.884F = 48.1. F = 54.4 N. = Force exerted. b. Work = F*d = 54.4 * 36.6 = 1992 J. c. Work = Fk*d = 48.1 * 36.6 = 1760 J. d. Work=Mg * d = 161.7 * 36.6 = 5918 J.
October 13, 2015

algebra
2.7*10^-5 / 9*10^-6 = 0.3*10^1 = 3. When dividing, subtract the exponent in the denominator from that in the numerator.
October 13, 2015

physics
h = 0.5g*t^2.
October 13, 2015

science
g on the moon = 1/6 g on earth: 1/6 * 60N = 10 N. = Wt. on the moon. Or M*g = 60 N. M*9.8 = 60. M = 6.122 kg. g = 9.8/6 = 1.633 m/s^2. on moon. M*g = 6.122 * 1.633 = 10 N.
October 13, 2015

phyisics
D = 28m[325o]CCW + 45m[270o]CCW. X = 28*Cos325 + 45*Cos270 = 22.9 + 0 = 22.9 m. Y = 28*sin325 - 45*sin270 = -16.1 - 45 = -61.1 m. Q4. Tan A = Y/X = -61.1/22.9 = -2.66812. A = -69.5o = [E69.5oS] = 290.5 CCW. D = Y/sin A = -61.5/sin290.5 = 65.2 m. V = D/T = 65.2m/6.9s = 9.5 m/s...
October 12, 2015

Math
a. h = -4.9*1^2 + 24.5*1 + 1. b. Y = Yo + g*Tr = 0 at max h. Tr = -Yo/g = -24.5/-9.8 = 2.5 s. = Rise time or time to reach max h. c. h max = -4.9Tr^2 + 24.5Tr + 1 d. h max = 0.5g*Tf^2 Tf = ?. T = Tr + Tf.
October 12, 2015

physics
Wb = M*g = 12 * 9.8 = 117.6 N. = Normal force, Fn. Fx-Fk = M*a. Fx-Fk = M*0 = 0. Fk = Fx = 30 N. Fk = u*Fn. u = Fk/Fn = 30/117.6 = 0.255. Note: Since the velocity is constant, the acceleration is zero.
October 12, 2015

Physics
Xo = 96.8 mi/h * 5280Ft/mi * 1h/3600s = 142 Ft/s. Dx = Xo*Tf = 60 Ft. 142Ft/s * Tf = 60. Tf = 0.423 s. = Fall time. d = 0.5g*Tf^2 = 16*0.423^2 = 2.86 Ft., Vertically.
October 12, 2015

Physics
See related Questions: Tue, 9-2-14, 11:13 AM.
October 12, 2015

Physics
1. Dx = Xo*Tf = 8.2 m. h = 0.5g*Tf^2 = 3.3 m. 4.9*Tf^2 = 3.3. Tf^2 = 0.673. Tf = 0.821 s. = Fall time. Xo*0.821 = 8.2 m. Xo = 10.0 m/s. 2. Dx = Xo*Tf. h = 0.5g*Tf^2 = 1.6 m. 4.9*Tf^2 = 1.6. Tf^2 = 0.327. Tf = 0.571 s. Dx = 10m/s * 0.571s. = 5.71 m.
October 12, 2015

Math
60mi/h=60mi/3600s. * 1600m/mi = 26.7 m/s 10mi/h = 10/60 * 26.7 = 4.44 m/s. 500Ft. * 1m/3.3Ft = 152 m. a = (Vf-Vo)/t = (26.7-0)/7.6 = 3.51 m/s. Vf^2 = Vo^2 + 2a*d. Vo^2 = Vf^2-2a*d = 4.44 - (-8.88)*152 = 1354.2 Vo = 36.8 m/s. = Max. initial velocity for the given stopping ...
October 12, 2015

Physics
Wc = M*g = 60 * 9.8 = 588 N. = Normal force, Fn. Fk = u*Fn = 0.3 * 588 = 176.4 N. Work = Fk*d = 176.4 * 12 = 2117 J. Fap-Fk = M*a. 200-176.4 = 60*a. 60a = 23.6. a = 0.393 m/s^2. Work = M*a * d = 60*0.393 * 12 = 283 J.
October 12, 2015

applied mechanics
Incomplete.
October 12, 2015

Physics
A = 0o: Fn = Wb = 120 N. = Normal force Fn = 120-F*sin A = 0.5*120. 120-100*sin A = 60. -100*sin A = -60. sin A = 0.60. A = 36.9o.
October 11, 2015

Physics
W1*d1 = W2*d2. 45*0.6 = 60*d2. d2 = 0.45 m.
October 11, 2015

Science
F = 0.060m * 950N/m = 57 N. Work = F*d = 57 * 0.06 = 3.42 J.
October 11, 2015

science
There are too many errors in your problem. Please retype.
October 10, 2015

PHYSICS
M*g = 25 N. M*9.8 = 25. M1 = 2.55 kg. h = L*sin30 = 1 * sin30 = 0.5 m. PE = Mg*h = 25 * 0.5 = 12.5 J. at top of incline. KE = 0.5M*V1^2 = 12.5 J. at bottom of incline. 0.5*2.55*V1^2 = 12.5. 1.28V1^2 = 12.5. V1^2 = 9.8. V1 = 3.13 m/s. at bottom of incline. M2 = 40/g = 40/9.8 = ...
October 10, 2015

Physics
F1 + F2 = 19[58o] + -25+16.5i = 19*Cos58+i19*sin58 -25 + 16.5i = 10.1 + 16.1i - 25 + 16.5i=-14.9+32.6i,Q2 = 35.8N.[65.4o] N. of W. = 35.8N[144.2o] CCW.
October 10, 2015

Calculus
Also isn't there an infinite number of solutions to this equation? How are you supposed to solve it then?
October 10, 2015

Calculus
Can you show some more steps in between I can't get how to solve for y and x with only 1 equation.
October 10, 2015

Calculus
(x^2+y^2)^2=16y Find all values of x where the tangent line is vertical I found the derivative and looked for where it was undefined but it didn't work
October 10, 2015

Physics
T1*sin148 + T2*sin74 = 725 N. Eq1: 0.53T1 + 0.96T2 = 725. T1*Cos148 + T2*Cos74 = 0. Eq2: -0.85T1 + 0.28T2 = 0. -0.85T1 = -0.28T2. T1 = 0.324T2. In Eq1, Replace T1 with 0.324T2: 0.53*0.324T2 + 0.96T2 = 725. 0.172T2 + 0.96T2 = 725. 1.13T2 = 725. T2 = 640.5 N. T1 = 0.324*640.5 = ...
October 10, 2015

Calculus
what is the limit as h approaches 0 of ((x+h)^pi-x^pi)/h? Multiple choice answers: A: lnx B: lnx (x^pi) C: Pi lnx D: (pi^2) ln (x^2) E: (pi^x) lnx I know this is d/dx x^pi, or Pi x^(Pi-1)
October 10, 2015

Physics
Yf^2 = \Yo^2 + 2g*h = 0. Yo^2 = -2g*h = -2*(-9.8)*25 = 490. Yo = 22.1 m/s. a. Yf = Yo + g*Tr = 0. 22.1 - 9.8Tr = 0. Tr = 2.26 s. = Rise time. Tf = Tr = 2.26 s. = Fall time. Xo = Yo = 22.1 m/s. = Hor. velocity. Dx = Xo*(Tr+Tf) = 22.1 * 4.52 = 100 m. b. Range = Vo^2*sin(2A)/g. ...
October 10, 2015

Science
V = 1.23m/4.66*10^-8s. = 2.639*10^7 m/s.
October 9, 2015

Conversions?
1. 4106/1000 = 4.106 kilomockingbirds. 2. 10^-3 * 10^6=10^3 = 1,000 Microphones
October 9, 2015

math
Glad I could help.
October 9, 2015

math
9 yrs. ago: Valerie's age = X yrs. Jose' age = 3x yrs. The present: Valerie: (x+9) yrs. old. Jose: (3x+9) yrs. old. x+9 + 3x+9 = 78. 4x + 18 = 78. 4x = 60. X = 15 yrs. 3x+9 = 3*15 + 9 = 54 yrs. = Jose's age.
October 9, 2015

Algebra
See previous post: Fri, 10-9-15, 2:o4 PM.
October 9, 2015

Algebra
P = Po(1+r)^n. Po = $4185. r = (4.1%/4)/100% = 0.010. n = 4Comp./yr. * t yrs. = 4t Compounding periods. P = 4185(1.010)^4t = 5019. 1.010^4t = 1.19928. 4t*Log 1.010 = Log 1.19928. 4t = Log 1.19928/Log 1.010. 18.26. t = 4.57 Yrs.
October 9, 2015

Algebra
Molly's Time = 3 + 2 = 5 h.
October 9, 2015

Algebra
Molly: d1=V*t = 27 * 2 = 54 Miles head- start. d2 = d1 + 54. 45*T = 27*T + 54 18T = 54. T = 54/18 = 3 h.
October 9, 2015

Math
3/4 + 1/8 + 1/2 = 6/8 + 1/8 + 4/8 = 11/8 = 1 3/8 Glasses.
October 9, 2015

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