Wednesday

April 16, 2014

April 16, 2014

Total # Posts: 8,508

**Physics (MOMENTUM)**

Ball B. Momentum = m*V. Ek = 0.5m*V^2. Ball A: Momentum = (m/2)*2V = m*V. Ek = 0.5m*V^2 a. Their momentum is equal. b. Their kinetic energy is equal.

**Math**

Incomplete.

**physics**

h = ho + (V^2-Vo^2)/2g h = 14.7 + (0-(7.53)^2)/-19.6 = 17.6 m. Above gnd. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*17.6 = 345 V = 18.6 m/s. V = Vo + g*t Tr = (V-Vo)/g = (0-7.53)/-9.8=0.768 s.= Rise time. h = Vo*t + 0.5g*t^2 = 17.6 m. 0 + 4.9t^2 = 17.6 t^2 = 3.59 Tf = 1.89 s. = Fall ti...

**science**

How are the resistors connected?

**pre algebra**

P = Po(1+r)^n P = 100(1+0.05)^5 P = 100(1.05)^5 = $127.63.

**physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*3 = 58.8 V = 7.67 m/s.

**mathematics**

See previous post.

**mathematics**

See previous post.

**mathematics**

X Nickels. 2x Dimes. (2X-4) Quarters. 5x + 10*2x + 25(2x-4) = 575 Cents. Solve for x.

**physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*1 = 19.6 V = 4.43 m/s.

**science**

See previous post.

**Physics**

a. Wo^2=1/LC=1/(0.015*5*10^-6)=1.33*10^7 Wo = 3651 Rad/s. b. Xl=0.25Wo*L=0.25*3651*0.015=13.7 Ohm Xc=1/(0.25*3651*5*10^-6) = 219 Ohms. Z^2 = R^2 + (Xl-Xc)^2 Z^2 = (80)^2 + (13.7-219)^2 = 48,548.1 Z = 220.3 Ohms. Im = V/Z = 40/220.3 = 0.182A. Xl = W*L = 3651*0.015 = 54.77 Ohms ...

**physics**

h = Vo*t + 0.5g*t^2 = 0.35 m 0 + 4.9t^2 = 0.35 t^2 = 0.0714 t = 0.257 s.

**science**

See previous.

**science**

Increase in velocity.

**science**

My answer is C. The force must act in the same direction as the motion.

**business math**

See previous post.

**Business Math**

X Banana splits @ $4.25 each. 4x Sundaes @ $3.60 each. 4.25*x + 3.60*4x = 3730 X = 200.

**Math**

[(3-5)+3*8]/4[8-4/2(7+1)] = ]-2+24]/4[-8] = (22/4) * (-8) = -44.

**acollege algebra**

Correction: (2,-7) should be (2,-3).

**acollege algebra**

Correction: F(x) = Y = 2(x-3)^2-5 Use the following points for graphing: (X,Y) (1,3) (2,-7) V(3,-5) (4,-3) (5,3)

**acollege algebra**

F(x) = Y = 2(x-3)^22(-5 Y = 2(x^2--6x+9)-5 Y = 2x^2-12x+18-5 Y = 2x^2-12x+13 h = -B/2A = 12/4 = 3 k = 2(3-3)^2-5 = -5 V(h,k) = (3,-5) Use Quad. Formula and get: X = 4.5,and 1.5. = X- Intercepts To find Y-int.,replace x in given Eq with 0 and solve for y. Y-int = 4.

**math**

I = Po*r*t = 5000*0.06*1 = $300.

**physics**

V = 3.42L * (309k/215k) = 4.92 L.

**math**

9/2 - 1/2 = 8/2 = 4.

**Math**

L = h/sinA = 32/sin39 = 51 m.

**Physics Need help plz**

Accuracy = (+-0.22/22)*100% = +- 1.0 %.

**um reviewing old subjects .. Linear Equations**

A = X Degrees. B = (x+24) Degrees. The sum of 2 complimentary angles = 90o: A + B = 90o X + (x+24) = 90 2x + 24 = 90 2x = 90-24 = 66 X = 33o X+24 = 57o

**physics**

Please leave space between words.

**physics**

Please clarify your problem.

**algebra**

X 10-point questions. Y 5-point questions. Eq1: X + Y = 21 Questions Eq2: 10x + 5y = 200 Points. Multiply Eq1 by -5 and add Eq1 and Eq2: -5x - 5y = -105 10x + 5y = 200 Solution set: (X,Y) = (19,2). 5x = 95 X = 19 In Eq1, replace x with 19: 19 + y = 21 Y = 2.

**algebra**

10 - 0.5y = 1.5x -1.5x - 0.5y = -10 Multiply both sides by -2: Eq1: 3x + y = 20 y = 0.5(6x+40) y = 3x + 20 Eq2: -3x + y = 20 Add Eq1 and Eq2: 2y = 40 Y = 20 In Eq1. replace y with 20: 3x + 20 = 20 3x = 20-20 = 0 X = 0. Solution Set: (x,Y) = (0,20).

**Physics**

V=pi*r^2 * h=3.14*0.35^2 * 2.1=0.8o8 m^3 Mass = 0.808 m^3 * 2200kg/m*3=1777.1 kg. Wt. = 1777.1kg * 1Lb/0.454kg = 3914 Lbs.

**math**

The slope of the perpendicular line is the negative reciprocal of the give slope. m = -(-1/8)= 1/8.

**Algebra**

y = -3x/2 + 3 Multiply both sides by -2: -2y = 3x - 6 2y = -3x + 6 2y = 6 - 3x Answer = A.

**algebra word problem**

X Students sold. X+100 Adult tickets sold. 2000-(x+x+100) = 1900-2x Children tickets sold. 10x + 12(x+100) + 5(1900-2x) = $19,700. 10x + 12x+1200 + 9500-10x = 19700 12x = 19700-10700 = 9000 X = 750 X+100 = 850 1900-2x = 400.

**Maths**

Use the law of cosines. cosA = (-a^2+b^2+c^2)/2bc. cosA=(-(8.6)^2+(9.1)^2+(9.7)^2)/176.54 = 0.58310. A = 54.33o. Area = 0.5*bc*sinA. Area=0.5*9.1*9.7*sin(54.33) = 35.9 cm^2

**physics**

See previous post.

**physics**

a. a = (V-Vo)/t = (11-0)/4.8=2.29 m/s^2. d = 0.5a*t^2 = 0.5*2.29*(4.8)^2=26.4 m. Work = F*d = mg*d = (79*9.8) * 26.4 = 20,439 J. b. P = F*d/t = 20439/4.8 = 4258 J/s = 4258 W.

**axia**

I'm assuming the account is compounded annually. A = Po(1+r)^n n = 1comp/yr. * 2yrs. = 2 Compounding periods. A = 4000(1.1)^2 = $4840.

**maths**

1. d = 16*t^2. 1 s. 16 Ft. 2 s. 64 Ft. 3 s. 144 Ft. d = 4.9*6^2 = 176.4 Ft in 6v s. 3. T = 75(1+0.10)^3 = 99.8o.

**Physics**

Incomplete.

**physics**

ho = 0.5*a*t^2 = 0.5*20*60^2 = 36,000 m. Vo = a*t = 20*60 1200 m/s. a. h. = ho + (V^2-Vo^2)2g h=36000 + (0-(1200)^2)/-19.6=109,469 m. b. V = Vo + g*t Tr = To + (V-Vo)/g=60 + (0-1200)/-9.8 = 182.4 s. h = Vo*t + 0.5g*t^2 = 109,469 m. 0 + 4.9t^2 = 109469 t^2 = 22,341 s Tf = 150 s...

**math**

s + 0.2s = 4200 1.2s = 4200 S = $3500 = Wayne's salary. Barry's Salary. s - 0.4s = 3500 0.6s = 3500 S = $5833.33 = Barry's salary.

**science**

V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = (0-20^2)/100 = -4 m/s^2.

**math**

23000-0.07*t*23000 = 3000 23000 - 1610t = 3000 -1610t = 3000-23000 = -20000 t = 12.42 Years.

**physics**

Fn = 193 - 0.39*193 = 117.73 = Net force. Power = Fn * d/t Power = 117.73 * 4.9/12 = 48.1 J/s = 48.1 Watts.

**physics 1**

h = Vo*t + 4.9t^2 = 1000 m. 0 + 4.9t^2 = 1000 t^2 = 204.08 t = 14.3 s. = Fall time. D = 50m/s * 14.3s = 714.3 m.

**physic**

Vo = 350Ft/s[60o]. Xo = 350*cos60 = 175 Ft/s Yo = 350*sin60 = 303 Ft/s. b. Y^2 = Yo^2 + 2g*h h = (Y^2-Yo^2)/2g h = (0-(303)^2)/-64 = 1435 Ft. c. Dx = Vo^2*sin(2A)/g Dx = (350)^2*sin(120)/32 = 3315 Ft. d. 350 Ft/s[60o]. Same as initial velocity.

**algebra**

2. h = Vo*t + 0.5g*t^2 = 84 Ft. 10t + 16t^2 = 84 16t^2 + 10t - 84 = 0 Use Quadratic Formula. t = 2 s.

**calculus**

See Wed, 1:58AM post.

**algebra**

X min. = Joe's time. 2x/3 = Frank's time. 1/x + 3/2x = 1/40 Multiply both sides by 2x: 2 + 3 = x/20 x/20 = 5 X = 100 min. = Joe's time. 2x/3=200/3 = 66.67 min. = Frank's time.

**math**

a. F(x) = x/(x+6).

**algebra**

Y = -16t^2 + 400 h = Xv = -B/2A - 0/-32 = 0. k = Yv = -16*0^2 + 400 = 400. V(0,400).

**Math**

d1 = d2 V*(4+1) = 50*4 = 200 5V = 200 V = 40 Mi/h = Adam's speed.

**math algebra**

(15+Vc)t = 20 Eq1: 15t + Vc*t = 20 (15-Vc)t = 10 Eq2: 15t - Vct = 10 Add Eq1 and Eq2: 15t + Vct = 20 15t _ Vct = 10 30t = 30 t = 1 h. 15*1 + Vc*1 = 20 Vc = 20-15 = 5 mi/h. = Velocity of current.

**math**

P = Po(1+r)^n r = (6%/2)/100% = 0.03 = Semi-annual % rate expressed as a decimal. n = 2Comp,/yr. * 25yrs. = 50 Compounding periods. Po(1.03)^50 = $600,000 Po*4.38391 = 600000 Po = $136,864.25 = Present value. Plug the above values into the given Eq. and get $

**Physics**

Power = F*d/t = mg*d/t =(60*10)*1.2/1.5 = 480 J/s = 480 Watts.

**math**

P = Po*e^rt 1000*e^0.079t = 100,000 e^0.079t = 100000/1000 = 100 Take Ln of both sides: 0.079t*Ln e = Ln 100 0.079t*1 = 4.61 t = 58.3 yrs. 1-1-2008 + 58.3yrs. = 4-19-2066.

**math**

Slope = -2, P(0,-3). Slope-intercept Form. Y = mx + b -2*0 + b = -3 b = -3. Eq.: Y = -2x - 3. Point-slope Form. (0,-3), (x,y). Slope = (y+3)/(x-0) = -2 Cross multiply: Eq.:y+3 =-2(x-0).

**mechanics**

F = m*a = 18 * 36 = 648 N.

**Physics**

I have no idea what your circuit looks like.

**algebra1**

T=(T1*T2)/(T1+T2)=(20*30)/(20+30)=12 min.

**Math**

P = Po*e^rt r*t = (3%/100%) * 2yrs. = 0.06 P = 2000*e^0.06 = $2123.67

**Algebra**

V = Vo + g*t t = (V-Vo)/g = (0-45)/-32 = 1.41 s. ht. = 6 + 45*1.41 - 0.5*32*(1.41)^2 = 37.64 Ft.

**math**

d = Vo*t + 0.5a*t^2 d = 4.5*7 + 0.5*2.5*7^2 = 92.75 m.

**algebra**

10/3x + 4/3 = (7+x)/2x Multiply both sides by 6x: 2*10 + 8x = 3(7+x) 20 + 8x = 21+3x 8x-3x = 21-20 = 1 5x = 1 X = 1/5.

**Algebra**

NOTE: B^2 = (-3)^2 = 9.

**Algebra**

Y = x^2 - 3x + 6. B^2 = (-3) = 9. 4*A*C = 4*1*6 = 24. B^2 - 4AC = 9 - 24 = -15 = The value under the radical. Since the value under the radical is negative, there are 2 imaginary solutions. Therefore, the graph does not touch or cross the x-axis. So there are no x-intercepts. ...

**algebra-word problem**

X+11 = 121 h.

**algebra-word problem**

X = The # of hours before the increase. (X+11) = The # of hours after the increase. (x+11)/x = 1.1 1.1x = x+11 1.1x - x = 11 0.1x = 11 X = 110 h.

**college physics**

Power = 7.0hp * 746W/hp = 5222 Watts = 5222 Joules/s. Mass = 475Lbs * 0.454kg/Lb = 215.65 kg.= Mass of boiler. d = 38Ft./3.3Ft/m = 11.52 m. Work=F*d = mg * d=215.65*9.8 *11.52= 24,346 Joules. t = 24346J * 1s/5222J = 4.66 s.

**applied physics**

Fp = 35*cos40 = 26.8 N. = Force parallel to yard. Work = Fp*d = 26.8 * 900 = 24,130 Joules

**applied physics**

Work = 11*94Lbs * d == 4340Ft-Lbs. 1034d = 4340 d = 4.2 Ft.

**applied physics**

V^2 = Vo^2 + 2g*d V^2 = 0 + 64*(5000-1000) = 256,000 V = 506 Ft/s

**physics**

a. V^2 = 0 + 19.8*6.4 = 126.72 V = 11.26 m/s.

**Science**

W1/W2=(F/2 *4d)/(F*d)=(2F*d)/(F*d)=2. W1 = Joe's work. W2 = Mary's work. Joe does twice as much work as Mary.

**physics**

V = Vo + g*t = 0 t = (V-Vo)/g = (0-2.6)/-9.8 = 0.265 s.

**nyoike**

producea java program which when given 3 sides of a triangle determines whether the traingle is an equilateral an issosceles or a scaline

**Physics**

mg*h = 0.5m*V^2 Divide both sides by m: g*h = 0.5V^2 V^2 = 2gh V = sqrt(2g*h.

**physics**

a = (V-Vo)/t = (10-0)/2 = 5 m/s^2.

**physics**

Speed = 30m/2s = 15 m/s.

**Physics**

See previous post.

**physics**

Fn = m*a = 40-24 = Net force. 8a = 16 a = 2 m/s^2.

**Solving an Equation in one variale**

Incomplete.

**geometry**

V=L*W*h=0.4m * 0.2m * 0.2m 0.016 m^3 Wt. = 0.016m^3 * 1700kg/m^3 = 27 kg.

**For the given functions f and g**

a. (F*g)(x) = sqrt(x)(5x-9) Domain: X => 0. Domain: All real values of X that are equal to or greater than zero. The value under the radical cannot be less than zero. b. F/g(x) = sqrt(x)/(5x-9)

**Math**

Use the following points for graphing: (X,Y) (-3,-15) (-2,-5) (-1,1) V(0,3) (1,1) (2,-5) (3,-15).

**physics**

Incomplete.

**Physics**

Incomplete.

**Math**

Tax=$125000*($6.35/$1000) + $125000($0.00587/$1.00) = 793.75 + 733.75=$ = $1527.50

**P&P**

d = 40m/min*6min + 200m = 440 m.

**physics**

Correction: V = 170 km/h[270o].

**physics**

V = 150[270o] + 20[270o] = 170km[270o].

**Intrest?**

See Related Questions: Fri,4-12-13,10:57AM.

**physics**

No. Magnitude AND direction must be equal: V1 = 70 km/h V2 = -70 km/h.

**Algebra**

3/(x+1) + 4/x = 2 Multiply both sides by X(x+1): 3x + 4(x+1) = 2x(x+1) 3x + 4x+4 = 2x^2 + 2x 7x - 2x -2x^2 = -4 -2x^2 +5x + 4 = 0 Use Quad. Formula and get: X = -0.64,and 3.14.

**Please Help! Rate of change...**

See Related Questions: Wed,4-17-13,12:03pm.

**Math**

See previous post.

**Algebra**

P = -25x^2 + 300x. h = Xv = -B/2A = -300/-50 = 6 Clerks. P = k = Yv = -25*6^2 + 300*6 = $900

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