Friday

December 9, 2016
Total # Posts: 12,461

**Calc 2**

∞ Σ n/(√n^7+5n+1) n=1 I just tried using a sub n and b sub n and got the limit = 1, therefore it diverges right? but I'm not sure

*May 11, 2015*

**ALGEBRA help ASAP**

At 0o: Tan A = Y/X X = r Tan A = Y/r = Sin A.

*May 11, 2015*

**pre calculus**

sin A = 3/5 = y/r, Q2. x^2 + y^2 = r^2 x^2 = r^2 - y^2 = 5^2 - 3^2=25 - 9 = 16 X = -4, Q2. Cos A = X/r = -4/5 Tan A = Y/X = 3/-4 = -3/4

*May 11, 2015*

**Physics**

Eq1: R1+R2 = E/I = 12.4/2.13 = 5.82 Ohms (R1*R2)/(R1+R2) = 12.4/9.01 = 1.38 Ohms Replace R1+R2 with 5.82 Ohms: R1*R2/5.82 = 1.38 R1*R2 = 5.82*1.38 = 8.0 R1 = 8/R2 In Eq1, replace R1 with 8/R2: 8/R2 + R2 = 5.82 8 + R2^2 = 5.82R2 R2^2 - 5.82R2 + 8 = 0 Use Quadratic Formula. R2...

*May 11, 2015*

**Math 12A Plain Trigonometry**

sin70.5 = 13/d d = 13/sin70.5 = 13.8 Miles.

*May 11, 2015*

**Analytic Geometry**

h = 0.5g*t^2 = 3 m. 4.9t^2 = 3 t^2 = 0.612 Tf = 0.782 s. = Fall time. Dx = Xo*Tf = 5 m. Xo * 0.782 = 5 Xo = 6.39 m/s = Hor. component of initial velocity. h = 0.5g*t^2 = 12 m. 4.9t^2 = 12 t^2 = 2.45 Tf = 1.56 s. Dx = Xo*Tf = 6.39m/s * 1.56s. = 10 m. From water outlet.

*May 11, 2015*

**Geometry**

C(x,y) B(8,2) x-8 = (8-0)/2 = 4 X = 12 y-2 = (2-0)/2 = 1 Y = 3 C(12,3) D(x,y) 12-x = 8-0 = 8 X = 4 3-y = 2-0 = 2 Y = 1 D(4,1)

*May 10, 2015*

**math**

P = Po + Po*r*t P = 7,000,000 + 7,000,000*0.05*12 = 11,200,000

*May 10, 2015*

**Math**

x-3y+9 = 0 -3y = -x - 9 Y = (1/3)x + 3 m = 1/3 b = 3

*May 10, 2015*

**Physics**

Out of phase.

*May 10, 2015*

**algebra**

N + .22N = 3,200,000 1.22N = 3,200,000 N = 2,622,951 or 2,623,000

*May 9, 2015*

**math**

Tan60 = 15/x X = 15/Tan60 = 8.66 Side = 2x = 2 * 8.66 = 17.32

*May 9, 2015*

**Physics**

Distance Traveled = 300 + 400 = 700 mi. Displacement = sqrt(300^2+400^2) = 500 m

*May 9, 2015*

**Math**

Tan26 = h/50 h = 50*Tan26 = 24.4 m.

*May 9, 2015*

**Simmons**

M*g = 2kg * 9.8N./kg = 19.6 N. = Wt. of box. Fp = 19.6*sin65 = 17.76 N. = Force parallel to the incline. Fn = 19.6*Cos65 = 8.28 N.=Perpendicular to the incline = Normal. Fs = u*Fn = 0.3 * 8.28 = 2.48 N. = Force of static friction. Fap-Fp-Fs = M*a Fap-17.76-2.48 = M*0 = 0 Fap...

*May 8, 2015*

**Physics**

Work = Energy output(Eo). Eff. = Eo/(Eo+800) = 0.20 Eo = 0.2(Eo+800) Eo = 0.2Eo + 160 0.8Eo = 160 Eo = = 200 J.

*May 8, 2015*

**Physics**

1609m/5280Ft * 100cm/m * 1Ft/12in = 2.54 cm/in.

*May 8, 2015*

**Physics**

Correct.

*May 8, 2015*

**Math**

850x > 300x + 7500 850x - 300x > 7500 550x > 7500 X > 13.6 Weeks.

*May 7, 2015*

**PreCal**

2|5x-5| + 4 = 20 2|5x-5| = 20-4 = 16 |5x-5| = 8 5x-5 = 8 5x = 13 X = 13/5 -(5x-5) = 8 -5x + 5 = 8 -5x = 3 X = -3/5

*May 7, 2015*

**math**

William: $X Jan: $2X Greg: $11. x + 2x + 11 = 26 x = ?.

*May 7, 2015*

**math**

PART A: Mr. Parker: $100/(5.4*3) = $6.17/m^2 Mr. Lewis: $115/(5.7*3.2) = $6.30/m^2 PART B: Mr. Parker: 49 Min./(5.4*3) = 3 Min/m^2 PART C: Mr. Lewis: (5.7*3.2)m^2 * 3Min/m^2=55min

*May 7, 2015*

**Algebra Readiness**

Slope = Y/X = 6/10 = 0.6 Note: 6/10 = 3/5(D).

*May 6, 2015*

**Physics**

Xc = 1/2pi*F*C = 79.62 Ohms. I = V/Xc = 30/79.62 = 0.377A = 37.7 mA.

*May 6, 2015*

**Physics**

Xl = 2pi*F*L = 6.28*25*30 = 4710 Ohms. I = V/Xl = 30/4710 = 0.0064 A = 6.4 mA

*May 6, 2015*

**physics**

4.5kW = 4500 W. = 4500 J./s Work = F*d = Mg * d = 3.56*10^7 * 1741.4 = 6199.4*10^7 = 6.199*10^10 J. T = 6.2*10^10J. * 1s/4500J = 1.38*10^7 s = 833.3 Hours.

*May 6, 2015*

**Physics**

See previous post: Wed, 55-6-15, 1:26 PM.

*May 6, 2015*

**Physics**

M*g = 40*9.8 = 392 N. = Wt. of sled. Fp = 392*sin 0 = 0 = Force parallel to the surface. Fn = 392*Cos 0 = 392 N. = Force perpendicular to the surface. Fs = u*Fn = 0.4 * 392 = 156.8 N. = Force of static friction. Fk = 0.25 * 392 N. = 98 N. = Force of kinetic friction. a. Fap-Fs...

*May 6, 2015*

**Trig**

sec A * sin A = 1/Cos A * sin A = Sin A/Cos A = Tan A.

*May 6, 2015*

**Physics**

X = 4 km/h Y = 3 km/h V = sqrt(X^2+Y^2)

*May 5, 2015*

**IDOC**

1/b(2b-10) = 17 Multiply both sides by b: 2b-10 = 17b 15b = -10 b = -2/3

*May 5, 2015*

**IDOC**

Multiply both sides by b: 2b-10 = 17b

*May 5, 2015*

**Physics**

V^2 = Vo^2 + 2g*h Vo = 12 m/s. g = -9.8 m/s^2 h = 5 m. V = ?

*May 5, 2015*

**science**

X = 3 km Y = 4 km D = sqrt(X^2+Y^2)

*May 5, 2015*

**chemistry**

what is the volume occupied by 2 moles of ammonia at s.t.p(1mole of gas at s.t.p=22.4)

*May 4, 2015*

**Physics**

I = 24/8 = 3A = Lamp current. Vr = 117-24 = 93 V. = Voltage across the resistor. R = Vr/I = 93/3 = 31 Ohms.

*May 4, 2015*

**math**

V = Vo(1-r)^t = 35,000/2 35,000(1-0.12)^t = 17,500 Divide both sides by 35,000: (0.88)^t = 0.5 Take Log of both sides: t*Log(0.88) = Log 0.5 t = Log 0.5/Log(0.88) = 5.42 Years.

*May 4, 2015*

**science**

Work = F*d = Mg*d = 80*9.8 * 6 = 4704 J

*May 3, 2015*

**math**

a. 19/20 - 5/8 - 7/10 = 38/40 - 25/40 - 28/40 = -15/40 = -3/8. b. (24/40)/(30/14)(25/63) = (3/8)/(15/7)(25/63) = (7/8)/(375/441) = 7/8 * 441/375 = 3087/3000 = 1029/1000 c. (-24/1)(1/1)(-1/1)(1/1)(-1/1)(1/30) = -24/30 = -4/5.

*May 1, 2015*

**Math**

22/7

*May 1, 2015*

**Physics**

1A = 1C/s 1.1*10^-3A = 1.1*10^-3 C/s. T = 3.40C * 1s/1.1*10^-3C = 3090 C.

*April 30, 2015*

**Math**

There appears to be a typo in your problem. So I'm assuming b = h = 14 in. At = bh/2 = 14*14/2 = 98 in^2 = Area of triangle. As = 7^2 = 49 in^2 = Area of the square. Ar = At-As = 98 - 49 = 49 in^2 = Area remaining.

*April 30, 2015*

**Consumer math**

I = Po*r*t = 4000*(0.095/360)*270 = $285

*April 30, 2015*

**Financial math**

Po = 0.80 * 235,000 = $188,000 P = (Po*r*t)/(1-(1+r)^-t) r = (4.5%/12)/100 = 0.00375 = Monthly % rate expressed as a decimal. t = 30yrs. * 12mo/yr. = 360 Months. Monthly Payments = P/t

*April 30, 2015*

**algebra**

(y+4)/3 + 6 = (3y-1)/4 - 2 4(y+4)/12 + 6 = 3(3y-1)/12 - 2 (4y+16)/12 + 6 = (9y-3)/12 - 2 Multiply both sides by 12: 4y + 16 + 72 = 9y - 3 - 24 4y - 9y = -27 -88 -5y = -115 Y = 23

*April 30, 2015*

**Math**

A.12mo/yr. * 10yrs. = 120 months I = Po*r*t = 20,000*(0.04/12)*120 = B. 360days/yr * 5yrs. = 1800 days I = 20,000*(0.08/360)*1800 =

*April 30, 2015*

**Physics**

P = 8.8*10^6 * 19*10^-3 =

*April 30, 2015*

**Physics**

Glad I could help!

*April 30, 2015*

**Physics**

a = F/M = 152/0.07 = 2171 m/s^2 V = Vo + a*t Vo = 0 a = 2171 m/s^2 t = 0.030 s. V = ? KE = o.5*M*V^2

*April 30, 2015*

**physics**

See Related Questions: Thu, 4-21-11, 9:53 AM.

*April 30, 2015*

**physics**

Dx = Xo*Tf = 200 m. 400 * Tf = 200 Tf = 0.5 s. = Fall time. d = 0.5g*Tf^2 = 4.9*0.5^2 = 1.23 m.

*April 29, 2015*

**science**

Incomplete.

*April 29, 2015*

**physics**

1. V^2 = Vo^2 + g*h V = 0 Vo = 50 m/s g = -9.8 m/s^2 h = ? 2. V = Vo + g*Tr = 0 Tr = -Vo/g = -50/-9.8 = 5.1 s. = Rise time = Time to reach max ht. 3. Tf = Tr = 5.1 s. = Fall time. Tr + Tf = 5.1 + 5.1 = 10.2 s. = Time in flight.

*April 29, 2015*

**Math**

V = sqrt(90*60*54) = 540 in^3

*April 29, 2015*

**physical science**

D = 90 Ft.

*April 29, 2015*

**math**

V = sqrt(90*54*60) = 540 Cubic units.

*April 29, 2015*

**physics**

V^2 = Vo^2 + 2g*h V = 0 Vo = 1.2 m/s g = -9.8 m/s^2 h = ?

*April 29, 2015*

**physics**

Distance from each end to the center = 5/2 = 2.5 m. 2.5 - 1.5 = 1.0 m from center. 40*1 = 25*d d = 1.6 m from center = 0.9 m from the end.

*April 29, 2015*

**trig**

Vpw = 630mi/3h = 210m1/h, Due North Vpw = Vp + Vw = 210i Vp + 15[318o] = 210i Vp + 15*Cos318+15*sin318 = 210i Vp + 11.15 -10i = 210i Vp = -11.15 + 210i + 10i = -11.15 + 220i ,Q2. Tan A = 220/-11.15 = -19.73094 A = -87.1o = 87.1o N. of W. = 92.9o CCW from + x-axis. = 2.9o W. of...

*April 28, 2015*

**algebra**

T1 = 5 h T2 = 6 h T = T1*T2/(T1+T2) = 30/11 = 2.73 h.

*April 28, 2015*

**geometry**

Area = pi*r^2 When the radius is doubled: Area = pi * (2r)^2 = pi * 4r^2. Therefore, the area is 4 times the original value.

*April 27, 2015*

**geometry**

Circumference = pi*2r = pi*Dia. = 3.14 * 50 = 157.1 Ft. When the radius is doubled, the diameter is also doubled. Therefore, the Circumference is doubled: Circumference = 3.14 * 100 = 314.2 Ft.

*April 27, 2015*

**Math 222**

See your previous post.

*April 27, 2015*

**Math 222**

See your previous post.

*April 27, 2015*

**Physics**

V = a*t = 10 * 3 = 30 m/s KE = 0.5*M*V^2 Solve for KE

*April 27, 2015*

**math- algebra**

5x > 2x + 18 5x-2x > 18 3x > 18 X > 6 Note: Any real value of X greater than 6 will satisfy the inequality.

*April 27, 2015*

**Math**

Correction: If Sin A = -0.204 A = -11.8o = 11.8o N. of W. = 168.2o CCW from + x-axis; Q2. If Sin A = 0.204 A = 11.8o S. of W. = 191.8o CCW from + x-axis.

*April 27, 2015*

**Math**

sin A = -0.204 A = -11.8o = 11.8o W. of S. = 258.2o CCW from + X-axis.

*April 27, 2015*

**Math 222**

x = -1 x+1 = 0 x = -2 x+2 = 0 (x+1)(x+2) = 0 x^2 + 2x + x + 2 = 0 x^2 + 3x + 2 = 0

*April 27, 2015*

**Math 222**

y^2 - 18y + (-18/2)^2 y^2 - 18y + 81

*April 27, 2015*

**physics**

See Related Questions: Mon, 2-11-13, 12:22 PM.

*April 27, 2015*

**physics**

E = 18 V. R1 = 61 Ohms R2 = 34 Ohms R3 = 90 Ohms R4 = 11 Ohms I2 = ? Req. = R4 + (R1+R2)R3/(R1+R2+R3) Req. = 11 + (95)90/185 = 11 + 46.22 = 57.22 Ohms. I4 = E/Req. = 18/57.22 = 0.315A I2 + I3 = 0.315A I3 = 95/90 * I2 = 1.056I2 I2 + 1.056I2 = 0.315 2.056I2 = 0.315 I2 = 0.1532A

*April 26, 2015*

**PHYSICS**

M1*V1 + M2*V2 = M1*V + M2*V 16.6*8.92 + 29.2*4.44i = 16.6V + 29.2V 148.1 + 129.6i = 45.8V 196.8[41.2o] = 45.8V V = 4.3 m/s[41.2o] a. Momentum = 196.8 kg-m/s b. Direction = 41.2o N. of E.

*April 26, 2015*

**Physics**

First arrow: V = Vo + g*Tr = 0 Tr = -Vo/g = -10/-10 = 1.0 s.=Rise time So #2 is shot at the same time #1 starts falling. h = Vo*Tr - 0.5g*Tr^2 h = 10*1 - 5*1^2 = 5 m. ho-0.5g*t^2 = Vo*t + 0.5g*t^2 5 - 5*t^2 = 15*t - 5*t^2 5 - 5t^2 + 5t^2 = 15t The 5t^2 terms cancel: 15t = 5 t...

*April 26, 2015*

**PHYSICS ANSWER CHECK**

Vo = 60mi/h * 1600m/mi * 1h/3600s = 26.67 m/s V = Vo + a*t = 0 a = -Vo/t = -26.67/2.6 = -10.26 m/s^2 M = 3225Lbs * 0.454kg/1Lb = = 1464 kg F = M*a = 1464 * (-10.26) = -15,022 N. Note: Your answer would have been correct if you had converted 60 mph to m/s.

*April 25, 2015*

**PHYSICS answer check**

See previous post: Thu, 4-23-15, 6:12 PM.

*April 25, 2015*

**physics**

Rate of doing work = power. P = Fe*Cos21 * V P = 2.3*Cos21 * 7.9 = 17 J/s = 17 Watts.

*April 25, 2015*

**maths**

2 bags 6 Pouches Pouch cost $X each. Bag cost $(X+24) each. 2(x+24) + 6*x = $568 Solve for x.

*April 25, 2015*

**PHYSICS**

KE = 0.5M*V^2 = 0.5*0.025*80^2 = 80 J. F*d = F*1 = 80 J. F = 80 N.

*April 24, 2015*

**Math**

A(-8, 12), M(x, y), B(-13, -2) X = ((-8) + (-13))/2 = -10 1/2 = -21/2 Y = (12 + (-2))/2 = 5 M(-21/2, 5)

*April 24, 2015*

**physics**

Req = R1 + R2 + R3 = 13 + 35 + 2000 = 2048 Ohms.

*April 24, 2015*

**Algbra**

d1 = Sarah's distance d2 = Chelsea's distance. d2 = d1 + 55 Vc*T = Vs*T + 55 75T = 55T + 55 20T = 55 T = 2.75 h. = 2h-45 Min.

*April 24, 2015*

**physics**

See previous post: Thu, 4-23-15, 6:12 PM

*April 23, 2015*

**Physics**

a. KE = 0.5*M*Vo^2 KE = 200 J. M = 0.02 kg Solve for Vo, the initial velocity. b. M*g*h = 200 M = 0.02 kg 9 = 9.8 m/s^2 Solve for h.

*April 23, 2015*

**Physics**

Wt. = 0.05kg + 9.8N/kg = 0.49 N.

*April 23, 2015*

**Physics**

Y = Yo + g*Tr = 0 Yo - 9.8*(3.4/2) = 0 Yo = 16.66 m/s = Ver. component of initial velocity. sin A = Yo/Vo sin55 = 16.66/Vo Vo = 16.66/sin55 = 20.34 m/s Xo = Vo*Cos55 = 20.34*Cos55 = 11.67 m/s. V = Xo+Yi = 11.67 + 0 = 11.67 m/s Momentum change = M*V - M*Vo M = 3.0 kg V = 11.67 ...

*April 23, 2015*

**Math--Please help!!**

See previous post: Tue, 4-21-15, :31 PM.

*April 22, 2015*

**Consumer math**

1. 9 2/3 - 1/6=29/3-1/6=58/6 - 1/6=57/6 (57/6)/1/6 = 57/6 * 6/1 = 57 1.10 + 57*0.20 = $12.50 2. 9 - 1/6 = 54/6 = 1/6 = 53/6 1.10 + 53*0.20 = $11.70

*April 22, 2015*

**physics 111**

3. d = V*T = 40 km V*2 = 40 V = 20 km/h 4. Fr = 100N[170o] + 100N[50o] X = 100*Cos170 + 100*Cos50 = -34.2 N. Y = 100*sin170 + 100*sin50 = 94 N. Q2. Tan A = Y/X = 94/-34.2 = -2.74854 A = -70o = 70o N. of W. = 110o CCW Fr = Y/sin A = 94/sin110 = 5. Fap*CosA-Fk = M*a Fap = 40 N. ...

*April 22, 2015*

**physics**

Please read and clarify your problem. What is the vertical acceleration?

*April 22, 2015*

**physics 111**

1. V = Vo + g*Tr = 0 The rise time(Tr) = 1/2 of time in air. Vo = -g*Tr = 10(4/2)= 20 m/s

*April 22, 2015*

**PHYSICS**

Correction: Replace Tan A = Yo/Vo with sin A = Yo/Vo = 21.32/57.4 = 0.37143 A = 21.8o = Launch angle. a. Vo = 57.4m/s[21.8o] Xo = 57.4*Cos21.8 = 53.3 m/s = Hor. component of initial velocity. V = Xo+Yi = 53.3 + 0 = 53.3 m/s at highest point. KE = 0.5*M*V^2 = 0.5*0.0505*53.3^2...

*April 22, 2015*

**PHYSICS**

Y^2 = Yo^2 + 2g*h = 0 Yo^2 = -2g*h = -2*(-9.8)*23.2 = 454.72 Yo = 21.32 m/s = Ver. component of initial velocity. Tan A = Yo/Vo = 21.32/57.4 = 0.37150 A = 20.38o a. Vo = 57.4m/s[20.4o] Xo = 57.4*Cos20.4 = 53.8 m/s = Hor. component of initial velocity. V = Xo + Yi = 53.8 + 0 = ...

*April 22, 2015*

**Science**

F = 30kg/15kg * 5kg = 10 kg.

*April 21, 2015*

**math**

I = Po*r*t = 1100*(0.1/12)*1 = $9.17

*April 21, 2015*

**Personal Finance**

I chose C also.

*April 21, 2015*

**Algebra**

Y = 2x^2 - 7x - 2 h = Xv = -B/2A = 7/4. k = 2*(7/4)^2 - 7*7/4 - 2 = -8.125 = -8 1/8 = -65/8 P(h, k) = (7/4, -65/8).

*April 21, 2015*

**math**

P/3 = $3.00 P = Price.

*April 21, 2015*

**Geometry**

1. Correct 2. Correct 3. Correct!!! You aced it!!

*April 21, 2015*

**Pysics science**

8*Cos40 + 8*sin40 + B = 20 6.13 + 5.14i + B = 20 B = 20 - 6.13 - 5.14i B = 13.87 - 5.14i B = sqrt(13.87^2+5.14^2)

*April 21, 2015*