Saturday

April 19, 2014

April 19, 2014

Total # Posts: 8,521

**math**

a. In the given Eq, replace X with 3 and solve. Multiply the results by 100. b. Same procedure as "a".

**Math**

Correct.

**math**

sin7o = 1000/L L=1000/sin7 = 8206 Ft=Line of site(hyp) L' = 8206 - 0.7*5280 = 4510 Ft. h = 4510*sin7 = 550 Ft.

**math**

h = 45*sin5 = 3.92 Tt. = 47 In.

**Science**

V = Vo + a*t = 50 m/s. 0 + 2t = 50 t = 25 s.

**physics**

D = 5km[45o] + 4km[30o] + 2km[-60o]. X = 5*cos45 + 4*cos30 + 2*cos(-60)=8 km. Y=5*sin45 + 4*sin30 + 2*sin(-60)=3.80km. tanA = Y/X = 3.80/8 = 0.47544 A = 25.4o D = 8/cos25.4 = 8.86 km.

**scientific notation am i doing it right?**

1. Correct. 2. 9.82*10^5 = 982000. 3. 9*10^-3 = 0.009 4. Correct.

**physics**

Fe = m*g = 400kg * 9.8N/kg = 3920 N. = Force of elevator. P = F * V = 3920 * 0,03 = 117.6 Joules/s = 117.6 Watts.

**math**

P = 1.39(1+0.005)^12 = $1.48.

**algebra**

Correction: 1. 7x/(x^2-4) = 7x/(x+2)(x-2). When X = +-2, the denominator = 0. Therefore, +-2 are not in the domain. Domain: All real values of X except +-2.

**algebra**

1. g(x) = 7x/(x^2-4) x^2-4 = 0 x^2 = 4 X = +- 2. Domain: -2 <X< 2. 2. F(x) = 5x*sqrt(x-2). 2 <=X< +Infinity.

**algebra**

(f-g)(x)= (2x+1)-(7x-1) = 2x+1-7x+1 = -5x+2. Domain: All real values of x. (f/g)(x) = (2x+1)/7x-1) 7x-1 = 0 7x = 1 X = 1/7 When X = 1/7, the denominator = 0 which is forbidden. Therefore, the domain is all real values of X except I/7. 1/7 <X< 1/7.

**math**

a. C = 0.50x + $50. b C = 0.50x + 50 = 80 0.5x = 80-50 = 30 X = 60 miles. c. Solve the Eq using several values of x.

**math**

Please clarify your problem and include all of the information.

**physics**

A = 73[5.5o]. X = 73*cos5.5 = 72.66 Units.

**physics**

d1 = d2. 28.8t = 0.5*2.03*t^2 28.8t = 1.015t^2 1.015t^2 - 28.8t = 0 Use Quadratic Formula and get: t = 28.4 s.

**physics**

h = Vo*t + 0.5g*t^2 = 67 m. 0 + 4.9t^2 = 67 t^2 = 13.67 Tf = 3.7 s = Fall time. d = Vo*Tf = 5.33m/s * 3.7s = 19.7 m.

**math**

how much will i have to pay back on 3200 dollars intrest rate 9% for a yr an a half

**algebra**

Please check your Eq for errors. My solution is based on the assumption that the 28t term is correct. V = Vo + g*Tr Tr = (V-Vo)/g = (0-28)/-9.8 = 2.86 s. = Rise time. Tf = Tr = 2.86 s. = Fall time. T = Tr + Tf = 2.86 + 2.86 = 5.72 s. = Time in air.

**physics**

D = Vo*t + 0.5a*t^2 D=5.9*19.5 + 0.5*2.12*(19.5)^2= 518 m.

**physics**

a1 =(V-Vo)/t = (25.9-0)/7.6 = 3.4 m/s^2. a2 = (15.4-25.9)/5 = -2.1 m/s^2. a=(a1+a2)/2=(3.4 + (-2.1))/2=0.65 m/s^2.

**Physics**

a=(V-Vo)/t = (-2-4.5)/0.3=-21.67 m/s^2

**math**

Y = 2x + 1 Slope = 2. Parallel lines have equal slopes. 1.m = -A/B = -4/-2 = 2. 2. Standard Form: -x + 2y = 4. m = -A/B = 1/2. 3. -2x + y = 6 m = 2/1 = 2. Note: All lines with a slope of 2 ARE parallel. 4. 2x - y = 4 m = -2/-1 = 2.

**algebra**

a. h = 50*1 - 16*1^2 = 34 Ft. b. V = Vo + g*t Tr = (V-Vo)/g = (0-50)/-32 = 1.56 s. = Rise time. Tf = Tr = 1.56 s. = Fall time. T = Tr + Tf = 1.56 + 1.56 = 3.125 s. = Time t0 return to earth. t

**So confusing! Help Math.**

Holly, what does the bar over the o mean?

**Math**

51. X^3/0.3^-3 = 125 0.3^3X^3 = 125 X^3 = 125/0.3^3 X^3 = 5^3/0.3^3 X = 5/0.3 X = 16.66666667. 67. e^3x = 8 3xLne = Ln8 3x*1 = Ln8 X = Ln8/3. 68. 1/e^x = 7 e^x = 1/7 x*Ln e = Ln 1/7 x*1 = Ln 1/7 X = Ln 1/7. 69. 3e2x+2 = 50 6ex = 48 X = 48/6e = 8/e = 2.943 70. |Ln x| = 1 Ln x =...

**physics**

D = 0.5a*t^2 = 5*5^2 = 125 m.

**math**

cos72 = NP/MN = 4/MN MN = 4/cos72 = 12.94 m. = Length of wire to point N. tan72 = MP/NP = MP/4 MP = 4*tan72 = 12.31 m. sin65 = MP/LM = 12.31/LM LM = 12.31/sin65 = 13.58 m. = Length of wire to point L.

**math**

See previous post.

**math**

1. d = 20m[45o] + 50m[110o] X = 20*cos45 + 50*cos110 = -2.96 m. Y = 20*sin45 + 50*sin110 = 61.1 m. tanAr = Y/X = 61.1/-2.96 = -20.64189 Ar = -87.23o = Reference angle. A = -87.23 + 180 = 92.8o d = Y/sinA = 61.1/sin92.8 = 61.2 m.= AC. 2. Bearing = 92.8-90 = 2.8o West of North.

**Precal**

Incomplete.

**Physics**

Incomplete.

**physics**

a=(V-Vo)/t a=(-11.4-12.5)/0.0139 = -1719 m/s^2.

**physics**

V = Vo + at T1 = (V-Vo)/a = (0-20.3)/-4 = 5.075 s. to stop. T2 = 19.4 s. @ rest. T3 = (V-Vo)/a = (20.3-0)/1.95 = 10.4 s. to regain speed. Time Lost = T1+T2+T3 = 5.075+19.4+10.4 = 34.875 s. d = 20.3m/s * 34.875s = 708 m. Behind the train.

**math**

If a number has a negative exponent, move the decimal to the left to convert to Standard form. If the exponent is positive, move the decimal to the right. 1. 8.0*10^8 = 800,000,000 m/s. We moved the decimal 8 places to the right. 2. 2.*10^-10 = 0.0000000002 nm. We moved the de...

**Physics**

We = 82kg * 9.8N/kg = 803.6 N. = Wt. on Earth. Wm = (1/6) * 803.6 = 134 N.

**7th Grade Math**

1. V = 2.83*r^2*h. V1/V2 = 2.83*(4r)^2*4h/(2.83*r^2*h) V1/V2 = 16r^2*4h/(r^2*h = 64. 2. A1 = 2pi*r^2 + 2pi*r*h A1 = 2pi*r(r+h) A2/A1 = (2pi*2r(2r+2h))/(2pi*r(r+h) A2/A1 = (4pi*r(2r+2h))/(2pi*r(r+h) A2/A1 = 2(2(r+h)/(r+h) = 4. 2. A shorter Method A1 = 2pi*r(r+h). Let r = 1, and...

**physics**

M.A. = 960/30 = 32.

**Geometry 1**

Incomplete.

**algebra**

40t = 55(t-3) 40t = 55t-165 55t-40t = 165 15t = 165 t = 11 h.

**Mathematics**

tanA = Y/X = 34/12 = 2.83333 A = 70.6o.

**physics**

F = m*g = 8kg * 9.8N/kg = 78.4 N. Epmax = F*h = 78.4 * 100 = 7840 Joules. Ek + Ep = 7840 Ek + 78.4*(100-40) = 7840 Ek + 4704 = 7840 Ek = 7840-4704 = 3136 Joules. While Ek goes from 0 to 3136 Joules, the total energy(Ek+Ep) remains constant at 7840 Joules.

**math**

1. tan35 = 95/QR QR = 95/tan35 = 136. 2. RS = 155 - QR = 155 - 136 = 19. 3. What do you mean by "the are of QRS"?

**math**

Bearing = 98 + 180 = 278o.

**math**

8cos^2X - 2 = 0 8cos^2x = 2 cos^2x = 2/8 = 0.25 cosx = sqrt(0.25) = 0.5 Xr = 60o = Reference angle. X-Xr = 180 x-60 = 180 X = 180+60 = 240o.

**math**

Area = 0.5*Ef*DF*sinF = 11 cm^2. 0.5*5.5*8*sinF = 11 22*sinF = 11 sinF = 0.5 F = 30o.

**Algebra**

x + (2x+24) + (3x+48) = 180o Solve for x.

**Math**

Incomplete.

**hsa practice**

Given: P1(3,4), P2(4,6). m = (6-4)/(4-3) = 2/1 = 2. P1(3,4). Y = mx + b = 4 2*3 + b = 4 6 + b = 4 b = 4-6 = -2. = Y-intercept. Eq: Y = 2x - 2.= Slope-Intercept form.

**algebra**

Y = x^2 + 3x + 6 = 4 Y = x^2 + 3x + 6-4 = 0 x^2 3x + 2 = 0 C = 2 = 1*2. (x+1)(x+2) = 0 x+1 = 0 X = -1. x+2 = 0 x = -2

**physics**

T^2 = 4*pi^2(L/g) T^2 = 39.48(1.8/9.8) = 7.25 T = 2.69 s.

**Physics**

Coefficient of static friction and weight.

**physic**

a. d = 50 km. b. V = 0. NOTE: Speed = 50km/5h = 10km/h.

**math**

See Related Questions:Mon,5-13-13,7:06pm

**algebra**

-4x^2 = 5x + 9 4x^2 + 5x + 9 = 0 Use Quadratic Formula: X = -5 +- (sqrt(5^2-4*4*9))/2*4 X = (-5 +- sqrt(-119))/8 X = (-5 +- 10.91i)/8 X = -0.625+1.36i, and -0.625-1.36i.

**Geometry**

x + (2x+24) + (3x+48) = 180o Solve for x.

**Math help**

I agree with your procedure and results. Be sure to take your graph up to 4 hours.

**math**

Use same procedure as previous problem.

**math**

P = Po(1+r)^n = $85,000 r = (4%/365)/100% = 0.000109589 = Daily % rate expressed as a decimal and based on 365 days per year. n = 365Comp/yr. * 15yrs. = 5475 Compounding periods. P = Po(1.000109589)^5475 = 85000 Po = 85000/(1.000109589)^5475 = $46650.53

**math**

c. Y = 3/x, Inverse variation. d. Y = 1/3x, Inverse variation. In inverse variation, Y decreases when X is increased.

**Physics, Capacitance **

What would be the capacitance of a ball the size of the sun, if a conducting material covered its entire surface (radius, R = 7108 m)?

**physics**

Ek=0.5m*V^2 = 0.5*75*12^2 = 5400 Joules.

**Physics**

Eff. = Po/Pi = 0.55 360/Pi = 0.55 Pi = 360/0.55 = 654.55 Watts = Power in Energy Wasted = 0.65455kW * (45/60)h = 0.491 kWh. Multiply Energy wasted by the cost per kWh. I don't know what 14.8p mean.

**Math**

X = Smaller number. (2x+6) = Larger number. (2x+6) + x = 2((2x+6) - x) 3x+6 = 2(x+6) 3x+6 = 2x+12 3x-2x = 12-6 X = 6 2x+6 = 2*6 + 6 = 18.

**algebra**

1. x+2y = 6 5x+3y = 2 Multiply both sides of Eq1 by -5 and add the 2 Eqs: -5x - 10y = -30 +5x + 3y = 2 -7y = -28 Y = 4. In Eq1, replace Y with 4: x + 2*4 = 6 X = 6-8 = -2. 2. Multiply both sides of Eq2 by 4 and add the 2 Eqs. 3. Multiply both sides of Eq2 by -6 and add the 2 E...

**Math**

a = (V-Vo)/t = (900-0)/2 = 450 Ft/s^2.

**Geometry**

1. x/2 = 2x/3 - 8. 2. x + 8 = 15. 3. x + 4 = 9. 4. 2x-5 = 35. 5. 10x = -80.

**Maths**

As=(60/360) * Ac = (60/360) * 3.14*10^2= 52.33 cm^2.

**math**

See previous post.

**math**

See previous post.

**math**

V = 103Ft/s[34o] + 22Ft./s[0o]. Xo = 103*cos34 + 22*cos0 = 107.4 Ft/s. Yo = 103*sin34 + 22*sin(00 = 57.6 Ft/s. tan A = Y/X = 57.6/107.4 = 0.53628 A = 28.2o. V = Xo/cosA = 107.4/cos28.2 = 121.6 Ft/s.[28.2o] Y^2 = Yo^2 + 2g*h hmax = ho + (Y^2-Yo^2)/2g hmax = 3 + (0-(57.6)^2)/-64...

**math**

X Ones. (X+2) Tens. (X-5) Hundreds. X + (X+2) + (X-5) = 18 3x + 2 - 5 = 18 3x = 21 X = 7 Ones. X+2 = 9 Tens. X-5 = 2 Hundreds. N = 297.

**Math**

P1 = = 80*$0.90 - $17.50 = $54.50 P2 = 98*$0.80 - $17.50 = $60.90 Increase = P2-P1 = 60.90-54.50 = $6.40 Increase = (6.40/54.50)*100% = 11.7%.

**Math**

The apothem(altitude) bisects the base, AC. tanA = h/3 tan60 = h/3 h = 3*tan60 = 5.2 = Ht. = Alt.= Apothem.

**physics**

R = r = 3 Ohms.

**Math**

Compounded Annually: P = Po(1+r)^n. n = 1Comp/yr * 1yr = 1. P = 800(1.038)^1 = $830.40 Simple Int. P = P + Po*r*t = 800 + 800*0.038*1= $830.40.

**science physics**

Speed=d/t=(500+200)/(120+10+60)=3.68m/s.

**physics**

a=(V-Vo)/t=(46.22-40.89)/0.002=2665m/s^2 F = m*a = 0.15 * 2665 = 399.75 N.

**Math**

X Dimes. X Quarters. 4X Nickels. 5*4x + 10x = 25x + 50 30x = 25x+50 5x = 50 X = 10 Dimes. X = 10 Quarters. 4X = 40 Nickels.

**Physics**

Wb = 2.8kg * 9.8N/kg = 27.44 N. = Wt. of block. Fb = 27.44N.[56.6o] = Force of block. Fp = 27.44Sin56.6 = 22.91 N. = Force parallel to the incline. a. cos56.6 = F/27.44 F = 27.44cos56.6 = 15.11 N. b. Fv = 27.44cos56.6 = 15.11 N. = Force perpendicular to the incline = normal.

**Alg 1**

60(t-1) = 35t 60t-60 = 35t 60t-35t = 60 25t = 60 t = 2.4 Hours. NOT 2.4Miles. d = 35*2.4 = 84 Mi.

**MATH**

L*W = 288 2L*2W = 4*L*W = 4*288 = 1152 yds^2. 2L+2W = 68 2(2L+2W) = 2*68 = 136 yds.

**Math**

You haven't given all of the INFO.

**math**

See 2:41pm post.

**MATH**

a. 7.5%-2.5% = 5%. b. 5%/2.5% = 2. = 200%.

**m ath**

Show an example of a problem you need help with.

**math**

Data: Recorded information or numbers which shows how a product or object performed.

**math**

X Women. (X-6) Men. X + (X-6) = 100. Solve for X.

**math**

Average = (a+b)/2 = (20+30)/2 = 25. Average = (a+b+c)/3 = (30+40+80)/3 = 50.

**math**

Mean = Average = (a+b)/2.

**mathematics**

A vertical line: X = 5 for all real values of Y.

**consumer math**

P = Po(1*r)^n P=2000(1.08)^6 = 2000*1.08^6 = $3173.75.

**math**

Rate = (24*19.63)/14260 = 0.033 = 3.3%.

**Physics**

V = 3.37mi/h[180o-62.5o] + 1.25mi/h[0o] V = X + Yi V = (3.37cos117.5+1.25)+i3.37sin117.5 V = (-1.56+1.25) + 2.99i V = -.306 + 2.99i = 3.0mi/h[95.84o] tan(95.84-90) = d/0.59 d = 0.59*tan(5.84) = 0.0603 mi=319 Ft.

**Physics**

Wc = m*g = 32.5kg * 9.8N/kg = 318.5 N.= Wt. of crate. Fc = 318.5N [0o] Fp = 318.5*sin(0) = 0 = Force parallel to surface. Fv = 318.5*cos(0) = 318.5 N. = Force perpendicular to surface. a. Work = F*d = 150 * 4.95 = 742.5 Joules. b. Fap-u*Fv = m*a 150-Fp-u*Fv = m*a 150-0-318.5u ...

**Math (Percentage)**

$X = Store's cost. Selling Price = X + 0.5X X + 0.5X = 300 1.5x = 300 X = $200 100%-30% = 70% Employees Cost = 0.7 * 200 = $140.

**physics**

C = pi * 2r = 3.14 * 31 = 97.4 In=8.1Ft. d = 58rev * 6.28rad/rev = 364.24 Rad. V=80mi/h*5280Ft/mi*6.28rad/8.1Ft*1h/3600s = 91 rad/s. = Vo. V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = (0-(91)^2)/728.48 = -11.4 rad/s^2

**physics**

h = 8steps * 0.4m/step = 3.2 m. Ep = mg*h = 90kg*9.8N/kg * 3.2 = 2822.4 Joules.

**Math**

V(t) = 120sin(120*pi*t) V(t) = 120sin(377t) 377*t = The angle in radians. B. Vmax=120sin(377*1/240)=120sin(90o)= 120 Volts. C. Vmin=120sin(377*1/80)=120sin(270o)= -120 Volts. D. 0, 1/120, and 1/60 Seconds. E. 120sinA = 60 sinA = 60/120 = 0.5 A = 30o. t=(30o/360o) * 1/60 = 1/36...

**Physics--please help!!**

(V+Vr)/(V-Vs) * Fo = 355 Hz (340+0)/(340-Vs) * 320 = 355 108800/(340-Vs) = 355 355(340-Vs) = 108800 340-Vs = 306.48 Vs = 340-306.48 = 33.5 m/s. = Velocity of source or vehicle. Vr = Velocity of receiver or person.

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