Wednesday
July 23, 2014

Posts by henry


Total # Posts: 8,897

physics
d1 = 0.5a*t^2 = 0.6*5.3^2 = 16.85 m. V1 = a*t = 1.2m/s^2 * 5.3s = 6.36 m/s. a. V = Vo + a.t V = 6.36m/s - 2.3m/s^2*1.60s = 2.68 m/s. b. V^2 = V0^2 + 2a*d d2 = V^2-Vo^2)/2a d2 = (2.68^2-6.36^2)/-4.6 = 7.23 m. D = d1 + d2 = 16.85 + 7.23 = 24.1 m.

Math
(150,80), (50,30). m =(30-80)/(50-150) = -50/-100 = 0.5 Y = mx + b Y = 0.5*150 + b = 80 b = 80-75 = 5 Eq: Y = 0.5x + 5 Error: The student interchanged the slope and Y-intercept.

jru-physics
PE = mg*h = 50*9.8*2m = 980 Joules

Math
Another Approach: %Decrease = ((15%-10%)/15%)*100% = (5/15)*100% = 33.33%

Math
(10%/15%)*100%=(10/15)*100%= 66.67%. 66.67% - 100%=-33.33% or 33.33% Decrease

Physics
See your 5:59 pm post.

Physics
a. Fa = ((V-Va)/(V+Vb))*Fb Fa = ((343-0)/(343+68.6))*960 = 800 Hz b. Fc=((343+114.33)/(343-0))*480=640 Hz. c. Fb = ((343+68.6)/(343-114.33))*1550 Fb = 2790 Hz.

Physics
Fr = ((Vs+Vr)/(Vs-Vo))*Fo = 205 Hz ((336+0)/(336-Vo))*200 = 205 ((336)/(336-Vo))*200 = 205 67,200)/(336-Vo) = 205 205(336-Vo) = 67200 68,880-205Vo = 67200 -205Vo = 67200-68880 = -1680 Vo = 8.2 m/s. = Speed of the train.

Physics
CORRECTION: b. Fr = 638.33 Hz.

Physics
Vo=120km/h = 120,000m/3600s = 33.33 m/s. a. Fr = ((Vs+Vr)/(Vs-Vo))*Fo Fr=(345+0)/(345-33.33)*700Hz = 774.9 Hz b. Fr = ((345-0)/(345+33.33))*700=356 Hz = Freq. heard by the receiver(person).

Physical Science
Yes, the answer is C, because KE + PE = A constant.

Physics
a. d = 115-160 = -45 miles. The negative sign means the number decreased. b A decreasing marker number means you are traveling South or West. Therefore, John is 45 miles South or West of town.

Math
((-3)^2+(-3)*(-2))/4*(-2) = (9+6)/-8 = 15/-8 = -15/8 = -1 7/8.

science
d1 = 0.5*3.5*5.9^2 = 60.9 m V1=a*t = 3.5*5.9 = 20.65 m/s. = Velocity after 3.5 s. d2 = Vo*t + 0.5a*t^2 d2 = 20.65*5.98 + 2.98*5.98^2 = 176.8 m. V2 = a*t = 2.98*5.98 = 17.82 m/s. = Velocity @ 176.8 m. d3 = (V^2-Vo^2)/2g d3 = (0-17.82^2)/-19.6 = 16.2 m. = Free fall distance up. ...

optical circuits
Total loss = -5 + -5 + -1 = -11 db 10*Log(Po/Pi) = -11 db. 10*Log(Po/2) = -11 Log(Po/2) = -1.1 Po = 2*10^-1.1 = 0.159 mW.

Physics
d1 + d2 = 5.3+4.2 = 9.5 km = Distance between the runners. 8.8t + 7.9t = 9.5 16.7t = 9.5 t = 0.569 h. to cross paths. d1 = 5.3 - 8.8*0.569 = 0.293 km West of flagpole. d2 = 4.2 - 7.9*0.569 = -0.295 km West of Flagpole. So they meet at approximately 0.294 km west of flagpole.

Algebra
Steve, that was an excellent explanation.

math
a. V = Vo + g*t Tr = (V-Vo)/g = (0-15)/-32 = 0.469 s. To reach max. Ht. = Rise time. b. h = ho + Vo*t + 0.5g*t^2 h = 4 + 15*0.469 - 16*(0.469)^2=7.52Ft. Above Gnd. c. h = Vo*t + 0.5g*t^2 = 7.52 Ft. 0 + 16*T^2 = 7.52 T^2 = 0.469 Tf = 0.685 s. = Fall time. T = Tr + Tf = 0.469 + ...

US History
True or False Check. 1. During the Starving Time of 1609-10, some of the colonists turned to cannibalism as a means of survival. True 2. Early settlers of Jamestown spent many of their waking hours bowling. True 3. The location of Jamestown was selected partially out of fear o...

phiycics
t = 144km * 1h/48km = 3 h.

Physic
Correction: The speed of the car does not have to be reduced to zero, because the truck is moving forward. It must be reduced to 50 km/h(13.9m/s). a = (V^2-Vo^2)/2d a = (13.9^2-27.8^2)/400 = -1.45 m/s^2.

Physic
Car Speed=100km/h=100000m/3600s=27.8m/s Truck Speed =(50/100) * 27.8=13.9 m/s. V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = (0-(27.8-13.9)^2)/400 = -0.483 m/s^2 NOTE: The effective speed of the car is less than the actual speed, because the truck is moving forward.

Science
d=109km/day * 1mi/1.6km*7days/wk = 476.875 mi/wk 1.1euros/L*$1.26/euro*3.8L/gal=$5.27/gal Cost = 476.875m1*1gal/39mi*5.27/gal = $64.44

Science , physics
Change = 35.4 - 99.9 = -64.5oC The negative sign means the change was a decrease.

m= ath
4 Liters(L) = 4000 Milliliters(mL). 4000/150 = 26.7 or 26 Beakers can be filled.

SAT Math
2. a is greater because it has the smaller reciprocal. 3. P/4<q/12 Multiply both sides by 12: 3P<q or q>3P. (P-1)/4 Let P = 3 (3-1)/4 = 2/4 = 1/2. (q-9)/12 Let q = 10 which greater than 3P. (10-9)/12 = 1/12. Therefore, (P-1)/4>(q-9)/12. This is true for values of q...

Math
(KR)^2 = (-5-2)^2 + (3-9)^2 = 85 KR = 9.22 (RN)^2 = (-5-0)^2 + (3+7)^2 = 125 RN = 11.18 (KN)^2 = (0-2)^2 + (-7-9)^2 = 260 KN = 16.12 P = 9.22 + 11.18 + 16.12 = 36.5

Algebra 2
See previous post.

Algebra 2
5681mg = 5681*10^-3g 5681*10*-3g * 10^-3 = 5681*10^-6 kg OR 5681mg * 10^-6=5681*10^-6 kg =0.005681 kg.

AP Physics
D = 10m[90o] + 7m[120o]. X = 10*cos90 + 7*cos120 = -3.50 m. Y = 10*sin90 + 7*sin120 = 16.1 m. tanAr = Y/X = 16.1/-3.5 = -4.58857 Ar = -77.7o = Reference angle. A = -77.7 + 180 = 102.3o D = X/cosA = -3.50/cos102.3 = 16.43 m.[102.3o]

algebra
a. 50/10^9. 15/10^9. b. 50*10^-9 15*10^-9.

Science Physics
I'm assuming R and C are in series. R = 10k ohms RC = 34us = 34*10^-6 s. Vr = E/e^(t/RC) = 11 Volts. 27/e^(t/RC) = 11 e^(t/RC) = 27/11 = 2.45455 Take Ln 0f both sides: (t/RC)*Ln e = Ln 2.45455 (t/RC)*1 = 0.89794 Multiply both sides by RC: t = 0.89794RC t=0.89794*(34*10^-6)...

Physics !!
1a. d1 = 0.5g*t^2 = 4.9*2^2 = 19.6 m. = Distance fallen by the 1st stone after 2 s. V1^2 = Vo1^2 + 2g*d V1^2 = 0 + 19.6*19.6 = 384.16 V1 = 19.6 m/s = Velocity of 1st stone after 2 s. d1 = d2-19.6 m. Vo1*t + 0.5g*t^2 = Vo2*t+0.5t^2-19.6 Vo1*t-Vo2*t+4.9t^2-4.9t^2 = -19.6 19.6t-2...

physics
V=(4.15*10^-2m)^3 = 7.15*10^-5m^3 Density=1.2kg/7.15*10^-5m^3=16,783kg/m^3

physics
R1 = 2 Megohms? R2 = 3 megohms? R3 = 15 Megohms? I = 3 Microamps? Please clarify your problem.

physics
X = 30m/30s = 1 m/s. Y = 1 m/s . tanA = Y/X = 1/1 = 1. A = 45o = Direction. V = 1/cos45 = 1.414 m/s[45o].

Physics
X = ? Y = -2.9 km. R = 4.25 km = Resultant. X^2 + Y^2 = R^2 X^2 + (-2.9)^2 = (4.25)^2 X^2 = (4.25)^2 - (-2.9)^2 = 9.653 X = 3.1 km tanA = -2.9/3.1 = -0.93548 A = -43.1 o A = -43.1 + 360 = 316.9o CCW. A = 316.9 - 270 = 46.9o East of South.

physics
V^2 = Vo^2 + 2a*h V^2 = 79^2 + 7.8*980 = 13,885 V = 117.83 m/s. @ 980 m a. V = Vo + a*t = 117.83 79 + 3.9t = 117.83 3.9t = 117.83-79 = 38.83 Tr1 = 9.96 s. to rise to 980 m. V = Vo + g*t 117.83 - 9.8t = 0 9.8t = 117.83 Tr2 = 12.02 s to reach max. ht. hmax = ho + (V^2-Vo^2)/2g h...

physics
V^2 = Vo + 2g*d V^2 = 0 + 19.6*(12-6) = 117.6 V = 10.84 m/s. V^2 = 0 + 19.6*12 = 235.2 V = 15.34 m/s

Math ASAP
As = 2*22 + 308 = 352 Sq. In. Same as previous results.

Math ASAP
SORRY! The calculated surface area was for a rectangular prism NOT a hexagonal prism.

Math ASAP
As=2*Ab + Al = 2*22 + 308 = 352 Sq. In.

Mathematics
A. P = Po + Po*(r/360)*t = $10,000 Po + Po*(0.043/360)*96 = 10,000 Po + 0.01146667Po = 10000 1.01146667Po = 10000 Po = $9886.63. = Amt. paid. B. %Yield=((10000-9886.63)/9886.63 *365/96 = 4.36

business math
P = Po + Po(0.04/360)*45 20000 + 20000(0.04/360)*45 = $20,100 after 45 days. Bal. = 20100-8000 = $12,100

MaTh
Ag + As = At As = At - Ag As = 3.14*6^2 - 3.14*5^2 = Area of strip. At = Total area. Ag = Area of garden.

science
h = Vo*t + 0.5g*t^2 = 160 m. 0 + 4.9t^2 = 160 t^2 = 32.65 t = 5.7 s. = Time to strike ground.

Math
3x^5 - 12x^4 + 18x^3. 1. Locate the smallest constant which is 3. If 3 will divide into the other constants with no remainder, factor out 3. 2. Factor out the variable with the smallest exponent which is x^3. We have factored out 3x^3. 3. To determine what goes inside of the p...

Physics
L=V*T = V/F=300*10^6 / 5.35*10^5=561 m.

algebra
30-13 means 30 decreased by 13 or 30 less(minus) 13.

algebra
13<30.

algebra
Where is the "question above"?

Math
A. (11-1)games/team * 11teams = 110 games played. Team 1. 10 Games 2. 10 Games 3. 10 4. 10 5. 10 6. 10 7. 10 8. 10 9. 10 10 10 11.10 Games. Total: 110 Games. B. (12-1)games/team * 12teams = 132 Games played.

MATH
a. A = -100 + 360 = 260o.

math
2(x-3/4)+3(x+2/3)+4(x-1/5) = 9x+17 2x-6/4+3x+6/3+4x-4/5 = 9x+17 9x-3/10 = 9x+17 9x-9x = 17+3/10 0 = 17 3/10 = 173/10. No Solution! Check and make sure the prob. is copied correctly.

Math (Finance)
See previous post: Mon,6:41pm.

Finance
5.17 Ci=49,000=The # of copies sold 1st year. C3 = C1*(1+r)^3) C3 = 49000(1.21)^3 = 86,806 Copies sold after 3 years. C4 = 86,806*(1.13) = 98,091 Copies sold in 4th year. 5.21a P = Po(1+r)^n r = (8.9%/12)/100% = 0.0074167 = Monthly % rate expressed as a decimal. n = 12Comp/yr ...

physics
Circumference = pi*2r = 3.14*100 = 314 m V=1rev/4min*314m/1rev1*1min/60s=1.31m/s

8th grade algebra
5x = The # of bikes rented. 2x = The # of scooters renteb 15.50*1.12*5x + 160*1.12*2x = 1600. 86.8x + 358.4x = 1600 445.2x = 1600 X = 3.59 Bikes = 5 * 3.59 = 18 Scooters = 2 * 3.59 = 7.

8th grade algebra
5x = The # of bikes rented. 2x = The # of scooters renteb 15.50*1.12*5x + 160*1.12*2x = 1600. 86.8x + 358.4x = 1600 445.2x = 1600 X = 3.59 Bikes = 5 * 3.59 = 18 Scooters = 2 * 3.59 = 7.

8th grade algebra
5x = The # of bikes rented. 2x = The # of scooters renteb 15.50*1.12*5x + 160*1.12*2x = 1600. 86.8x + 358.4x = 1600 445.2x = 1600 X = 3.59 Bikes = 5 * 3.59 = 18 Scooters = 2 * 3.59 = 7.

Physics
The current entering a point is equal to the current leaving the point. Therefore, the current leaving the positive terminal of a battery is equal to the current entering the negative terminal. This is true for the light bulb or any load.

math
P = (Po*r*t)/(1-(1+r)^-t) Po = 1598 * 1.05 = $1677.90 r = (15%/12)/100% = 0.0125 = Monthly % rate expressed as a decimal. t = 3yrs * 12mo./yr = 36 Months. Plug the above values into the given Eq and get: P = 2093.94 Monthly Payment = P/t

Physics
The brightness increases.

Science
Wb = m*g = 17.25kg * 9.8N/kg = 169 N. = Wt of body. Fv = m*g = 169 N. = Force perpendicular to the table. Fs = u*Fv = 0.34*169 = 57.5 N. = Force of static friction.

physics
P = F * d/t = F * V = mg * V P=400*9.8 * 0.03m/s = 118 J/s.=118 Watts

Math
63miles/22gal. = 2.86 Miles/gal. D = 66gal * 2.86mi/gal = 189 Miles.

physics
Rmax = V/I = (500000*.97)/1000=485 Ohms=Max. conductor resistance. Dmax = 485 Ohms / 0.026Ohms/km=18,654 km.

Physic
Fp = mg*sin23 = 597.8*2in23=233.6 N.= Force parallel to the hill. Fv = mg*cos23 = 597.8*cos23=550.3 N.= Force perpendicular to the hill. Fk = 72 N. a = (Fp-Fk)/m = (233.6-72)/61=2.65 m/s^2 V^2 = Vo^2 + 2a*d V^2 = (3.5)^2 + 2*2.65*62 = 340.85 V = 18.5 m/s.

Pre- Algebra
1. Y = -2x - 4. (1,3). Parallel lines have equal slopes: m1 = m2 = -2. Y = mx + b = 3 -2*1 + b = 3 b = 3+2 = 5 Eq: Y = -2x + 5 2. Y = 3x+3. (1,1). The slope of the line is equal to the negat1ive reciprocal of the slope of the given line. m1 = 3 m2 = -1/3. Y = mx + b = 1 (-1/3)...

hydromechanic
Fap-Ff = m*a 124-Ff = m*0 = 0 Ff = 124 N. = Force of friction. u = Ff/Fl = 124/1026 = 0.121 = Coefficient of friction. Fap = Force applied.

basic math
The DIGIT in the units(ones) position is 2. TENS Position: 1. HUNDREDS position: 5. THOUSANDS position: 5. TENS of THOUSANDS position: 5.

math
The hypotenuse is greater than either of the other 2 sides but less than the sum. Therefore the answer is d. c^2 = 5^2 + 12^2 = 25 + 144 = 169 c = 13.

Physics
V^2 = Vo^2 + 2g*h Vo^2 = V^2 - 2g*h. Vo^2 = 0 + 19.6*23 = 450.8 Vo = 21.2 m. h = (0.5Vo)^2-Vo^2)/2g h = ((10.62)^2-(21.2^2))/-19.6=17.2 m.

MaThS
A. Y = -2x+1, and Y = -2x+3. m1 = m2 = -2. The lines are parallel, because their slopes are equal. B. x+y/3+5 = 0, and 2y+6x = 1 x+y/3=-5, and 6x+2y = 1. 3x+y = -15, and 6x+2y = 1 m1 = -A/B = -3/1 = -3 m2 = -6/2 = -3 The slopes are equal; therefore, the lines are parallel.

algebra
10. 16-9+25 = 32 11. 32/(-7+5)^3 = 32/-8 = -4. 12. 4^3-(2-5)^3 = 64 - (-27) = 91

math
Gregg: p + q Coins. Brother: 8p + 4q Coins. Sum = 8p+p + q+4q = 9p + 5q

math
1. 0x+6y-5x = 5x+6y. 2. 9x^2+10+4x^2+7 = 13x^2+17.

algebra
P1(1,-3),P2(2,4). D^2 = (2-1)^2 + (4+3)^2 = 50 D = 7.07

Maths
tan 60o = (Y1+Y2)/X1 = 3000/X1 X1*tan 60 = 3000 X1 = 3000/tan60 = 1732 m. tan 30o = (Y1+Y2)/(X1+X2)=3000/(1732+X2) (1732+X2)*tan30 = 3000 1732+X2 = 3000/tan30 = 5196 X2 = 5196-1732 = 3464 m tan30 = Y2/X2 = Y2/3464 Y2 = 3464*tan30 = 2,000 m. Y1 = 3000-2000 = 1,000 m. = Distance...

introduction to finance-16
1. P = Po*(1+r)^n Po = $4,000. r = (4%/100%) = 0.04 n = 1Comp./yr * 5yrs = 5 Compounding periods. Plug the above values into the given Eq and get: P = $4,866.61. 2. P = Po(1+(y-1))*(1+r)^n Y = Length of loan = 5 years. P = 4000(1+4)*(1.04)^5 = $24,333.06

math
Eq1: x*y = -84 Eq2: x+y = 5 x+y = 5 y = 5-x In Eq1, replace y with 5-x: x*(5-x) = -84 5x-x^2 = -84 -x^2+5x+84 = 0 Use Quadratic Formula and get: X = -7, and 12.

Math
The angles are assumed to be complimentary(sum=90o). DCE + ECF = 90o 4x+15 + 6x-5 = 90 10x + 10 = 90 10x = 80 X = 8 DCE = 4*8 + 15 = 47o

Mechanics, Waves and Optics
Wt. of crate=m*g=18kg * 9.8N/kg=176.4 N. Fv = 176.4*cos0 = 176.4 N. = Force perpendicular to the surface. Fk = u*Fv = 0.5 * 176.4 = 88.2 N. = Force of kinetic friction. Fap*cos20-Fk = m*a Fap*0.94-88.2 = 18*0 = 0 0.94Fap = 88.2 Fap = 93.9 N. = Force applied b. Tension = Fap = ...

physical science
V = Vo + a*t = 10 m/s. 6 + a*2 = 10 2a = 4 a = 2 m/s^2.

geometry
a. RS + ST = RT 8y+4 + 4y+8 = 15y-9. Solve for y. b. Replace y with the value calculated in prob. a.

Algebra
P = Po(1+r)^n P = $5000 Po = $3500 r = (4.5%/12)/100% = 0.00375 = Monthly % rate expressed as a decimal. n = 12Comp/yr * T yrs = 12T = The # of compounding periods. P = 3500*(1.00375)^12T = 5000 (1.00375)^12T = 5000/3500 = 1.42857 Take Log of both sides: 12T*Log (1.00375) = Lo...

Mathematic
1. 2/(2/3) + 3/4/(4/5). 2/(2/3) + (3/4)/(4/5) = 2*(3/2) + (3/4)*(5/4) = 6/2 + 15/16 = 48/16 + 15/16 = 63/16 2. (2/5)(2/3)/(5/6)/(3/10) = (2/5)(2/3)(6/5)(10/3) = 240/225 = 48/45 = 16/15. The answer cannot be less than one.

All subjects
You are welcome! We are glad we can help.

MatHS
The angle of inclination is always between 0o and 180o and is measured CCW from the positive x-axis. A. x+y+1 = 0 x+y = -1 Tan A = m = -A/B = -1/1 = -1 Ar = -45o = Reference angle. A = -45 + 180 = 135o. B. 3-2y = 9x 9x+2y = 3 Tan A = m = -A/B = -9/2 = -4.5 Ar = -77.47o A = -77...

maths
See previous post: Tue,8-6-13,12:09 PM

maths
See previous post: 12:09 PM.

maths
Y = 2x Tan A = m1 = 2 A = 63.43o (-1,7/3),(0,2). m2 = Tan B = (2-7/3)/(0+1) = (-1/3)/1 = -1/3. B = -18.43o = -18.43o C = A-B = 63.43 - (-18.43) = 81.9o = Angle between A and B.

Math
What is the question?

maths
CORRECTION: m1 = m2 = -A/B = 6/2 = 3 Y = mx + b = -1 3*3 + b = -1 b = -10 Eq: Y = 3x - 10

maths
(3,-1). -6x + 2y = 1 Parallel lines have equal slopes: m1 = m2 = -A/B = 6/-2 = -3 Y = mx + b = -1 -3*3 + b = -1 b = 8 Eq: Y = -3x + 8

mathematics
P(-6,-2). 3x + 2y = 6 m1 = -A/B = -3/2 m2 = -(-2/3) = 2/3 = Negative reciprocal Y = mx + b = -2 2x/3 + b = -2 (2*-6)/3 + b = -2 -4 + b = -2 b = 2. Eq: Y = 2x/3 + 2

physics
See previous post.

physics
Assuming no wind: Vo*t + 0.5g*t^2 = 1.4 m. 0 + 0.5*1.63*t^2 = 1.4 0.815t^2 = 1.4 t^2 = 1.72 t = 1.31 s.

algebra
Yes, post your problem.

Physics
h1 = Vo*t + 0.5g*t^2 h1 = -9*18 + 4.9*18^2 = 1426 m Above ground when bag was released. h2 = 9*18 = 162 m.. Above point of release. h = 1426 + 162 = 1588 m. Above ground.

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