Thursday
October 23, 2014

Posts by henry


Total # Posts: 9,329

Math
2. A cube has 6 edges. As = 6 * 3^2 = 6 * 9 = 54 Sq. In.
November 25, 2013

finance
1. P = (Po*r*t)/(1-(1+r)^-t) r = (9%/12)/100% = 0.0075 = Monthly % rate expressed as a decimal. t = 12mo/yr * 5yrs. = 60 Months. Plug th above values into the givenEq and get: P = $12,455.01 I = P-Po 2. Monthly = P/t 3. P = Po + Po*r*t Po = $10,000 r = 0.0075 t = 60 Months ...
November 25, 2013

physics
Fap-Fk = m*a 30-Fk = 2 * 10 = 20 Fk = 30-20 = 10 N. = Force of kinetic friction.
November 25, 2013

geometry
See Related Questions: Thu,5-25-11,11:28 AM.
November 24, 2013

Science, Physics, math, calculus
a. h = 0.5g*t^2 = 0.77 4.9t^2 = 0.77 t^2 = 0.1571 t = 0.396 s. = Fall time. Dx = Xo * t = 5.15 m. Xo * 0.396 = 5.15 Xo = 13 m/s = Break speed. b. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*0.77 = 15.09 V = 3.88 m/s
November 24, 2013

Physics
h = 0.5g*t^2 = 50 m. 4.9t^2 = 50 t^2 = 10.2 Tf = 3.19 s. = Fall time. d = V*Tf = 100m/s * 3.19s = 319 m.
November 24, 2013

PHYSICS
CORRECTION: T = 1.15 Milliseconds.
November 24, 2013

PHYSICS
CORRECTION: d. Vr = I*R = (0.8*0.857)*7 = 4.8 Volts Vi=6-4.8=1.2 Volts across the inductor. V/e^(T/0.714) = 1.2 6/e^(1.40T) = 1.2 e^1.40T = 6/1.2 = 5 1.40T*Ln e = Ln 5 1.40T = 1.609 T = 1.15 s. 7 =
November 24, 2013

PHYSICS
a. T.C.=L/R=5.0/7=0.714 Milliseconds b. T/TC = 0.25mS/0.714mS = 0.350 Vi = V/e^(T/TC) = 6/e^0.350 = 4.23 Volts after 250 uS. I=Vr/R = (V-Vi)/R = (6-4.23)/7= 0.253A. c. I=Vr/R = (V-Vi)/R = (6-0)/7 = 0.857A d. Vr=I*R = (0.8*0.857)*7 = 4.80 Volts. Vi = 6-4.8 = 1.2 Volts. = ...
November 24, 2013

Math
Incomplete.
November 24, 2013

physics
Fr = 975N[0o] + 745N[60o] + 1175N[90o] X=975 + 745*cos60 + 1175*cos90=1347.5 N Y = 745*sin60 + 1175*sin90 = 1820.2 N. tan A = Y/X = 1820.2/1347.5 = 1.31079 A = 53.5o Fr = Y/sin A = 1820.2/sin53.5=2264.3 N. [53.5o].
November 24, 2013

physics
Ht. = 50 m.? a. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*50 = 980 V = 31.3 m/s. b. V = Vo + g*t = 31.3 m/s. 0 + 9.8t = 31.3 t = 3.19 s. c. m = 2.0Lb * 0.454kg/Lb = 0.908 kg. KE = m*V^2/2 = 0.908*31.3^2/2 = 444.8 J.
November 24, 2013

physics
Ws = m*g = 77.7kg * 9.8N/kg = 761.5 N = Wt. of skier. Fp = 761.5*sin35.7 = 444.3 N. = Force parallel to slope. Fn = 761.5*cos35.7 = 618.4 = Normal = Force perpendicular to slope. Fk = u*Fn = 0.08 * 618.4 = 49.47 N. = Force of kinetic friction. Fp-Fk = m*a a=(Fp-Fk)/m=(444.3-49...
November 22, 2013

science
KE = 0.5m*V^2 = 2.5*4^2 = 40 J.
November 22, 2013

Please help!- Physics
d = 483[180o ] + 347[106o] + 347[106o] d = 483[180 + 694[106o] X = 483*cos180 + 694*cos106 = -674.3 km Y = 483*sin180 + 694*sin106 = 667.1 km tan Ar = Y/X = 667.1/-674.3 = -0.98935 Ar = -44.69o = Reference angle. A = 180-44.69 = 135.3o d = X/cosA = -674.3/cos135.3 = 948.7 km [...
November 22, 2013

Math
Incomplete.
November 21, 2013

physics
3.2 cm from equilibrium position: KE + PE = mg*d 0 + PE = mg*d/2 Halfway to the equilibrium position: KE + PE = mg*d mg*d/2 + mg*d/2 = mg*d KE = mg*d/2 = 0.5m*V^2 0.5m*V^2 = mg*d/2 = 3.92*0.032/2 0.2*V^2 = 0.06272 V^2 = 0.3136 V = 0.56 m/s.
November 21, 2013

Physics
CORRECTION: V = 81.6km/h[74.93o] D = 245 km[74.93o]
November 20, 2013

Physics
V = 100km/h[90o] + 30km/h[315o] X = 100*cos90 + 30*cos315 = 21.21 km/h Y = 100*sin90 + 30*sin315 = 78.79 km/h tan A = Y/X = 78.79/21.21 = 3.71461 A = 74.93o V=Y/sinA = 78.79/sin74.93=81.6 km/h [78.79] D=V*t = 81.6[78.79] * 3 = 245 km[78.8o]
November 20, 2013

Math
Parallel lines have equal slopes.
November 20, 2013

Math
Parallel lines have equal slopes.
November 20, 2013

Math
Parallel lines have equal slopes.
November 20, 2013

Math
2x - 3 = 4y Eq1: 2x - 4y = 3 m1 = -A/B = -2/-4 = 1/2 m2 = -(2/1) = -2 Y = mx + b Eq2: Y =-2x - 5/4.
November 20, 2013

Math
See previous post: Wed,11-20-13,6:18PM.
November 20, 2013

Math
Eq1: x + 2y = 10. m1 = -A/B = -1/2 The slope of the 2nd line = the negative reciprocal of m1: m2 = -(-2/1) = 2. Y = mx + b Eq2: Y = 2x - 10 or 2x - y = 10
November 20, 2013

physics
Energy = 120 * 5 *6h /1000=3.6 KWh Used Cost = 3.6kwh * 0.090/kwh = 0.324 or 32.4 Cents.
November 20, 2013

Physics
L = h/sin A = 2/sin 30 = 4 m. = Length of incline. KE = mg*h-Fk*L 0.5m*V^2 = mg*h-Fk*l 0.2*4.50^2 = 3.92*2 - Fk*4 4.05 = 7.84 - 4Fk 4Fk = 7.84-4.05 = 3.79 Fk = 0.948 N. = Force of kinetic friction.
November 19, 2013

physics
Fn = m * a =47 * 4.50
November 19, 2013

Physics
Yes. For a given initial velocity, the larger the angle the greater the vertical component of initial velocity. The increase in vertical velocity causes an increase in the max. ht.
November 19, 2013

Physics - projectile
V = Vo = 50 m/s.
November 19, 2013

Physics
b. h = Vo*t + 0.5g*t^2 = 3.05 8t + 4.9t^2 - 3.05 = 0 Use Quadratic Formula and get: t = 0.319 s. c. V^2 = Vo^2 + 2g*h V^2 = 8^2 + 19.6*3.05 = 123.78 V = 11.13 m/s.
November 19, 2013

MATH
A. Y = ho - 8X ho = The initial ht. B. When he got on the elevator, it was at the initial height(ho) and decreased at a rate of 8 feet per second for 12 seconds. C. Y = ho _ 8x = 240 Ft. ho - 8*12 = 240 ho = 240 + 96 = 336 Ft. above gnd. D. Y = 336 - 8x = 0 336 - 8x = 0 8x = ...
November 19, 2013

math
N = 0.57 * 11
November 19, 2013

Physics
d = 0.5g*t^2 = 75 4.9t^2 = 75 t^2 = 15.31 Tf = 3.912 s. = Fall time. d = V*Tf = 7-4 = 3 m. V * 3.912 = 3 V = 0.769 m/s.
November 19, 2013

math
Did your book give the total # of Robinsons? Something is missing.
November 18, 2013

physical science
P = F * d/t = 96 * 2.8/4.6 = 58.43 J/s = 58.43 Watts.
November 18, 2013

college algebra
4^(x-3) = 3^(2x) (x-3)*Log4 = 2x*Log 3 Divide both sides by Log 4: x-3 = 2x * 0.79248 = 1.5850x x - 1.5850x = 3 -0.5850x = 3 X = -5.1282
November 18, 2013

science
Magnitude = 210 N. Direction = 30o South of West = 210o CCW.
November 18, 2013

science
Magnitude = 200 N. Direction = 60o North of East = 60o CCW.
November 18, 2013

science
Magnitude = 125 N. Direction = North(Positive Y-axis).
November 18, 2013

math
Sally has X postcards. Marta has X postcards. X = 4(X-18) Solve for X.
November 18, 2013

Math
Y = 5 For all values of X. (0,5),(5,5),(2,5),(-3,5).
November 18, 2013

science
500+(65-47)sk/wk*105days*1wk/7days=770 Skunks.
November 18, 2013

Phyics
d1 = 0.5a*t^2 = 15 m. 0.5*t^2 = 15 t^2 = 30 T1 = 5.477 s. V = a*t = 1m/s^2 * 5.477s = 5.477 m/s. d2 = V * t = 5.477m/s * 15s = 82.2 m. D = d1 + d2 = 15 + 82.2 = 97.2 m. = Distance at which he was caught. T = T1 + T2 = 5.477 + 15 = 20.48 s To catch up.
November 18, 2013

math
(25%/15%/10% = (1-0.25)(1-0.15)(1-0.10)= 0.75 * 0.85 * 0.90 = 0.57375
November 18, 2013

math
a. X + 27.80*20 = 914 X = $358. b. C = 358 + 27.80x X = The number of years since 1981. c. 2000-1981 = 19 years. C = 358 + 17.80*19 = $528.20
November 18, 2013

Check my answers please- Physics
1. A force that makes the net force on an object 0. 2. It is equal in magnitude and opposite in direction. 3. An object in equilibrium must not be in motion. 7. 90 N.
November 18, 2013

algebra2
See previous post: Mon,11-18-13,11:59 AM.
November 18, 2013

algebra2
CD: $X Savings: $4X Mutual: $(15,000-5X) 0.02X + 0.01*4X + 0.1(15000-5x) = 210 0.06X + 1500 - 0.5X = 210 -0.44X = 210-1500 = -1290 X = 2931.82 4X = 4*2931.82 = $11,727.27 = Savings.
November 18, 2013

math
Bal. = 423.78 + 123.42 - 100 = 447.20 Int. = 447.20 *(0.15/12) * 1 = $5.59
November 18, 2013

Physics
Incomplete.
November 18, 2013

Business math
P = Po*(1+r)^n r = (0.75%/365)/100% = 2.055*10^-5 = Daily % rate expressed as a decimal. n = 1comp./day * 21days = 21 compounding periods. Plug the above values into the given Eq and get: $9,0003.88
November 17, 2013

physic
Vo=36mi/h * 1600m/mi * 1h/3600s=16 m/s. V = Vo + a*t = 0 16 + a*2.4 = 0 2.4a = -16 a = -6.67 m/s^2. F = m*a = 58 * (-6.67) = -386.7 N. The negative sign means that the force was in the opposite direction of the motion.
November 17, 2013

Math
P = 350hp * 746W/hp = 261,100 Watts.
November 17, 2013

physics
Wb = m*g = 7.6kg * 9.8N/kg = 74.48 N. = Wt. of block. Fs = 8 N ? Fs = us*Fv = 8 N. us*74.48 = 6 us = 0.081
November 17, 2013

geometry
See previous post: Sat, 11-16-13, 7:13 PM.
November 17, 2013

GEOMETRY
1. Triangle #1 a = 8 b = 15 c = 18 Triangle #2: d = 10 e = ? f = ?. a/d = b/e = c/f = 8/10 15/e = 8/10 e = 18.75 18/f = 8/10 f = 22.5 2. Scale Factor=5/4 = 15/12=25/20 = 1.25 3. x/r = y/p = z/n.
November 16, 2013

physics
Fn = m*a m = Fn/a = 50/25 = 2 kg
November 16, 2013

Trig
V1 + V2 = 1200[70o] + 900[205o] X = 1200*cos70 + 900*cos205 = -405.3 Y = 1200*sin70 + 900*sin205 = 747.3 tanAr = Y/X = 747,3/-405.3 = -1.84376 Ar = -61.53o = Reference angle. A = -61.53 + 180 = 118.5o Vr = Y/sinA = 747.3/sin118.5 = 850.3[118.5o] = Resultant vector.
November 15, 2013

nature of science
A. The speed and direction.
November 15, 2013

Math
V1 = 1.5 *1.5 * 0.25 = 0.5625 in^3. V2 = 3.25 * 3.50 * 0.25 = 2.844 in^3. V2/V1 = 2.844/0.5625 = 5.056 = 505.6%. % Increase = 505.6% - 100% = 405.6 %.
November 15, 2013

physics
h = 9.7*sin30 = 4.85 m. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*4.85 = 95.06 V = 9.75 m/s.
November 14, 2013

Physics
F1=m*g = 0.151[26.2o]*9.8=1.480N[26.2o] F2 = 0.215[281o]*9.8 = 2.107N[281o] F3[Ao] F = F1 + F2 + F3 F=1.480N[26.2o] + 2.107N[281] + F3[Ao] X = 1.480*cos26.2+2.107*cos281+F3*cosA=0 X = 1.328 + 0.4020 + F3*cosA = 0 F3*cosA = -1.73 cosA = -1.73/F3. Y = 1.480*sin26.2+2.107*sin281+...
November 14, 2013

MATH
P = Po + Po*r*t P = 15,000 + 15,000*0.045*(8/12) Solve for P.
November 14, 2013

Math
6w + 20 = 60 6w = 40 W = 6 4/6 or 7 Weeks.
November 14, 2013

4th grade math
1. a/7 = 20 Multiply both sides by 7: a = 7 * 20 = 140. Check: 140/7 = 20 2. Same procedure as #1. 3. Same procedure as #1.
November 14, 2013

Physics
a. F*cos20-Fk = m*a = m*0 = 0. F*cos20-u(Fn+F*sin20) = 0 300*cos20 - u(1000+300*sin20) = 0 281.9 - 1102.6u = 0 1102.6u = 281.9 u = 0.256 = Coefficient of kinetic friction. b. m*g = 1000N. m = 1000/g = 1000/9.8 = 102 kg. 300*cos20 - 0.256(1000-300*sin20)=m*a 281.9 - 229.7 = m*a...
November 14, 2013

math
Scott ate X Fries Mike ate (2x+1) Fries. Holly ate (x-5) Fries. Total fries ordered = Fries ate + 6: ORDER = X + (2x+1) + (x-5) + 6 = 4x + 2.
November 14, 2013

physics
Tr + Tf = 4.8s. = Rise time + Fall time = Time in air. Tr = Tf = 4.8/2 = 2.4 s. Dx = 60yds * 3Ft/yd * 1m/3.3Ft=54.55 m. Dx = Xo * (Tr+Tf) = 54.55 m. Xo * 4.8 = 54.55 Xo = 11.36 m/s. = Hor. component of initial velocity. Y = Yo + g*Tr = 0 @ max ht. Yo - 9.8*2.4 = 0 Yo = 23.52 m...
November 14, 2013

physics
See your 6:11 PM post.
November 13, 2013

physics
Work = F*d = 1 * 2000 = 2000 Joules. Calories = 2000J * 1cal/4.184J = 478
November 13, 2013

Physics
V = 90km/h = 90000m/3600s = 25 m/s. a = (V-Vo)/t = (25-0)/6 = 4.167 m/s^2 d = 0.5a*t^2 = 0.5*4.167*6^2 = 75 m. P = F*d/t = mg * d/t P = 13720 * 75/6 = 171,500 J/s.
November 13, 2013

Math-Algebra
1. F = m*a = 25 * 3 = 75 N.
November 13, 2013

Fly Ball Lab - Projectile Motion Please HELP FAST!
Dx = Xo * T = 48.9 m. Xo * 3.60 = 48.9 Xo = 13.58 m/s = Hor. component of initial velocity. Tr = Tf = T/2 = 3.60/2 = 1.80 s. = Rise and fall times. Y = Yo + g*Tr = 0 @ hmax. Yo - 9.8*1.8 = 0 Yo = 17.64 m/s = Ver. component of initial velocity. tan A = Yo/Xo = 17.64/13.58 = 1....
November 12, 2013

math
0.25 - (-1.5) = 0.25 + 1.5 = 1.75
November 12, 2013

math
1 1/2 - 2 = 3/2 - 4/2 = -1/2.
November 12, 2013

Physics
1. F = 250*2 + 25 = 525 N. Work = F*d = 525 * 2 = 1050 Joules. 2. P = F*d/t = 525 * 2/3 = 350 J/s. = 350 Watts.
November 12, 2013

Physics
Wt = m*g = 24kg * 10N/kg = 240 N.
November 12, 2013

MATH
A. P1 = Po*r*t/(1-(1+r)^-t) Po = $225,000 r = (5%/12)/100% = 0.004167 = Monthly % rate expressed as a decimal. t = 12mo/yr * 30yrs = 360 Months. Plug the above values in the given Eq and get: P1 = $434,810.88 I = P1-Po B. P2 = (Po*r*t)/(1-(1+r)^-t) Use same procedure as A.
November 12, 2013

physics
a=(V^2-Vo^2)/2d=(0-90^2)/1.2m=-6750m/s^2 F = m*a = 0.04 * -6750 = -270 N.
November 12, 2013

math
a = (V-Vo)/t = (0-35)/0.02 = -1750 m/s^2 F = m*a = 0.15 * -1750 = -262.5 N.
November 11, 2013

Math
611/14 = 43.64 Estimate = 600/15 = 40. 76 + 8 = 84 Estimate = 75 + 10 = 85 Estimates can be done without the calculator when the proper numbers are chosen.
November 11, 2013

Math
x = 3y - 6 = 0 3y - 6 = 0 3y = 6 Y = 2 = y-int.
November 11, 2013

Math
2/1 < 2x/5 < 3/1 Multiply the inequality by 5: 10 < 2x < 15 Divide by 2: 5 < X < 7 1/2 Solution: X = 6, and X = 7.
November 11, 2013

Math
2y = x - 8 Replace x with 0 and solve for y: 2y = 0 - 8 Y = -4 = y-int. Eq: Y = -2x - 4
November 11, 2013

algebra
5.7*10^4.
November 11, 2013

algebra
db=10*Log(2.42*10^5)=10*Log(242000) = 54
November 11, 2013

physics
Fr = 283N.[41o] + 283N.[0o] X = 283*cos41 + 283 = 496.6 N. Y = 283*sin41 = 185.7 N. Fr^2 = X^2 + Y^2 Fr^2 = 496.6^2+185.7^2 = 281,096.05 Fr = 530.2 N. Ff = u*mg = 0.283 * 264.6 = 74.9 N. a = (Fr-Ff)/m=(530.2-74.9)/27=16.9 m/s^2
November 10, 2013

physics
Wb = m*g = 29kg * 9.8N/kg = 284.2 N. = Wt. of the block. 1. Fp = 284.2*sin A = Force parallel to the incline. Fn = 284.2*cos A = Normal or Force perpendicular to the incline. Fs = us*Fn = 0.7*284.2*cos A=199*cos A Fp-Fs = m*a = m*0 = 0 284.2*sinA - 199*c0sA = 0 284.2sinA = ...
November 10, 2013

Physics
h = 0.5g*t^2 = 2.4 m. 4.9t^2 = 2.4 t^2 = 0.490 Tf = 0.7 s. Dx = Xo * Tf = 4.8m/s * 0.7s = 3.36 m from the table.
November 10, 2013

Physics
d = 0.5g*t^2 = 24.6 m. 0.5g*3.4^2 = 24.6 Solve for g.
November 9, 2013

physics
Dr = 12km[30o] + 8km[90o] + 4km[165o] X = 12*cos30+8*cos90+4*cos165 = 6.53 km Y = 12*sin30+8*sin90+4*sin165 = 15.0 km tan A = Y/X = 15/6.53 = 2.29709 A = 66.5o Dr = Y/sin A = 15.0/sin66.5 = 16.4 km[66.5o].
November 9, 2013

Math
See your previous post, Tyrone.
November 9, 2013

MATH MATH MATH
See your previous post, Tyrone.
November 9, 2013

math
See your previous post.
November 9, 2013

Math
See your previous post.
November 9, 2013

MATH
See your previous post.
November 9, 2013

MATH
Correction: P = (Po*r*t)/(1-(1+r)^-t).
November 9, 2013

MATH
Loan amt. = 0.8 * 195,000 = $156,000 P = Po*r*t/(1-(1-(1+r)^-t) r = (6%/12)/100% = 0.005 = Monthly % rate expressed asva decimal. t = 30yrs * 12mo/yr = 360 Months. P1 = (156000*0.005*360)/(1-1.005^-360) = $336,707.57 I = P-Po = P2 = (195000*0.005*360)/(1-1.005^-360) = $420,884...
November 9, 2013

Physics 11
(1/6) * 9.8m/s^2
November 8, 2013

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