# Posts by henry

Total # Posts: 13,334

**Algebra**

Correct!

*January 5, 2016*

**Algebra**

Correct.

*January 5, 2016*

**Algebra.**

To break even: Income = Expense. 5x + 1300 = 3x + 1800 + 1500. 5x - 3x = 1800 + 1500 - 1300. 2x = 2000. X = 1000 Tickets.

*January 5, 2016*

**Algebra**

P = 2L + 2W. W = L. P = 2L + 2L = 4L. 20< P < 94. 20< 4L < 94. Divide by 4: 5< L < 23.5 in. 5< W < 23.5 in.

*January 5, 2016*

**Algebra 1**

1. (-3,2).

*January 5, 2016*

**Algebra 1**

Correct.

*January 5, 2016*

**Algebra 1**

Eq1: 4x + 2y = 10. Eq2: Y = -3x + 6. In Eq1, replace y with -3x+6 and solve for x: 4x + 2(-3x+6) = 10. 4x - 6x + 12 = 10. -2x = -2. X = 1. In Eq2, replace x with 1 and solve for y: Y = -3*1 + 6 = 3. Solution: (1,3).

*January 4, 2016*

**Algebra 1**

None of the give answers satisfy BOTH of the given equations. Remember that each answer must satisfy BOTH equations. My answer: (-2/3,-77/3) satisfies BOTH equations.

*January 4, 2016*

**Algebra 1**

Eq1: 4x - y = 23. Eq2: 7x - y = 21. Multiply Eq2 by -1 and add: +4x - y = 23. -7x + y = -21. Sum: -3x = 2. X = -2/3. In Eq1, replace x with -2/3 and solve for y. 4(-2/3) - y = 23. Y = ? You should get: Y = -77/2 = -25 2/3.

*January 4, 2016*

**Algebra 1**

Eq2: y + 4 = -3x. Y = -3x - 4. Eq1 and Eq2 are identical. Therefore, there are an infinite number of solutions. The graph is a single line.

*January 4, 2016*

**algebra 1**

A. Correct. B. In Eq1, replace x with 30+y and solve for y: 30+y + y = 60. 2y = 30. Y = 15 Minutes on free hand exercises. C. Yes, but the time spent in the gym would be 55 minutes(15+40) instead of 60 minutes.

*January 4, 2016*

**math**

7256chickens * 3290feathers/chicken = 23,872,240 Feathers to be plucked. 23,872,240fe * 2.6s/83.6fe * 1h/3600s = 206.2 h.

*January 4, 2016*

**Math**

Unless otherwise indicated, all angles are measured CCW from +x-axis. Ship #1: d1 = 11.5km/h[52o] * 2h = 22km[52o]. Ship #2: d2 = 13km/h[ 317o] * 2h = 26km[317o]. d2-d1 = 26[317o] - 22[52o]. X = 26*Cos317 - 22*Cos52) = 5.47 km. Y = 26*sin317 - 22*sin52 = -35.1 km. d2-d1 = Sqrt...

*January 3, 2016*

**physics**

V = Vo + a*t = 0. a = -Vo/t = -3/5 = -0.6 m/s^2.

*January 2, 2016*

**Calculus**

Okay I didn't know you could do that haha

*January 2, 2016*

**Calculus**

Wait, but how can you let u=x^3 when there is not an x^3 in the equation

*January 2, 2016*

**Calculus**

Last one for me. Evaluate (3x^2)/sqrt(1-x^6) dx I changed sqrt (1-x^6) into 1^(1/2)- x^(3) and let u=1^(1/2)- x^(3) then I got du/dx=3x^2 and subbed dx=du/3x^2 into the equation and got x-(x^4/4) but its not right. Options 7x^3/(3sqrt(1-x^7) + C cos-1(3x) + C sin-1(x^3) + C ...

*January 2, 2016*

**Calculus**

Im think im going to go with B then

*January 2, 2016*

**Calculus**

Okay Thanks. That one confused me.

*January 2, 2016*

**Calculus**

Okay will do. So I'm presuming your saying the answer is B. I think D works.

*January 2, 2016*

**Calculus**

Wait so A is right or is it wrong?

*January 2, 2016*

**Calculus**

Which of the following integrals cannot be evaluated using a simple substitution? I think it is A because if you would substitute there would be nothing left in the equation? Is that right? Options ∫√(x-1) ∫1/√(1-x^2) ∫x/√(1-x^2) ∫&#...

*January 2, 2016*

**Calculus**

Oh shoot I misread my answer. Thanks

*January 2, 2016*

**Calculus**

∫(x^3-x^2)/x^2 I got (x^2)/(2)-x + C but that's not one of the answers Options x - 1 + C (x^2/2)-(x^3/3) + C (x^4-x^3)/4x^2 + C (x^2/2) -x + C

*January 2, 2016*

**Calculus**

Yes Thank you

*January 2, 2016*

**Calculus**

∫((cos^3(x)/(1-sin^(2)) What is the derivative of that integral? I have been trying to use trig identities but can't find one to simplify this equation. I can't find one for (cos^3(x) or (1-sin^(2)) My options -sin(x) + C sin(x) + C (1/4)cos^(4)(x) + C None of ...

*January 2, 2016*

**Math**

Yes, it is I, your humble servant(LOL).

*January 1, 2016*

**Math**

T = 2 h. Ta = 3 h. Tb = ? T = Ta*Tb/(Ta+Tb) = 2. 3*Tb/(3+Tb) = 2. Tb = ?.

*January 1, 2016*

**Physics**

F = M*a, M = F/a = 26.5/6.5.

*January 1, 2016*

**English**

I chose C

*January 1, 2016*

**Maths**

g Girls in the class. 4g + 3 Boys in class. Total = g + (4g+3). The total should have been given.

*December 31, 2015*

**physics in kinematics**

Vo = 18m/s[37o]. Xo = 18*Cos37 = m/s. Yo = 18*sin37 = m/s.

*December 30, 2015*

**Physics**

A. Vr = -104 - 398i = 411.4km/h[75.4o] S. of W. = 14.6o W. of S. B. 411.4km/h[14.6o] E. of S.

*December 29, 2015*

**Science**

V^2 = Vo^2 + 2a*d = 0 + 2*0.5*100 = 100. V = 10 m/s. V=10m/s * 1km/1000m * 3600s/h = 36 km/h.

*December 29, 2015*

**physics**

Fr = 10N.[0o] + 30N.[120o] + 50N.[240o] X = 10 + 30*Cos120 + 50*Cos240 = -30 N. Y = 30*sin120 + 50*sin240 = -17.3 N. Tan A = Y/X = -17.3/-30 = 0.57735. A=30o S. of W. = 210o CCW from +x-axis. Fr = -30/Cos210 = 34.64 N. @ 210o CCW.

*December 28, 2015*

**PHYSICS**

Fr = Sqrt(F1^2 + F2^2) = Resultant force

*December 28, 2015*

**Calculus**

I tried to use partial fractions to do it, but it didn't work.

*December 27, 2015*

**Calculus**

Find the integral of 2/((2-x)(x+2)^2)dx.

*December 27, 2015*

**Physics**

I = (5^2/20^2)*X = (1/16)X W/m^2.

*December 26, 2015*

**Precalc**

The "j" means there is a 90-degree phase difference between the two terms and they cannot be added directly. Another method of writing the polar form: 2.83[45o].

*December 26, 2015*

**physics**

Work = F*d = 1500*Cos60 * 30 =

*December 26, 2015*

**Calculus**

Solve the following problem by separation of variables. T^2y'-t=ty+y+1 Y(1)=0 Y is a function of t.

*December 25, 2015*

**Calculus**

Wait, why is it the integral from 3-5 instead of 0-2?

*December 23, 2015*

**Calculus**

Sorry I forgot the dx after the integral.

*December 23, 2015*

**Calculus**

Find the integral from 0 to 2 of xsqrt(5-sqrt4-x^2)). The hint said to use substitution of u=sqrt(4-x^2), and that I needed one more substitution, but I don't know how to do it.

*December 23, 2015*

**Algebra 1**

Since there are 2 variables and only 1 Eq, I have to solve for 1 variable in terms of the other.

*December 23, 2015*

**Algebra 1**

12AB + 7B = 5A. 12AB - 5A = -7B. A(12B - 5) = -7B. Divide by (12B-5): A = -(7B/(12B-5)).

*December 23, 2015*

**physics**

Glad I could help.

*December 23, 2015*

**physics**

By definition, acceleration means to increase speed. When speed is decreasing it is called Deceleration. So you can't do both at the same time. When an object is moving, it is either accelerating, decelerating or moving at a constant speed. In other words, there are 3 ...

*December 23, 2015*

**physics**

d = 75N * 1m/1500N = 0.05 m. PE=0.5F * d = 0.5*75 * 0.05 = 1.875 J.

*December 21, 2015*

**physics 1**

1a. V = Vo + a*T1 = 0. T1 = -Vo/a = -22.5/-3.95=5.70 s To stop. V = Vo + a*T2 = 22.5. T2 = (22.5-Vo)/a = (22.5-0)/4.91=4.58 s. To accelerate back up to speed. T1+45+T2 = 5.70 + 45 + 4.58 = 55.3 s. 2. Hare: r*t = 1000. 1.5t = 1000. t = 666.67 s., Non-stop. Tortoise: r*t = 1000...

*December 20, 2015*

**physics**

Assuming the 3.5 m/s is horizontal: h = 0.5g*t^2. g = 9.8 m/s^2. t = ? A3. h = Vo*t + 0.5g*t^2 h = 230 m. Vo = -7.9 m/s(plane moving upward). g = 9.8 m/s^2. t = ? K5. The problem doesn't say what the captain is trying to do.

*December 20, 2015*

**physics**

Ma*Va + Mb*Vb = Ma*V + Mb*V. 30.7*2.64 + 109*1.29i + 30.7V + 109V. 81.05 + 140.6i = 139.7V. 162.3m/s[60o] = 139.7V. V = 1.16m/s[60o] N. of E.

*December 20, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V. 2864*V1 + 856*0 = 2864*7.5 + 856*7.5. V1 = ?

*December 20, 2015*

**physics**

M1*V1 + M2*V2 = M1*28.7 + M2*V. 0.192*44.4 + 0.459*0 = 0.192*28.7 + 0.459V. V = ?

*December 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*(-0.43) + M2*V. 0.13*0.22+0.22*(-0.30)=-0.43*0.13 + 0.22V. V = ? Multiply your answer by 100 to convert to cm/s.

*December 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*25. 24.9*22 + 13.2*11.8 = 24.9V + 13.2*25. V = ?

*December 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V. 13.2*6.8 + 3*(-3.5) = 13.2V + 3V. V = ?

*December 19, 2015*

**physics**

a. V = Vo + g*t = 0. Vo - 9.8*2 = 0. Vo = 19.6 m/s. b. h = Vo*t + 0.5g*t^2. g = -9.8 m/s^2. t = 2 s. h = ?. c. Tr+Tf = 2 + 2 = 4 s. To fall back to top of bldg. Tr = Rise time. Tf = Fall time. 8-4 = 4 s. To fall from top of bldg. to gnd. h = Vo*t + o.5g*t^2. Vo = 19.6 m/s. t...

*December 18, 2015*

**Language Arts Project/Essay HELP!**

Ugh, I am not really good at writing, sorry but I fell I'm useless here. I would better recommend you to contcat Supreme essay service. Those guys are real professionals in what they do. Best of luck!

*December 18, 2015*

**MATH HELP**

A = (3)^5/2 * (3)^5/2 = (3)^10/2 = 3^5 = 243 in^2.

*December 17, 2015*

**College Algebra**

1. P1 = 0.64 + 0.30*0.64 = P2 = 0.64 + 0.40*0.64 = P3 = 2. P = 0.64 + m*0.64 = 1.10 0.64m = 1.10 - 0.64 = 0.46. m = 0.719 = 71.9%.

*December 17, 2015*

**Math**

A = 2*(15*5) + 2(30*5) + 30*15=900 Ft^2. = Total area to be painted. 900Ft^2 * 1gal/250Ft^2 = 3.6 Gal. of paint needed. Buy 4-1gal. cans.

*December 17, 2015*

**PHYSICS! Really Confused! Test Tmrw**

V^2 = Vo^2 + 2g*h = 0. h = -Vo^2/2g + 10 = -(5^2)/-19.6 = 11.28 m. h = 0.5g*T^2 = 11.28 m. 4.9T^2 = 11.28. T^2 = 2.30. T = 1.52 s. d = Vt*T = 30 * 1.52 = 45.6 m.

*December 17, 2015*

**Math**

(Y+1)+4

*December 16, 2015*

**physics**

See previous post: Wed,8-12-15, 12:14 AM.

*December 16, 2015*

**physics**

Correction: r = (d1+d2)/(43.3+T) = 1.99. (170.2+1.13T)/(43.3+T) = 1.99. Solve for T.

*December 16, 2015*

**physics**

d1 = 3.93m/s * 43.3s = 170.2 m. d2 = 1.13*T. r = (d1+d2)/T = 1.99 m/s. (170.2+1.13T)/T = 1.99. Multiply by T: 170.2 + 1.13T = 1.99T. 1.99T - 1.13T = 170.2. 0.86T = 170.2. T = 198 s.

*December 16, 2015*

**=**

Diode Connected: Vd + (I2+Id)R1 = 6 Volts. 0.7 + (I2+1.0)R1 = 6. 0.7 + I2*R1 + R1 = 6. Eq1: I2R1 + R1 = 5.3. Diode disconnected: V2 + I2*R1 = 6 Volts. 2 + I2R1 = 6. Eq2: I2R1 = 4. In Eq1, replace I2H1 with 4: 4 + R1 = 5.3. R1 = 1.3k = 1300 Ohms. In Eq2, replace R1 with 1.3k: ...

*December 16, 2015*

**Algebra**

You show the Ht. of only 7 players and the Wt. of only 6 players.

*December 16, 2015*

**Mathematics**

Show that the root equation (x-a)(x-b)=k^2 are always real numbers

*December 16, 2015*

**Mathematics**

Factorice 16(a-2b)^2-(a+b)^2 leaving your answer in the simplest form

*December 16, 2015*

**pre algebra**

P = Po(1+r)^n. Po = $2000. r = 0.051/2 = 0.0255 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 7yrs. = 14 Compounding periods.

*December 15, 2015*

**Algebra**

1. x-1/5 = +-3. 5x - 1 = +-15. 5x = 16, and -14. X = 16/5, or -14/5. 2. D. decreasing nonlinear.

*December 15, 2015*

**Math**

0.64N. N = the number of boxes sold.

*December 15, 2015*

**physics**

Fr = 25N.[25o] + F2[-73o] Since the acceleration is parallel to the x-axis, the sum of Y components of velocity equals 0: 25*sin25 + F2*sin(-73) = 0. 10.57 -0.956F2 = 0. -0.956F2 = -10.57. F2 = 11.1N[-73o].

*December 15, 2015*

**physics**

Vo = 56m/s[35o]. Xo = 56*Cos35 = 45.9 m/s. Yo = 56*sin35 = 32.1 m/s. Y = Yo*t + 0.5g*t^2=32.1*2.9 -4.9*2.9^2 = 52 m. X = Xo*T = 45.9m/s * 2.9s = 133 m.

*December 15, 2015*

**Physics**

V^2 = Vo^2 + 2g*h. Vo = 0. V = ?

*December 14, 2015*

**Math**

1-3/4 = 4/4-3/4 = 1/4 Eaten.

*December 14, 2015*

**Science**

Eff. = 70/100 * 100%.

*December 14, 2015*

**Math**

a. d1 = 200/sin43 = 293 Ft. b. d2 = 200/tan43. c. d3 = d2/Cos16. d. h = 200 + d2*Tan16

*December 14, 2015*

**Business Math**

P = Po + Po*r*t P = 1700 + 1700*(0.12/12)*18 = $2,006.

*December 14, 2015*

**Physics**

V = 50,000m/3600s = 13.9 m/s. t = 20min ? = 1200 s. a = (V-Vo)/t = Vo = 0. a/g * 100% =

*December 14, 2015*

**Math**

The driver formed a rectangle with 10 km horizontal sides and 20 km vertical sides(northward).

*December 14, 2015*

**Physics Help**

Vo = 100m/s[60o]. Xo = 100*Cos60 = 50 m/s. Yo = 100*sin60 = 86.6 m/s. Y^2 = Yo^2 + 2g*h = 86.6^2 - 19.6*150 = 4560. Y = 67.5 m/s.

*December 13, 2015*

**Physics (angle Vector)**

Vb - 5.4i = 11.8. Vb = 11.8 + 5.4i = 13m/s[24.6o] N. of E. = Compass heading. 9-5.4i) =

*December 13, 2015*

**math**

Started with $X. x/3 + x/2 = x - 9.00. Multiply by 6 and solve for x.

*December 13, 2015*

**algebra**

Sold X none student tickets. Sold Y student tickets. Eq1: x + y = 937. Eq2: 5x + 3y = 3943. Multiply Eq1 by -3 and use Elimination Method.

*December 13, 2015*

**Algebra**

Right!

*December 13, 2015*

**physics**

Incomplete.

*December 13, 2015*

**physics**

Oops! I misread the numbers. Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs. 9.77Lbs * 5days/10Lbs. = 4.9 Days or 5 days.

*December 13, 2015*

**physics**

Total = 23*33 + 12*11 + 1*1 = 892 Lbs. 892Lbs * 5days/10Lbs = 446 Days.

*December 13, 2015*

**Mathematics**

(x-6)*Log4 = 3x*Log2. Divide by Log4: x-6 = 3x*Log2/Log4. x-6 = 3x*0.5 = 1.5x. x-1.5x = 6. -0.5x = 6. X = -12.

*December 13, 2015*

**8th grade algebra**

Correction: In your case, 48 is the area of the base: V = B*h = 48m^2 * 7m = 336 m^3 or 336 cubic meters. Again, take half of the base only when it is the diameter.

*December 12, 2015*

**8th grade algebra**

V = pi*r^2*h = 3.14*24^2*7 = 12,660.5 cm^3(Not m^3). V = B*h, B=Area of the base, V=pi*r^2*h 48 is not the area of the base; it is the diameter of the base. Diameter*height = Square units. Diameter/2 = Radius. So you take 1/2 of the diameter to get the radius. I hope this helps.

*December 12, 2015*

**Physics**

-2.8 + Vb = -10.4i. Vb = 2.8 - 10.4i. = 10.8m/s[-74.9o] = 74.9o S. of E. = 15.1o E. of S.

*December 11, 2015*

**algebra**

1/4 + 1/3 + 1/2 = 3/12 + 4/12 + 6/12 = 13/12 = 1 1/12. Impossible, because 13/12 is more than a whole pizza.

*December 11, 2015*

**Physics**

101kpa = 101*10^3pa = 1.01*10^5 pa.

*December 11, 2015*

**science**

Increasing the voltage increases the current and power(P = E*I); therefore, the voltage should be increased.

*December 11, 2015*

**Math**

15/0.6 =

*December 11, 2015*