Saturday

October 25, 2014

October 25, 2014

Total # Posts: 9,344

**physics**

Ws = m*g = 80kg * 9.8N/kg = 784 N. = Wt. of sled. Fp = 784*sin25 = 331.3 N. = Force parallel to the incline. Fn = 784*cos25 = 710.5 N. = Normal force = Force perpendicular to the incline. Fk = u*Fn = 0.7 * 710.5 = 497.4 N. = Force of kinetic friction. F-Fp-Fk = m*a F-331.3-497...
*December 21, 2013*

**math**

Rate = 300/6 = 50 Words/min. 2. $4.00/25 oz = $016/oz. $7.00/90oz = $0.08/0z. 3. d/12 = 96/8 8d = 12*96 = 1152 d = 1152/8 = $144
*December 21, 2013*

**physics**

Elastic limit.
*December 19, 2013*

**Science**

Yes, I use that trick when there are more conversions than we have here.
*December 19, 2013*

**Science**

V = 32km/h = 32000m/3600s = 8.89 m/s. 32km = 32,000 m. 1h = 3600s.
*December 19, 2013*

**math**

See previous post: 8:51 AM.
*December 19, 2013*

**physics**

V^2 = Vo^2 + 2a*d a = (V^2-V0^2)/2d a = (51^2-0)/150 = 17.34 m/s^2.
*December 18, 2013*

**math help**

(1*2*3*z)^2 = 144 (6z)^2 = 144 36z^2 = 144 z^2 = 4 Z = +-2.
*December 18, 2013*

**Physics**

See 3:47 AM post.
*December 18, 2013*

**Physics**

h = 50 m. Vo = 35m/s[50o] Xo = 35*cos50 = 22.50 m/s. Yo = 35*sin50 = 26.81 m/s. a. Y = Yo + g*t = 0 at max ht. 26.81 - 9.8t = 0 9.8t = 26.81 Tr = 26.81/9.8 = 2.74 s. = Rise time. hmax=ho + Yo*Tr - 0.5g*Tr^2 hmax=50+26.81*2.74 - 4.9*2.74^2=86.67 m. Above gnd. 0.5g*t^2 = 86.67 4...
*December 18, 2013*

**Physics**

1D. Cannot be determined, because we don't know the time. 2D. 5D.V = a*t = 2m/s^2 * 8s. = 16 m/s. 6B. V = Vo + g*t = 0 + 10*4 = 40 m/s. 7A. X = 100*cos 30 = 87 N. 8B.
*December 17, 2013*

**Physics**

F = (0.06m/1m) * 18N = 1.08 N. a = F/m = 1.08/7.66*10^-3 = 141 m/s^2. V^2 = Vo^2 + 2a>d V^2 = 0 + 282*0.06 = 16.92 V = 4.11 m/s. V^2 = 4.11^2 + 282*0.03 = 25.35 V = 5.03 m/s.
*December 17, 2013*

**Math**

L = (30/6) * 10Ft = 50 Ft
*December 16, 2013*

**physics- multiple choice**

1. True 2. 98 N, down. 3. Fn = m*g - 1000 = 600kg * 9.8-1000 = 5880 - 1000 = 4880 N.
*December 16, 2013*

**physics. HELP**

See previous post: Mon,12-16-13,7:15 PM.
*December 16, 2013*

**physics. HELP**

See previous post: Mon,12-16-13,7:11 PM.
*December 16, 2013*

**physics. HELP**

See previous post: Mon,12-16-13,7:07 PM.
*December 16, 2013*

**physics**

D = Xo * 1.8 = 30 m. Xo = 30/1.8 = 16.67 m/s=Hor. component of initial velocity. Y = Yo + g*Tr = 0 at max Ht. Yo - 9.8*(1.8/2) = 0 Yo - 8.82 = 0 Yo = 8.82 m/s = Ver. component of initial velocity. a. Vo^2=Xo^2 + Yo^2=16.67^2 + 8.82^2 = 355.7 Vo = 18.9 m/s = Initial velocity. b...
*December 16, 2013*

**physics**

Vo = 6 m/s[35o] = Initial velocity. Xo = 6*cos35 = 4.91 m/s.=Hor. component of initial velocity. Yo = 6*sin35 = 3.44 m/s=Ver. component of initial velocity. a. Y = Yo + g*t = 0 3.44 - 9.8t = 0 9.8t = 3.44 Tr = 3.44/9.8 = 0.3512 s. = Rise time. Tf = Tr = 0.3512 m/s = Fall time...
*December 16, 2013*

**physics**

D = Xo*t = 8.90 m Xo * 1.1 = 8.9 Xo = 8.9/1.1 = 8.09 m/s = Hor. component of initial velocity. Vo = Xo/cos A = 8.09/cos30=9.34 m/s[30o] = Initial velocity or take-off speed.
*December 16, 2013*

**physics**

d = V*t = 170 40*t = 170 t = 4.25 s. d2 = 0.5g*t^2 d2 = 4.9 * 4.25^2 = 88.5 m. = Vertical drop.
*December 16, 2013*

**phyics**

h = 1.5 m? h = 0.5g*t^2 = 1.5 m. Solve for t.
*December 16, 2013*

**math**

If the absolute value of a number is 21, the number can be positive or negative 21: 3x+12 => +-21 3x => +-21-12 X = (+-21-12)/3 = 3 or -11.
*December 16, 2013*

**algebra**

6j-5 < 2(3j-4) 6j-5 < 6j-8 6j-6j < -8+5 0 < -3. False.
*December 16, 2013*

**physics**

Net Force = Fap - Fk = 420-0.22*1420 = 107.6 N.
*December 16, 2013*

**physics**

d1 = 15m/s * 2s. = 30 m head start. d2 = 0.5a*t^2 = 30 + 15t 1*t^2 = 30 + 15t t^2 - 15t = 30 t^2 - 15t - 30 = 0 Use Quadratic Formula and get: t = 16.79 s.
*December 16, 2013*

**Physics**

V^2 = Vo^2 + 2g*d V^2 = 0 + 19.6*(58-25) = 646.8 V = 25.43 m/s.
*December 15, 2013*

**Mathematics**

Amt = 1.1*480 - 480 = 48
*December 14, 2013*

**Physics**

V=0.25rev/s * 6.28rad/rev = 1.57 rad/s. Note: The person's distance from the center does not affect the angular velocity. But the linear velocity decreases as the person walks toward the center.
*December 14, 2013*

**math**

h(n) = (100/90 * n h(27) = (100/9) * 27 = $300.
*December 14, 2013*

**Pre Calculus**

sec A*tan A/sin A = 1/cos A*sin A/cos A = sin A/cos^2 A/sin A = sin A/cos^2 A * 1/sin A = 1/cos^2 A.
*December 14, 2013*

**physics**

Circumference=pi*2r = 3.14 * 3 = 9.42 m. m = 15 kg. V = 5rad/s * 9.42m/6.28rad = 7.50 m/s. KE = 0.5m*V^2 = 0.5*15*7.50^2 = 421.9 J. Fp = mg*sinA = 15*9.8*sin15 = 38.05 N. = Force parallel to the incline. Fn = mg*cosA = 15*9.8*cos15 = 142 N. = Normal = Force perpendicular to ...
*December 14, 2013*

**Physics**

See previous post.
*December 11, 2013*

**Physics**

a. Wt.=m*g = 275kg * 9.8N/kg=2695 N = Wt of piano. Fp = 2695*sin30 = 1348 N. = Force parallel to incline. Fn = 2695*cos30 = 2334 N. = Normal = Force perpendicular to incline Fk = u*Fn = 0.40 * 2334 = 933.6 N. = Force of kinetic friction. Fex-Fp-Fk = m*a Fex-1348-933.6 = m*0 = ...
*December 11, 2013*

**Quick Math Help**

C = mx + b C = 5.5x + 10. The slope = 5.5. So the cost would decrease.
*December 11, 2013*

**Math**

2bags * 8.5Lbs/bag = 17 Lbs of mints. 17/(1/12) = 17 * 12/1=204 Place setting. 256-204 = 52 Short.
*December 11, 2013*

**Physics**

F = ((Vs+Vr)/(Vs-Vd))*Fd = 2355 Hz. ((343+0)/(343-Vd))*2000 = 2355 ((343)/(343-Vd))*2000 = 2355 686000/(343-Vd) = 2355 2355(343-Vd) = 686000 343-Vd = 291.3 -Vd = 291.3-343 = -51.7 Vd = 51.7 m/s = Velocity of the diver.
*December 11, 2013*

**Physics**

Vo = 9.37km/h = 9370m/3600s = 2.60 m/s hmax = (V^2-Vo^2)/2g = (0-2.60^2)/19.6 = 0.345 m.
*December 11, 2013*

**GEOMETRY PLZ HELP!**

See previous post: Tue,12-10-13,8:35 PM.
*December 10, 2013*

**Pre-calc**

Logx 16 = -2. x^-2 = 16 1/x^2 = 16 16x^2 = 1 x^2 = 1/16 x = 1/4.
*December 10, 2013*

**geometry**

c^2 = a^2 + b^2 c^2 = 6^2 + 6^2 = 72 c = 8.49 Ft. = 101.82 In. 101.82/4 = 25.46 or 25 Wall panels. 0.46 * 4 = 1.8 Inches. .
*December 10, 2013*

**pre calculus**

X^2 - 3X - 7 = 0 This Eq cannot be factored. Use the Quadratic Formula: X = (-B +- sqrt(B^2-4AC))/2A X = (3 +- Sqrt(9+28))/2 X = (3 +- 6.08)/2 = 4.54, and -1.54.
*December 10, 2013*

**college intermediate algebra**

1st person: X min. 2nd person: (X+20) min. X*(X+20)/(X+X+20) = 24 min. (X^2+20X)/(2X+20) = 24 X^2+20X = 48X+480 X^2-28X-480 = 0 Use Quadratic formula and get: X = 40 min. X+20 = 60 min.
*December 10, 2013*

**Ap Physics 1**

See previous post: Tue,12-10-13,9:37 AM.
*December 10, 2013*

**Ap Physics 1**

b. Fap-2100 = m*a Fap-2100 = 71,905*0.21 Fap-2100 = 15,100 Fap = 17,200 N.
*December 10, 2013*

**Ap Physics 1**

Fap = 17,500 N. = Force applied. Fk = 2400 N. = Force of kinetic friction a. m=(Fap-Fk)/a m = (17,500-2400)/0.21=71,905 kg.
*December 10, 2013*

**Physics**

L = V/F = 5.9*10^-4 m. V/2.60 = 5.9*10^-4 V = 1.534*10^-3 m/uS. d=1.534*10^-3m/uS * 11/2*!0^6uS=8440 m.
*December 10, 2013*

**science**

Amt. left = (1/2)^6 = (1/2)^3*(1/2)^3 =1/8 * 1/8 = 1/64 (1/64) * 100% = 1.65%
*December 9, 2013*

**physics**

See previous 5:35 PM post.
*December 9, 2013*

**physics**

See previous 5:35 PM post.
*December 9, 2013*

**physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*150 = 2,940 V = 54.2 m/s.
*December 9, 2013*

**Physics**

Overflow = The increase in vol. Same procedure as previous problem.
*December 8, 2013*

**Physics**

Increase = a(T-To)Vo = 1.63*10^-4(20-15)0.3=2.45*10^-4 m^3.
*December 8, 2013*

**Physics**

Overflow = a(T-To)Vo Overflow=3.7*10^-4(90-20)100=2.59 cm^3
*December 8, 2013*

**Math**

1. 0.5^3x-2 = 14 0.5^3x = 14+2 = 16 Take Log of both sides: 3x*Log 0.5 = Log 16 Divide both sides by Log 0.5: 3x = Log 16/Log0.5 = -4 Divide both sides by 3: X = -4/3 2. Log(x-1)-Log x = Log(x-3) Log((x-1)/x) = Log(x-3) B. f(x) = (x+2)/x; g(x) = 7/(x-5) a. F(g(x)) = (7/(x-5)+2...
*December 8, 2013*

**Physics**

Fc = m*g = 4000kg * 9.8N/kg = 39,200 N. = Force of car. Fp = 39200*sin19.6 = 13,150 N. = Force parallel to the slope. Fn = 39200*cos19.6 = 36,929 N. = Normal Force = Force perpendicular to the slope Fk = 4,000 N. = Force of kinetic friction. a=(Fp-Fk)/m a = (13150-4000)/4000=2...
*December 6, 2013*

**Dyanamics**

1. A = 32km/h[135o],CCW Xa = 32*cos135 = -22.63 km/h Ya = 32*sin135 = 22.63 km/h B = 24km/h[220o],CCW Xb = 24*cos220 = -18.39 km/h Yb = 24*sin220 = -15.43 km/h Xa and Xb are in same direction. So we subtract: Xc=Xb-Xa = -18.39 - (-22.63)=4.24 km/h Yc = Yb+Ya = -15.43 + 22.63...
*December 6, 2013*

**physics**

F = m*a = 9 * 3 = 27 N.
*December 6, 2013*

**physics**

To = 9C/5 + 32 = 9*35/5 + 32 = 95oF. T = 9*(-12)/5 + 32 = 10.4oF. a max = 7.9*10^-6/oF. Change = a*(T-To)ho 7.9*10^-6*(10.4-95)*170 = -11.36 cm. Change = 11.36 cm decrease
*December 6, 2013*

**physics**

Vo = 16m/s[20o] Yo = 16*sin20 = 5.47 m/s. Y = Yo + g*t = 0 At max. Ht. 5.47 - 9.8t = 0 9.8t = 5.47 Tr = 0.558 s. = Rise time Tf = Tr = 0.558 s. = Fall time. T = Tr+Tf = 0.558 + 0.558 = 1.12 s.
*December 6, 2013*

**Geometry**

As = 2W*h + 2L*W + 2L*h = 214 m^2. 70 + 14L + 10L = 214 24L = 144 L = 6 m. V = L*W*h = 6 * 7 * 5 = 210 m^3.
*December 6, 2013*

**physics**

A = 6m[30o[ Y = 6*sin30 = 3m = North Component. B = 7m[132o], CCW. Y = 7*sin132 = 5,20 m. = North component. The component along the north direction of person A is smaller.
*December 6, 2013*

**physics**

a = (V-V)/t = (44-0)/0.028 = 1571 m/s^2 F = m*a = 0.49 * 1571 = 770 N.
*December 6, 2013*

**Physics**

See previous post: Thu,12-5-13,3:00 PM.
*December 5, 2013*

**physics**

T= F = m*a = 454 * 3.51 = 1594 N.
*December 5, 2013*

**physics, buoyance**

A. Hb=(Do/Dw)*Ho=(730/1000)*0.2=0.146 m Below the the water. Ha = 0.2 - 0.146 = 0.054 m Above water. B.Mc=V*D = 0.2^3m^3 * 730kg/m^3=5.84 kg. = Mass of cube. (Mc+Mo)/Vc = Dw(Density of water). (5.84+Mo)/0.008 = 1000kg/m^3 5.84 + Mo = 8 Mo = 2.16 kg = Mass of object to be added.
*December 5, 2013*

**Physics**

See previous post: Tue,12-3-13,10:36 PM.
*December 4, 2013*

**physics**

Vc = 46.4mi/3600s * 1600m/mi = 20.62 m/s Circumference=pi*2r=3.14 * 0.568=1.784 m Period =(1.784m/20.62m)*1s. = 0.0865 s.
*December 4, 2013*

**Math**

a. x = 3 x-3 = 0 x = -1 x+1 = 0 x = -5 x+5 = 0 Y = (x-3)(x+1)(x+5) = 0 Multiply the 1st two parenthesis: Y = (x^2-2x-3)(x+5) = 0 Eq: Y = x^3 + 3x^2 -13x - 15 = 0
*December 4, 2013*

**Physics**

See previous post: Tue,12-3-13,10:36 PM.
*December 4, 2013*

**brief calc**

2q/3 = 8-p2q/3 = 8-6 = 2 2q/3 = 2 2q = 6 q = 3
*December 4, 2013*

**brief calc**

q = 130 2*11 = 108.
*December 4, 2013*

**physics**

I=V/(Ro+Ra) = 10/(1k+0.05k) = 9.5238 mA. = Measured current. I=10/1k = 10.00 mA=Theoretical current. Accuracy = ((10.00 - 9.5238)/10)*100%4.762 %.
*December 3, 2013*

**Physics**

At top of hill: KE + PE = mg*h 0 + PE = mg*h PE = mg*h At bottom of hill: KE + PE = mg*h KE + 0 = mg*h KE = mg*h = 0.5m*V^2 0.5m*V^2 = mg*h V^2 = 2g*h V = Sqrt(2g*h). V = Sqrt(19.6*h). Sqrt means Square root.
*December 3, 2013*

**physics**

See previous post.
*December 3, 2013*

**physics**

Fc = m*g = 29kg * 9.8N/kg = 284.2 N. = Force of crate. Fap-Fs = m*a 90-u*Fc = m*0 90 - u*284.2 = 0 u*284.2 = 90 us = 0.317
*December 3, 2013*

**math**

T = (2/5) * 2 = 4/5 or 0.8 h.
*December 3, 2013*

**Physics**

a. a=F/m = 3.34*10^7/2.77*10^6 = 12.06 m/s^2. b. t = 2.5min * 60s/min = 150 s. h = 0.5a(2t-1) h = 6.03*(300-1) = 1803 m.
*December 3, 2013*

**Maths**

100% - 40.25% - 30.76% = 28.99 % Greater than 5.5 Ft. People = 0.2899 * 120M=34.79 M Greater than 5.5 Ft.
*December 3, 2013*

**science**

P = 40.2hp * 746W/hp = 29,989 Watts. = 29,989 Joules/s. T = 5.9*10*5J/(2.9989*10^4J/s=19.67 s.
*December 3, 2013*

**Physics**

B. L = V/F = 343/239.7 1.43 When flying away.
*December 2, 2013*

**Physics**

A. L = V/F = 343/258 = 1.33 m. B. F = ((Vs+Vr)/(Vs-Vg))*Fo = 258 Hz ((343+0)/(343-12.6))*Fo = 258 (343/330.4) * Fo = 258 1.0381Fo = 258 Fo = 248.5 Hz=Initial Freq. of the goose F = ((343-0)/(343+12.6))*248.5 F = (343/355.6) * 248.5 = 239.7 Hz When flying away.
*December 2, 2013*

**Physics**

A. L = V*T =V*(1/F)=V/F L = 343/4.4*10^6 = 7.95*10^-5m. B. L = 1580/4.4*10^6 = 359*10^-6=3.59*10^-4 m.
*December 2, 2013*

**math **

what property is described in this equation: 24x5=(20x5)+(4x5)
*December 2, 2013*

**Physics**

Fs = m*g = 87.1kg * 9.8N/kg = 853.6 N. = Force of snowboarder. Fp = 853.6*sin36.7 = 510.1 N. = Force parallel to hill. Fn = 853.6*cos36.7 = 684.4 N = Normal = Force perpendicular to hill. Fk = u*Fn = 0.106 * 684.4 = 72.55 N. = Force of kinetic friction. a=(Fp-Fk)/m=(510.1-72....
*December 2, 2013*

**Algebra**

x^2 + y^2 + 8x + 2y + 8 = 0 x^2+8x+(8/2)^2+y^2+2y+(2/2)^2=-8+(8/2)^2 +(2/2)^2. x^2+8x+16 + y^2+2y+1 = -8+16+1 Eq: (x+4)^2 + (y+1)^2 = 9 C(-4,-1). r2 = 9 r = +-3
*December 2, 2013*

**Geometry**

See previous post: Mon,12-2-13,7:39 AM.
*December 2, 2013*

**Geometry**

See previous post:Mon,12-2-13,7:39 AM.
*December 2, 2013*

**Geometry**

The diagonals form 2 30o-60o rt. triangles. h = 24*sin30 = 12 In. W = 24*cos30 = 20.8 In. P = 2*(W+h) = 2*(20.8+12) = 65.6 In.
*December 2, 2013*

**physics**

v = Vmax*sinWt v = 100*sin(1000t) Vrms = 0.707 * 100 = 70.7 Volts. W = 2pi*F = 1000 6.28*F = 1000 F = 159 Hz. Xl = W*L = 1000 * 0.5 = 500 Ohms. Xc=1/W*C=1/(1000*4.6*10^-6)=-217.4 Ohms tan A = (Xl+Xc)/R tanA = (500+(-217.4))/400 = 0.7065 A = 35.2o Z = R/cos A = 400/cos35.2 = ...
*December 2, 2013*

**physics**

h = Vo*t + 0.5g*t^2 = 20 37.8t _ 4.9t^2 = 20 -4.9t^2 + 37.8t - 20 = 0 Use Quadratic Formula and get: t = 0.571, and 7.14 s. So, when the ball is rising; it reaches 20 m in 0.571 s. When it is falling, it reaches 20 m in 7.14 s.
*December 1, 2013*

**physics**

See your previous post: Sun,12-1-13,10:34 PM.
*December 1, 2013*

**physics**

See previous post: Fri,11-29-13,8:15 PM.
*December 1, 2013*

**physics. again.**

V== Vo + g*t = 10 m/s. 37.8 + (-9.8)t = 10 -9.8t = 10-37.8 =-27.8 t = 2.84 s. h = Vo*t + 0.5g*t^2 h = 37.8*2.84 - 4.9*2.84^2 = 67.83 m.
*December 1, 2013*

**physics**

Fs = m*g = 22kg * 9.8N/kg = 215.6 N. = Force of the sled. Fp = 215.6*sin6 = 22.54 N. = Force parallel to the incline. Fn = 215.6*cos6 = 214.4 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.2 * 214.4 = 42.88 N. = Force of kinetic friction. V = 64km/h = 64000m/...
*December 1, 2013*

**5th grade math**

I'm glad I could help, and thanks for your response.
*December 1, 2013*

**5th grade math**

4th Grade: 9 Left-handed students. Total = 3 * 9 = 27 Students. 9/27 = 1/3 Are left-handed. 5th Grade: 7 Left-handed students. Total = 30-2 = 28 Sudents. 7/28 = 1/4 Are left-handed. 6th Grade: 6 Left-handed students. Total = 27+3 = 30 Students. 6/30 = 1/5 Are left-handed. The ...
*December 1, 2013*

**Physics**

r2 = r1 + a*(T-To)r1 = 4.42 cm. 4.40 + 1.3*10^-4(T-20)4.40 = 4.42 4.40 + 5.72*10^-4(T-20) = 4.42 5.72*10^-4(T-20) = 4.42-4.40 = 0.02 5.72*10^-4T - 114.4*10^-4 = 0.02 5.72*10^-4T = 0.02 + 0.01144 = 0.03144 T = 314.4*10^-4/5.72*10^-4 = 54.97o
*December 1, 2013*

**Math**

Same procedure as previous post: Sun,12-1-13,7:39 PM.
*December 1, 2013*

**Math**

Given: A(-8,3), B(-6,1). m = -1 A(-8,3), P(x,y). m== -1. m = (y-3)/(x-(-8)) = -1 m = (y-3)/(x+8) = -1 Cross multiply: y-3 = -1(x+8) y-3 = -x-8 Eq: x + y = -5 Or x + y +5 = 0 Replace y with 0: x + 0 = -5 X = -5 = X-intercept. Replace X with 0: 0 + y = -5 Y = -5 = y-int.
*December 1, 2013*

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