Saturday

August 23, 2014

August 23, 2014

Total # Posts: 8,929

**physics**

Wc = m * g = 16kg * 9.8N/kg = 156.8 N. = Wt. of the cart. Fe*cos28-Ff = m*a 0.8829Fe - 54 = m*0 = 0 0.8829Fe = 54 Fe = 61.2 N. = Force exerted. W = Fe*cos28 * d W = 61.2*cos28 * 20 = 1080 Joules = Work done on cart.
*October 11, 2013*

**physics**

d = (V^2-Vo^2)/2g d = (53^2-3.14^2)/19.6 = 143 m.
*October 11, 2013*

**physics**

a = (V-Vo)/t = (42-0)/7.3 = 5.75 m/s^2. F = m*a = 5700 * 5.75 = 32,795 N.
*October 11, 2013*

**physics**

Incomplete.
*October 11, 2013*

**Physics**

See previous post: Fri,10-13-13,2:36 AM.
*October 11, 2013*

**Physics**

See previous post: Fri,10-11-13,2:36 AM.
*October 11, 2013*

**Physics**

CORRECTION: Vo=89,000m/1h = 89000/3600s = 24.72 m/s a. V = Vo + va*t T = (V-V0)/a + Tr T = (0-24.72)/-4 + 2s.=8.18 s.=Stopping time. d = Vo*t + 0.5a*t^2 d=24.72*8.18 + 0.5*(-40*8.18*2=68.38 m. b. T = (0-24.72)/-8 + 2s = 5.09 s. d=24.72*5.09 + 0.5*(-8)*5.09^2= 22.19 m.
*October 11, 2013*

**Physics**

Vo=85000m/h = 85000m/3600s = 23.61 m/s. a. V = Vo + a*t T = (V-Vo)/a + Tr T = (0-23.61)/-4 + 2s = 7.9 s = Stopping time. d = Vo*t + 0.5a*t^2 d = 23.61*7.9 + 0.5*-4*7.9^2 = 61.7m b. T = (0-23.61)/-8 + 2s = 4.95 s. d=23.61*4.95 + 0.5*(-8)*4.95^2=18.86 m.
*October 11, 2013*

**physics**

a=(V^2-Vo^2)/2d a=(55^2-20^2)/3000=0.875m/s^2 V = Vo + a*t t = (V-Vo)/a = (55-20)/0.875 = 40 s.
*October 11, 2013*

**Physics**

Vo = 21m/s[41o] Xo = 21*c0s41 = 15.85 m/s. Yo = 21*sin41 = 13.78 m/s. D = Xo * Tf = 59 m. 15.85 * Tf = 59 Tf = 3.722 s. = Fall time. h = Yo*t + 0.5g*t^2 h = 13.78*3.722 + 4.9*3.722^2 = 119.2 m
*October 10, 2013*

**AP physics c**

a. Work = F * d = m*g/10 * d Work = 63*(9.8/10) * 10 = 617.4 Joules. b. Work=m*g * d = 63*9.8 * 10 = 6174 J.
*October 10, 2013*

**physics**

Vo=12mi/h * 1600m/mi * 1h/3600s.=5.33m/s a=(V-Vo)/t = (0-5.33)/1.9=-2.807 m/s^2.
*October 10, 2013*

**physics PLEASE HELP ME**

See previous post: Thu,10-10-13,7:27PM. thu,10-10-13,7:27 PM.
*October 10, 2013*

**physics PLEASE HELP ME**

See previous post: thu,10-10-13,7:27 PM.
*October 10, 2013*

**physics PLEASE HELP ME**

See previous post: Thu,10-10-13,7:46 PM.
*October 10, 2013*

**Physics**

a = (V^2-Vo^2)/2d a = (5^2-0)/39.2 = 0.6378 m/s^2.
*October 10, 2013*

**consumer math**

P = Po(1+r)^n n = 1comp./yr * 5yrs = 5 compounding periods. P = 15000(1.06)^5 = $20,73.38
*October 10, 2013*

**Physics**

h = 0.5g*t^2 = 35 m. 4.9t^2 = 35 t^2 = 7.143 Tf = 2.673 s. = Fall time. D = Xo * Tf = 18m/s * 2.673s = 48.11 m.
*October 10, 2013*

**Physics**

V^2 = Vo^2 + 2g*d = 46.5^2 Vo^2 + 19.6*55 = 2162 Vo^2 = 2162 - 1078 = 1084 Vo = 32.92 m/s.
*October 10, 2013*

**Math**

Decimal
*October 10, 2013*

**science**

Wt. = m * g = (67+12) * 9.8 = 774.2 N.
*October 10, 2013*

**Physics**

Vo = 10m/s[-25o] Xo = 10*cos(-25) = 9.063 m/s Yo = 10*sin(-25) = -4.226 m/s. a. D=Xo * Tf = 9.063m/s * 3.60s=32.63 m. b. h = Yo*t + 0.5g*t^2 h = -4.226*3.6 + 4.9*3.6^2 = 48.29 m. c. Y^2 = Yo^2 + 2g*h Y^2 = -4.226^2 + 19.6*48.29 = 964.3 m. Y = 31.05 m/s.
*October 10, 2013*

**physics**

If a single force is used: a = -255 + 650 = 395 m/s^2 F = m * a = 0.1 * 395 = 39.5 N. Along the +x axis. If 2 forces are used: F1 = 0.1 * (-255 = -25.5 N. Along the -x axis. F2 = 0.1 * 650 = 65 N. Along the +x axis. Fn = -25.5 + 65 = 39.5 N. = Net force Acting along the +x axis.
*October 9, 2013*

**Physics**

d = Vo*t + 0.5a*t^2 = 3600 m. 5*162 + 0.5a*162^2 = 3600 810 + 13122a = 3600 13122a = 3600-810 = 2790 a = 0.2126 m/s^2 V=Vo + a*t = 5 + 0.2126*162 = 39.44 m/s.
*October 9, 2013*

**physics**

P = F * d/t = mg * d/t P = 4.01*9.8 * 0.21/24 = 0.3439 J/h = 9.6*10^-5 J/s.
*October 9, 2013*

**math**

V = Vo + a*t = 0 30 - 4*t = 0 -4t = -30 t = 7.5 s. _
*October 9, 2013*

**6th grade math**

3 3/4 = 15/4. Wires=100in/(15/4) = 100 * 4/15 = 26 2/3 2/3 * 3 3/4 = 2/3 * 15/4 = 2.5 Inches left over. So we have 26-3 3/4 inch wires with 2.5 inches left over.
*October 8, 2013*

**Physics**

a. V = 343 m/s. b. L = V/F = 343/20 = 17.15 m.
*October 8, 2013*

**physics**

See previous post:Tue,10-8-13,5:11 PM.
*October 8, 2013*

**physics**

Fr = Y/sinA = 8.9/sin30 = 17.8 N.[30o]
*October 8, 2013*

**physics**

(Fr)^2 = 9.93^2 + 1.23^2 = 100.1 Fr = 10.0 N. = Resultant force. a = Fr/m = 10/3.02 = 3.31 m/s^2.
*October 8, 2013*

**physics**

V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g = (0-16^20/3.24=79 m.
*October 7, 2013*

**Business Math**

I = Po*(r/360)*d = 15 740*(r/360)*59days = 15 121.3r = 15 r = 0,1237 = 12.37%.
*October 7, 2013*

**physics**

See previous post:7:33 PM
*October 7, 2013*

**physics**

Range = Vo^2*sin(2A)/g = 63 m. Vo^2*sin(76)/9.8 = 63 0.0990Vo^2 = 63 Vo^2 = 636.3 Vo = 25.23 m/s[38o]
*October 7, 2013*

**Physics**

F = m * g = 2.5kg * 9.8N/kg = 24.5 N. d = (24.5N/50N) * 1m = 0.49m. = 49 cm. End of spring = 21 + 49 = 70 cm.
*October 7, 2013*

**physics**

V=Vo + g*t = -0.60 + 9.81*2.8=26.87 m/s d = Vo*t + 0.5g*t^2 d = -0.60*2.8 + 4.9*2.8^2 = 36.74 m below the pelican.
*October 7, 2013*

**Science**

F2 = F1 = m * g = 1kg * 9.8N/kg = 9.8 N. F1 = Force of the book. F2 = Force of ihe table. The 2 forces are equal and opposite.
*October 7, 2013*

**math**

P = 5*((3x) + (2x+2) + (5x-3) + (2x+2)) P=5*(3x+2x+2+5x-3+2x+2)=5*(12x+1)=60x+5
*October 7, 2013*

**Business Math**

I = Po*(r/360)*d I = 2500*(0.1175/360)*136days = $110.97 AMT. = 2500 + 110.97 = $2610.97
*October 7, 2013*

**physics**

X = 30 km/h Y = 5 km/h V^2 = 30^2 + 5^2 = 925 V = 30.4 km/h
*October 7, 2013*

**chemistry**

An aqueous solution of glucose is made by disolving 8.75 g of glucose in 100 mL of water. Calculate molarity, molality and the mole fraction
*October 7, 2013*

**Algebra**

Eq1: 3x-2y+2z = 30 Eq2: -x+3y-4z = -33 Eq3: 2x-4y+3z = 42 Multiply Eq1 by 2 and add Eq1 and Eq2: 6x-4y+4z = 60 -x+3y-4z = -33 Eq4:5x-y = 27 = Sum. Multiply Eq2 by 3 and Eq3 by 4 and add Eq2 and Eq3: -3x+9y-12z = -99 8x-16y+12z = 168 Eq5: 5x-7y = 69 Multiply Eq4 by -1 and add ...
*October 7, 2013*

**science physics**

a = (V-Vo)/t a = (12-4)/4 = 2 m/s^2.
*October 7, 2013*

**physics**

d = 26.2/cos25 = 28.91 m. = Distance the boat must travel to reach shore. T = d/r = 28.91m./4.5m/s = 6.42 s.
*October 7, 2013*

**physics**

T = d/r = 93Ft/2Ft/s = 46.5 s. To ride 93 Ft. V = d/T = 12Ft/46.5s. = 0.258 Ft./s.
*October 6, 2013*

**Physics**

Vo = 12m/s[20o] Xo = 12*cos20 = 11.28 m/s. Yo = 12*sin20 = 4.10 m/s. Y = Yo + g*Tr = 0 @ max. ht. 4.10 - 9.8Tr = 0 -9.8Tr = -4.10 Tr = 0.419 s. = Rise time. Tf = Tr = 0.419 s. T = Tr + Tf = 0.419 + 0.419 = 0.838 s.= Time in air.
*October 6, 2013*

**physics**

Vo = 26.9m/s[63.2o] Xo = 26.9*cos63.2 = 12.13 m/s. Yo = 26.9*sin63.2 = 24.01 m/s. Y^2 = Yo^2 + 2g*h h = (Y^2-Yo^2)/2g = (0-24.01^2)/-19.6 = 29.41 m.
*October 6, 2013*

**Physics**

h = Vo*t + 0.5g*t%2 = 45 m. h = 4.9t^2 = 45 t^2 = 9.18 Tf = 3.03 s. = Fall time. Dist. = Xo * Tf = 35 m. Xo * 3.03 = 35 Xo = 11.55 m/s = Hor. component of initial velocity. Yo = 0.
*October 6, 2013*

**Physics**

a. h1 = V1*t + 0.5g*t^2 h1 = 11*1 - 5*1^2 = 6 m. Head start. V^2 = V1^2 + 2g*h V^2 = 11^2 - 20*6 = 1 V = 1.0 m/s. h2=V2*t + 0.5g*t^2 = 6 + V*t + 0.5g*t^2 16*t - 5*t^2 = 6 + 1*t - 0.5g*t^2 The 0.5g*t^2 terms cancel: 16t - t = 6 15t = 6.0 t = 0.4 s. to catch up.
*October 6, 2013*

**physics**

V = 22m/s[-40.3o] Xo = 22*cos(-40.3) = 16.78 m/s. = Hor. component of initial velocity. Y = 22*sin(-40.3) = -14.23 m/s. Xo * Tf = 62.3 m. 16.78 * Tf = 62.3 Tf = 3.71 s. = Fall time. Y = Yo + g*Tf = -14.23 m/s. a. Yo + 9.8*3.71 = -14.23 Yo + 36.38 = -14.23 Yo = -14.23 - 36.38...
*October 5, 2013*

**Physics**

You didn't give all of the INFO. Density = m/V = 50kg/1m^3 = 50kg/m^3
*October 5, 2013*

**physics**

1. V = a*t = 1.8m/s^2 * 4.5s. = 8.1 m/s. X = 6.1 m/s. Y = 8.1 m/s. tan A = Y/X = 8.1/6.1 = 1.32787 A = 53o = Direction. 2. V = Y/sinA = 8.1/sin53 = 10.14 m/s.
*October 5, 2013*

**physics**

Vo = 20m/s[35o] Xo = 20*cos35 = 16.38 m/s. Yo = 20*sin35 = 11.47 m/s. a. Tr = (Y-Yo)/g = 0-11.47/-10=1.147 s = Rise time. h = Yo*t + 0.5g*t^2 = hmax = 11.47*1.147 - 5*1.147^2 = 6.58 m h = 0.5g*t^2 = 6.58-6 = 0.58 m. 5t^2 = 0.58 t^2 = 0.116 Tf = 0.341 s. = Fall time. Range=Xo*(...
*October 5, 2013*

**Physics**

a. Wr = m * g = 500kg * 9.8N/kg = 4900 N. b. a=Fn/m = (13500-4900)/500=17.2 m/s^2
*October 5, 2013*

**physics**

V^2 = Vo^2 + 2g*h Vo^2 = -2g*h = -2*-9.8*107 = 2097.2 Vo = 45.8 m/s. V = Vo + gt = 0 @ max. ht. Tr = (V-Vo0/g = (0-45.8)/-9.8 = 4.67 s. = Rise time. Tf = Tr = 4.67 s. = Fall time. T = Tr + Tf = 4.67 + 4.67 = 9.35 s. = Time in air.
*October 5, 2013*

**physics**

Wb = m * g = 74kg * 9.8N/kg = 725.2 N. = Weight of box. Fs = u * Wb = 1.1 * 725.2 = 797.7 N. = Force of static friction.
*October 4, 2013*

**Physics**

a=F/m = (4*415)/140,000=0.011857 m/s^2
*October 4, 2013*

**math**

Cost = $2375 * 0.85 * 0.80 * 0.80=$1292 Discount = 2375 - 1292 = $1083.
*October 4, 2013*

**science**

V2 = 1000 * 380/760 * 25/50 e. None of these.
*October 4, 2013*

**PHYSICS**

Wc = m * g = 200 N. m * 9.8 = 200 m = 20.41 kg. = Mass of crate. F = 55N.[35o.] 55*cos35 - Fk = m*a 45.05 - Fk = m*0 = 0 Fk = 45.05 = Force of kinetic friction. u = Fk/Wc = 45.05/200 = 0.225
*October 3, 2013*

**PHYSICS**

Wb = m * g = 100kg * 9.8N/kg = 980 N. F1 = 980*sin15 = 253.6 N. = Force parallel to the ramp. F2 = 980*cosi5 = 946.6 N. = Force perpendicular to the ramp. Fs = F1 = 253.6 N. @ 15o u = Fs/F2 = 253.6/946.6 = 0.268
*October 3, 2013*

**PHYSICS**

Ws = m*g = 150 N. = Weight of sled. m = 150/g = 150/9.8 = 15.31 kg. F1 = 150*sin28 = 70.42 N. = Force parallel to the slope. F2 = 150*cos28 = 132.4 N. = Force perpendicular to the slope. a = F1/m = 70.42/15.31 = 4.60 m/s^2.
*October 3, 2013*

**physics**

W1 = m * g = 10kg * 9.8N/kg = 98 N. = Wt. 0f m1. Fs = u * mg = 0.69 * 98 = 67.62 N. = Force of static friction. m2 * g = Fs = 67.62 N. m2 * 9.8 = 67.62 m2 = 6.9 kg.
*October 3, 2013*

**physics**

Vo = 15.4m/s[38.7o] Xo = 15.4*cos38.7 = 12 m/s. Yo = 15.4*sin38.7 = 9.63 m/s. Range = Vo^2*sin(2A)/g Range = 15.4^2*sin(77.4)/9.8 = 23.62 m. Range = Xo * T = 23.62 m. Range = 12 * T = 23.62 T = 1.97 s. in air. d=Vr * T = 23.62-17.7 = 5.92 m. to run. Vr * 1.97 = 5.92 Vr = 3.0 m...
*October 3, 2013*

**Physics**

See 11:48 PM post.
*October 2, 2013*

**Physics**

A. h = 0.5g*t^2 = 0.809 m. 4.9t^2 = 0.809 t^2 = 0.1651 t = 0.4063 s. Xo * t = 18.3 m. Xo * 0.4063 = 18.3 Xo = 45 m/s. = Velocity of the pitch. B. h = 0.5g*t^2 = 5.4 m 4.9*t^2 = 5.4 t^2 = 1.1 Tf = = 1.05 = Fall time of each vessel. Ds = Xo * Tf = 15m/s * 1.05s. = 15.75m. = Dist...
*October 2, 2013*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*26.8 = 525.28 V = 22.92 m/s.
*October 2, 2013*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 20*500 = 10,000 V = 100 m/s.
*October 2, 2013*

**physics**

You did not give the angle for F2.
*October 2, 2013*

**Physics**

u * F = 7.01 N. 0.44 * F = 7.01 F = 15.93 N.
*October 2, 2013*

**Intermediate Algebra**

4x^2 + x - 1. Use Quadratic formula. X = (-B +-Sqrt(B^2-4AC))/2A X = (-1 +-Sqrt(1+16))/8 X = (-1 +-Sqrt(17))/8 X = (-1 +- 4.12)/8 = 0.39, and -0.64
*October 2, 2013*

**Intermediate Algebra**

11 1/2 * 11^3 = 23/2 * 11^3 = 23/2 * 1331 = 15,306.5
*October 2, 2013*

**Physics**

a. Wr = m * g = 56kg * 9.8N/kg = 549. N = Weight of refrigerator. Fs = u*Wr = 0.7 * 549 = 384 N. = Force of static friction which points in the +x direction. b. F = -384 N.
*October 2, 2013*

**Math**

X = The # of $10 bills. 3X = the # of $5. bills. 3x+30 = The # of $1 bills. 10x + 5*3x + 1*(3x+30) = 170 10x + 15x + 3x + 30 = 170 28x = 140 X = 5-$10 bills. 3x = 3*5 = 15-$5 bills. 3x+30 = 3*5 + 30 = 45-$1 bills.
*October 1, 2013*

**physics**

a. Wt. = m * g 25kg * 9.8N/kg = 245 N. F1 = Force parallel to the incline. F2 = Force perpendicular to the incline. Q1. F1 = 245*sinA = u*F2 245*sinA = 0.45*245*cosA Divide both sides by 245*cosA: sinA/cosA = 0.45 Replace SinA/cosA with tanA: tanA = 0.45 A = 24.2o = Angle of ...
*October 1, 2013*

**physics**

V^2 = X^2 + Y^2 V^2 = 3.8^2 + 1,6^2 = 17 V = 4.12 m/s
*October 1, 2013*

**math**

I = Po*r*t = 17,000*0.025*5 = $2125
*October 1, 2013*

**Physics**

Correction: h = (0-20^2)/-19.6 = 20.4 m.
*October 1, 2013*

**Physics**

1. KE = 0.5m*V^2 = 5*20^2 = 2000 Joules 2. V^2 = Vo^2 + 2g*h = h = (V^2-Vo^2)/2g h = (0-20^20/-19.6 = 20.4 m.
*October 1, 2013*

**interest**

I = Po*r*t = 400 Po*(8.5/360)*30days = 400 0.70833*Po = 400 Po = $564.71 4564.71.
*September 30, 2013*

**Physics**

a. T=290km/81km/h + 210km/80km/h + 25/60 = 6.62 h. b. V = d/T = (290+210)/6.62 = 75.5 km/h.
*September 30, 2013*

**MATH**

P = Po + Po*r*t P = 675 + 675*0.1925*1 = $804.94
*September 30, 2013*

**Geometry**

Incomplete.
*September 29, 2013*

**math**

b. Amt. = 600*3 + 3200 = $5000 To start with. c. $3200/$ = 600 = 5.3 Months
*September 29, 2013*

**Physics**

h = 1.94*sin27.5 = 0.896 m. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*0.896 = 17.56 V = 4.19 m/s.
*September 29, 2013*

**physics**

See previous post: Sun,9-29-13,4:54 PM.
*September 29, 2013*

**physics**

a. V = Vo + g*t = 19 m/s. 39 - 9.8*t = 19 -9.8t = 19-39 = -20 t = 2.04 s. b. V = Vo + g*t = -19 m/s. 39 - 9.8t = -19 -9.8t = -58 t = 5.92 s.
*September 29, 2013*

**physics**

a. V^2 = Vo^2 + 2a*d a=(V^2-Vo^2)/2d = (15^2-0)/250=0.9 m/s^2 b. V = Vo + a*t t = (V-Vo)/a = (15-0)/0.9 = 16.67 s.
*September 29, 2013*

**physics**

Tr = 0.5 * 4.84 = 2.42 s. = Rise time. V = Vo + g.t = 0 @ max ht. Vo - 9.8*(2.42) = 0 Vo = 23.72 m/s. = Initial velocity. h = Vo*t + 0.5g*t^2 h = 23.72*2.42 - 4.9*2.42^2 = 28.7 m.
*September 29, 2013*

**physics**

See previous post.
*September 29, 2013*

**physics**

a. F = 7 + 10 = 17 N. b. F = 10-7 = 3 N. c. F1 = 7N[45o]. F2 = 10N[105o]. X = 7*cos45 + 10*cos105 = 2.36 N. Y = 7*sin45 + 10*sin105 = 14.6 N. tanA = Y/X = 14.6/2.36 = 6.18644 A = 80.8o Fr=Y/sinA = 14.6/sin80.8=14.8 N.[80.8o] = Resultant force. d. Fr = 7[160o] + 10[160o] = 17N[...
*September 29, 2013*

**Grade 12 physics**

F1 = 15N[66o],CCW. F2 = Pull South. F3 = Pull West. a. X = 15*cos66 + F3 = 0 F3 = -15*cos66 = -6.10 N. Y = 15*sin66 + F2 = 0 F2 = -15*sin66 = -13.7 N. b. X = 15*cos66-6.10 = 0 Y = 15*sin66 = 13.7 N.=13.7N Fn = X + Yi = 0 + Yi = 13.7i=13.7N[90o]
*September 29, 2013*

**physics**

Fa + Fb + Fc = 2.33N[S12.2W]
*September 29, 2013*

**physics**

Fa = 2.3N[235o],CCW. Fb = 3.6N[104o],CCW. Fc = 4.2N[294o],CCW. X=2.3*cos235+3.6*cos104+4.2*cos294 = -0.482 N. Y=2.3*sin235+3.6*sin104+4.2*sin294= -2.28 N. tan Ar = Y/X = -2.28/-0.482 = 4.62215 Ar = 77.8o = Reference angle. A = 77.8 + 180 = 257.8o CCW = 12.2o W of S. Fr = Y/...
*September 29, 2013*

**maths**

P = Po(1+r)^n n = 4Comp./yr * 5yrs. = 20 Compounding periods. P = 10,000(1+r)^20 = $20,000 Divide both sides by 10,000: (1+r)^20 = 2 Take Log of both sides: 20*Log(1+r) = Log 2 Divide both sides by 20: Log(1+r) = 0.015051 1+r = 10^0.015051 = 1.035265 r = 1.035265-1 = 0.035265...
*September 29, 2013*

**Physics**

a. 8.1[52o] + 8[180o] X = 8.1*cos52 + 8*cos180 = 4.99 Units Y = 8.1*sin52 + 8*sin180 = 6.38 Units. Mag. = Sqrt(4.99^2+6.38^2 = 8.1 Units tanA = Y/X = 6.38/4.99 = 1.27856 A = 51.97o = Direction. b. 8.1[52o] - 8[180o] Subtract and use same procedure as "a".
*September 29, 2013*

**physics**

Vf = 3.2m/s + 0.68*8 = 8.64 m/s.
*September 28, 2013*

**physics**

Incomplete.
*September 28, 2013*

**physics**

h = 168 - 0.5g*t^2 h = 168 - 4.9*2.24^2 = 143.4 m
*September 28, 2013*

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