# Posts by henry

Total # Posts: 13,448

**Calculus**

A particle moves along the x-axis with velocity v(t) = sin(2t), with t measured in seconds and v(t) measured in feet per second. Find the total distance travelled by the particle from t = 0 to t = π seconds. Do I have to take the integral of the equation like ∫ sin(...

**Calculus**

f(x) and g(x) are a differentiable function for all reals and h(x) = g[f(2x)]. The table below gives selected values for f(x), g(x), f '(x), and g '(x). Find the value of h '(1). (4 points) x 1 2 3 4 5 6 f(x) 0 3 2 1 2 0 g(x) 1 3 2 6 5 0 f '(x) 3 2 1 4 0 2 g &#...

**Math Fractions**

Total = X pages. Monday: 1/6 * x = x/6 Pages read. x-x/6 = 6x/6 - x/6 = 5x/6 Remaining. Tuesday: 2/5 * 5x/6 = x/3 Pages read. 5x/6 - x/3 = 5x/6 - 2x/6 = 3x/6 Remaining. Wednesday: 1/3 * 3x/6 = x/6 Pages read. 3x/6 - x/6 = 2x/6 = x/3 Remaining. x/3 = 60, X = 180 Pages.

**physcis**

a. V = Vo + g*Tr = 0, Tr = -Vo/g = -20/-32 = 0.625 s. = Rise time. Tf = Tr = 0.625 s. = Fall time from max ht. to top of bldg. h = Vo*T + 0.5g*T^2. h = 60 Ft., Vo = 20 Ft/s, g = 32 Ft/s^2, T = ?. Tr+Tf+T = Time to reach gnd. b. V^2 = Vo^2 + 2g*h. Vo = 20 Ft/s, g = 32 Ft/s^2, h...

**Calculus**

Compare the rates of growth of f(x) = x + sinx and g(x) = x as x approaches infinity. f(x) grows faster than g(x) as x goes to infinity. g(x) grows faster than f(x) as x goes to infinity. f(x) and g(x) grow at the same rate as x goes to infinity. The rate of growth cannot be ...

**Calculus**

Which of the following functions grows the fastest as x goes to infinity? 3^x ln(x) e^4x x^10 I put e^4x but I thought that 3^x might have been it too. I know for sure that it is not ln(x) and x^10 because those grow much slower.

**Calculus**

Which of the following functions grows the slowest as x goes to infinity? x^e e^x ex they all grow the same rate. I think it is c because it does not have any exponents.

**Calculus**

The graph of f ′(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is false? (4 points) The graph of f has an inflection point at x = 0. The graph of f has a relative maximum at x = 0. The graph of f is always concave down. ...

**Physics**

Oops!! Please disregard my first post. First Student: Xo = Cos60.34 = 0.4949 Yo = sin60.34 = 0.8690 Y = Yo + g*Tr = 0, Tr = -Yo/g = -0.8690/-9.8 = 0.0887 s. = Rise time. Tf = Tr = 0.0887 s. T = Tr+Tf = 0.0887 + 0.0887 = 0.1774 s. = Time in air. Dx = Xo*T = 0.4949 * 0.1774 = 0....

**Physics**

Xo = Cos60.34 = 0.4949 Yo = sin60.34 = 0.8690

**physics**

M1*V1 + M2*V2 = M1V + M2*V. 3250*44 - 1500*17 = 3250V + 1500V. V = ? Direction: North.

**electronics**

Normally, the zener is connected in parallel with the load; it tends to maintain a constant voltage across the load. The zener is protected by a series resistor through which the zener and load current flows. If the load is removed, all of the current flows through the zener ...

**electronics**

1. The voltage dropped across the diodes might not be equal or the voltages from the center-tapped transformer might not be equal. Therefore, you could have a defective transformer or diode. 2.In cases where there are large variations in the input voltage and the load, a zener...

**Math**

The errors in your problem makes it difficult to understand.

**Algebra**

(T1+T2+T3)/3 = 19, T1+T2+T3 = 3*19 = 57. (57+T4)/4 = 21, T4 = 27 Degrees.

**Physical Science**

F = M*a = 100,000-82,000 = 18000, 30,000*a = 18000, a = 0.6 m/s^2.

**Math**

My answer is B.

**Physics**

Energy = 0.5C*V^2 = 0.5*14.1*45^2 = 14,276 uJ. = 0.01428 J. Energy = 0.5*14.1*V^2 = 0.001428, V^2 = 2.03*10^-4, Vc = 1.425 Volts when 90% of it's energy is lost. 45/e^x = 1.425, e^x = 31.6, X = 3.45 = t/RC = t/1.13, 1.13*3.45 = 3.90 mS. = 3.90*10^-3 s. = Time to loose 90% ...

**Physics**

T = R*C = 0.08k * 14.1uF = 1.13 Milliseconds. a. 45/e^x = 4.5, e^x = 45/4.5 = 10, X = 2.303 = t/T = t/1.13, t = 1.13 * 2.303 = 2.60 mS = 2.6*10^-3 s. b. i = v/R = 4.5/80 = 0.056 Amps.

**Physics**

T1 = 460.8N.[68.9o] N. of W. a. -T1*Cos68.9 = -T2*Cos33.8, -T2 = -T1*Cos68.9/Cos33.8, T2 = 0.433T1 = 0.433*460.8 = 199.6 N.[33.8o]. b. Y = 460*sin68.9 + 199.6*sin33.8 = 540.2 N. M*g = 540.2, M = 540.2/9.8 = 55.12 kg.

**Math/Finance**

Assuming simple interest. P = Po + Po*r*t = 4000. 2000 + 2000*r*2 = 4000. r = APR expressed as a decimal.

**Physics**

d = 27.8 * 20 = 556 m. Head start. 0.5a*t^2 = 556 + 27.8t. 1.5t^2 = 556 + 27.8t. 1.5t^2 - 27.8t - 556 = 0. t = Time required for B to catchup. 0.5a*t^2 = Distance at which B catches up.

**Physics**

a. db = 10*Log(I/Io) = 130. 10*Log(I/10^-12) = 130. Log(I/10^-12) = 13. I/10^-12 = 10^13. I = 10 W/m^2. b. db = 10*Log(20/10^-12) = 133. Doubling the sound intensity increases the sound level by only 3 db.

**physics**

Incomplete.

**SCIENCE**

Incomplete.

**Math**

I chose b also.

**Math**

1. Correct. 2. Correct.

**Basic electricity**

The given units are incorrect.

**science**

20 minutes per hour makes no sense. So let's assume: Vo = 20m/s[53o]. Xo = 20*Cos53 = 12.0 m/s. Yo = 20*sin53 = 16.0 m/s. a. Y = Yo + g*Tr = 0, 16 - 9.8*Tr = 0, -9.8Tr = -16, Tr = 1.63 s. = Rise time. Tf = Tr = 1.63 s. = Fall time. T = Tr+Tf = 1.63 + 1.63 = 3.27 s. = Time ...

**MATH HELP**

My answer is b.

**Math College Algebra (urgent before 2hours)**

The zero of a function is the value of X when Y or F(x) = 0. In other words it is the solution to the function. Example: Y = 2x + 4 = 0, 2x = -4, X = -2. So x = -2 when y = 0: (-2,0). 2. g(y) = y^2-3y+2 = 0, C = 2 = (-1)*(-2), Sum = B = -3. (y-1)(y-2) = 0, y-1 = 0, Y = 1, y-2...

**Science**

10o W. of N. = 100o CCW. 10o E. of N. = 80o CCW. Fr = 1.8*10^6[100o] + 1.8*10^6[80o]=-3.126*10^5+1.773*10^5i + 3.126^10^5+1.773*10^5i = 3.546*10^5i = 3.546*10^5[90o] = 3.546*10^5N., Due North. = Resultant force. Work = Fr*d = 3.546*10^5 * 500 =

**science**

F1 = 15N[0o], F2 = 20N[135o]. F1+F2 = 15 + -14.1+14.1i = 0.9 + 14.1i = 14.2 N.[86.4o] = 0.89 + 14.18i F3 must be equal to F1+F2 in magnitude and 180o out of phase: F3 = 14.2N[86.4+180] = 14.2[266.4o].= 14.2[86.4o] S. of W. = -0.89 - 14.18i

**Physics**

a. Work = Change in kinetic energy: Work = 0.5M*V^2-0.5M*Vo^2, Vo = 0, Work = 0.5M*V^2 = 0.5*845*25^2 = 264,063 J. Po = W/t = 264063/60 = 4401 J/s. = 4401 Watts = Power out. Pi = 4401/0.95 = 4633 Watts = Power in. Pi = 12*I = 4633, I = 4633/12 = 386 Amps.

**Maths**

r = 35/4 = 8 3/4% = 8.75% = 0.0875. I = Po*r*t = 3000*(0.0875/12)*14 = 90.0875*

**Physics**

1. V^2 = Vo^2 + 2g*h. Vo = 0, g = 9.8 m/s^2, h = 80 m, V = ?. 2. 0.5g*t^2 = 80. g = 9.8 m/s^2, t = ?.

**Physics**

Wc = M*g = 35*9.8 = 343 N. Fp = 343*sin26 = 150.4 N. = Force parallel to the incline. Fn = 343*Cos26 = 308.3 N. = Normal. Fp-Fk = M*a. 150.4-0.33*308.3 = 35*a. 35a = 48.66. a = 1.39 m/s^2. V = Vo + a*t = 0 + 1.39*2.5 = 3.48 m/s.

**physics**

V^2 = Vo^2 + 2g*h, V = 0, Vo = 5m/s, g = -10m/s^2, h = ?.

**physics**

177 + 0.00506(T-28.7)177 = 116. 177 + 0.8956(T-28.7) = 116. 177 + 0.8956T-25.7 = 116. 0.8956T + 151.3 = 116. 0.8956T = 116-151.3 = -35.3. T = -39.4oC.

**physics**

F = M*a, F = 37.5 N, a = 2.80 m/s^2, M = ?.

**Cal 2**

The region bounded by y=3/(1+x^2), y=0, x=0 and x=3 is rotated about the line x=3. Using cylindrical shells, set up an integral for the volume of the resulting solid. The limits of integration are:

**Biology**

How are the following terms related to the process of transcription and one another? Eukaryotes, Prokaryotes, membrane-bound nucleus, introns, exons, precursor RNA (pre-mRNA), mature RNA, heterochromatin, euchromatin, and structural gene.

**geometry**

Or 7.5/7 = x/18, X = ?.

**physics**

Vector V1: Vx = -6.5 units. Vy = 0. Vector V2: V = 8.3[60o] Vx = 8.3*Cos60 = Vy = 8.3in60 = V1 + V2 = -6.5 + 8.3[60] = -6.5 + 4.15+7.19i = -2.35 + 7.19i = 7.56[71.9o] N. of W. = 108o CCW

**physics**

Do you mean constant velocity? If so, d = V*t, t = d/V.

**physical science**

d = 0.5a*t^2. d = 10 m, t = 45 s, a = ?.

**mathematics**

David: X years old. John: x+4 years old. Joe: x-2 years old. x + x+4 + x-2 = 41. Solve for x and add 8 years to John's age.

**Pysics**

D = -400 + 200[135o] + 100i = -400 - 141.4+141.4i + 100i = -541.4 + 241.4i = 593 km[24o] N. of W.

**Science**

1. V = Vo + a*t. V = 3.2 m/s, Vo = 1.2 m/s, t = 2.5 s, a = ?. 2. V = Vo + a*t. V = 34 m/s, Vo = 0, t = 2.5 s, a = ?. d = 0.5a*t^2. 3. r = 30m/4.2s. = 4. d = r*t, t = ?.

**Math**

The simplification process starts inside the expression: ((3x)^4/(6x)^3)^2 = (81x^4/216x^3)^2 = (3x/8)^2 = 9x^2/64.

**Math**

Y = 3x. 3 = The number of wheels per tricycle. X = The number of tricycles. Y = The total number of wheels to be ordered.

**math**

15, 5, 3, 0.8, -5.

**Math**

Po*e^(rt) = 2Po. Divide both sides by Po: e^rt = 2. rt = 0.08t. e^0.08t = 2. 0.08t*Log e = Log 2. 0.08t = Log2/Log e = 0.693 t = 8.7 yrs.

**math**

a. Tan 24 = h/500, h = ?. b. Tan 27 = (h+L)/500. L = Length of flag = ? h = Ht. of bldg. calculated in part a.

**physics**

See previous post: Mon, 2-8-16, 7:33 PM.

**science**

30kW = 30 kJ/s. Work = 30kJ/s * 15s = 450 kJ.

**Calculus 2**

Sketch the region in the first quadrant enclosed by y=7/x, y=2x, and y=x/2. Decide whether to integrate with respect to x or y. Then find the area of the region.

**physics**

a. Vr = -100i + 70km[330o] = -100i + 60.6-35i = 60.6 - 135i = 148km[65.8o] S. of E = 24.2o E. of S. = Resultant velocity of the goose. Do you mean 20o W. of S.? If so, Direction = 24.2 + 20 = 44.2o W. of S. b. d = V*t = 1000, t = 1000/V = 1000/148 = 6.76 h.

**SIMPLE INTEREST**

I = Po*r*t = 5000*0.04*2 = $400. (25/4)% = 6.25%. I = 5000*0.0625*2 = $625. Gain = (625-400)/2yrs. = $112.50 per year.

**SIMPLE INTEREST**

I = Po*r*t = 0.125Po. Po*0.1*t = 0.125Po. t = 1.25 yrs. = 15 Months.

**SIMPLE INTEREST**

I = Po*r*t = 1344-1200. Po = 1200, r = 0.06, t = ?.

**SIMPLE INTEREST**

I = Po*r*t = 1770. r = 0.08 t = (15/2)yrs. = 7.5 yrs. Po = ?.

**SIMPLE INTEREST**

There are errors in your problem; please make corrections.

**science**

Sketch: From a point, draw 2 arrows pointing upward and one arrow pointing downward.

**science**

Fr = 5.3 + 2.2 - 10.7 = -3.2 N. = 3.2 N. downward.

**Engineering**

Mass = 0.00072kg/cm^3 * 37854cm^3/gal * 5gal. = 136.3 kg.

**physics**

h = V*t + 0.5g*t^2 = 2 m. V*0.1 + 4.9*0.1^2 = 2. 0.1V = 2-0.049 = 1.95. V = 19.5 m/s at top of the window. V^2 = Vo^2 + 2g*h. V = 19.5 m/s, Vo = 0, g = 9.8 m/s^2, h = ?.

**Finance**

P = Po(1+r)^n. P = $16,860. r = 5.75%/100 = 0.0575 n = 1Comp./yr. * 6yrs. = 6 Compounding periods. Po = ?.

**science**

a. h = 0.5g*t^2. h = 20 m., g = 9.8 m/s^2. t = ?. b. d = 10m/s * t. t = Value calculated in part "a".

**physics**

a. V^2 = Vo^2 + 2g*h = 0. Vo^2 = -2g*h = -(-19.6)*0.18 = 3.53, Vo = 1.88 m/s. b. KE = 0.5M*Vo^2 = 0.5*0.54*10^-6*1.88^2 = 9.54*10^-7 Joules.

**Physics**

Xo = 2.9 m/s. Tan 43.6 = Y/Xo = Y/2.9. Y = 2.9*Tan 43.6 = 2.76 m/s. V^2 = Vo^2 + 2g*d = 2.76^2. 0 + 19.6d = 7.63, d = 0.389 m. h = 1.14 - 0.389 = 0.751 m. Above the floor.

**physics**

See previous post: Thu,2-4-16, 11:20 AM.

**Physics**

Oops! The name is Henry.

**science**

V^2 = Vo^2 + 2g*h. Vo = 0, g = 9.8 m/s^2, h = 80 m. V = ?.

**Physics**

Xo = 19.8 m/s. Yo = 16.4 m/s. a. Y = Yo + g*Tr = 0, Tr = -Yo/g = -16.4/-9.8 = 1.67 s. = Rise time. b. h = Yo*Tr + 0.5g*Tr^2. g = -9.8 m/s^2. c. T = Tr+Tf, Tf = Tr = 1.67 = Fall time. T = Tr+Tr = 1.67 + 1.67 = d. T = 2Tr. e. d = Xo*T.

**physics**

0.5g*t^2 = 25 m. 4.9*t^2 = 25, t^2 = 5.1, t = 2.26 s. Y = Yo + g*t = 0 + 9.8*2.26 = 22.1 m/s. = Ver. component of final velocity. V = 16 + 22.1i = 27.3m/s[54.1o].

**physics help please**

See previous post: Thu, 2-4-16, 10:47 PM.

**physics**

See previous post: Wed, 2-3-16, 11:49 AM.

**Math**

1. 12.5/10.5 = 1.190 = 119%. 119%-100% = 19% Increase. 2. 71.4/80.2 = 0.890 = 89.0% 89%-100% = -11% = 11% Decrease.

**maths**

X votes. x+300 Votes. Total = x + x+300 = 2x+300. x/(2x+300) = 0.4 x = 0.8x + 120 0.2x = 120. X = 600. Total = 2x+300 = 2*600 + 300 = 1500 votes.

**physics**

Energy = P*t = 6*0.5 * 5/60 = 0.25 Watt-hours.

**Physics**

L = V/F, F = V/L. The one with the shortest wavelength(2) has the highest freq. or pitch.

**physics**

C = pi*2r = 3.14 * 40 = 125.6 cm. A = 360o/125.6cm * 30cm = 86o.

**Physics**

Vo = 10.1m/s[62.4o]. Yo = 10.1*sin62.4 = 8.95 m/s. Y^2 = Yo^2 + 2g*h. Y = 0, g = -9.8 m/s^2, h = ?.

**Math**

d = r*t = 40 * 3 = 120 mi. d = 60 * T =120, T = 120/60 = 2 h.

**Physics**

Unless otherwise stated, all angles are measured CCW from +x-axis. a. F=267[23o] - 377=245.8+104.3i - 377 = -131.2 + 104.3i = 168N[38.5o]N. of W. b. F3 and F should be equal in magnitude and 180o out of phase: Therefore, F3 = 168N[38.5o]S. of E.

**physic**

Oops! Disregard last line of this post.

**physic**

Vo = 15m/s[35o]. Yo = 15*sin35 = 8.60 m/s. Y = Yo + g*Tr = 0, Tr = -Yo/g = -8.60/-9.8 = 0.88 s. = Rise time. h1 = Yo*Tr + 0.5g*Tr^2. h1 = 8.60*0.88 - 4.9*0.88^2 = 3.77 m. Above top of bldg. Tr+Tf = 2.7, Tf = 2.7-Tr = 2.7-0.88 = 1.82 s. = Fall time from max ht. to gnd. h2 = 0....

**physic**

Tr = Rise time, Tf = Fall time. a. Tr + Tf = 2 s, Tf = Tr, Tr+Tr = 2, 2Tr = 2, Tr = 1 s. V = Vo + g*Tr = 0, Vo = -g*Tr = 9.8*1 = 9.8 m/s. b. Yo = 9.8 m/s(Part a), Vo*sin40 = 9.8, Vo = 9.8/sin40 = 15.25 m/s.

**physics**

a. V = 205mi/h * 1600m/mi * 1h/3600s = 91.1 m/s. V = Vo + a*t. V = 91.1 m/s, Vo = 0, t = 2.70 s. a = ?. b. d = 0.5a*t^2. a = Value cal. in part "a", t = 2.70 s, d = ?.

**physics**

a. V^2 = Vo^2 + 2g*h V = 0, Vo = 19.0 m/s, g = -9.8 m/s^2, h = ? b. V = Vo + g*t. V = 0, Vo = 19.0 m/s,g = -9.8 m/s^2, t = ?.

**science**

100%-30% = 70% Below the surface. Db/Dw = 0.7, Db = 0.7Dw = 0.7*0.998 = 0.699 g/cm^3.

**SCIENCE**

Wo = F*d=M*g * d = 150*9.8 * 2.5 = 3675 J. = Work output or work done. Input = 3675/0.6, but it did not ask for the input.

**science**

M*V = 1.4, 0.7*V = 1.4, V = ?.

**math**

100%-8% = 92%. Cost = 0.92 * 968

**Physics**

See previous post: Tue, 1-26-16, 1:52 PM.

**Math**

See previous post.

**Math**

See previous post.

**Math**

-15x+3 >= -3(4x-7). -15x+3 >= -12x+21. -15x + 12x >= 21-3. -3x >= 18. X <= -6. When multiplying or dividing an inequality by a negative number, the inequality sign should be reversed.

**science(physics)**

a. Vo = 36000m/3600s. = 10 m/s. a = -(Vo^2)/2d = -(10^2)/80 = -1.25 m/s^2. b. F = M*a = 100 * (-1.25) = -125 N. The negative sign means the force opposes the motion.