Tuesday
June 28, 2016

Posts by henry

Total # Posts: 11,871

physics
See previous post: Mon. 4-6-15, 8:58 AM.
April 6, 2015

physics
V = Vo + a*t = 30 m/s 0 + a*20 = 30 a = 1.5 m/s^2 d = 0.5a*t^2 = 0.5*1.5*10^2 = 75 m.
April 6, 2015

Physics
V = g*t V = 20*1 = 20 m/s. V = 20*2 = 40 m/s. V = 20*3 = 60 m/s. Increase = 20 m/s with each second.
April 5, 2015

math
(1/2)/3 = 1/2 * 1/3 = 1/6 of the Half- pie. 1/2 * 1/6 = 1/12 of the whole pie.
April 4, 2015

physics
Momentum before the collision=Momentum after the collision: M1*V1 + M2*V2 = M1*V + M2*V 0.075*80 + 13*0 = 0.075*V + 13*V 6 + 0 = 13.075V V = 0.459 m/s
April 4, 2015

physics
M!*V1 + M2*V2 = M1*V + M2*V 0.075*80 + 13*0 = 0.075*V + 13*V 6 + 0 = 13.075V
April 4, 2015

Physics
M*g = 13 N. = Wt. of puck. M = 13/g = 13/9.8 = 1.33 kg. Fn = 13*cos37 = 10.4 N. Fk = u*Fn = 0.08 * 10.4 = 0.831 N. sin37 = h/3 h = 3*sin37 = 1.81 m. PE = Mg*h - Fk*d = 13*1.81 - 0.831*3 = 21.04 J. At bottom of ramp: KE = PE = 0.5*M*V^2 = 21.04 J. 0.5*1.33*V^2 = 21.04 V^2 = 21....
April 3, 2015

Physics
V^2 = Vo^2 + 2a*d = 0 + 2a*2pi = 4a*pi V = 2*sqrt(pi*a) = 2*1.772*sqrt a = 3.54*sqrt a
April 3, 2015

math
Sam has X stamps. Jill has (576-X) Stamps. X-x/7 = 6x/7 = Sam's bal. 576-x + x/7 = 576 - 6x/7 = Jill's bal. 1/4(576-6x/7) = 144 - 6x/28 3/4(576-6x/7) = 432 - 9x/14 = Jill's new bal. 6x/7 + 144-6x/28 = 144 + 24x/28-6x/28 = 144 + 9x/14 = Sam's new bal. Jill's...
April 2, 2015

Physics
M*g = 475 * 9.8 = 4655 N. P = F*d/t = Mg * d/t = 4655 * 10/24 = 1940 J/s = = 1940 W. = 1.94 kW
April 2, 2015

math help`
Any pair of parallel lines will have equal slopes. I don't know what you mean by "some is always -1".
April 2, 2015

math
Multiply Eq1 by -2 and add the Eqs: -4x + 6y = 4 +4x + y = 24 Sum: 7y = 28 Y = 4 In Eq1, replace Y with 4 and solve for X
April 2, 2015

algebra
d1 = d2 60 + 60t = 80t 20t = 60 t = 3 h.
April 2, 2015

Physics
When t = 0, X = 0-0 +6 = 6 m. When t = 3 s., X = 3^2 - 4*3 + 6 = 3 m. d = 6-3 = 3 m.
April 2, 2015

physics
See previous post: Wed, 4-1-15, 6:39 AM.
April 2, 2015

Physics
If they were wired in series, All lights will go out when one bulb burns out. Therefore, they are connected in parallel.
April 2, 2015

Physics 101
Correction: a = (Fp-Fk)/M = (122.6-63.65)/25 = 2.36 m/s^2
April 2, 2015

Physics 101
M*g = 25 * 9.8 = 245 N. = Wt. of the box Fp = 245*sin30 = 122.5 N. = Force parallel to the incline. Fn = 245*Cos30 = 212.2 N. = Force perpendicular to the incline. Fk = u*Fn = 0.30 * 212.2 N. = 63.65 N. = Force of kinetic friction. a = (Fp-Fk)/M*sin30 = (122.5-63.65)/12.5 = 4....
April 2, 2015

Finances
a. P = Po(1+r)^n Po = $600 r = 1.5%/100 = 0.015 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 2yrs. = 24 Compounding periods. Solve for P. Monthly Payment = P/24 a. Simple Interest: P = Po + Po*r*t = 600 + 600*0.015*24 Solve for P. Monthly payment = P/24 b. Same ...
April 1, 2015

Physic
V = Vo + a*t V = 6.5 m/s Vo = 0 t = 22 s. Solve for a. d = 0.5a*t^2 t = 22 s. Solve for d
April 1, 2015

Physic
V = Vo + a*t v = 22 m/s Vo = 5 m/s t = 18 s. Solve for a.
April 1, 2015

Physic
M*g = 637 N. g = 9.8 m/s^2 M = Mass in kg Solve for M.
April 1, 2015

Geometry
X = 3-2.5 = 0.5 m. Y = 1.5 m. Tan A = Y/X = 1.5/0.5 = 3.0 A = 71.57o Tan 71.57 = h/3 Solve for h.
April 1, 2015

math
See previous post: Tue, 3-31-15, 5:18 PM.
April 1, 2015

physics
M*g = 150 N = Wt. of the boy = Normal force(Fn). Fk = u*Fn = 0.05 * 150 = 7.5 N. = Force of kinetic friction. Fap-Fk = M*a Fap-7.5 = M*0 = 0 Fap = 7.5 N. = Force applied.
April 1, 2015

algebra
V = Vo + g*t = 128 - 32*2 = 64 Ft/s after 2 s. V = 128 - 32*4 = 0 After 4 s. Vavg = (0+4)/2 = 2 Ft/s
April 1, 2015

precalculus
U(3,1), V(6,-1) A. Tan A = (-1-1)/(6-3) = -2/3=-0.66666 A = -33.7o = 33.7 S. of E.
March 31, 2015

business math
P = Po(1+r)^n Po = $8,500 r = (6/4)/100 = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 12yrs. = 48 Compounding periods. Solve for P. I = P-Po
March 31, 2015

Physics
Incomplete.
March 31, 2015

Physics
R = 120 Ohms. C = 40 uF = 40*10^-6 Farads. RC = 120 * 40*10^-6 = 4.8*10^-3 seconds t/RC = t/4.8*10^-3 = 208.3t 1/e^208.3t = 0.25 e^208.3t = 4 208.3t*Ln e = Ln 4 208.3t = 1.386 t = 0.00666 s. = 6.66 Milliseconds
March 30, 2015

physics
M1*V1 + M2*V2 = M1*V + M2*V 0.205*7.8 + 0.029*15 = 0.205*V + 0.029*V Solve for V.
March 30, 2015

Physical Science
Mass = 1000sacks * 20kg/sack = 20,000kg d = 1000sacks * 1m/sack = 1000 m. Power = F*d/t = Mg * d/t = 20000*9.8 * 1000/1800s = 108,889 J/s = 108,889 Watts
March 30, 2015

math
1. Po = 0.8 * 1687.00 = $1349.60 = Amt. financed. P = Po(1+r)^30 r = 16/12/100 = 0.0133 = Monthly % rate expressed as a decimal. P = 2008.05 I = P-Po = 2008.05 - 1349.60 = $658.45 2. Round and then estimate. ESTIMATE = 458 + 43 = 501.
March 29, 2015

math
1. Correct. 2. I = Po*r*t = 1100*(0.08/12 )*1 = $7.33 3. State Tax = 0.015 * 515 = $7.73 Medicare Tax = 0.0145 * 515 = $7.47 4. P = Po + Po*r*t = 619 + 619*(0.13/12)*1 = 625.71 5. 830.78-144 = $686.78 The given bal. is not compatible with the loan: 144/mo * 24mo = $3456 3456-...
March 29, 2015

Physics
44.2 + Dg = 212 m Dg = 212 - 44.2 = 167.8 m = Distance of green car. Vor = 23km/h = 23,000m/3600s = 6.39 m/s. Vr = 46km/h = 46,000m/3600s = 12.78 m/s. Vor*T1 = 44.2 6.39T1 = 44.2 T1 = 6.92 s. = Time to pass. Vr*T2 = 76.3 12.78*T2 = 76.3 T2 = 5.97 s. = Time to pass. a. Vog*T1...
March 29, 2015

physics
1. P = Mg * Vavg = 85*9.8 * 8/2 = 3332 J/s = 3332 Watts 2a. Momentum = M1*V1 + M2*V2 = 1000*30 + 3400*20i = 30,000 - 68,000i,Q4 = sqrt(30,000^2+68000^2) = 74,324 kg-m/s 2b. Total final momentum = Total initial momentum = 74,324 kg-m/s. 2c. M1*V1 + M2*V2 = M1*V + M2*V 30,000 - ...
March 29, 2015

math
X Qtrs (152-x) Dimes 25x + 10(152-x) = 2705 Cents 25x + 1520-10x = 2705 15x = 2705 - 1520 = 1185 X = 79
March 28, 2015

physics
The max range occurs at 45o. Vo = 25.8m/s[45o] Xo = 25.8*Cos45 = 18.2 m/s Yo = 25.8*sin45 = 18.2 m/s a. Y = Yo + g*Tr = 0 Tr = -Yo/g = -18.2/-9.8 = 1.86 s = Rise time. Tf = Tr = 1.86 s = Fall time. Tr+Tf = 1.86+1.86 = 3.72 s. = Time in air. b. Dx = Xo*(Tr+Tf)=18.2 * 3.72 = 67....
March 28, 2015

Maths
I = Po*r*t Po = $500 r = 0.06 = APR expressed as a decimal. t = 10 years. Solve for I.
March 28, 2015

Physics
a. M*g = 56 * 9.8 = 548.8 N. = Wt. of refrigerator = Normalforce(Fn). Fs = u*Fn = 0.58 * 549 = 318.3 N. = Force of static friction. b. Fap-Fs = M*a Fap - 318.3 = M*0 = 0 Fap = 318.3 = Force applied.
March 27, 2015

PHYSICS
a. Vsc = Vs + Vc = 1.24i + 0.553, Q1. Tan A = Y/X = 1.24/0.553 = 2.240 A = 66o CCW. V = Y/sin A = 1.24/sin66 = 1.36m/s d1 = 2.24km/sin66 = 2.45 km = 2450 m. to cross d1 = V*t t = d1/V = 2450/1.36 = 1802 s. = 30 Min. to cross. b. d2 = 2450*Cos66 = 997 m. Downstream.
March 27, 2015

math
4x - 3y = 8
March 26, 2015

PHYSICS
Correction: h = 0.5g*t^2 = 2.7 4.9t^2 = 2.7 t^2 = 0.551 Tf1 = 0.74 s = Fall time to board. Tr = Tf1 = 0.74 s = Rise time. h = 0.5g*t^2 = 3 + 2.7 = 5.7 4.9t^2 = 5.7 t^2 = 1.16 Tf2 = 1.08 s = Fall time from max ht. to the water. Dx = Xo*(Tr+Tf2) = 2.9 m. Xo = 2.9/(0.74+1.08) = 1...
March 26, 2015

PHYSICS
h = 0.5a*t^2 = 3+2.7 = 5.7 m. 4.9t^2 = 5.7 t^2 = 1.16 Tf = 1.08 s. = Fall time. Dx = Xo*Tf = 2.9 m Xo * 1.08 = 2.9 Xo = 2.69 m/s = Hor. component of initial velocity. Y^2 = Yo^2 + 2g*h = 0 Yo^2 = -2g*h = -2*(-9.8)*2.7 = 52.92 Yo = 7.27 m/s = Ver. component of initial velocity...
March 26, 2015

Physics
r1 = 8.8 m/s = Your speed. r2 = 0.8 * 8.8 = 7.04 m/s = Your bro. speed. 8.8t = 110 t = 12.5 s 7.04t = 110-d 7.04*12.5 = 110-d d = 110-88 = 22 m. Head start.
March 26, 2015

algebra
OOPS!! Please disregard the above calculations and answer.
March 25, 2015

algebra
(x-5)/(x-9) = (x-5)(x+5)/(x-9)(x+5) = (x-5)(x+5))/(x^2+5x-9x-45) = (x-5)(x+5))/(x^2-4x-45) = (x-5)(x+5)/(x+5)(x-9) = (x-5)/(x-9)
March 25, 2015

math
Do you mean 240/80 = 3? If so, your answer is correct.
March 25, 2015

physic
Since their is no acceleration, the force of friction(Fk) is = the hor. force applied: Fap - Fk = M*a Fap - Fk = M*0 = 0 Fk = Fap = 200 N.
March 25, 2015

physics
Dw/1000 = 0.78 Dw = 780kg/m^3 = Density of wood.
March 25, 2015

physics
Db/Dw = 400/1000 = 2/5
March 25, 2015

physics
Vo = 29.2m/s[31.7o] Xo = 29.2*Cos31.7 = 24.84 m/s Yo = 29.2*sin31.7 = 15.34 m/s Y = Yo + g*Tr = o Tr = -Yo/g = -15.34/-9.8 = 1.57 s. = Rise time. Dx = Xo*Tr = 24.84m/s * 1.57s = 38.9 m.
March 25, 2015

physics
M*g = 0.53 * 9.8 = 5.2 N. = Wt. of the mass. K = 1/0.039 * 5.2N = 133.2N/m
March 25, 2015

physics
Dx = Vx * Tf = 20.6 m. 27.7 * Tf = 20.6 Tf = 0.744 = Fall time. h = 0.5g*Tf^2 g = +9.8 m/s^2 Solve for h.
March 25, 2015

Math
Correct.
March 24, 2015

Math
1. P = Po(1+r)^n Po = $5,000 r = (6%/4)/100 = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 2yrs. = 8 Compounding periods. Solve for P.
March 24, 2015

Physics
V = a*t
March 24, 2015

Physics
Vpw = Vp + Vw = -245 m/s Vp + 38i = -245 Vp = -245-38i(Q3). Tan A = Y/X = -38/-245 = 0.15510 A = 8.82o S. of W. = 188.82o CCW.
March 24, 2015

Math
1. I = P - Po = 516.50*6 - 3000 = $99. I = 99/0.5yr = $198/yr. APR = (198/3000) * 100 = 6.6%
March 24, 2015

Math
1. % Increase = (6.58-4.80)*100/4.80 = 37.083 2. 1125 + 0.262*1125 = $1419.75 1419.75 - 1125 = $294.75 Saved when paid annually.
March 24, 2015

physics
E = emf = 24V. R1 = 5 Ohms R2 = 9 Ohms R3 = 12 Ohms a. 1/Req = 1/R1 + 1/R2 + 1/R3 1/Req = 1/5 + 1/9 + 1/12 = 0.3944444 Req = 2.535 Ohms b. It = I1+I2+I3 = E/Req = 24/2.535 = 9.47A I2 = 12/9 * I3 = 1.33I3 I1 = 12/5 * I3 = 2.4I3 I3 + 1.33I3 + 2.4I3 = 9.47 4.733I3 = 9.47 I3 = 2....
March 23, 2015

Math
A. 2x + 3y = 7 -x + 2y = -7 Multiply Eq2 by 2 and add the Eqs. 2x + 3y = 7 -2x + 4y = -14 sum = 7y = -7 Y = -1 In Eq1, replace y with -1 and solve for x: 2x + 3*(-1) = 7 2x = 10 X = 5 P(5,-1) B. P(5,-1), Q(-9,2). D^2=(-9-5)^2 + (2-(-1))^2=196 + 9 = 205 D = 14.3 Y = mx + b m...
March 23, 2015

physics
a1 = 10,000/500 = 20 m/s^2 a2 = 14,000/780 = 17.95 m/s^2 500 kg boat moves faster.
March 23, 2015

physics
M*g = 20 * 9.8 = 196 N. = Wt. of box. Fp = 196*sin3 = 10.26 N. = Force parallel to the incline. Fn = 196*Cos3 = 195.7 N. = Force perpendicular to the incline. Fk = u*Fn = 0.1 * 195.7 = 19.57 N. = Force of kinetic friction. a = (Fap-Fp-Fk)/M = (50-10.26-19.57)/20 =1.01 m/s^2 V^...
March 23, 2015

Physics
Fx - Fk = M*a Fex*Cos24 - 25 = M*0 = 0 Fex*Cos24 = 25 Fex = 27.4 N. = Force exerted Work = Fx*d = 27.4*Cos24 * 18 = 450.6 Joules
March 22, 2015

physics
a = Fap-Fk)/M = (150-95)/46 = 1.20 m/s^2
March 22, 2015

pre algebra
2.Add all like-terms: 2x^2-6x^2 = -4x^2 -4x+3x = -x 8 + 7 = 15 Results: -4x^2 - x + 15 3. Add all like-terms:
March 22, 2015

Vector
a. Tan A = Y/X = 10/26 = 0.38462 A = 21.04o E of N. Tan A = d/150 d = 150*Tan 21.04 = 57.7 m = Distance downstream. b. To offset the affect of the current, the swimmer must head 21.04o W. of N. Vsc = Vs + Vc = 26i Vs + 10 = 26i Vs = -10 + 26i Tan A = 26/-10 = -2.600 X = -68.96...
March 22, 2015

physics
M1*V1 + M2*V2 = M1*V3 + M2*V4 0.4*0 + 0.50*V2=0.40*1.4[37o] + 0.5*1.86 0 + 0.50V2 = 0.447 + 0.337i + 0.93 0.5V2 = 1.377 + 0.337i V2 = 2.754 + 0.674i V2 = sqrt(2.754^2+0.674^2) m/s
March 21, 2015

sicence
V^2 = Vo^2 + 2g*h Vo = 0 g = +9.8 m/s^2 h = 4 m. Solve for V.
March 21, 2015

physics
Va = 120revs/10s * 6.28rad/rev = 75.36 rad/s. = Angular velocity. a = (V-Vo)/t = (75.36-0)/10=7.54 rad/s^2
March 21, 2015

physics
V = Vo + a*t V = 40 rad/s Vo = 72 rad/s a = -4 rad/s^2 Solve for t
March 21, 2015

physics
a = (Fe-Fa)/M = (31.5*10^6-0.18*10^6)/2.764*10^6 = 31.32*10^6/2.764*10^6 = 11.33 m/s^2
March 21, 2015

Physics
Incomplete.
March 21, 2015

maths
V = As*h = 1760 * h = 12,320 cm^3 Solve for h.
March 21, 2015

physics
2*10^30kg * 1proton/2*10^-27kg = 1*10^57 Protons
March 21, 2015

Medical physics
Silver: V = L*W*h = 3*3*3 = 3^3 = 27 cm^3 Wt. = V*D = 27cm^3 * 10g/cm^3=270 grams Aluminum: V = 4*4*4 = 64 cm^3 Wt. = 64cm^3 * 2.96g/cm^3 = 189.4 grams
March 21, 2015

math _ HELP !!
(-3,5), (-1,4) Y = mx + b m = (y2-y1)/(x2-x1) = (4-5)/(-1-(-3)) = -1/2 = The slope. Y = (-1/2)(-3) + b = 5 3/2 + b = 5 b = 5 - 3/2 = 10/2 - 3/2 = 7/2 Eq: Y = (-1/2)x + 7/2
March 21, 2015

physics
Ts = (768kV/1kV) * 200 = 153,600 Turns.
March 20, 2015

physics
See previous post: Thu, 3-19-15, 12:01 AM.
March 19, 2015

physics
Vo = 10m/s[30o] Xo = 10*Cos30 = 8.66 m/s Yo = 10*sin30 = 5 m/s 1. Y = Yo * g*Tr = 0 Tr = -Yo/g = -5/-9.8 = 0.51 s. = Rise time. h = ho + -(Yo^2)/2g = 19 + -(5^2)/-19.6 = 20.3 m. Above gnd. h = 0.5g*t^2 = 20.3 4.9t^2 = 20.3 t^2 = 4.14 Tf = 2.03 s. = Fall time. Dx = Xo*(Tr+Tf...
March 19, 2015

physics
Vo = 20m/s[40o] Above the hor.? Xo = 20*Cos40 = 15.32 m/s. Yo = 20*sin40 = 12.86 m/s. 1. Y^2 = Yo^2 + 2g*h = 0 h = 35 + -(Yo^2)/2g h = 35 + -(12.86^2)/-19.6 = 43.44 m Above the green. Y = Yo + g*Tr = 0 Tr = -Yo/g = -12.86/-9.8 = 1.31 s. = Rise time. h = 0.5g*t^2 = 43.44 4.9t^2...
March 19, 2015

physics
V*D = 400cm^3 * 0.998g/cm^3 = 399.2 Grams = 0.399 kg F = M*g = 0.399 * 9.8 = 3.91 N. = Upthrust
March 19, 2015

physics
Correct.
March 19, 2015

physics help
1. D1 = Vx * Tf h = 0.5g*Tf^2 Tf^2 = h/0.5g Tf = sqrt (h/0.5g) = Fall time of fired bullet. h = 0.5g*Tf^2 Tf^2 = h/0.5g Tf = sqrt (h/0.5g) = Fall time of the dropped bullet. Therefore, the fall times are equal. 2. Directly at it.
March 19, 2015

physics
Vo = 54m/s[42o] Xo = 54*Cos42 = 40.1 m/s. Yo = 54*sin42 = 36.1 m/s. a. Y = Yo + g*Tr = 0 Tr = -Yo/g = -36.1/-9.8 = 3.69 s. = Rise time. Y^2 = Yo^2 + 2g*h = 0 h = -(Yo^2)/2g = (36.1^2)/-19.6=66.5 m. 0.5g*t^2 = 66.5-14 = 52.5 4.9t^2 = 52.5 t^2 = 10.71 t = 3.27 s. = Fall time(Tf...
March 19, 2015

maths
364
March 18, 2015

maths
357
March 18, 2015

algebra
An amusement park charges $8 admission and average of 2000 visitors per day. A survey shows that , for each $1 increase in the admission cost, 100 fewer people would visit the park. Write an equation to express the revenue, R(x) dollars, in terms of a price increase of x ...
March 18, 2015

algebra
May i ask how you found it?
March 18, 2015

algebra
A rectangular lot is bordered on one side by a stream and on the other three sides by 600m of fencing. Find the dimensions of the lot if area is a maximum.
March 18, 2015

algebra
9.6 = 0.128^2/0.11x^3 Multiply both sides by x^3: 9.6x^3 = 0.128^2/0.11 = 0.14895 Divide both sides by 9.6: x^3 = 0.01552 Take cube root of both sides by raising to the 1/3 power: (x^3)^1/3 = 0.01552^(1/3) X = 0.24944
March 18, 2015

physics
d = V1*T1 + V2*T2 = 118*1.05 + 40*1.15 = 169.9 km. Vavg = d/(T1+T2) = 169.9/2.20 = 77.2 km/h.
March 18, 2015

Physics
F = M*a = 1100 * 4.6 = 5060 N. d = 0.5a*t^2 = 0.5*4.6*5^2 = 57.5 m. P = F*d/t = 5060 * 57.5/5 = 58,190 J./s = 58,190 W.
March 18, 2015

physics
d1 + d2 = 18 m. 0.5g*t^2 + Vo*t + 0.5g*t^2 = 18 4.9t^2 + Vo*t - 4.9t^2 = 18 Vo*t = 18 20t = 18 t = 0.9 s. d1 = 0.5g*t^2 = 4.9 * 0.9^2 = 3.97 m.
March 17, 2015

math - slope-intercept
The slope of the 3 perpendicular lines must be the negative RECIPRECAL of the first line. 1. Y = (2/3)x + 4 2. Y = (-3/2)x + 4 3. Y = (-3/2)x + 5 4. Y = (-3/2)x + 6
March 17, 2015

math
Ta = 8:00AM + 1 1/2h = 9:30 AM. = Time arrived. d = r*T = 20 km T = 20/r = 20/80 = 1/4 h. = 15 min. Travel time. Ta = 8:30AM + 15 min = 8:45 AM. = Time arrived. 9:30AM - 8:45AM = 8:90 - 8:45 = :45 Min = Difference in arrival time.
March 17, 2015

Maths
90T = 70(T+1) 90T = 70T + 70 20T = 70 T = 3.5 h.
March 17, 2015

Calculus
Compute dy/dx using the chain rule. y = (u/4) + (4/u) u = (x - x^7) dy/dx =
March 17, 2015

physics
KE = 0.5*M*Vo^2 = 1400 J. Vo^2 = 1400/0.5M = 1400/2 = 700 Vo = 26.5 m/s. = Initial velocity. KE = 0.5*M*Xo^2 = 120 J. Xo^2 = 120/0.5M = 120/2 = 60 Xo = 7.75 m/s=Hor. component of initial velocity. Xo = Vo*Cos A = 7.75 m/s. 26.5*Cos A = 7.75 Cos A = 0.29230 A = 73o Yo = Vo*sin ...
March 17, 2015

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