Friday
January 20, 2017

Posts by henry

Total # Posts: 13,043

Mathematics
Show that the root equation (x-a)(x-b)=k^2 are always real numbers
December 16, 2015

Mathematics
Factorice 16(a-2b)^2-(a+b)^2 leaving your answer in the simplest form
December 16, 2015

pre algebra
P = Po(1+r)^n. Po = $2000. r = 0.051/2 = 0.0255 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 7yrs. = 14 Compounding periods.
December 15, 2015

Algebra
1. x-1/5 = +-3. 5x - 1 = +-15. 5x = 16, and -14. X = 16/5, or -14/5. 2. D. decreasing nonlinear.
December 15, 2015

Math
0.64N. N = the number of boxes sold.
December 15, 2015

physics
Fr = 25N.[25o] + F2[-73o] Since the acceleration is parallel to the x-axis, the sum of Y components of velocity equals 0: 25*sin25 + F2*sin(-73) = 0. 10.57 -0.956F2 = 0. -0.956F2 = -10.57. F2 = 11.1N[-73o].
December 15, 2015

physics
Vo = 56m/s[35o]. Xo = 56*Cos35 = 45.9 m/s. Yo = 56*sin35 = 32.1 m/s. Y = Yo*t + 0.5g*t^2=32.1*2.9 -4.9*2.9^2 = 52 m. X = Xo*T = 45.9m/s * 2.9s = 133 m.
December 15, 2015

Physics
V^2 = Vo^2 + 2g*h. Vo = 0. V = ?
December 14, 2015

Math
1-3/4 = 4/4-3/4 = 1/4 Eaten.
December 14, 2015

Science
Eff. = 70/100 * 100%.
December 14, 2015

Math
a. d1 = 200/sin43 = 293 Ft. b. d2 = 200/tan43. c. d3 = d2/Cos16. d. h = 200 + d2*Tan16
December 14, 2015

Business Math
P = Po + Po*r*t P = 1700 + 1700*(0.12/12)*18 = $2,006.
December 14, 2015

Physics
V = 50,000m/3600s = 13.9 m/s. t = 20min ? = 1200 s. a = (V-Vo)/t = Vo = 0. a/g * 100% =
December 14, 2015

Math
The driver formed a rectangle with 10 km horizontal sides and 20 km vertical sides(northward).
December 14, 2015

Physics Help
Vo = 100m/s[60o]. Xo = 100*Cos60 = 50 m/s. Yo = 100*sin60 = 86.6 m/s. Y^2 = Yo^2 + 2g*h = 86.6^2 - 19.6*150 = 4560. Y = 67.5 m/s.
December 13, 2015

Physics (angle Vector)
Vb - 5.4i = 11.8. Vb = 11.8 + 5.4i = 13m/s[24.6o] N. of E. = Compass heading. 9-5.4i) =
December 13, 2015

math
Started with $X. x/3 + x/2 = x - 9.00. Multiply by 6 and solve for x.
December 13, 2015

algebra
Sold X none student tickets. Sold Y student tickets. Eq1: x + y = 937. Eq2: 5x + 3y = 3943. Multiply Eq1 by -3 and use Elimination Method.
December 13, 2015

Algebra
Right!
December 13, 2015

physics
Incomplete.
December 13, 2015

physics
Oops! I misread the numbers. Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs. 9.77Lbs * 5days/10Lbs. = 4.9 Days or 5 days.
December 13, 2015

physics
Total = 23*33 + 12*11 + 1*1 = 892 Lbs. 892Lbs * 5days/10Lbs = 446 Days.
December 13, 2015

Mathematics
(x-6)*Log4 = 3x*Log2. Divide by Log4: x-6 = 3x*Log2/Log4. x-6 = 3x*0.5 = 1.5x. x-1.5x = 6. -0.5x = 6. X = -12.
December 13, 2015

8th grade algebra
Correction: In your case, 48 is the area of the base: V = B*h = 48m^2 * 7m = 336 m^3 or 336 cubic meters. Again, take half of the base only when it is the diameter.
December 12, 2015

8th grade algebra
V = pi*r^2*h = 3.14*24^2*7 = 12,660.5 cm^3(Not m^3). V = B*h, B=Area of the base, V=pi*r^2*h 48 is not the area of the base; it is the diameter of the base. Diameter*height = Square units. Diameter/2 = Radius. So you take 1/2 of the diameter to get the radius. I hope this helps.
December 12, 2015

Physics
-2.8 + Vb = -10.4i. Vb = 2.8 - 10.4i. = 10.8m/s[-74.9o] = 74.9o S. of E. = 15.1o E. of S.
December 11, 2015

algebra
1/4 + 1/3 + 1/2 = 3/12 + 4/12 + 6/12 = 13/12 = 1 1/12. Impossible, because 13/12 is more than a whole pizza.
December 11, 2015

Physics
101kpa = 101*10^3pa = 1.01*10^5 pa.
December 11, 2015

science
Increasing the voltage increases the current and power(P = E*I); therefore, the voltage should be increased.
December 11, 2015

Math
15/0.6 =
December 11, 2015

math
V1 = 75i mi/h. V2 = 60 mi/h Tan A = V1/V2=75/60 = 1.2500, A = 51.3o. d1 = 250*sin51.3 = 195 mi. V1*T = 195, 75 * T = 195, T = 2.60 h. = 156 min.
December 10, 2015

Marh
Tan 32 = h/(X1+X2), (X1+X2) = h/Tan 32 = 918/Tan32 = 1469 Ft. Tan 58 = h/X1, X1 = h/Tan 58 = 918/Tan58 = 574 Ft. X1 + X2 = 1469. 574 + X2 = 1469. X2 = Distance between the 2 people.
December 10, 2015

science
Incomplete.
December 10, 2015

algebra
Sold X cakes. Sold Y pies. Eq1: x + y = 9. Eq2: 13x + 6y = 75. Multiply Eq1 by -6 and add the Eqs.
December 10, 2015

physics
Incomplete.
December 9, 2015

physics
k = 66N/8.3cm = 7.95 N/cm. F = 11cm * 7.95N/cm =
December 9, 2015

phy 105
A student's Blood pressure reading 120/70 millimeters of mercury.
December 9, 2015

physics
Ws = M*g = 81.2 * 9.8 = 796 N. = Wt. of sled = Normal force, Fn. Fk = u*Fn = 0.172 * 796 = 137 N. = Force of kinetic friction. Fap-Fk = M*a. Fap-137 = M*0 = 0. Fap = 137 N. = Force applied. Work = Fap*d = 137 * 3.12 = 427 J. = 0.427 kJ.
December 9, 2015

Math
(2,1), (4,5). Slope = (y2-y1)/(x2-x1) = (5-1)/(4-2) =
December 9, 2015

geometry
Correction: A = 4.83*5^2.
December 9, 2015

geometry
A = 4.83*s^2 = 3.83*5^2 = 120.75 m^2.
December 9, 2015

Math
An ordered pair is a single point and not a line; Therefore, it has no slope.
December 9, 2015

Math
A. Plug your calculated value of T(2 s.) into the given Eq and solve for S, the ht. B. Tr = 2 s. = Rise time(part A). h = 0.5g*Tf^2 = 264 Ft. g = 32Ft/s^2. Tf = Fall time. Tf = ? Tr + Tf = Time to reach gnd. C. S(o) = ht. when t = 0. In the given Eq, replace t with zero and ...
December 9, 2015

Algebra
(1 3/4)sugar/(2/3)milk = (7/4)/(2/3) = 7/4 * 3/2 = 21/8 = (2 5/8)/1
December 8, 2015

Math
r^2 = X^2 + Y^2 (-12)^2 + 5^2 = 169. r = 13. sin A = Y/r = 5/13 = 0.3846.
December 8, 2015

Math
a. X = Sheldon's distance. x+4 = Leonard's distance. c. x + x+4 = 26. d. 2x = 26-4 = 22. X = 11.
December 8, 2015

math
Let X = 3: 3x/2 + 7/2 = 2^x. 3*3/2 + 7/2 = 2^3. 9/2 + 7/2 = 8. 16/2 = 8. 8 = 8. So X = 3 satisfies the Eq.
December 8, 2015

Math: Geometry
New Line = EF/(1/2) = 2EF.
December 8, 2015

contemporary mathematics
392mi/t = 322/t + 20. 392 = 322 + 20t. 20t = 392 - 322 = 70. t = 3.5 h. r = 392mi/3.5h = 112 mi/h = Speed of the P. train. r = 322mi/3.5h = 92 mi/h = Speed of the F. train.
December 8, 2015

Physics
X = 5m/s. = Vw. Y = 4 m/s = Vd. a. Tan A = Y/X = 4/5 = 0.8, A = 38.7o. N. of E. = 51.3o E. of N. Vr = X/Cos A=5/Cos38.7=6.4 m/s[38.7o] = Resultant drone velocity. b. d = 120/sin38.7 = 192 m. To cross the field. V*t = 192, 4*t = 192, t = 48 s.
December 7, 2015

physics
M(g+a)= 478. a = ?
December 7, 2015

physics
See previous post: Fri, 11-28-14, 9:52 PM.
December 7, 2015

math
A = b*h = 300yds^2. 15h = 300. h = 20 yds.
December 7, 2015

math
Scale = 16in/5ft = 3.2 in/ft. Width = 15Ft * 3.2in/ft. = 48 in. Height = 10ft * 3.2in/ft. = 32 in. Area = 48 * 32 = Square inches.
December 7, 2015

AC circuits
Note: If the voltage across the resistor is incorrect, all voltages will be wrong.
December 6, 2015

AC circuits
I = VR/R = 10/4 = 2.5A. = Current through all components(R,L, and C). VL = I*XL = 2.5 * 6 = j15.0 Volts. Vc = I*Xc = 2.5 * 8 = -j20.0 Volts. Z = R + j(XL-Xc)) = 4 + j(6-8) = 4 - j2 = 4.47 Ohms[-26.6o]. Es = I*Z = 2.5 * 4.47 = 11.2 Volts. Pf = Cos(-26.6) = 0.894 = Power factor...
December 6, 2015

Physics
There are errors in your problem that makes it difficult to understand. X = 3 km/h. Y = 10 km/h. Tan A = Y/X = 10/3 = 3.33333. A = 73.3o N. of E. = 16.7o E. of N. d1 = 5/Tan73.3 = 1.50 km downstream. d2 = Sqrt(1.5^2 + 5^2) = 5.22 km to cross. 2. Direction to offset affect of ...
December 6, 2015

Physics
L = 40 + 12*10^-6/Co(T-20) = 40.01. 40 + 12*10^-6T - 240*10^-6 = 40.01. 40 - 0.00024 + 12*10^-6T = 40.01. 39.99976 + 12*10^-6 = 40.01. 12*10^-6T = 40.01 - 39.99976 = 0.01024. T = 853.333 Degrees C.
December 6, 2015

math
post it.
December 6, 2015

Physics
Ws = M*g = 150*9.8 = 1470 N. Fp = 1470*sin40 = 945 N.=Force parallel to the ramp. Fn = 1470*Cos40 = 1126 N. = Normal force Fk = u*Fn = 0.54 * 1126 = 608 N. = Force of kinetic friction. Fp-Fc-Fk = M*a. 945-Fc-608 = M*0 = 0. 337-Fc = 0. Fc = 337 N. = Force of the curator. a. ...
December 5, 2015

Math
3x - 5x = 18. 2x = 18. X = 9. 3x = 3*9 = 27 = 1st number. 5x = 5*9 = 45 = 2nd number.
December 5, 2015

MATH
7.48*10^5.
December 5, 2015

math
I = 280/40 * 4 = 28 Amps. or E = I*R = 4*280 = 1120 v. I = E/R = 1120/40 = 28 Amps.
December 3, 2015

PreCalculas
2. D(3/4,-3), V(h,-3), F(5/4,-3). 1/2a = 5/4-3/4 = 2/4 = 1/2. 2a = 2, a = 1. 1/4a = 1/(4*1) = 1/4. h = 3/4 + 1/4a = 3/4 + 1/4 = 4/4 = 1. X = a(y-k)^2 + h. X = (y+3)^2 + 1, Vertex form. X = y^2 + 6y + 10, Standard form.
December 3, 2015

PreCalculas
1. V(2,5), F(2,-3). 1/4a = -3-5 = -8. 4a = -1/8. a = -1/32. Y = a(x-h)^2 + k. Y = (-1/32)(x-2)^2 + 5, Vertex Form
December 3, 2015

physics
See previous post: Tue, 12-1-15, 12:30 PM.
December 3, 2015

physics
a football thrown at 45o has max range: Range = Vo^2*sin(2A)/g=36^2*sin(90)/9.8 = 132.2 m.
December 3, 2015

math
6*Cos x + 2.46*Cos x - 1.72*sin x = 7*Cos x. 8.46*Cos x - 1.72*sin x = 7*Cos x. 8.46*Cos x - 7*Cos x = 1.72*sin x. 1.46*Cos x = 1.72*sin x. Divide by Cos x: 1.72*sin x/Cos x = 1.46. Replace sin x/Cos x with Tan x: 1.72*Tan x = 1.46. Tan x = 1.46/1.72 = 0.84848. X = 40.3 Degrees.
December 3, 2015

physics
V^2 = Vo^2 + 2g*h. Vo = 0. g = 9.8 m/s^2. h = 3 m. V = ?
December 3, 2015

pysics
Vo = 200m/s[35o]. Yo = 200*sin35 = 114.7 m/s. Y^2 = Yo^2 + 2g*h. Y = 0. g = -9.8 m/s^2. h = ?
December 3, 2015

Physics Check My Work Please
g is used when the motion is vertical. The block is moving horizontally. Therefore, the acceleration must be calculated: Fk = Ma, a = Fk/M = -12/8 = -1.5 m/s^2. V^2 = Vo^2 + 2a*d. a = -1.5 m/s^2. Fk is negative, because it opposed the motion.
December 3, 2015

Math
N = 4*8 = 32 Students.
December 2, 2015

Physics
PE = KE Mg*h = 0.5M*V^2. M*g = 45*9.8. h = ?
December 2, 2015

Physics
See previous post: Tue, 12-1-15, 12:33 PM.
December 2, 2015

algebra
-7y^2-4y+6 = 7y^2-4y-4-2y^2+2y+6. -12y^2-2y+4 = 0. Divide by -2: 6y^2 + y - 2 = 0. A*C = -12 = 4*(-3) 6y^2 + (4y-3y) - 2 = 0. (6y^2+4y) - (3y+2) = 0. 2y(3y+2) - (3y+2) = 0. (3y+2)(2y-1) = 0. 3y+2 = 0, Y = -2/3. 2y-1 = 0, Y = 1/2.
December 2, 2015

Science
Unless otherwise indicated, all angles are measured CCW from +x-axis. Vr = 725m/s[131.2o] + 106.7m/2[68.2o]. X = 725*Cos131.2 + 106.7*Cos68.2= -438 m/s. Y = 725*sin131.2 + 106.7*sin68.2 = 645 m/s. Tan A = Y/X = 645/-438 = -1.47162. A = 55.8o N. of W. Vr = Y/sin A = 645/sin55.8...
December 2, 2015

Science
Vp = 725m/s[W.48.8oN] + 106.7[E68.2N] = -725*Cos48.8+725*sin48.8 + 106.7*Cos68.2 +106.7*sin68.2 = -478+546i + 39.6+99.1i = -438.4 + 645.1i = 780m/s[W55.8oN] = 780m/s[N34.2oW].
December 2, 2015

Algebra plz help
1. Correct. 2. Correct. 3. Incorrect. See previous post: Mon, 11-30-15, 9:08 PM.
December 2, 2015

math
Proportion: S/m = 2/11. 16/m = 2/11, m = 88 min. 19/m = 2/11, m = 104 min.
December 2, 2015

Physics
Need more INFO.
December 2, 2015

Physics
V = 60,000/3600s = 16.7 m/s. C = pi*D = 3.14 * 0.75m = 2.36 m. Va = 16.7m/s * 6.28Rad/2.36m=44.3 Rad/s.
December 2, 2015

physics
Vo = 172.5m/s[30o]. Xo = 172.5*Cos30 = 149.4 m/s. Yo = 172.5*sin30 = 86.25 m/s. a. Yf^2 = Yo^2 + 2g*h. h = -(Yo)^2/2g = -(86.25)^2/19.6 = 379.5 m. b. Y = Yo + g*Tr = 0. Tr = -Yo/g = -86.25/-9.8 = 8.80 s. = Rise time. NOTE: In your Eq, use (-)9.8 for g.
December 1, 2015

Physics
Vo = 5.2m/s[56o]. Xo = 5.2*Cos56 = 2.91 m/s. Yo = 5.2*sin56 = 4.31 m/s. h=-Yo^2/2g + 1.1=-(4.31)^2/-20 + 1.1 = 2.03 m. Above gnd. Y^2 = Yo^2 + 2g*h = 0 + 20*2.03 = 40.6 Y = 6.37 m/s. X = Xo = 2.91 m/s.
December 1, 2015

Physics
Eq1: Xo = Vo*Cos A = Speed at max h. Vo = 6.8Xo. In Eq1, replace Vo with 6.8Xo: Xo = 6.8Xo*Cos A. Divide by 6.8Xo: Cos A = 1/6.8 = 0.14706 A = 81.5 Degrees.
December 1, 2015

Physics
Vo = 29.6m/s[46.9o]. Xo = 29.6*Cos46.9. = m/s. Yo = 29.6*sin46.9 = m/s. Y = Yo + g*Tr. Y = 0. g = -9.8 m/s^2. Tr = Rise time. Tr = ? Y^2 = Yo^2 + 2g*h. Y = 0. h = ? 0.5g*Tf^2 = h + 32. g = 9.8 m/s^2. Tf = Fall time. Tf = ? D = Xo*(Tr+Tf).
December 1, 2015

waves andoscillation
F = 0.13m * 130N/m = 16.9 N. a = F/M = 16.9/0.60 = 28.2 m/s^2.
November 30, 2015

PHYSICS
Displacement = 1000i +1000i + 200[225o] = 1000i + 200*Cos225 + 200*sin225 = 1000i - 141.4 - 141.4i = -141.4 + 858.6i = 870m[99.4o]CCW = 80.6o N. of W. V = D/t = 870m[99.4o]/960s = 0.91 m/s.
November 30, 2015

Algebra
(3/2,-2), (-3,7/3). Slope = (y2-y1)/(x2-x1). Slope = (7/3-(-2))/(-3-3/2) = (7/3+2)/(-6/2-3/2) = (7/3+6/3)/(-9/2) = (13/3)/(-9/2) = 13/3 * (-2/9) = -26/27.
November 30, 2015

science
The signal rides on a higher frequency called the carrier frequency. The carrier is modulated in the transmitter and demodulated in the radio. To demodulate means to separate the voice or music from the carrier. The carrier may be Frequency Modulated (FM) or Amplitude ...
November 30, 2015

Math
d1 = V1*T1 = 40 * 3 = 120 mi. d2 = V2*T2 = 55 * T2 = 55T2. Vavg. = (d1+d2)/(T1+T2) = 50 mi/h. (120+55T2)/(3+T2) = 50. 120 + 55T2 = 150 + 50T2. 5T2 = 30. T2 = 6 Hours.
November 30, 2015

PHYSICS
V = d/t = (300 + 100)/(60+20) = 5 m/s.
November 30, 2015

Math
A function crosses a vertical line only once. Your relation crosses a vertical line twice:(-8,-6), and (-8,1). The x-coordinate shows twice; that is the clue. Therefore, it is not a function.
November 30, 2015

Math
Correct.
November 30, 2015

geometry
a^2 + b^2 = c^2. a^2 + 48^2 = 80^2. a = ?
November 30, 2015

physics
X = 6 mi/h = Velocity of the current. Y = 13 mi/h = Velocity of the boat. Tan A = Y/X = 13/6 = 2.16666. A = 65.2o N. of E. = 24.8o E. of N. Due to the current. Direction: Head 24.8o W. of N. To offset affect of the current. Tan A =
November 30, 2015

math
A. h = 30Ft * 1.26cm/Ft = 37.8 cm. = Ht. of the model. 37.8cm * 1toothpick/6.3cm = 6 Toothpicks B. 37.8cm/7.6 =
November 30, 2015

Math
Db + Dc = 510 mi. Vb*t + Vc*t = 510. Vb*t + (Vb+33.4)t = 510. t = 8.5 hrs. Vb = ? Vc = Vb + 33.4.
November 29, 2015

algebra
V = y(5y^2+31y+6). A*C = 5*6 = 30 = 1*30. V = y(5y^2+(y+30y)+6) = 0. y(5y^2+y)(30y+6) = 0. y*y(5y+1)6(5y+1) = 0 6y^2(5y+1)(5y+1) = 0. 6y^2 = 0, Y = 0. 5y+1 = 0, Y = -1/5.
November 29, 2015

physics
Mg*h = 0.5M*V^2. h = 0.5V^2/g = 0.5*8.5^2/9.8 = 3.69 m. V^2 = Vo^2 + 2g*h. Vo = 1.5 m/s. g = 9.8 m/s^2. V = ?
November 29, 2015

Physics
F2*d2 = F1*d1. F2*6 = 4*3 = 12. F2 = 2 N.
November 29, 2015

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