Wednesday
May 4, 2016

# Posts by henry

Total # Posts: 11,797

MATHSS
Theta = 4 Rad. Wo = 3.2? Rad/s a = 0.6rad/s^2 Theta = Wo*t + 0.5a*t^2 = 4 rads. 3.2t + 0.5*0.6t^2 = 4 0.3t^2 + 3.2t - 4 = 0 Use Quadratic Formula. t = 1.13 s (Wo = 3.2 rad/s). t = 0.125 s (Wo = 32 rad/s).
April 11, 2015

Mathematics
Leslie: 4.5Laps/0.75h = 6 Laps/h Kala: 3.5Laps/0.75h = 4.67 Laps/h 6Laps/h - 4.67Laps/h = 1.33 Laps/h. Therefore, Leslie can run 1.33 more laps in 1 hr. than Kayla.
April 10, 2015

PHYSICS
Impulse = M*V = 3 * 2 = 6
April 10, 2015

Physics
Vr = 14 * pi*r^2 * h = 3.14*(0.295/2)^2 * 6.5 = 6.22 m^3 = Volume of the raft. Vr*Dr = 6.22m^3 * 600kg/m^3 = 3732 kg = Mass of the raft. Vw*Dw = 6.22m^3 * 1000kg/m^3 = 6220 kg = Mass of the water displaced. 6220 - 3732 = 2488 kg can be added to the raft. 2488kg * 1person/75kg...
April 9, 2015

Maths
a. X stamps, Total. 124 stamps, Australia 0.3x stamps, France 0.3x-12 stamps, Japan X = 124 + 0.3x + 0.3x-12 0.4x = 112 X = 280 b. 280 + n = 1.25*280 = 350 n = 70 Stamps from Lisa's aunt. (0.3x+n)/350 = (84+70)/350 = 0.44 = 44% from France.
April 9, 2015

Physics
a. Fr = 10N[60o]CCW + 15N[0o] X = 10*Cos60 + 15 = 20 N. Y = 10*sin60 = 8.7 N. Q1. Tan A = Y/X = 8.7/20 = 0.433 A = 23.4o N. of E. Fr = X/Cos A = 20/Cos23.4=21.8 N.[23.4o] N. of E. = 23.4o CCW b. Equilibrant: X = -20 Y = -8.7 Q3. Tan A = Y/X = -8.7/-20 = 0.433 A = 23.4o S. of W...
April 9, 2015

Physic
R1 = 1.4k Ohms R2 = 2.5k Ohms R3 = 3.7k Ohms P1 max = I1^2*R1 = 500 mW I1^2*1.4 = 500 I1^2 = 357.14 I1 = 18.9mA, max = Total current. Req. = R1 + (R2*R3)/(R2+R3) = 1.4 + (2.5*3.7)/(2.5+3.7) = 1.4 + 1.49 = 2.89k Ohms E max = I1*Req = 18.9 * 2.89 = 54.6 V. =
April 9, 2015

math
b. h = Vo*t + 0.5g*t^2 Vo = 192 Ft/s g = -32Ft/s^2 h = 432 Ft. Solve for t(Use Quadratic formula). c. h max = -(Vo^2)/2g = -(192^2)/-64 = 576 Ft. d. V = Vo + g*Tr = 0 Tr = -Vo/g = -192/-32 = 6 s. = Rise time Tf = Tr = 6 s. = Fall time. Tr+Tf = 6 + 6 = 12 s. to hit gnd.
April 9, 2015

math
h = Vo*t + 0.5g*t^2 Vo = 192Ft/s t = 10 s. g = -32Ft/s^2 Solve for h.
April 9, 2015

Physics
M*g = 330 * 9.8 = 3234 N. = Wt. of sled. Fp = 3234*sin6 = 38 N. = Force parallel to the incline. Fn = 3234*Cos6 = 3216 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.135 * 3216 = 434.2 N. = Force of kinetic friction. a = (Fap-Fk)/M = (1780-434)/330 = 4.08 m/s^...
April 9, 2015

Physics
Vo = 101km/h = 101,000m/3600s = 28.1 m/s = Initial velocity. See Related Questions: Tue, 10-28-14, 2:33 AM.
April 9, 2015

math
P = Po - Po*r*t = 11,090.41 120,000 - 120,000*r*12 = 11,090.41 -1,440,000r = 11,090.41 - 120,000 r = 0.0756 = 7.56% per annum
April 8, 2015

Physics
M*g = 59.9 * 9.8 = 587 N. = Wt. of girl and sled. Fp = 587*sin30 + 131 = 424.5 N. = Force parallel to the incline. Fn = 587*Cos30 = 508.4 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.217 * 508.4 = 110.3 N. = Force of kinetic friction. a=(Fp-Fk)/M = (424.5-...
April 8, 2015

DPS PHYCIS
Fr = 10[30] + 10[60o] X = 10*Cos30 + 10*Cos60 = 13.66 Units Y = 10*sin30 + 10*sin60 = 13.66 Units Fr = sqrt(X^2+Y^2)
April 8, 2015

Physics
Wavelength=V*P = V*(1/F) = V*(1/3.8) = 0.48 m. V/3.8 = 0.48 V = 1.82 m/s
April 8, 2015

Physics
1. V = 3400rev/min * 6.28rad/rev * 1min/60s = 356 rad/s V = Vo + a*t V = 356 rad/s Vo = 0 t = 50 s. Solve for a(rad/s^2).
April 7, 2015

physics
M1*V1 + M2*V2 = M1*V + M2*V 15*5 + 3*V2 = 15*1.5 + 3*1.5 3V2 = 27 - 75 = -48 V2 = -16 m/s = 16 m/s to the left.
April 7, 2015

Physics
a. V = Vo + a*t V = 51.5 m/s Vo = 41.5 m/s a = 2.65 m/s^2 Solve for t. b. Same procedure and answer as part a.
April 7, 2015

Grambling
a. D = 4.58 + 6.25i - 8.65 - 1.84i = -4.07 + 4.41i, Q2 D = sqrt(4.07^2+4.41^2) km. b. Tan A = Y/X = 4.41/-4.07 = -1.08354 A = -47.3o = 47.3o N. of W.
April 7, 2015

Grambling
V^2 = Vo^2 + 2a*d V = 11.4 m/s Vo = 83.8 m/s d = 750 m. Solve for a. It should be negative.
April 7, 2015

Physics
h = 6.03*sin21.5 = 2.21 m. V^2 = Vo^2 + 2g*h = 4.87^2 + 19.6*2.21 V = Final velocity Vo = 4.87 m/s g = 9.8 m/s^2 Solve for V.
April 7, 2015

Physics
PE max = Mg*h-Fk*h = 0.5*M*V^2 M = 98.5 kg g = 9.8 m/s^2 h = 4 m V = 1.81 m/s. Solve for Fk. Divide both sides by M, and solve for Fk
April 7, 2015

math help
Tank #1 = T min. Tank #2 = (T+60) min. T*(T+60)/(T+T+60) = 40 min (T^2+60T)/(2T+60) = 40 T^2+60T = 80T+2400 T^2 - 20T - 2400 = 0 Use Quadratic Formula. T = 60 min. T + 60 = 60 + 60 = 120 min.
April 7, 2015

A. Ri = 0.4 + 0.4 = 0.8 Ohms B. I = E/(Ri+Rm+Ra+Rb) = 24/6.95 = 3.45A
April 7, 2015

Physics
D. P = 12 * 1.4 = 16.8W. = Greatest energy consumption.
April 6, 2015

geometry
2x+5 + 5x-79 + 122 = 180 7x = 180 + 79 = 259 X = 37 m<YWZ = 5x-79 = 5*37 - 79 = 106o
April 6, 2015

physics
a. 5000 Watts = 5,000 J/s = 5000 Joules every second.
April 6, 2015

Physics
a. Circumference = pi * 2r = 3.14 * 0.9 = 2.83 m. Arc = 2.83m/360o * 170o = 1.33 m. b. V = 0.25rad/s * 2.83m/6.28rads = 0.113 m/s. c. If the velocity is constant, the acceleration is zero.
April 6, 2015

physics
Max ht. occurs at 45o. Vo = 4m/s[45o] Yo = 4*sin45 = 2.83 m/s = Ver. component of initial velocity. Y^2 = Yo^2 + 2g*h Y = 0 Yo = 2.83 m/s. g = 9.8 m/s^2 Solve for h.
April 6, 2015

physics
See previous post: Mon. 4-6-15, 8:58 AM.
April 6, 2015

physics
V = Vo + a*t = 30 m/s 0 + a*20 = 30 a = 1.5 m/s^2 d = 0.5a*t^2 = 0.5*1.5*10^2 = 75 m.
April 6, 2015

Physics
V = g*t V = 20*1 = 20 m/s. V = 20*2 = 40 m/s. V = 20*3 = 60 m/s. Increase = 20 m/s with each second.
April 5, 2015

math
(1/2)/3 = 1/2 * 1/3 = 1/6 of the Half- pie. 1/2 * 1/6 = 1/12 of the whole pie.
April 4, 2015

physics
Momentum before the collision=Momentum after the collision: M1*V1 + M2*V2 = M1*V + M2*V 0.075*80 + 13*0 = 0.075*V + 13*V 6 + 0 = 13.075V V = 0.459 m/s
April 4, 2015

physics
M!*V1 + M2*V2 = M1*V + M2*V 0.075*80 + 13*0 = 0.075*V + 13*V 6 + 0 = 13.075V
April 4, 2015

Physics
M*g = 13 N. = Wt. of puck. M = 13/g = 13/9.8 = 1.33 kg. Fn = 13*cos37 = 10.4 N. Fk = u*Fn = 0.08 * 10.4 = 0.831 N. sin37 = h/3 h = 3*sin37 = 1.81 m. PE = Mg*h - Fk*d = 13*1.81 - 0.831*3 = 21.04 J. At bottom of ramp: KE = PE = 0.5*M*V^2 = 21.04 J. 0.5*1.33*V^2 = 21.04 V^2 = 21....
April 3, 2015

Physics
V^2 = Vo^2 + 2a*d = 0 + 2a*2pi = 4a*pi V = 2*sqrt(pi*a) = 2*1.772*sqrt a = 3.54*sqrt a
April 3, 2015

math
Sam has X stamps. Jill has (576-X) Stamps. X-x/7 = 6x/7 = Sam's bal. 576-x + x/7 = 576 - 6x/7 = Jill's bal. 1/4(576-6x/7) = 144 - 6x/28 3/4(576-6x/7) = 432 - 9x/14 = Jill's new bal. 6x/7 + 144-6x/28 = 144 + 24x/28-6x/28 = 144 + 9x/14 = Sam's new bal. Jill's...
April 2, 2015

Physics
M*g = 475 * 9.8 = 4655 N. P = F*d/t = Mg * d/t = 4655 * 10/24 = 1940 J/s = = 1940 W. = 1.94 kW
April 2, 2015

math help`
Any pair of parallel lines will have equal slopes. I don't know what you mean by "some is always -1".
April 2, 2015

math
Multiply Eq1 by -2 and add the Eqs: -4x + 6y = 4 +4x + y = 24 Sum: 7y = 28 Y = 4 In Eq1, replace Y with 4 and solve for X
April 2, 2015

algebra
d1 = d2 60 + 60t = 80t 20t = 60 t = 3 h.
April 2, 2015

Physics
When t = 0, X = 0-0 +6 = 6 m. When t = 3 s., X = 3^2 - 4*3 + 6 = 3 m. d = 6-3 = 3 m.
April 2, 2015

physics
See previous post: Wed, 4-1-15, 6:39 AM.
April 2, 2015

Physics
If they were wired in series, All lights will go out when one bulb burns out. Therefore, they are connected in parallel.
April 2, 2015

Physics 101
Correction: a = (Fp-Fk)/M = (122.6-63.65)/25 = 2.36 m/s^2
April 2, 2015

Physics 101
M*g = 25 * 9.8 = 245 N. = Wt. of the box Fp = 245*sin30 = 122.5 N. = Force parallel to the incline. Fn = 245*Cos30 = 212.2 N. = Force perpendicular to the incline. Fk = u*Fn = 0.30 * 212.2 N. = 63.65 N. = Force of kinetic friction. a = (Fp-Fk)/M*sin30 = (122.5-63.65)/12.5 = 4....
April 2, 2015

Finances
a. P = Po(1+r)^n Po = \$600 r = 1.5%/100 = 0.015 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 2yrs. = 24 Compounding periods. Solve for P. Monthly Payment = P/24 a. Simple Interest: P = Po + Po*r*t = 600 + 600*0.015*24 Solve for P. Monthly payment = P/24 b. Same ...
April 1, 2015

Physic
V = Vo + a*t V = 6.5 m/s Vo = 0 t = 22 s. Solve for a. d = 0.5a*t^2 t = 22 s. Solve for d
April 1, 2015

Physic
V = Vo + a*t v = 22 m/s Vo = 5 m/s t = 18 s. Solve for a.
April 1, 2015

Physic
M*g = 637 N. g = 9.8 m/s^2 M = Mass in kg Solve for M.
April 1, 2015

Geometry
X = 3-2.5 = 0.5 m. Y = 1.5 m. Tan A = Y/X = 1.5/0.5 = 3.0 A = 71.57o Tan 71.57 = h/3 Solve for h.
April 1, 2015

math
See previous post: Tue, 3-31-15, 5:18 PM.
April 1, 2015

physics
M*g = 150 N = Wt. of the boy = Normal force(Fn). Fk = u*Fn = 0.05 * 150 = 7.5 N. = Force of kinetic friction. Fap-Fk = M*a Fap-7.5 = M*0 = 0 Fap = 7.5 N. = Force applied.
April 1, 2015

algebra
V = Vo + g*t = 128 - 32*2 = 64 Ft/s after 2 s. V = 128 - 32*4 = 0 After 4 s. Vavg = (0+4)/2 = 2 Ft/s
April 1, 2015

precalculus
U(3,1), V(6,-1) A. Tan A = (-1-1)/(6-3) = -2/3=-0.66666 A = -33.7o = 33.7 S. of E.
March 31, 2015

P = Po(1+r)^n Po = \$8,500 r = (6/4)/100 = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 12yrs. = 48 Compounding periods. Solve for P. I = P-Po
March 31, 2015

Physics
Incomplete.
March 31, 2015

Physics
R = 120 Ohms. C = 40 uF = 40*10^-6 Farads. RC = 120 * 40*10^-6 = 4.8*10^-3 seconds t/RC = t/4.8*10^-3 = 208.3t 1/e^208.3t = 0.25 e^208.3t = 4 208.3t*Ln e = Ln 4 208.3t = 1.386 t = 0.00666 s. = 6.66 Milliseconds
March 30, 2015

physics
M1*V1 + M2*V2 = M1*V + M2*V 0.205*7.8 + 0.029*15 = 0.205*V + 0.029*V Solve for V.
March 30, 2015

Physical Science
Mass = 1000sacks * 20kg/sack = 20,000kg d = 1000sacks * 1m/sack = 1000 m. Power = F*d/t = Mg * d/t = 20000*9.8 * 1000/1800s = 108,889 J/s = 108,889 Watts
March 30, 2015

math
1. Po = 0.8 * 1687.00 = \$1349.60 = Amt. financed. P = Po(1+r)^30 r = 16/12/100 = 0.0133 = Monthly % rate expressed as a decimal. P = 2008.05 I = P-Po = 2008.05 - 1349.60 = \$658.45 2. Round and then estimate. ESTIMATE = 458 + 43 = 501.
March 29, 2015

math
1. Correct. 2. I = Po*r*t = 1100*(0.08/12 )*1 = \$7.33 3. State Tax = 0.015 * 515 = \$7.73 Medicare Tax = 0.0145 * 515 = \$7.47 4. P = Po + Po*r*t = 619 + 619*(0.13/12)*1 = 625.71 5. 830.78-144 = \$686.78 The given bal. is not compatible with the loan: 144/mo * 24mo = \$3456 3456-...
March 29, 2015

Physics
44.2 + Dg = 212 m Dg = 212 - 44.2 = 167.8 m = Distance of green car. Vor = 23km/h = 23,000m/3600s = 6.39 m/s. Vr = 46km/h = 46,000m/3600s = 12.78 m/s. Vor*T1 = 44.2 6.39T1 = 44.2 T1 = 6.92 s. = Time to pass. Vr*T2 = 76.3 12.78*T2 = 76.3 T2 = 5.97 s. = Time to pass. a. Vog*T1...
March 29, 2015

physics
1. P = Mg * Vavg = 85*9.8 * 8/2 = 3332 J/s = 3332 Watts 2a. Momentum = M1*V1 + M2*V2 = 1000*30 + 3400*20i = 30,000 - 68,000i,Q4 = sqrt(30,000^2+68000^2) = 74,324 kg-m/s 2b. Total final momentum = Total initial momentum = 74,324 kg-m/s. 2c. M1*V1 + M2*V2 = M1*V + M2*V 30,000 - ...
March 29, 2015

math
X Qtrs (152-x) Dimes 25x + 10(152-x) = 2705 Cents 25x + 1520-10x = 2705 15x = 2705 - 1520 = 1185 X = 79
March 28, 2015

physics
The max range occurs at 45o. Vo = 25.8m/s[45o] Xo = 25.8*Cos45 = 18.2 m/s Yo = 25.8*sin45 = 18.2 m/s a. Y = Yo + g*Tr = 0 Tr = -Yo/g = -18.2/-9.8 = 1.86 s = Rise time. Tf = Tr = 1.86 s = Fall time. Tr+Tf = 1.86+1.86 = 3.72 s. = Time in air. b. Dx = Xo*(Tr+Tf)=18.2 * 3.72 = 67....
March 28, 2015

Maths
I = Po*r*t Po = \$500 r = 0.06 = APR expressed as a decimal. t = 10 years. Solve for I.
March 28, 2015

Physics
a. M*g = 56 * 9.8 = 548.8 N. = Wt. of refrigerator = Normalforce(Fn). Fs = u*Fn = 0.58 * 549 = 318.3 N. = Force of static friction. b. Fap-Fs = M*a Fap - 318.3 = M*0 = 0 Fap = 318.3 = Force applied.
March 27, 2015

PHYSICS
a. Vsc = Vs + Vc = 1.24i + 0.553, Q1. Tan A = Y/X = 1.24/0.553 = 2.240 A = 66o CCW. V = Y/sin A = 1.24/sin66 = 1.36m/s d1 = 2.24km/sin66 = 2.45 km = 2450 m. to cross d1 = V*t t = d1/V = 2450/1.36 = 1802 s. = 30 Min. to cross. b. d2 = 2450*Cos66 = 997 m. Downstream.
March 27, 2015

math
4x - 3y = 8
March 26, 2015

PHYSICS
Correction: h = 0.5g*t^2 = 2.7 4.9t^2 = 2.7 t^2 = 0.551 Tf1 = 0.74 s = Fall time to board. Tr = Tf1 = 0.74 s = Rise time. h = 0.5g*t^2 = 3 + 2.7 = 5.7 4.9t^2 = 5.7 t^2 = 1.16 Tf2 = 1.08 s = Fall time from max ht. to the water. Dx = Xo*(Tr+Tf2) = 2.9 m. Xo = 2.9/(0.74+1.08) = 1...
March 26, 2015

PHYSICS
h = 0.5a*t^2 = 3+2.7 = 5.7 m. 4.9t^2 = 5.7 t^2 = 1.16 Tf = 1.08 s. = Fall time. Dx = Xo*Tf = 2.9 m Xo * 1.08 = 2.9 Xo = 2.69 m/s = Hor. component of initial velocity. Y^2 = Yo^2 + 2g*h = 0 Yo^2 = -2g*h = -2*(-9.8)*2.7 = 52.92 Yo = 7.27 m/s = Ver. component of initial velocity...
March 26, 2015

Physics
r1 = 8.8 m/s = Your speed. r2 = 0.8 * 8.8 = 7.04 m/s = Your bro. speed. 8.8t = 110 t = 12.5 s 7.04t = 110-d 7.04*12.5 = 110-d d = 110-88 = 22 m. Head start.
March 26, 2015

algebra
March 25, 2015

algebra
(x-5)/(x-9) = (x-5)(x+5)/(x-9)(x+5) = (x-5)(x+5))/(x^2+5x-9x-45) = (x-5)(x+5))/(x^2-4x-45) = (x-5)(x+5)/(x+5)(x-9) = (x-5)/(x-9)
March 25, 2015

math
Do you mean 240/80 = 3? If so, your answer is correct.
March 25, 2015

physic
Since their is no acceleration, the force of friction(Fk) is = the hor. force applied: Fap - Fk = M*a Fap - Fk = M*0 = 0 Fk = Fap = 200 N.
March 25, 2015

physics
Dw/1000 = 0.78 Dw = 780kg/m^3 = Density of wood.
March 25, 2015

physics
Db/Dw = 400/1000 = 2/5
March 25, 2015

physics
Vo = 29.2m/s[31.7o] Xo = 29.2*Cos31.7 = 24.84 m/s Yo = 29.2*sin31.7 = 15.34 m/s Y = Yo + g*Tr = o Tr = -Yo/g = -15.34/-9.8 = 1.57 s. = Rise time. Dx = Xo*Tr = 24.84m/s * 1.57s = 38.9 m.
March 25, 2015

physics
M*g = 0.53 * 9.8 = 5.2 N. = Wt. of the mass. K = 1/0.039 * 5.2N = 133.2N/m
March 25, 2015

physics
Dx = Vx * Tf = 20.6 m. 27.7 * Tf = 20.6 Tf = 0.744 = Fall time. h = 0.5g*Tf^2 g = +9.8 m/s^2 Solve for h.
March 25, 2015

Math
Correct.
March 24, 2015

Math
1. P = Po(1+r)^n Po = \$5,000 r = (6%/4)/100 = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 2yrs. = 8 Compounding periods. Solve for P.
March 24, 2015

Physics
V = a*t
March 24, 2015

Physics
Vpw = Vp + Vw = -245 m/s Vp + 38i = -245 Vp = -245-38i(Q3). Tan A = Y/X = -38/-245 = 0.15510 A = 8.82o S. of W. = 188.82o CCW.
March 24, 2015

Math
1. I = P - Po = 516.50*6 - 3000 = \$99. I = 99/0.5yr = \$198/yr. APR = (198/3000) * 100 = 6.6%
March 24, 2015

Math
1. % Increase = (6.58-4.80)*100/4.80 = 37.083 2. 1125 + 0.262*1125 = \$1419.75 1419.75 - 1125 = \$294.75 Saved when paid annually.
March 24, 2015

physics
E = emf = 24V. R1 = 5 Ohms R2 = 9 Ohms R3 = 12 Ohms a. 1/Req = 1/R1 + 1/R2 + 1/R3 1/Req = 1/5 + 1/9 + 1/12 = 0.3944444 Req = 2.535 Ohms b. It = I1+I2+I3 = E/Req = 24/2.535 = 9.47A I2 = 12/9 * I3 = 1.33I3 I1 = 12/5 * I3 = 2.4I3 I3 + 1.33I3 + 2.4I3 = 9.47 4.733I3 = 9.47 I3 = 2....
March 23, 2015

Math
A. 2x + 3y = 7 -x + 2y = -7 Multiply Eq2 by 2 and add the Eqs. 2x + 3y = 7 -2x + 4y = -14 sum = 7y = -7 Y = -1 In Eq1, replace y with -1 and solve for x: 2x + 3*(-1) = 7 2x = 10 X = 5 P(5,-1) B. P(5,-1), Q(-9,2). D^2=(-9-5)^2 + (2-(-1))^2=196 + 9 = 205 D = 14.3 Y = mx + b m...
March 23, 2015

physics
a1 = 10,000/500 = 20 m/s^2 a2 = 14,000/780 = 17.95 m/s^2 500 kg boat moves faster.
March 23, 2015

physics
M*g = 20 * 9.8 = 196 N. = Wt. of box. Fp = 196*sin3 = 10.26 N. = Force parallel to the incline. Fn = 196*Cos3 = 195.7 N. = Force perpendicular to the incline. Fk = u*Fn = 0.1 * 195.7 = 19.57 N. = Force of kinetic friction. a = (Fap-Fp-Fk)/M = (50-10.26-19.57)/20 =1.01 m/s^2 V^...
March 23, 2015

Physics
Fx - Fk = M*a Fex*Cos24 - 25 = M*0 = 0 Fex*Cos24 = 25 Fex = 27.4 N. = Force exerted Work = Fx*d = 27.4*Cos24 * 18 = 450.6 Joules
March 22, 2015

physics
a = Fap-Fk)/M = (150-95)/46 = 1.20 m/s^2
March 22, 2015

pre algebra
2.Add all like-terms: 2x^2-6x^2 = -4x^2 -4x+3x = -x 8 + 7 = 15 Results: -4x^2 - x + 15 3. Add all like-terms:
March 22, 2015

Vector
a. Tan A = Y/X = 10/26 = 0.38462 A = 21.04o E of N. Tan A = d/150 d = 150*Tan 21.04 = 57.7 m = Distance downstream. b. To offset the affect of the current, the swimmer must head 21.04o W. of N. Vsc = Vs + Vc = 26i Vs + 10 = 26i Vs = -10 + 26i Tan A = 26/-10 = -2.600 X = -68.96...
March 22, 2015

physics
M1*V1 + M2*V2 = M1*V3 + M2*V4 0.4*0 + 0.50*V2=0.40*1.4[37o] + 0.5*1.86 0 + 0.50V2 = 0.447 + 0.337i + 0.93 0.5V2 = 1.377 + 0.337i V2 = 2.754 + 0.674i V2 = sqrt(2.754^2+0.674^2) m/s
March 21, 2015

sicence
V^2 = Vo^2 + 2g*h Vo = 0 g = +9.8 m/s^2 h = 4 m. Solve for V.
March 21, 2015

physics
Va = 120revs/10s * 6.28rad/rev = 75.36 rad/s. = Angular velocity. a = (V-Vo)/t = (75.36-0)/10=7.54 rad/s^2
March 21, 2015