Sunday

November 23, 2014

November 23, 2014

Total # Posts: 9,581

**math **

for the line segment whose endpoints are r(1,2) and s(6,7), find the point located 3/4 the distance from r to s.
*March 26, 2014*

**math 2**

Thank you so much reiny : )
*March 26, 2014*

**math 2**

A segment with endpoints C (3,4) and D (11,3) is divided by a point E such that CE and DE form a 3:5 ratio. Find E.
*March 26, 2014*

**math**

So I continued working where you left off and got y=0.5x+2.5 is that correct? or is it y=0.5x-2.5? I am pretty sure that it is the first one but I just wanna make sure.
*March 26, 2014*

**math**

Write an equation of a line perpendicular to line AB below in slope-intercept form that passes through the point (7, 6). A (0,1) B (-2,5)
*March 26, 2014*

**Math**

Wow thanks! It is correct! :D
*March 26, 2014*

**Math**

Write an equation of a line perpendicular to y=1/2x-5 in slope-intercept form that passes through the point (2, -7).
*March 26, 2014*

**6th Grade Math**

Blue = 3/10 Red = 4/10 = 2/5 Green = 3/10
*March 26, 2014*

**Physics**

h = Vo*t + 0.5g*t^2 = 2 m. 0 + 4.9*t^2 = 2 t^2 = 0.4082 t = 0.639 s. = Fall time. V = Vo + g*t = g*t. g = 10 m/s^2 Use the following points for graphing. (t,v) = (0,0), (0.2,2), (0.3,3),(0.5,5), (0.6,6).
*March 26, 2014*

**math**

P = (Po*r*t)/(1-(1+r)^-t) Po = Initial principal = $199,000 r = (7.01%/12)/100% = 0.00584 = Monthly % rate expressed as a decimal. t = 25yrs * 12mo/yr. = 300 Months. Plug the above values into the given Eq. and get: P = $422,328.10 Int.(Tot.) = P-Po = $223,328.10 Monthly ...
*March 26, 2014*

**Physical science**

See Related Questions: Wed,9-25-13,3:20 PM.
*March 26, 2014*

**physics**

Ingrid: 2h, 21min, 06s = Blake-: 2h, 06min, 50s = 2h, 20min, 66s 2h, 06min, 50s Diff. = 14min, 16s. = = 14.267min = Blake's winning margin. Tb = 120 + 6 + 50/60 = 126.833min = Blake's time. Vb = d/Tb = 42,195m/126.833min = 332.681 m/min = Blake's speed. d = 332....
*March 25, 2014*

**physics**

See Related Questions: Fri,3-21-14,8:55 PM.
*March 24, 2014*

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt. of box. Fn = 1127*cos46 = 782.9 N. = Normal force.
*March 24, 2014*

**physics**

Circumference = pi*D = 3.14 * 0.7m = 2.20 m. b. Va = 2m/s * 6.28rad/2.20m=5.71 rad/s = Angular velocity.
*March 24, 2014*

**physics**

h = (V^2-Vo^2)/2g = (0-(8^2))/-19.6 = 3.27 m.
*March 24, 2014*

**physics**

d = 0.5g*t^2 = 20-12 = 8 m. 4.9t^2 = 8 t^2 = 1.63 t = 1.28 s. = Fall time. Range = V*t = 4m/s * 1.28s = 5.12 m. 5.12m > 5 m. Therefore, he will make it.
*March 23, 2014*

**math**

Eq1: 5x - y = 20 Eq2: 4x + 3y = 16 Multiply Eq1 by 3 and add the Eqs: 15x - 3y = 60 +4x + 3y = 16 Sum: 19x = 76 X = 4 In Eq1, replace x with 4 and solve for y: 5*4 - y = 20 20-y = 20 Y = 0. Solution: (x,y) = (4,0).
*March 23, 2014*

**physics**

See Related Questions:Fri,3-21-14,8:55PM
*March 23, 2014*

**Physics**

Vo = 50m/s[37o] Xo = 50*cos37 = 39.93 m/s. Yo = 50*sin37 = 30.09 m/s. Tr = (Y-Yo)/g = (0-30.09)/-9.8 = 3.07 s = Rise time. Tf = Tr = 3.07 s. = Fall time. T = Tr+Tf = 3.07 + 3.07 = 6.14 s. = Time in air. d = Xo*T = 39.93m/s * 6.14s = 245.2 m. = Total dist. traveled.
*March 23, 2014*

**trigonometry**

The ladder is the hyp. of a rt. triangle X = ? Y1 = 8 Ft. Y2 = 84-8 = 76 Ft. A = 60o Tan 60 = Y2/X = 76/X X = 76/Tan60 = 43.88 Ft. = Dist. from bldg.
*March 23, 2014*

**Physics**

h=(V^2-Vo^2)/2g = (0-(8^2))/-19.6=3.27 m
*March 23, 2014*

**physics**

V = d/t = (t^3-3t^2+2)/4=(4^3-3*4^2+2)/4 = 4.5 m/s.
*March 23, 2014*

**physics**

a. 1.5km * 1000m/km * 1*10^6um/m = 1.5*10^9 Microns. b. 1.5um * 1m/10^6um * 100cm/m = 1.5*10^-4 cm c. 1.5yds * 3Ft/yd * 1m/3.3Ft * 10^6um/m = 1.364*10^6 Microns.
*March 23, 2014*

**physics**

h=(V^2-Vo^2)/2g = (0-(-8^2)/-19.6 = 3.27 m.
*March 23, 2014*

**physics**

T = 3 25/60 + (7 35/60-3 25/60) T = 3.417 + (7.583-3.417) = 7.583 Min. = 455 s. t = (7.583-3.417)min * 60s/min = 250 s. d = V*t = 1.65m/s * 250s = 412.4 m. V = d/T = 412.4m/455s = 0.906 m/s.
*March 23, 2014*

**math**

Given: F(x) = 1 - 3x. g(x) = x^2 - 1. F(g(x)) = F(x^2-1) F(x^2-1) = 1 - 3(x^2-1) = 1 - 3x^2 + 3 = -3x^2 + 4 F(g(x)) = -3x^2 + 4
*March 22, 2014*

**physics**

m*g = 50 * 9.8 = 490 N. = Wt. of crate = Normal force (Fn). a. Fs = u*Fn + u*F*sin30 Fs = 0.75*490 + 0.375F = 367.5 + 0.375F F*cosA-Fs = m*a F*cos30-(367.5+0.375F) = m*0 = 0 0.866F-367.5-0.375F = 0 0.866F-0.375F = 367.5 0.491F = 367.5 F = 748.5 N b. Fs = 0.75*490 - 0.75*F*...
*March 21, 2014*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 20^2 - 19.6*15 = 106 V = 10.30 m/s.
*March 21, 2014*

**physics**

a = (V^2-Vo^2)/2d a = (0-(56)^2)/0.036 = -87,111 m/s^2 F = m*a = 850 * (-87,111)=-74,044,444 N.
*March 21, 2014*

**Physics**

V = 25 + 4 = 29 km/h.
*March 21, 2014*

**Math**

Vo = 200 Ft/s = Initial velocity. g = 2*(-16) = -32 Ft/s^2. hmax = (V^2-Vo^2)/2g = (0-(200)^2)/-64 = 625 Ft. Yes, because his max. ht. is greater than the ht. of the building.
*March 20, 2014*

**math**

C = pi*2r = (22/7) * 2(7n-21) C = (44/7) * (7n-21) = (308n - 924)/7 = 44n - 132
*March 20, 2014*

**physics**

m*g = 30 * 9.8 = 294 N. = Wt of cabinet. Fs = u*mg = 0.8 * 294 = 235.2 N.
*March 20, 2014*

**Math Help**

1. x^2 - 10x + 25 = 0 25 = -5 * -5 (x-5)(x-5) = 0 x-5 = 0 X = 5 x-5 = 0 X = 5 Solution set: X = 5, and 5. 2. 2x^2 + 9x -5 = 0 A*C = 2 * -5 = -10 = -1*10 2x^2 + (-x+10x) - 5 = 0 (2x^2-x) + (10x-5) = 0 x(2x-1) + 5(2x-1) = 0 (2x-1)(x+5) = 0 2x-1 = 0 2x = 1 X = 1/2 x+5 = 0 X = -5 ...
*March 20, 2014*

**Quick math help**

1. (3p^5*5p^2) + (7p^3*2p^4) = 15p^7 + 14p^7 = 29p^7 2. (6x^2-2xy+3y^2)-(4x^2-xy-y^2) = 6x^2-2xy+3y^2 -4x^2+xy+y^2 = 2x^2 - xy + 4y^2
*March 20, 2014*

**physics**

See previous post.
*March 20, 2014*

**physics**

When resistors are connected across a voltage source, the voltage will remain constant if the internal resistance of the source is much smaller than the total resistance connected across the source.
*March 20, 2014*

**Physics**

Correction: F*cosA-Fp = m*a F*cos46-810.7 = m*0 = 0 F*cos46 = 810.7 F = 1167 N.
*March 20, 2014*

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt of box. Fp = 1127*sin46 = 810.7 N. = Force parallel to the ramp. F-Fp = m*a F - 810.7 = m*0 = 0 F = 810.7 N. Fn = 1127*cos46 = 782.9 N. = Normal force.
*March 20, 2014*

**Physics**

30days * 24h/day = 720 Hours kW * h = (60/1000)kW * 720h = 43.2 kWh Cost = 43.2kWh * 0.10/kWh = $4.32
*March 20, 2014*

**physics**

A + B = 220[0o] + 220[120o] R = 220 + 220*cos120 + (220*sin120)I = 220-110 + 190.5i = 110 + 190.5i = 220[60o].
*March 20, 2014*

**Physics**

Fo = ((Vs+Vo)/(Vs-Vt))*Ft = 122 Hz ((340+0)/(340-Vt))*118 = 122 (340/(340-Vt))*118 = 122 40,120/(340-Vt) = 122 41,480-122Vt = 40,120 -122Vt = 40,120 - 41,480 = -1360 Vt = 11.15 m/s. = Velocity of the train.
*March 20, 2014*

**physics**

Speed = 1/0.005 = 200 On-States/s.
*March 20, 2014*

**Science**

d = V*T = 7.83*10^10 m. 3*10^8m/s * T = 7.83*10^10 T = 2.61*10^2 = 261 s. = 4.35 min.
*March 20, 2014*

**Algebra**

See previous post.
*March 19, 2014*

**Algebra**

F(-5,1), V(-2,1) VF = -5-(-2) = -3 = 1/4a 1/4a = -3 4a = -1/3 a = -1/12 = p. X = a(y-k)^2 + h X = (-1/12)(y-1)^2 - 2. Vertex Form.
*March 19, 2014*

**Physics**

X = -69 km/h Y = 215 km/h Tan Ar = Y/X = 215/-69 = -3.11594 Ar = -72.21o = Reference angle. A = -72.21 + 180 = 107.8o V=Y/sinA = 215/sin107.8=225.8km/h[107.8]
*March 19, 2014*

**phsyics**

Coefficient of Linear Exp.=(3.6*10^-5)/3 = 1.2*10^-5/C. L = Lo + a*(T-To)Lo L = 17 + 1.2*10^-5*(5-100)17 = 17 - 0.0194 = 16.981 m.
*March 19, 2014*

**Dont I need more info for this Math problem??**

Since the compounding frequency was not given, you'll have to use simple interest. P = Po + Po*r*t P=2,000 + 2000*0.03*4=2000 + 240 = 2240. Always show the Eq before plugging-in the values.
*March 19, 2014*

**phsyics**

a. Circumference = pi*2r = 3.14*2r = 6.28r V = C/t = 2pi*r/t b. V = 6.28*100m/14s = 45 m/s.
*March 19, 2014*

**phsyics**

a. V = Vp+Vw = 60 + (-40) = 20 km/h. b. V = 60 + 40 = 100 km/h.
*March 19, 2014*

**physics**

Vb = (Dc/Dw)*Vc = (100/1000)*Vc = 3 m^3 0.1Vc = 3 Vc = 30 m^3. = Vol. of cylinder.
*March 19, 2014*

**Physical Science**

P = V*I = 110 * 15
*March 19, 2014*

**physics**

Vo = 6.93 m/s[45.6o] Xo = 6.93*cos45.6 = 4.85 m/s Yo = 6,93*sin45.6 = 4.95 m/s. h = (Y^2-Yo^2)/2g = (0-4.95^2)/-19.6 = 1.25 m.
*March 19, 2014*

**physic**

a. KE = 0.5m*V^2 = 0.5m*0 = 0 J. The velocity is zero at the max. ht. b. V^2 = Vo^2 + 2g*h V^2 = 41.8^2 - 19.6*(34.5-8.88) V^2 = 1245.09 V = 35.29 m/s.
*March 19, 2014*

**Physics**

V^2 = Vo^2 + 2g*h = 0 at peak. Vo^2 - 19.6*16.6 = 0 Vo^2 = 325.4 Vo = 18.04 m/s = Speed at which ball was kicked.
*March 18, 2014*

**PHysiscs**

Fn = m*g = (83.5+68+62+55) * 9.8
*March 18, 2014*

**Maths**

10km[0o].
*March 18, 2014*

**Physics**

Circumference = pi * 2r = 3.14 * 0.20 = 0.6283 m/rev. Va = 24m/s * 6.28rad/0.6283m = 240 rad/s = Angular velocity. V = 24m/s * 1rev/0.6283m * 60s/min = 2292 RPM.
*March 17, 2014*

**Physics**

Circumference = pi * 2r = 3.14 * 0.620 = 1.95 m/rev. 8.5*10^7m * 1rev/1.95m = 4.36*10^7 Revs = 43.6 Million Revs.
*March 17, 2014*

**Physics**

a. Y^2 = Yo^2 + 2g*h = 0 m/s @ max. ht. Yo^2 - 19.6*0.750 = 0 Yo^2 = 14.7 Yo = 3.83 m/s. = Initial ver. velocity. b. Y = Yo + g*Tr = 0 m/s @ max. ht. Y = 3.83 - 9.8Tr = 0 9.8Tr = 3.83 Tr = 0.3908 s. = Rise time. Dx=Xo * Tr = 5m/s * 0.3908s. = 1.95 m. From basket.
*March 17, 2014*

**Physics**

Range = Vo^2*sin(2A)/g = 78 m. 34^2*sin(2A)/9.8 = 78 Solve for A.
*March 17, 2014*

**PHYSICS**

See previous post: Mon,3-17-14,8:03 PM.
*March 17, 2014*

**Physics**

m*g = 20 N. m = 20/g = 20/9.8 = 2.041 kg A. Work = 0.5m*Vo^2 - 0.5m*V^2 = mg*h 1.02*Vo^2 - 1.02*25^2 = 20*14.8 1.02Vo^2 - 637.5 = 290 1.02Vo^2 = 290 + 637.5 = 927.5 Vo^2 = 909.31 Vo = 30.15 m/s. B. h = (V^2-Vo^2)/2g = (0-30.15^2)/-19.6 = 46.38 m.
*March 17, 2014*

**physics**

Ratio = (331+0.6T1)/(331+0.6T2) = (331+0)/(331+60) = 0.847
*March 17, 2014*

**math**

-16t^2 + 120t = 0 Use Quadratic Formula and get: Tr = 3.75 s. = Rise time or time to reach max ht. Tf = Tr = 3.75 s. = Fall time. T = Tr + Tf = 3.75 + 3.75 = 7.50 s. To strike gnd.
*March 17, 2014*

**physics**

1. 15 - 6 = 9 N. = Net force. 2. a = Fn/m = 9/3 = 3 m/s^2.
*March 16, 2014*

**physics**

F = m*a = 60 * 2.5 = 150 N. V = Vo + a*t = 0 + 2.5*4 = 10 m/s.
*March 14, 2014*

**physics**

a=(V^2-Vo)/2d = (0-20^2)/1000=-0.4 m/s^2 F = m*a = 10000 * -0.4 = -4,000 N.
*March 14, 2014*

**Physics**

V = Vo + a*t = 0 + 0.3*30 = 9 m/s. d = (V^2-Vo^2)/2a = (9^2-0)/0.6 = 135 m.
*March 14, 2014*

**math**

F(x) = 5x^2 + 8x + 5 = 0 Quadratic Formula: X = (-B +- sqrt(B^2-4AC))/2a X = (-8 +- sqrt(64-100))/10 = (-8 +- sqrt(36*(-1))/10 = (-8 +- 6i)/10 = -0.8 +- 0.6i = -0.8 + 0.6i, and -0.8 - 0.6i. So we have 2 imaginary solutions.
*March 14, 2014*

**math**

x^2 + 5x - 2 < 0 Solve and graph: x^2 + 5x - 2 = 0 Use Quadratic Formula an get: X = -5.37, and 0.372 Solution to inequality:-5.37 < X < 0.372
*March 14, 2014*

**physics**

m*g = 15.7 * 9.8 = 153.9 N. = Wt. of block. Fn = 153.9*cos12.1 = 150.4 N.
*March 14, 2014*

**Physics**

PEmax=mg*hmax = 28*9.8 * 159=43,630 J. = KEmax @ bottom of hill with no friction. KE = 14*31.3^2 = 13,716 J. Energy lost = 43,630 - 13,716=29,914 J.
*March 14, 2014*

**physics-impulse**

Impulse = 2*m*V*cos45
*March 14, 2014*

**Physics**

Energy = m*g*h.
*March 14, 2014*

**math**

0.002N = 76 N = 38,000
*March 14, 2014*

**math**

GP = 22/day*6days + 0.18*2766.50 =
*March 14, 2014*

**Physics**

m*g = 295 * 9.8 = 2891 N. = Wt. of box. = Fn = Normal force. Fs = u*Fn = 0.2 * 2891 = 578.2 N. = Force of static friction. Fe-Fs = m*a Fe - 578.2 = m*0 = 0 Fe = 578.2 N. = Force of engine. Energy=Work = Fe*d = 578.2 * 2.8=1619 J.
*March 14, 2014*

**Algebra**

1. 18 = 1*18 = 1*2*9 = 1*2*3*3. Factors: N = {1,2,3,9,18}. 3a. 5.25x => 252 4a. Inequality: 88 < (78+93+x)/3 < 90 264 < 171 + x < 270 93 < X < 99 The inequality says: (78+93+x)/3 is greater than 88 but less than 90.
*March 13, 2014*

**physics**

V = Vo + g*t = 0 + 9.8*3 = 29.4 m/s
*March 13, 2014*

**phys**

m*g = 12kg * 9.8N/kg = 117.6 N. = Wt. of the crate. Fs = u*mg = 0.4 * 117.6 = 47.04 N. = Force of static friction. F*cos(-30) - Fs = m*a 0.8669F - 47.04 = m*0 = 0 0.866F = 47.04 F = 54.32 N.
*March 12, 2014*

**Science... plz help~!**

F = m*a = 40 * 10 = 400 N.
*March 12, 2014*

**finance**

P = Po*r*t/(1-(1+r)^-t) Po = $13,000 = Loan amount. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. t = 12mo/yr * 10yrs = 120 Months. P = (13000*0.005*120)/(1-(1.005)^-120) = $17,319.20 = Amt. to be paid. Monthly Payment = P/t = 17319.20/120 = $144.33 Payment...
*March 12, 2014*

**Gr 11 - math linear systems**

(10-2)x - 2000 = $16,000 8x - 2000 = 16000 8x = 18000 X = 2,250 Tickets.
*March 11, 2014*

**math**

2. Shifted 5units down. 5. -7x^2 + 6x + 3 = 0 Use Quadratic formula and get 2 solutions : -0.354, and 1.211. 6. Y = 3x^2 + 18x + 27 = 0 x^2 * 6x + 9 = 0 (x+3)(x+3) = 0 x+3 = 0, x = -3. x+3 = 0, X = -3. 2 solutions : -3, and -3. 11. Use Quad. Formula and get 3.54 s. 12. V = Vo...
*March 11, 2014*

**physics**

V = Vo + g*t = 0 + 10*1=10 m/s. T = 1s. d = Vo*t + 0.5g*t^2 d = 10*1 + 5*1^2 = 15 m.
*March 11, 2014*

**physics**

My answer is B also.
*March 11, 2014*

**Physics**

P = 16/12 = 1.333 s.
*March 11, 2014*

**Physics**

d = V*t = 305 m. V*(1.85/2) = 305 V = 329.7 m/s.
*March 11, 2014*

**physics**

a = (V-Vo)/t = (-8-16)/0.04 = -600 m/s^2 F = m*a = 0.2 * (-600) = -120 N.
*March 11, 2014*

**physics**

Xo = 0.9 m/s? D = Xo*t = 0.9m/s * 0.4s = 0.36 m.
*March 11, 2014*

**physics**

B. 10 m/s, North.
*March 11, 2014*

**physics**

PEmax = mg*hmax = mg*4.07 J. Change = 0-mg*4.07 = -3900 mg = 958.2 N. = Wt. of the vaulter.
*March 11, 2014*

**math**

Fp = 1.5*sin18 = Parallel Force(Wt.) Fn=1.5*cos18 = Normal or perpendicular force(Wt.).
*March 11, 2014*

**physics**

Fh = 151 Hz Vr = 28.7 m/s Vs = 343 m/s Fr = ((Vs+Vr)/(Vs-Vh)) * Fh Fr = ((343+28.7)/(343-0)) * 151 Hz = (371.7/343) * 151 = 163.6 Hz = Freq. heard by the receiver(Passenger).
*March 11, 2014*

**Physics**

P = F*d/t = 0.5 * 2.1/1.1 = 0.955 J/s = 0.955 Watts.
*March 10, 2014*

**Physics!**

PE = F*h = mg*h = 1.2*9.8 * 4 = 47.04 J.
*March 10, 2014*

**Science**

LiOH + W = 231 grams 33.7 + W = 231 W = 197.3 Grams of water. Concentration = LiOH/(W+LiOH) = 33.7/231 = 0.146 = 14.6%
*March 10, 2014*

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