Wednesday

May 25, 2016
Total # Posts: 11,830

**Physics**

M*g = 40*9.8 = 392 N. = Wt. of sled. Fp = 392*sin 0 = 0 = Force parallel to the surface. Fn = 392*Cos 0 = 392 N. = Force perpendicular to the surface. Fs = u*Fn = 0.4 * 392 = 156.8 N. = Force of static friction. Fk = 0.25 * 392 N. = 98 N. = Force of kinetic friction. a. Fap-Fs...
*May 6, 2015*

**Trig**

sec A * sin A = 1/Cos A * sin A = Sin A/Cos A = Tan A.
*May 6, 2015*

**Physics**

X = 4 km/h Y = 3 km/h V = sqrt(X^2+Y^2)
*May 5, 2015*

**IDOC**

1/b(2b-10) = 17 Multiply both sides by b: 2b-10 = 17b 15b = -10 b = -2/3
*May 5, 2015*

**IDOC**

Multiply both sides by b: 2b-10 = 17b
*May 5, 2015*

**Physics**

V^2 = Vo^2 + 2g*h Vo = 12 m/s. g = -9.8 m/s^2 h = 5 m. V = ?
*May 5, 2015*

**science**

X = 3 km Y = 4 km D = sqrt(X^2+Y^2)
*May 5, 2015*

**chemistry**

what is the volume occupied by 2 moles of ammonia at s.t.p(1mole of gas at s.t.p=22.4)
*May 4, 2015*

**Physics**

I = 24/8 = 3A = Lamp current. Vr = 117-24 = 93 V. = Voltage across the resistor. R = Vr/I = 93/3 = 31 Ohms.
*May 4, 2015*

**math**

V = Vo(1-r)^t = 35,000/2 35,000(1-0.12)^t = 17,500 Divide both sides by 35,000: (0.88)^t = 0.5 Take Log of both sides: t*Log(0.88) = Log 0.5 t = Log 0.5/Log(0.88) = 5.42 Years.
*May 4, 2015*

**science**

Work = F*d = Mg*d = 80*9.8 * 6 = 4704 J
*May 3, 2015*

**math**

a. 19/20 - 5/8 - 7/10 = 38/40 - 25/40 - 28/40 = -15/40 = -3/8. b. (24/40)/(30/14)(25/63) = (3/8)/(15/7)(25/63) = (7/8)/(375/441) = 7/8 * 441/375 = 3087/3000 = 1029/1000 c. (-24/1)(1/1)(-1/1)(1/1)(-1/1)(1/30) = -24/30 = -4/5.
*May 1, 2015*

**Math**

22/7
*May 1, 2015*

**Physics**

1A = 1C/s 1.1*10^-3A = 1.1*10^-3 C/s. T = 3.40C * 1s/1.1*10^-3C = 3090 C.
*April 30, 2015*

**Math**

There appears to be a typo in your problem. So I'm assuming b = h = 14 in. At = bh/2 = 14*14/2 = 98 in^2 = Area of triangle. As = 7^2 = 49 in^2 = Area of the square. Ar = At-As = 98 - 49 = 49 in^2 = Area remaining.
*April 30, 2015*

**Consumer math**

I = Po*r*t = 4000*(0.095/360)*270 = $285
*April 30, 2015*

**Financial math**

Po = 0.80 * 235,000 = $188,000 P = (Po*r*t)/(1-(1+r)^-t) r = (4.5%/12)/100 = 0.00375 = Monthly % rate expressed as a decimal. t = 30yrs. * 12mo/yr. = 360 Months. Monthly Payments = P/t
*April 30, 2015*

**algebra**

(y+4)/3 + 6 = (3y-1)/4 - 2 4(y+4)/12 + 6 = 3(3y-1)/12 - 2 (4y+16)/12 + 6 = (9y-3)/12 - 2 Multiply both sides by 12: 4y + 16 + 72 = 9y - 3 - 24 4y - 9y = -27 -88 -5y = -115 Y = 23
*April 30, 2015*

**Math**

A.12mo/yr. * 10yrs. = 120 months I = Po*r*t = 20,000*(0.04/12)*120 = B. 360days/yr * 5yrs. = 1800 days I = 20,000*(0.08/360)*1800 =
*April 30, 2015*

**Physics**

P = 8.8*10^6 * 19*10^-3 =
*April 30, 2015*

**Physics**

Glad I could help!
*April 30, 2015*

**Physics**

a = F/M = 152/0.07 = 2171 m/s^2 V = Vo + a*t Vo = 0 a = 2171 m/s^2 t = 0.030 s. V = ? KE = o.5*M*V^2
*April 30, 2015*

**physics**

See Related Questions: Thu, 4-21-11, 9:53 AM.
*April 30, 2015*

**physics**

Dx = Xo*Tf = 200 m. 400 * Tf = 200 Tf = 0.5 s. = Fall time. d = 0.5g*Tf^2 = 4.9*0.5^2 = 1.23 m.
*April 29, 2015*

**science**

Incomplete.
*April 29, 2015*

**physics**

1. V^2 = Vo^2 + g*h V = 0 Vo = 50 m/s g = -9.8 m/s^2 h = ? 2. V = Vo + g*Tr = 0 Tr = -Vo/g = -50/-9.8 = 5.1 s. = Rise time = Time to reach max ht. 3. Tf = Tr = 5.1 s. = Fall time. Tr + Tf = 5.1 + 5.1 = 10.2 s. = Time in flight.
*April 29, 2015*

**Math**

V = sqrt(90*60*54) = 540 in^3
*April 29, 2015*

**physical science**

D = 90 Ft.
*April 29, 2015*

**math**

V = sqrt(90*54*60) = 540 Cubic units.
*April 29, 2015*

**physics**

V^2 = Vo^2 + 2g*h V = 0 Vo = 1.2 m/s g = -9.8 m/s^2 h = ?
*April 29, 2015*

**physics**

Distance from each end to the center = 5/2 = 2.5 m. 2.5 - 1.5 = 1.0 m from center. 40*1 = 25*d d = 1.6 m from center = 0.9 m from the end.
*April 29, 2015*

**trig**

Vpw = 630mi/3h = 210m1/h, Due North Vpw = Vp + Vw = 210i Vp + 15[318o] = 210i Vp + 15*Cos318+15*sin318 = 210i Vp + 11.15 -10i = 210i Vp = -11.15 + 210i + 10i = -11.15 + 220i ,Q2. Tan A = 220/-11.15 = -19.73094 A = -87.1o = 87.1o N. of W. = 92.9o CCW from + x-axis. = 2.9o W. of...
*April 28, 2015*

**algebra**

T1 = 5 h T2 = 6 h T = T1*T2/(T1+T2) = 30/11 = 2.73 h.
*April 28, 2015*

**geometry**

Area = pi*r^2 When the radius is doubled: Area = pi * (2r)^2 = pi * 4r^2. Therefore, the area is 4 times the original value.
*April 27, 2015*

**geometry**

Circumference = pi*2r = pi*Dia. = 3.14 * 50 = 157.1 Ft. When the radius is doubled, the diameter is also doubled. Therefore, the Circumference is doubled: Circumference = 3.14 * 100 = 314.2 Ft.
*April 27, 2015*

**Math 222**

See your previous post.
*April 27, 2015*

**Math 222**

See your previous post.
*April 27, 2015*

**Physics**

V = a*t = 10 * 3 = 30 m/s KE = 0.5*M*V^2 Solve for KE
*April 27, 2015*

**math- algebra**

5x > 2x + 18 5x-2x > 18 3x > 18 X > 6 Note: Any real value of X greater than 6 will satisfy the inequality.
*April 27, 2015*

**Math**

Correction: If Sin A = -0.204 A = -11.8o = 11.8o N. of W. = 168.2o CCW from + x-axis; Q2. If Sin A = 0.204 A = 11.8o S. of W. = 191.8o CCW from + x-axis.
*April 27, 2015*

**Math**

sin A = -0.204 A = -11.8o = 11.8o W. of S. = 258.2o CCW from + X-axis.
*April 27, 2015*

**Math 222**

x = -1 x+1 = 0 x = -2 x+2 = 0 (x+1)(x+2) = 0 x^2 + 2x + x + 2 = 0 x^2 + 3x + 2 = 0
*April 27, 2015*

**Math 222**

y^2 - 18y + (-18/2)^2 y^2 - 18y + 81
*April 27, 2015*

**physics**

See Related Questions: Mon, 2-11-13, 12:22 PM.
*April 27, 2015*

**physics**

E = 18 V. R1 = 61 Ohms R2 = 34 Ohms R3 = 90 Ohms R4 = 11 Ohms I2 = ? Req. = R4 + (R1+R2)R3/(R1+R2+R3) Req. = 11 + (95)90/185 = 11 + 46.22 = 57.22 Ohms. I4 = E/Req. = 18/57.22 = 0.315A I2 + I3 = 0.315A I3 = 95/90 * I2 = 1.056I2 I2 + 1.056I2 = 0.315 2.056I2 = 0.315 I2 = 0.1532A
*April 26, 2015*

**PHYSICS**

M1*V1 + M2*V2 = M1*V + M2*V 16.6*8.92 + 29.2*4.44i = 16.6V + 29.2V 148.1 + 129.6i = 45.8V 196.8[41.2o] = 45.8V V = 4.3 m/s[41.2o] a. Momentum = 196.8 kg-m/s b. Direction = 41.2o N. of E.
*April 26, 2015*

**Physics**

First arrow: V = Vo + g*Tr = 0 Tr = -Vo/g = -10/-10 = 1.0 s.=Rise time So #2 is shot at the same time #1 starts falling. h = Vo*Tr - 0.5g*Tr^2 h = 10*1 - 5*1^2 = 5 m. ho-0.5g*t^2 = Vo*t + 0.5g*t^2 5 - 5*t^2 = 15*t - 5*t^2 5 - 5t^2 + 5t^2 = 15t The 5t^2 terms cancel: 15t = 5 t...
*April 26, 2015*

**PHYSICS ANSWER CHECK**

Vo = 60mi/h * 1600m/mi * 1h/3600s = 26.67 m/s V = Vo + a*t = 0 a = -Vo/t = -26.67/2.6 = -10.26 m/s^2 M = 3225Lbs * 0.454kg/1Lb = = 1464 kg F = M*a = 1464 * (-10.26) = -15,022 N. Note: Your answer would have been correct if you had converted 60 mph to m/s.
*April 25, 2015*

**PHYSICS answer check**

See previous post: Thu, 4-23-15, 6:12 PM.
*April 25, 2015*

**physics**

Rate of doing work = power. P = Fe*Cos21 * V P = 2.3*Cos21 * 7.9 = 17 J/s = 17 Watts.
*April 25, 2015*

**maths**

2 bags 6 Pouches Pouch cost $X each. Bag cost $(X+24) each. 2(x+24) + 6*x = $568 Solve for x.
*April 25, 2015*

**PHYSICS**

KE = 0.5M*V^2 = 0.5*0.025*80^2 = 80 J. F*d = F*1 = 80 J. F = 80 N.
*April 24, 2015*

**Math**

A(-8, 12), M(x, y), B(-13, -2) X = ((-8) + (-13))/2 = -10 1/2 = -21/2 Y = (12 + (-2))/2 = 5 M(-21/2, 5)
*April 24, 2015*

**physics**

Req = R1 + R2 + R3 = 13 + 35 + 2000 = 2048 Ohms.
*April 24, 2015*

**Algbra**

d1 = Sarah's distance d2 = Chelsea's distance. d2 = d1 + 55 Vc*T = Vs*T + 55 75T = 55T + 55 20T = 55 T = 2.75 h. = 2h-45 Min.
*April 24, 2015*

**physics**

See previous post: Thu, 4-23-15, 6:12 PM
*April 23, 2015*

**Physics**

a. KE = 0.5*M*Vo^2 KE = 200 J. M = 0.02 kg Solve for Vo, the initial velocity. b. M*g*h = 200 M = 0.02 kg 9 = 9.8 m/s^2 Solve for h.
*April 23, 2015*

**Physics**

Wt. = 0.05kg + 9.8N/kg = 0.49 N.
*April 23, 2015*

**Physics**

Y = Yo + g*Tr = 0 Yo - 9.8*(3.4/2) = 0 Yo = 16.66 m/s = Ver. component of initial velocity. sin A = Yo/Vo sin55 = 16.66/Vo Vo = 16.66/sin55 = 20.34 m/s Xo = Vo*Cos55 = 20.34*Cos55 = 11.67 m/s. V = Xo+Yi = 11.67 + 0 = 11.67 m/s Momentum change = M*V - M*Vo M = 3.0 kg V = 11.67 ...
*April 23, 2015*

**Math--Please help!!**

See previous post: Tue, 4-21-15, :31 PM.
*April 22, 2015*

**Consumer math**

1. 9 2/3 - 1/6=29/3-1/6=58/6 - 1/6=57/6 (57/6)/1/6 = 57/6 * 6/1 = 57 1.10 + 57*0.20 = $12.50 2. 9 - 1/6 = 54/6 = 1/6 = 53/6 1.10 + 53*0.20 = $11.70
*April 22, 2015*

**physics 111**

3. d = V*T = 40 km V*2 = 40 V = 20 km/h 4. Fr = 100N[170o] + 100N[50o] X = 100*Cos170 + 100*Cos50 = -34.2 N. Y = 100*sin170 + 100*sin50 = 94 N. Q2. Tan A = Y/X = 94/-34.2 = -2.74854 A = -70o = 70o N. of W. = 110o CCW Fr = Y/sin A = 94/sin110 = 5. Fap*CosA-Fk = M*a Fap = 40 N. ...
*April 22, 2015*

**physics**

Please read and clarify your problem. What is the vertical acceleration?
*April 22, 2015*

**physics 111**

1. V = Vo + g*Tr = 0 The rise time(Tr) = 1/2 of time in air. Vo = -g*Tr = 10(4/2)= 20 m/s
*April 22, 2015*

**PHYSICS**

Correction: Replace Tan A = Yo/Vo with sin A = Yo/Vo = 21.32/57.4 = 0.37143 A = 21.8o = Launch angle. a. Vo = 57.4m/s[21.8o] Xo = 57.4*Cos21.8 = 53.3 m/s = Hor. component of initial velocity. V = Xo+Yi = 53.3 + 0 = 53.3 m/s at highest point. KE = 0.5*M*V^2 = 0.5*0.0505*53.3^2...
*April 22, 2015*

**PHYSICS**

Y^2 = Yo^2 + 2g*h = 0 Yo^2 = -2g*h = -2*(-9.8)*23.2 = 454.72 Yo = 21.32 m/s = Ver. component of initial velocity. Tan A = Yo/Vo = 21.32/57.4 = 0.37150 A = 20.38o a. Vo = 57.4m/s[20.4o] Xo = 57.4*Cos20.4 = 53.8 m/s = Hor. component of initial velocity. V = Xo + Yi = 53.8 + 0 = ...
*April 22, 2015*

**Science**

F = 30kg/15kg * 5kg = 10 kg.
*April 21, 2015*

**math**

I = Po*r*t = 1100*(0.1/12)*1 = $9.17
*April 21, 2015*

**Personal Finance**

I chose C also.
*April 21, 2015*

**Algebra**

Y = 2x^2 - 7x - 2 h = Xv = -B/2A = 7/4. k = 2*(7/4)^2 - 7*7/4 - 2 = -8.125 = -8 1/8 = -65/8 P(h, k) = (7/4, -65/8).
*April 21, 2015*

**math**

P/3 = $3.00 P = Price.
*April 21, 2015*

**Geometry**

1. Correct 2. Correct 3. Correct!!! You aced it!!
*April 21, 2015*

**Pysics science**

8*Cos40 + 8*sin40 + B = 20 6.13 + 5.14i + B = 20 B = 20 - 6.13 - 5.14i B = 13.87 - 5.14i B = sqrt(13.87^2+5.14^2)
*April 21, 2015*

**Physics**

V^2 = Vo^2 + 2a*d V = 0 Vo = 50km/h = 50000m/3600s = 13.89 m/s d = 35 m. Solve for a. It will be negative.
*April 21, 2015*

**Math**

See previous post: Sun, 4-19-15, 7:26 PM
*April 20, 2015*

**Math**

Bracelet: 28/2 = 14 Green beads. Necklace: 56/4 = 14 Green beads.
*April 20, 2015*

**Physics**

d = 0.5*a*t^2 = 0.5*2*3.54^2 = 12.53 Rad
*April 20, 2015*

**MATH**

See previous post: Sun, 4-19-15, 7:26 PM.
*April 20, 2015*

**Physics**

Note: The Y component of the velocity decreases with time and is zero at the maximum height. The velocity increases as the stone falls. c. Dx = Xo*t = 13.91 * 1.76 = 24.48 m. d. Y = Yo + g*Tr = 0 12.35 - 9.8Tr = 0 9.8Tr = 12.35 Tr = 1.26 s. = Rise time or time to reach max ht...
*April 19, 2015*

**Physics**

Vo = 18.6m/s[41.6o] Xo = 18.6*Cos41.6 = 13.91 m/s Yo = 18.6*sin41.6 = 12.35 m/s a. X = Xo=13.91 m/s and does not change. Dx = Xo*t = 13.91 * 1.06 = 14.74 m. b. Y = Yo + g*t = 12.35 - 9.8*1.06 = 1.962 m/s h = Yo*t + 0.5g*t^2 Yo=12.35 m/s, t = 1.06 s, g=-9.8 m/s^2. Solve for h. ...
*April 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V 11.2i - 18 = 4*V + 5*V = 9V V = -2 + 1.24i = 2.36m/s[31.9o] N. of W. = 2.36m/s[148.1o] CCW Momentum = M1*V + M2*V = 4*2.36[31.9] + 6*2.36[31.9] = 9.44[31.9] + 14.2[31.9o]=23.6m/s[31.9o] N. of W.
*April 19, 2015*

**Math**

I = Po*r*t = 875*(0.1425/12)*8 = $83.13
*April 19, 2015*

**science**

V = 60 mi/h * 1613m/mi * 1h/3600s = 26.9 m/s. V = Vo + a*t V = 26.9 m/s. Vo = 0 a = 2m/s^2 Solve for t.
*April 19, 2015*

**physics**

d = 110 - Vo*t = 110 - 20*0.7 = 96 m.
*April 19, 2015*

**algebra**

Multiply Eq2 by -4 and add Eq1 and Eq2: 2x + 4y + 2z = 144 -16x - 4y - 2z = -480 Sum: -14x = -336 X = 24 Multiply Eq1 by -2; add Eq1 and Eq3: -4x - 8y - 4z = -288 +x + 3y + 4z = 144 Sum: -3x - 5y = -144. X = 24. Solve for y: -3*24 - 5y = -144 -72 - 5y = -144 -5y = -144 + 72...
*April 18, 2015*

**science**

See previous post: Thu, 1-22-15, 12:20 AM.
*April 18, 2015*

**Algebra**

x = -1/3 x + 1/3 = 0 x = 3/7 x - 3/7 = 0 (x+1/3)(x-3/7) = 0 x^2 - 3x/7 + x/3 - 1/7 = 0 Multiply by 21: 21x^2 -9x + 7x - 3 = 0 21x^2 - 2x - 3 = 0
*April 17, 2015*

**Algebra**

Use same procedure as previous problem.
*April 17, 2015*

**Algebra**

x^2 - 2x + 2 = 0 X = (-B +- sqrt(B^2-4AC))/2A X = (2 +- sqrt(4-8))/2 X = (2 +- sqrt(-4))/2 X = (2 +- sqrt(4(-1))/2 X = (2 +- 2sqrt(-1)/2 X = (2 +- 2i)/2 = 1 +- i = 1+i, and 1-i. Check: (1+i)^2 - 2(1+i) + 2 = 1 + 2i - 1 - 2 -2i + 2 = 0
*April 17, 2015*

**Algebra**

(x+2)^2 + (x-7)(x-2) = 16 x^2 + 4x + 4 + x^2 - 2x -7x + 14 = 16 2x^2 - 5x + 18 = 16 2x^2 - 5x + 2 = 0 A*C = 2*2 = 4 = (-1)*(-4). Choose the pair of factors whose sum = B 2x^2 - (x+4x) +2 = 0 (2x^2-x) - (4x-2) = 0 x(2x-1) - 2(2x-1) = 0 (2x-1)(x-2) = 0 2x-1 = 0 2x = 1 X = 1/2 x-...
*April 17, 2015*

**Help with Psychology**

To help Karen overcome her fear of thunderstorms, a behavior therapist asks her to relax and imagine watching light rain with distant thunder. The therapist is using... a) client-centered therapy b) cognitive therapy c) systematic desensitization d) aversive conditioning ** ...
*April 17, 2015*

**Physics**

db = 10*Log W/Wo = 100 10*Log W/10^-12 = 100 Log W/10^-12 = 10 Log W - Log 10^-12 = 10 Log W = 10 + Log 10^-12 = 10-12 = -2 W = 10^-2 = 0.01 Watts.
*April 17, 2015*

**physics**

D = 5 + 10[30o] X = 5 + 10*Cos30 = 13.66 m. Y = 10*sin30 = 5 m. D = sqrt(X^2+Y^2) = sqrt(13.66^2 + 5^2) = 14.5 m.
*April 17, 2015*

**Math**

F = M*a = 0.04 * 2.5 = 0.1 N. a = F/M = 0.1/0.050 = 2.0 m/s^2
*April 16, 2015*

**exponential equations**

See previous post: Tue, 4-7-15, 7:04 AM.
*April 16, 2015*

**Physics**

h = 0.5g*t^2 g = 9.8 m/s^2. h = 0.75 m. Solve for t(Fall time). V^2 = Vo^2 + 2g*h Vo = 0 Solve for V. Dx = Xo*t Xo = 1.50 m/s t = Fall time. Solve for Dx
*April 16, 2015*

**math**

One Solution: Add to verify. -3x + 2y = 4 3x + 2y = 4 No Solution: Multiply Eq1 by (-1) and add. -3x + 2y = 4 -3x + 2y = 6 Infinite Solutions: Multiply Eq1 by 3 and compare. -3x + 2y = 4 -9x + 6y = 12
*April 16, 2015*

**College Physics**

See Related Questions: Thu, 8-26-14, 5:07 PM.
*April 16, 2015*

**math**

= 0.36603
*April 16, 2015*

**physics**

2nd Cable Direction = 30o E. of N.
*April 15, 2015*