Wednesday

July 27, 2016
Total # Posts: 11,916

**physics**

The initial velocity is negative,because the stone was moving upward before it began to free fall. In other words, the balloon containing the stone was moving upward as the stone began to move downward. If the stone had been THROWN downward from a stationary object, the ...
*August 25, 2015*

**physics**

See previous post: Sat, 8-22-15, 11:06 AM
*August 25, 2015*

**Physics**

A. V^2 = Vo^2 + 2g*h = 9.5^2 - 19.6*3.6 = 19.69. V = 4.44 m/s. B. V = Vo + g*t = 4.44. 9.5 - 9.8t = 4.44. -9.8t = -5.06. t = 0.533 s.
*August 24, 2015*

**Physics**

M*g = 1.5 * 9.8 = 14.7 N.=Wt. of blk A. a. PE = M*g*h = 14.7*0.5 = 7.35 J. b. V^2 = Vo^2 + 2g*h = 0 + 19.6*0.5 = 9.8. 3.13 m/s. KE = 0.5M*V^2 = 0.5*1.5*3.13^2 = 7.35 J. c. M1*V1 + M2*V2 = M1*V + M2*V. 1.5*3.13 + 1.5*0 = 1.5V + 1.5V. 4.7 + 0 = 3V. V = 1.57 m/s. d. KEa = KEb = ...
*August 24, 2015*

**Physics**

Vo = 20mi/h * 5280Ft/mi * 1h/3600s. = 29.3 m/s. V = 30/20 * 29.3 = 44 m/s. a = (V-Vo)/t = (30-20)/t = 10/t. d = 0.5*a*t^2 = 500 Ft. 0.5*(10/t)*t^2 = 500. 5t = 500. t = 100 s. a = 10/t = 10/100 = 0.10 Ft/s^2
*August 24, 2015*

**Physics**

d1 = d2. V1*t1 = 0.5a*t^2. V1*12 = 0.5*4.4*12^2. Solve for V1(m/s).
*August 23, 2015*

**physics**

See Related Questions: Thu, 9-15-11, 4:06 PM.
*August 23, 2015*

**physics**

d1 = V1*t1 t1 = d1/V1 = 20/30 = 0.667 h. V2=40Ft/s * 1m1/5280Ft * 3600s/h = 27.3 mi/h. t2 = d2/V2 = 20/27.3 = 0.733 h. V3 = 90km/h * 1m1/1.6km = 56.3 mi/h. t3 = d3/V3 = 20/56.3 = 0.355 h. d = d1+d2+d3 = 20 + 20 + 20 = 60 mi. T = t1+t2+t3 = 0.667 + 0.733 + 0.355 = 1.76 h. V = d...
*August 23, 2015*

**Physics**

See previous post: Sat, 8-22-15, 10:49 AM
*August 23, 2015*

**calc**

V = t^2 - 2t = 3^2 - 2*3 = 3 Ft/min. d = V*t = 3Ft./min. * 3min. = 9 Ft.
*August 22, 2015*

**Physics**

h = Vo*t + 0.5g*t^2 = -8*6 + 4.9*6^2 = 128.4 m.
*August 22, 2015*

**Physics**

M*g = 1500 * 9.8 = 14,700 N. = Wt. of block. = Normal(Fn). Fap-Fs = M*a. 200-Fs = M*0 = 0. Fs = 200 N. Fs = u*Fn. u = Fs/Fn = 200/14,700 = 0.0136.
*August 22, 2015*

**physics**

W1*d1 = W2*d2. 10 * 2.5 = 15*d2. d2 = 25/15 = 1.67 m. from the center. d2 = 2.5-1.67 = 0.83 m. from the end.
*August 22, 2015*

**Maths proportions**

1. 9/4.5 = 5/L. Solve for L. 2. 36/20.52 = 120/C. 3. Same procedure as #1and #2. 4. 20 Grams = 0.02 kg. C = 0.020kg * 60/kg = 5. ht. = 623Ft. * 1m/3.281Ft
*August 22, 2015*

**Physics.**

d = V*t.
*August 21, 2015*

**math**

B is my answer also.
*August 21, 2015*

**Algebra**

2x(x-5)^-3(1-2x(x-5)^-1) = 2x/(x-5)^3 * (1-2x/(x-5)) = 2x/(x-5)^3 * ((x-5)/(x-5)-2x/(x-5) = 2x/(x-5)^3 * (-x-5)/(x-5) = 2x(-x-5))/(x-5)^4).
*August 21, 2015*

**Trigonometry and Analysis**

To avoid the decimals: $1.00 = 100 Cents. $0.84 = 84 Cents. 0.01 = 1 Cent.
*August 21, 2015*

**Trigonometry and Analysis**

X Dimes. 2x Pennies. 10*x + 1*2x = 84 Cents. 12x = 84. X = 7 Dimes. 2x = 2*7 = 14 Pennies.
*August 21, 2015*

**Physics**

Vsw = Vs + Vw = 3 + 2i, Q1. Tan A = 2/3 = 0.66667. A = 33.7o E. of N. Body angle = 33.7o W. of N.
*August 21, 2015*

**ALGEBRA**

1b. 3. Divide each price by the wt of the cereal and choose the lowest price: 4.29/28oz = $0.15/oz.
*August 21, 2015*

**Physics**

Range = Vo^2*sin(2A)/g=200^2*sin(60)/9.8 = 3535 m.
*August 21, 2015*

**physics**

V = Vo + a*t = 6 + 1.5*4 = 12 m/s. d1 = Vo*t + 0.5*a*t^2=6*4 + 0.5*1.5*4^2 = 24 + 12 = 36 m. d2 = (V^2-Vo^2)/2a = (0-144)/-2.4=60 m. d = d1+d2 = 36 + 60 96 m.
*August 21, 2015*

**Physics**

See previous post: Thu, 8-20-15, 4:47 PM.
*August 20, 2015*

**Physics**

V=34mi/h * 1609m/mi * 1h/3600s.=15.2 m/s. d = V*t = 80 m. 15.2t = 80. t = 5.3 s.
*August 20, 2015*

**Physics-PLEASE HELP**

d1 = V1*t1 = 1 km. t1 = 1/V1 = 1/5 = 0.20 h. t2 = 1/V2 = 1/7 = 0.143 s. V=d/(t1+t2)=2km/(0.20+0.143)h=5.8 km/h.
*August 20, 2015*

**Pre-Calculus**

1. D(0.5,1), V(h,1), F(1.5,1). F - D = 1/2a. 1.5-0.5 = 1/2a. 1/2a = 1. 2a = 1. a = 0.5. h-0.5 = 1/4a = 1/2 = 0.5. h = 1.0. X = a(y-k)^2 + h. X = 0.5(y-1)^2 + 1. Vertex form. X = 0.5(y^2-2y+1). X = 0.5y^2 -y + 1.5. Standard form.
*August 19, 2015*

**math**

Y = x^4 - x^3 - 12x^2 = 0. Roots are: -3, 0, and 4.
*August 19, 2015*

**math**

Y = x^3 - 13x - 12 = 0. X = -1, x+1 = 0. (x^3 - 13x - 12)/(x+1) = x*2 - x - 12. x^3-13x-12 = (x+1)(x^2-x-12). Factor the Quadratic: (x+1)(x+3)(x-4) = 0. x+3 = 0, X = -3. x-4 = 0, X = 4. The roots are: X = -1, -3, and 4.
*August 19, 2015*

**math**

Y = x^3 -2x^2 - 7x - 4 = 0. By trial and error, I found that (-1) satisfies the Eq, and it is our 1st root. x = -1, x + 1 = 0. Using synthetic(Long-hand) division, divide the cubic Eq by x+1: (X^3 - 2x^2 - 7x - 4)/(x+1)=x^2 - 3x - 4 x^3 - 2x^2 -7x - 4 = (x+1)(x^2-3x-4). Factor...
*August 19, 2015*

**physics**

post it.
*August 19, 2015*

**physics**

D = 10.3[90o] + 6.1[45] + 5[180]. X = 10.3*Cos90 + 6.1*Cos45 + 5*Cos180 = 0 + 4.31 - 5 = -0.69 Blocks. Y = 10.3*sin90 + 6.1*sin45 + 5*sin180 = 10.3 + 4.31 + 0 = 14.61 Blocks. D = sqrt(X^2+Y^2) = sqrt((-0.69)^2 + 14.61^2) = 14.6 Blocks. Tan A = Y/X = 14.61/-0.69 = -87.3o = 87....
*August 18, 2015*

**usiness math**

P = Po + Po*r*t = 30,000 + 30,000*(0.04/360)*45 - 10,000 = 30,000 + 150 -10,000 = $20,150.
*August 18, 2015*

**physics**

Xo = 15 m/s = Hor. component of initial velocity. Tr = 1.2 + 1.2 = 2.4 s. = Rise time. Y = Yo + g*Tr = 0. Yo = -g*Tr = -(-9.8)*2.4 = 23.5 m/s. = Ver. component 0f initial velocity. Y = Yo + g*t = 23.5-9.8*1.2 = 11.74 m/s. a. V = sqrt(Xo^2+Y^2)=sqrt(15^2+11.74^2) = 19 m/s. b. Y...
*August 18, 2015*

**Physics PLEASE HELP!**

KE = 0.5M*V^2. M = 1.*10^-3 kg. V = 1.*10^3 m/s. Solve for KE.
*August 17, 2015*

**physics**

d = V*t = 8.69*10^-2. 4.61*10^-6m/s * t = 8.69*10^-2. t = 8.69*10^-2/4.61*10^-6 = 1.89*10^4 = 18900 s. = 5.25 h.
*August 17, 2015*

**physics**

Xo = 25 m/s. Remains constant. Yo = 45 m/s. Decreases to zero at max ht. Therefore, V = 25 m/s at max ht.
*August 17, 2015*

**physical science**

V = a*t = 3.125 * 4 = 12.5 m/s.
*August 17, 2015*

**physics**

Vo = 20m/s.[50o]. Xo = 20*Cos50 = 12.9 m/s. Yo = 20*sin50 = 15.3 m/s. Y = 0 m/s at max ht. KE = 0.5M*Xo^2 = 0.5*0.8*12.9^2 = 66.6 J.
*August 17, 2015*

**Physics**

Impulse = F*t.
*August 16, 2015*

**Physics**

D = 1200m[90o] + 2000[0] + 500[225]. X = 1200*Cos90 + 2000*Cos0 + 500*Cos225 = 0 + 2000 - 354 = 1646 m. Y = 1200*sin90 + 2000*sin0 + 500*sin225 = 1200 + 0 - 354 = 846 m. Tan A = Y/X = 846/1646 = 0.51397. A = D = X/Cos A.
*August 16, 2015*

**physics**

a. F = 160N/m * 0.15m = 22.5 N. b. a = F/m = 22.5/0.40 = 56.25 m/s^2.
*August 16, 2015*

**physics**

Vo = 180000,/3600s. = 50 m/s. a. V = Vo + a*t = 0. t =-Vo/a = -50/-0.4 = 125 s. b. D = Vo*t + 0.5a*t^2. D = 50*125 - 0.2*2500 = 3125 m.
*August 16, 2015*

**science**

M1*V1 + M2*V2 = M1*V + M2*V. 6.4*9.9 + 2.1*0 = 6.4V + 2.1V. Solve for V.
*August 16, 2015*

**science**

p1 = M*V = 3.4 * 9.9 = 33.7. = Momentum. p2 = 3.4 * (-4.5) = -15.3. p2-p1 = -15.3 - 33.7 = -49. Magnitude = 49. The negative sign means the momentum decreased.
*August 16, 2015*

**math**

A. d = 6t + 5t = 11 km. 11t = 11. t = 1 hr. = Time they meet. d1 = 6km/h * 1h = 6km. = Distance Rodney traveled when they met. d2 = 5km/h * 1h = 5km = Distance Ca0uls traveled. B. 6(t-1/12) + 5t = 11 km. 6t-0.5 + 5t = 11. 11t = 11.5. t = 1.045 h.
*August 15, 2015*

**AP Physics**

a. Dp + Df = 345 m. 27*(T-0.36) + 5.9T = 345. 27T-9.72 + 5.9T = 345. 32.9T = 354.72. T = 10.78 s. = Time they meet. V = Vo + a*T = 0. a = -Vo/T = -27/10.78 = -2.50 m/s^2. = Min. rate.
*August 15, 2015*

**physics**

a. V1 = Vo + a*t=12.5 + 0.450*7=15.7m/s. d1 = 12.5*7 + 0.225*7^2 = 98.5 m. b. d2 = V1*T2 = 300-98.5 = 201.5 15.7*T2 = 201.5 T2 = 12.8 s. T1+T2 = 7 + 12.8 = 19.8 s. To travel 300 m with acceleration. d = Vo*T3 = 300 m. 12.5*T3 = 300. T3 = 24 s. To travel 300 m without ...
*August 15, 2015*

**Physics**

M*g = 96.3 * 9.8=943.7 N.=Wt. of player. = Normal force(Fn). a. Fk = u*Fn = 0.619 * 943.7 = 584.2 N. b. a = u*g = 0.619 * (-9.8)=-6.07 m/s^2. V = Vo + a*t = 0. Vo = -a*t = -(-6.07)*1.0 = 6.07 m/s.
*August 15, 2015*

**Algebra 1**

The ans. is B.
*August 14, 2015*

**Algebra 1**

Y = (x+3)(x-2) = 0. x+3 = 0. x = -3. x-2 = 0. x = 2. So the ans. is a.
*August 14, 2015*

**Algebra 1**

Y = a(x-h)^2 + k = -1. a(0-4)^2 - 5 = -1 16a - 5 = -1. 16a = 4. a = 0.25. Y = 0.25(x-4)^2 - 5.
*August 14, 2015*

**physics**

R = 4m[90o] + 15m[0o] + 18m[-37o]. X = 4*Cos90 + 15*Cos0 + 18*Cos(-37o) = 0 + 15 + 14.4 = 29.4 m. Y = 4*sin90 + 15*sin0 + 18*sin(-37) = 4 + 0 -10.8 = -6.8 m. a. sqrt(X^2+Y^2)=sqrt(29.4^2+(-6.8)^2) = 30.2 m. = Magnitude. b. Tan A = Y/X = -6.8/29.4 = -0.23129. A = -13.3o = 13.3o...
*August 14, 2015*

**physics**

M*g = 14.4 * 9.8 = 141.1 N.=Wt. of sled. Fn = 141.1 - 66.9*sin32 = 105.7 N. = Normal force. Fap*Cos A-Fk = M*a. 66.9*Cos32-Fk = M*0 = 0. Fk = 56.7 N. = Force of kinetic friction. u = Fk/Fn.
*August 14, 2015*

**physics**

a. D=0.744[0o] + 0.925[270o] + 3.97[161.7o] CCW. X = 0.744+0.925*Cos270+3.97*Cos161.7 = 0.744 + 0 - 0.949 = - 0.205 km. Y = 0 + 0.925*sin270 + 3.97*sin161.7 = 0 - 0.925 + 1.25 = 0.325 km. Tan A = Y/X = 0.325/-0.205 = -1.58537. A = -57.8o = 57.8o N. of W. = 122.2o CCW D=Y/sinA=...
*August 14, 2015*

**physics**

V1 = 36,000m/3600s. = 10 m/s. V1 = a*T1 = 10 m/s. 0.5*T1 = 10. T1 = 20 s. d1 = 0.5a*T1^2 = 0.5*0.5*20^2 = 100 m. d2 = V1*T2 = 1000 m. 10 * T2 = 1000. T2 = 100 s. V = V1 + a*T3 = 0. a = -V1/T3 = -10/20 = -0.5 m/s^2. V^2 = V1^2 + 2a*d3 = 0 d3 = -V1^2/2a = -(10^2)/-1 = 100 m. d...
*August 14, 2015*

**Math**

Glad I could help.
*August 13, 2015*

**Math**

Width = W. L = 2W - 5. 2W + 2L = 62 cm. 2W + 2(2W-5) = 62. 2W + 4W - 10 = 62. 6W = 72. W = 12 cm.
*August 13, 2015*

**Physics**

See previous post: Wed, 8-12-15, 9:20 PM.
*August 12, 2015*

**Physics**

d = Vo*t + 0.5*a*t^2 = 245 m. V = a*t = 34 m/s. a = 34/t. d = Vo*t + 0.5(34/t)t^2 = 245. 0 + 17t = 245. t = 14.4 s. a = 34/t = 34/14.4 = 2.36 m/s^2.
*August 12, 2015*

**physics**

V1 = a*T1 = 2.4 * 10 = 24 m/s. d1 = 0.5a*T1^2 = 1.2*10^2 = 120 m. a. d2 = V1*T2 = 24 * 25 = 600 m. V^2 = V1^2 + 2a*d3 = 0 d3 = -V1^2/2a = -(24^2)/-3 = 192 m. d = d1+d2+d3 = 120 + 600 + 192 = 912 m. = Total distance traveled. b. V = V1 + a*T3 = 0. T3 = -V1/a = -24/-1.5 = 16 s. ...
*August 12, 2015*

**Finance**

Account A: P = Po + Po*r*t = $6500. Po + Po*0.06*1 = 6500. Po + 0.06Po = 6500. 1.06Po = 6500. Po = $6,132.08 = Present value. Account B: Same procedure as A.
*August 12, 2015*

**Finance**

P = Po + Po*r*t = $15,000. Po + Po*0.07*1 = 15,000. 1.07Po = 15,000. Po = 14,018.69 = Present value.
*August 12, 2015*

**physics**

M*g = 1870 * 9.8 = 18,326 N.=Wt. of car. Fp = 18,326*sin12.1 = 3841 N. a. Fn = 18,326*Cos12.1=17,919 N.= Normal. b. Fp-Fs = M*a. 3841-Fs = 1870*0 = 0. Fs = 3841 N. = Force of static friction.
*August 12, 2015*

**physics**

M*g = 15.5 * 9.8 = 151.9 N.=Wt. 0f sled. Fn = 151.9 - 76.7*sin27 = 117 N. Fap-Fk = M*a. 76.7*Cos27-Fk = M*0 = 0. Fk = 68.3 N.=Force of kinetic friction. u = Fk/Fn 68.3/117 = 0.584.
*August 12, 2015*

**physics**

See previous post: Wed, 8-12-15, 12:14 AM.
*August 12, 2015*

**Physics**

V1 = a*t = = 76.7 * 1.89 = 145 m/s. h1 = 0.5a*t^2 = 0.5*76.7*1.89^2 = 137 m. h2 = h1 + -V1^2/2g=137 + (-145)^2/-19.6 = 1210 m. Above gnd.
*August 12, 2015*

**Urgent math**

a. Let n = 3. 2*3^2 > (3+1)^2. 18 > 16. True. Let n = 4. 2*4^2 > (4+1)^2. 32 > 25. True. Check b, and c.
*August 11, 2015*

**physics**

Vo = 6.87m/s.[51.9o]. Yo = 6.87*sin51.9 = 5.41 m/s. = Vertical component of initial velocity. Y^2 = Yo^2 + 2g*h = 0. h = -Yo^2/2g = -6.87^2/-19.6 = 2.41 m.
*August 11, 2015*

**Math**

119-108 = 11db. db = 10*Log I2/I1 = 11. Log I2/I1 = 1.1. I2/I1 = 10^1.1 = 12.59 or 13.
*August 10, 2015*

**Algebra 2**

The answer is 1.
*August 10, 2015*

**engineering physics 1-science**

a = F/M = 68/32 = 2.125 m/s^2.
*August 9, 2015*

**physics**

See previous post: Sat, 8-8-15, 7:02 PM.
*August 8, 2015*

**physics**

M*g = 50.9 * 9.8 = 499 N. = Wt. of crate. = Normal(Fn). Fs = u*Fn = 0.526 * 499 = 264 N. = Force of static friction. Fk = 0.311 * 499 = 155.2 N. = Force of kinetic friction. a. (Fap-Fs) = M*a. Fap-264 = M*0 = 0. Fap = 264 N. = Fore applied. b. (Fap-Fk) = M*a. Fap-155.2 = M*0...
*August 8, 2015*

**physics**

Tan A = 1.31/1.81 = 0.72376. A = 35.9o Tan 35.9 = d/2.290. d1 = 2.290*Tan35.9 = 1.658 km downstream. sin35.9 = 1.31/V2. V2 = 1.31/sin35.9 = 2.23 m/s d2 = sqrt(2.29^2+1.66^2) = 2.83 km = Distance across with wind. d2 = V2*t = 2830 m. 2.23*t = 2830. t = 1269 s. = 21 Min. to cross.
*August 8, 2015*

**physics**

Vo = 19m/s[36o]. Xo = 19*Cos36 = 15.4 m/s. Yo = 19*sin36 = 11.2 m/s. Y^2 = Yo^2 + 2g*h = 0. h = -Yo^2/2g = -(11.2^2)/-19.6 = 6.4 m. Y^2 = Yo^2 + 2g*h = 0 + 19.6(6.4-2.7) = 72.52. Y = 8.5 m/s = Ver. component of final velocity. V = sqrt(Xo^2+Y^2) = sqrt(15.4^2+8.5^2)= 17.6 m/s.
*August 8, 2015*

**Physics**

D = sqrt(20^2+20^2) = 28.3 m. Tan Ar = 20/20 = 1. Ar = 45o A = 45 + 180 = 225o. CCW from +x-axis.
*August 8, 2015*

**Physics**

See previous post: Fri, 8-7-15, 10:42 AM.
*August 8, 2015*

**Physics**

Glad I could help.
*August 7, 2015*

**Physics**

d = V*t = 20 m = 0.02 km. 160 * t = 0.02. t = 1.25*10^-4 hr. = 0.45 s. To travel 20 meters. Rev = 1800rev/60s * 0.45s. = 13.5. Yes!!
*August 7, 2015*

**physics**

a. a = 10.5/3.18 = 3.3 m/s^2. b. d = 0.5a*t^2 = 0.5*3.3*3.18^2 = 16.7 m.
*August 7, 2015*

**physics**

M*g = 1000 * 9.8 = 9800 N. = Wt. of car. a = 25/10 = 2.5 m/s^2. d = 0.5a*t^2 = 1.25*10^2 = 125 m. P = F * d/t = 9800 * 125/10 = 122,500J/s = 122,500 Watts.
*August 7, 2015*

**calculus**

h = Vo*t + 0.5g*t^2 = -15*8 + 16*8^2 = -120 + 1024 = 904 Ft.
*August 6, 2015*

**trigonometry**

Tan(75/2) = &an37.5o = 0.76733.
*August 6, 2015*

**physics**

Gun A: V = Vo + g*Tr = 0. Tr = -Vo/g = -44.7/-9.8 = 4.56 s. = Rise time. h = Vo*Tr + 0.5g*Tr^2 = 44.7*4.56 - 4.9*4.56^2 = 102 m. Tf = Tr = 4.56 s. = Time to fall back to top of cliff. T = Tr+Tf = 4.56 + 4.56 = 9.12 s. = Time to rise and fall back to top of cliff. The time ...
*August 6, 2015*

**physics**

d = V*t = 2350 m. 25.5*t = 2350. t = 92.2 s. To reach the next exit. d = 0.5a*t^2 = 2350 m. 0.5a*92.2^2 = 2350. 4250.42a = 2350. a = 0.553 m/s^2.
*August 6, 2015*

**Calculus**

Can someone show how to solve this problem Find the equation of the tangent line to the curve given by, x=3e^t y=5e^-t at the point where t=0 Thanks!
*August 5, 2015*

**Physical Science**

Fr = 10[0o] + 8[90o] + 6[135o] + 4[270o]= Resultant force. X = 10 + 6*Cos135 = 5.76 N. Y = 8 + 6*sin135 - 4 = 8.24 N. Tan A = Y/X. A = Fr = Y/sinA =
*August 5, 2015*

**mth 156**

P = Po*(1+r)^n. P = $55,000. r = 5%/4/100% = 0.0125. n = 7yrs. * 4Comp./yr. = 28 Compounding periods. Solve for Po.
*August 5, 2015*

**Calculus**

Can someone show how to solve this problem Find the equation of the line normal to the graph of y = x^2 + 1 that passes through the point (1, 2). Thanks!
*August 5, 2015*

**physics**

230*10*CosA = 1410. CosA = 0.6130 = Power factor. A = 52.2o. = Phase angle. I^2*R = 1410W. 10^2 * R = 1410. R1 = 14.1 Ohms. = Resistance of coil. Tan52.2 = Xl/R = Xl/14.1 Xl = 14.1*Tan52.2 = 18.2 Ohms=Reactance of coil. Z1 = R1/CosA = 14.1/Cos52.2 = 23 Ohms. Parallel: Zp = 230...
*August 4, 2015*

**math**

3^200/3^50 = 3^(200-50) = 3^150.
*August 3, 2015*

**math**

(1,0), (0,1). Slope = (1-0)/(0-1) = 1/-1 = -1.
*August 3, 2015*

**physics**

Dx = Xo*Tf = 25 m. 4m/s * Tf = 25. Tf = 6.25 s. = Fall time. h = 0.5g*Tf^2.
*August 3, 2015*

**Algebra**

6 3/4 + x = 8. 6 + 3/4 +x = 8. Multiply both sides by 4: 24 + 3 + 4x = 32. 4x = 32-27 = 5. X = 5/4 = 1 1/4 = 1.25.
*August 2, 2015*

**math**

See Related Questions: Fri, 6-27-14, 2:15 AM.
*August 2, 2015*

**Real Estate**

See previous post: Sat, 8-1-15, 5:01 PM.
*August 2, 2015*

**Real Estate**

Ps-0.06Ps = 75,000 + 10,000. 0.94Ps = 85,000. Ps = $90,426 = Selling price.
*August 2, 2015*

**SLCS**

F1 + F2 = 602 N. F1 = (1.5/0.5)F2 = 3F2. 3F2 + F2 = 602. F2 = 150.5 N. = Paul's force. 3F2 = 3 * 150.5 = 451.5 N. = Justin's force.
*August 2, 2015*

**net**

Ps-0.07Ps = 6,8000 + 45,000. Solve for Ps, the selling price.
*August 1, 2015*