Tuesday

September 1, 2015
Total # Posts: 16

**math**

oh yeah thaNKS.:)
*July 16, 2011*

**math**

pls. explain
*July 16, 2011*

**math**

how did yu get 107.75?
*July 16, 2011*

**math**

thanks :)
*July 16, 2011*

**math**

Triangle ABC has are 30cm^2, AC=9 cm and BC= 7cm. Calculate the measureof angle ACB and the larget possible length of AB.
*July 16, 2011*

**math**

pls. explain why there is no real number è that satisfies ither sinè=2 or cos è=2.
*July 13, 2011*

**math**

two angles in a triangle measure degreeand 38. the longest side is 24cm longer than the shortest side. write to explain how you would determine the length of the shortest side. can i use sin law or the cosine law.pls. explain..
*July 11, 2011*

**math**

simplify: c-d/d-c
*July 6, 2011*

**math**

how would i get the domain and range of f(x)= sq.root of 3-x-4? pls. explain.
*July 4, 2011*

**math**

april sells specialty teddy bears at various summer festivals. her profit for a week,P, in dollars, can be modelled by P= -0.1n^2 + 30n - 1200, where n is the umber of teddy bearsshe sells during the week. a.) According to this model, could april ever earn a profit of $2000. b...
*June 20, 2011*

**Chemistry**

v1=c2v2/c1 v1= (0.2M)(200ml)/(6M) v1=6.67 ml HCl
*June 20, 2011*

**math**

thanks :)
*June 18, 2011*

**math**

in his spare time, kim likes to go cycling. he cycles partly on paved surfaces and partly off-road, through hilly and wooded areas. he cycles at 25km/hon paved surfacesand at 10 km/h off-road. one day, he cycled 41km in 2h. how far did he cycle off road?
*June 18, 2011*

**Chemistry**

2n Ca(OH)2= n HCl 2[c Ca(OH)2 v Ca(OH)2] = c HCl v HCl c Ca(OH)2= c HCl v HCl/2v Ca(OH)2 c Ca(OH)2= (0.158M)(32.40mL)/2(27mL) c Ca(OH)2= 0.111M pls. check if it's right:)
*June 18, 2011*

**math**

thanks :)
*June 18, 2011*

**math**

shanon needs 20g of 80% of gold to make a pendan. she has some 85% gold and some 70% gold, from broken jewelry and wants to know how much she should use. determine the quantity of each alloy that she should use.
*June 18, 2011*

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