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April 20, 2014

Posts by elena


Total # Posts: 4,311

physics
Young’s Modulus E=17•10⁹ N/m² σ=Eε mg/A=E(ΔL/L) ΔL= mgL/AE= 4mgL/ πD²E= =4•12900•9.8•9.4/π•0.42²•17•10⁹= =5•10⁻⁴ m=0.5 mm.

physics
http://answers.yahoo.com/question/index?qid=20100103015632AABnYzd

physics
http://answers.yahoo.com/question/index?qid=20121115115746AAMELdR

Physics
m₁a=- m₁g+T₁ …….(1) - m₂a=T₂- m₂g ……(2) Iε=(T₂-T₁)R => T₂-T₁ = Iε/R=Ia/R² If the wheel is disc I=mR²/2 => T₂-T₁= Iε/R= mR²a/2R²=ma/2 subtract (2...

Physics, Chemistry, Science
• The majority of gas used in most SCUBA tanks is compressed air. This air is composed of the same elements everywhere - 21% Oxygen 79% Nitrogen. Advanced SCUBA divers may use an "enhanced" mixture of 32% (up to about 40%) Oxygen with the balance being Nitrogen....

Physics
s=at²/2 a=2s/t²=2•0.939/0.6²=5.22 m/s² F=ma=2.2•5.22=11.484 N

Physics
s=at²/2 a=2s/t²=2•0.939/0.6²=5.22 m/s² F=ma=2.2•5.22=11.484 N

physics
http://answers.yahoo.com/question/index?qid=20090617182342AAVRQWx

Physics
to Anton: F=qvB? where q=e v: m mile/s -> m/s B= 5•10⁻⁵ T

Physics
X: m₁v₁=m₁u₁cosα+m₂u₂cosβ Y: 0=m₁u₁sinα - m₂u₂cosβ m₁v₁-m₁u₁cosα = m₂u₂cosβ …(1) m₁u₁sinα= m₂u₂cosβ ……...

Science (Physics)
on the Earth W= mg=30•10=300 N on the Moon W₁=mg₁=mg/6 = =W/6 =300/6 = 50 N mg=GmM/R² g=G M/R² => M=gR²/G the gravitational constant G =6.67•10⁻¹¹ N•m²/kg², Earth’s radius is R = 6.378•10⁶ ...

Physics
s₁=15 m, a=1 m/s²,t₂=15 s s₁=v²/2a v=sqrt(2as₁) v=at₁ t₁=v/a s₂=vt₂ s= s₁+s₂ t=t₁+t₂

Physics- torque
sinα=(3.92-0.506)/8.35 =0.409 α =sin⁻¹0.409 = 24.13º F=832•cosα=832•0.913 =759.6 N τ=759.6•3.92=2977.6 N•m

Physical Science
(E) 210/82 Pb -> 210/83 Bi + 0/-1 e + y (C) 49.6 grams

physics
sinα=(3.92-0.506)/8.35 =0.409 α =sin⁻¹0.409 = 24.13º F=832•cosα=832•0.913 =759.6 N τ=759.6•3.92=2977.6 N•m

physics
h=gt²/2 => t=sqrt{2h/g} => t₁=t₂

Physics - pendulum
T₁=2π•sqrt{L/g₁} T₂=2π•sqrt{L/g₂} g₂=g₁(T₁/T₂)²

Physics - Oscillations
T=2π•sqrt{m/k} T=t/N t/N=2π•sqrt{m/k} (t/2πN)²=m/k k=m(2πN/t)²

physics
F=691+89=780 N p=(F/2)/A=F/2A => A=F/2p=780/2•8.4•10⁵=4.6 10⁻⁴m²

physics
ρ=m/V =m/πr²h= =15700/π•1.35²•3.94=696 kg/m³

physics
I=mr²/2 mgh= mv²/2 +Iω²/2 = =mv²/2 +mr²v²/r²4 = = mv²/2+ mv²/4 =3mv²/4 v=sqrt{4gh/3} => c)both in same time.

Physics
5 N 8.5 N 0 N

Physics
- a force that makes the net force on an object zero - It is equal in magnitude and opposite in direction - A moving object in equilibrium continues at a constant velocity.

Physics
W = ∫F•dx = a•x + (b/2) •x² - (c/3) •x³ x=0.794 m a = 12600 N, b = 8420 N/m, c = 10100 N/m^2,

Physics
when the arrow representing the vector would point toward negative x <-- 10.4 km/h <--

Physics, Elena Please Help If u can.
I need the figure

physics
Son : m, v Father : M, u M=4m mv²/2=3Mu²/2 => mv²/2=3•4mu²/2 => v²=12 u²…..(1) mv²/2= M(u+1.8)²/2 mv²/2= 4m(u+1.8)²/2 v²= 4(u+1.8)² ….(2) Substitute v² from (1) in (2) 12 u²=4(u+1.8)...

PHYSICS
m₁a=m₁g-T₁ m₂a=T₂ - m₂gsinα Iε=(T₁-T₂)R => T₁-T₂ = Iε/R=Ia/R²=mR²a/2 R²=ma/2 m₁a+ m₂a= m₁g-T₁+ T₂ - =m₁g- m₂gsinα –( T₁-T̀...

physics
T=38.2 N, T₁=28.9 N, T₂=17,4 Buoyant force F In the air T = mg …. (1) In the water T₁=mg-F₁ …..(2) In the unknown liquid T₂=mg-F₂ ….. (3) Substitute (1) in (2) and (3) F₁=mg- T₁=T-T₁=38.2-28.9=9.3 N F₂=...

Math- urgent
-3 (x-8)+7x=12 -3x+24 +7x=12 4x=-12 x=-3

math
12 persons Each has 2 balloons and 3 prizes

physics
Max force the man can apply is F= F(fr)= μN=μmg=0.78•93•9.8=710.9 N Max acceleration a=F/M = 710.9/104000=0.0068 m/s²

Math- urgent
If x+4•7=-2 then x+28=-2 x=-30 If x+ 4⁷=-2 then x+16384=-2 x=-16386

Math
V=75• 135•0.03=303.75 m³= 303750 L t=V/V₀=303750/250=1215 min=20.25 hours

PHYSICS HELP
m₁a=m₁g-T₁ m₂a=T₂- F(fr) 0=m₂g-N Iε=(T₁-T₂)R =>T₁-T₂ = Iε/R=Ia/R² N= m₂g, F(fr)=μN=μm₂g m₁a+ m₂a= m₁g-T₁+ T₂- F(fr)= =m₁g- μm₂g &#...

science
a) Mg + 2HCl = MgCl₂ + H₂ b) 2K + 2H₂O = 2KOH + H₂ c) 2Li + 2H₂O = 2LiOH + H₂ d) 4Fe + 3O₂ = 2Fe₂O₃

physics
http://www.astro.queensu.ca/~tjb/hw/P10706/hw8_old.pdf

Density Problem
density ρ=m/V V=4πR³/3 kilometers -> meters!

Science (Physics)
On the Earth h=v²/2g On the Moon H=v²/2g₁ H/h= v²2g/2g₁v²=g/g₁ H=h g/g₁=24.2•9.8/1.6= 148.225 m

Phyics
v(max) =Aω= 2πA/T

physics
x=Asinωt v=Aωcosωt a=-Aω²sinωt =- ω²x=-(2π/T)²x |a/x| = (2π/T)² T=2 π sqrt{ x/a}=2 π•sqrt(0.235/2.3)=2 s.

Physics
Q=cmΔT= 4186•0.6•20 = 50232 J. ΔQ=Q₀-Q=140000-50232=89768 J m₁=ΔQ/λ=89768/335000=0.268 J M=0.6-0.268=0.332 kg

physics
http://hyperphysics.phy-astr.gsu.edu/hbase/geoopt/raydiag.html

Physics
http://mech.subwiki.org/wiki/Limiting_coefficient_of_static_friction

Physics
ma=mgsinα-F(fr)=mgsinα-μN= =mgsinα-μmgcosα μ(stat.fr) => a=0 0= mgsinα-μmgcosα μ=tanα

Physics
mg=500 N vector T + vecrorT +vector mg = 0 y-projection : 2Tsinα = mg T=mg/2sinα=500/2sin10=1439.7 N

Physics
ma=mgsinα-F(fr)=mgsinα-μN= =mgsinα-μmgcosα μ(stat.fr) => a=0 0= mgsinα-μmgcosα μ=tanα

Physics
on the Earth W= mg on the Moon W₁=mg₁=mg/6 =9=W/6 =900/6 =150 N

Physics
N=mg±Fsinα + if α is measured below the horizontal - if α is measured above the horizontal (a) mgcosα =μN μ = mgcosα/N (b) ma=Fcosα –F(fr) = = Fcosα – μN Solve for ‘a’

Physics
W = ∫F•dx = a•x + (b/2) •x² - (c/3) •x³ = =12600•0.794 +8420•0.794²/2 -10100•0.794³/3= =10004.4+2654.1-5055.7 =7602.8 J

Physics
W = ∫F•dx = a•x + (b/2) •x² - (c/3) •x³

Physics
mgh = mv²/2 v=sqrt(2gh)

physics
F(x) =17cos68-19 = F(y) = 17sin68+16.5 = F=sqrt{F(x)²+F(y)²}= tanα =F(y)/F(x)=

Physics
F(x)=93.3 +73.1cos45 +181 cos 45 = F(y)=73.1 sin45 -182sin 45 = F=sqrt{F(x)²+F(y)²}=

Physics
x: F=Tsinα y: mg=Tcosα F/mg=Tsinα/ Tcosα tanα =F/mg=67.7/14.9•9.8 = 0.46 α =arctan0.46= 24.9⁰ T=F/sinα=67.7/sin24.9=67.7/0.42=161 N

physics
a=v²/2s=22²/2•1.55 =156.13 m/s² t=v/a=22/156.13=0.14 s

physics
k=F/x=21.3/0.19 = 112 N/m

Physics
m₁=6.646•10⁻²⁷ kg, v₁=3.4•10⁶ m/s, m₂=3.287•10⁻²⁵-6.646•10⁻²⁷=3.22054•10⁻²⁵ kg, v₂=? p₁=m₁v₁=6.646•10⁻²⁷•3.4&...

Physics
v=v₀+at

Physics
s=(v₀²-v²)/2a v= sqrt{ v₀²-2as}

physics
τ=Iε=(2mR²/5)ε= =2•12•0.22²•12/5 =2.79 N•m

Physics Classical Mechanics
http://web.mit.edu/8.01t/www/materials/ProblemSets/Raw/old_files_fall07/ps10sol.pdf

Physics Classical Mechanics`
http://ocw.mit.edu/courses/physics/8-01sc-physics-i-classical-mechanics-fall-2010/two-dimensional-rotational-motion/two-dimensional-rotational-dynamics/MIT8_01SC_problems21_soln.pdf

physics
R₀=8 Ω, T₀=20℃, R₁=8.4 Ω, T₁=70℃, T₂ = - 10℃ R₂=? R=R₀[1-αΔT] R₁=R₀[1-αΔT₁] 8.4=8[1+(70-20)α] α={8.4/8 – 1)/50 = 10⁻³ K⁻¹ R₂=R...

physics Important please
R₀=8 Ω, T₀=20℃, R₁=8.4 Ω, T₁=70℃, T₂ = - 10℃ R₂=? R=R₀[1-αΔT] R₁=R₀[1-αΔT₁] 8.4=8[1+(70-20)α] α={8.4/8 – 1)/50 = 10⁻³ K⁻¹ R₂=R...

physics Important please
q=It=Ut/R

Phyics
W=mg=ρVg= ρπr²hg= =2.2•10³•π•0.55²•1.9•9.8 = =38929 N=173173 lb

phyics
F₁=kx₁ F₂=kx₂ F₁/F₂=x₁/x₂ F₂=F₁x₂/x₁

physics
KE=W(resistive force) mv²/2 = Fs F= mv²/2s

physics
mv²/R =mg v=sqrt(gR)

Physics
do=15.1 cm, R=8.55 cm, H= 6.7 cm di= ? h=? 1/do – 1/di = -2/R 1/di = 1/do+2/R = 1/15.1 +2/8.55. di= 3.33 cm The virtual image is smaller and closer to the mirror than the object h/di =H/do => h=H•di/do = 6.7•3.33/15.1 =1.48 cm

Physics please HELP
KE=Iω²/2 =I•4π²/2T² T=2 π•sqrt{I/2•KE} If KE↓ => T↑

physics
C=ε₀A/d C=q/U=> q=CU = ε₀AU/d E=σ/2ε₀ =q/A•2ε₀= = ε₀AU/d•A•2ε₀=U/d The same result may be obtained from E=-gradΔU => E=ΔU/Δx =U/d

Physics please HELP
KE=Iω²/2 =I•4π²/2T² T=2 π•sqrt{I/2•KE} If KE↓ => T↑

physics
Energy = PE = PE₁₂+PE₁₃+PE₁₄+PE₂₃+PE₂₄+PE₃₄= =kq₁q₂/a +kq₁q₃/a+kq₁q₄/a+ kq₂q₃/a+kq₂q₄/a +kq₃q₄/a . Since q₁=q₂=q₃=q...

PHYSICS(HELP)
Prob # 7 ocw.mit.edu/courses/physics/8-01sc-physics-i-classical-mechanics-fall-2010/two-dimensional-rotational-motion/two-dimensional-rotational-dynamics/MIT8_01SC_problems21_soln.pdf

physics
F=ma=mΔv/Δt=m[v₂-v₁]/Δt= =0.38•[-1.9-2.3]/3•10⁻³ = - 532 N ( direction: from the wall)

Physics falling ladder
http://www.mathematische-basteleien.de/ladder.htm

physics
a=v²/2s

Phyics
T=2π•sqrt(L/g) L=T²g/4π² = =8.36²•9.8/4π²=17.35 m

physics
q₁ = 3 e, q₂ = 12e, q₃ = 5e The electric field at the midpoint is E= kq₂/(x/2)²- kq₁/(x/2)²= =k(12e-3e)/(x/2)² =k36e/x² (directed to the 3e charge) F= q₃E=k36e•5e/x²= =k•180e/x², where k =9•10S...

physics
q₁ = 3 e, q₂ = 12e, q₃ = 5e The electric field at the midpoint is E= kq₂/(x/2)²- kq₁/(x/2)²= =k(12e-3e)/(x/2)² =k36e/x² (directed to the 3e charge) F= q₃E=k36e•5e/x²= =k•180e/x², where k =9•10S...

physics
q₁ = 3 e, q₂ = 12e, q₃ = 5e The electric field at the midpoint is E= kq₂/(x/2)²- kq₁/(x/2)²= =k(12e-3e)/(x/2)² =k36e/x² (directed to the 3e charge) F= q₃E=k36e•5e/x²= =k•180e/x², where k =9•10S...

Physics Part 2
m₁=m₂=m=0.17 kg, α=45° v=5.6 m/s, v₁=3.5 m/s, v₂=? vector p =vector p₁+vector p₂ p₂=sqrt{p₁²+p²-2p₁•p•cosα} = =m•sqrt{3.5²+5.6²-2•3.5•5.6•cos45°} = =m•...

PHYSICS (HELP)
R=2 m, Ic=9000 kg•m², r₀=1.2 m, m=20 kg, F=200 N, Δt=18 s. I=Ic+2I₀=Ic+2m r₀² = =9000+2•20•1.2²=9057.6 kg•m². M=Iα α=M/I=FR/I =200•2/9057.6 = 0.044 rad/s² ω=α•Δt =0.044•...

additional science: physics
m=F/g=1.94/9.7=0.2 kg g=GmM/(R+H)² g₀=GmM/R² =9.8 m/s²

physics
the gravitational constant G =6.67•10⁻¹¹ N•m²/kg², F =G•m₁•m₂/R²= G•m² /R² F/W=F/mg = G•m² /R²mg = G•m /R²g. mg= G•m•M/R²=> g= G•M/R² . F/W= G...

Physics
Distance between charges is d=sqrt{3²+3²} =4.24 cm x=d/2 =4.24/2 =2.12 cm =0.0212 m E=kq₁/x²-kq₂/x² = =k12e/x²-k3e/x²=k9e/x²= =9•10⁹•9•1.6•10⁻¹⁹/0.0212²= =2.9•10⁻⁵ N/C

Physics ASAP PLease
ΔV =V(∞)-V V(∞)=0 V=0 => ΔV = 0 Work of electric field = q₃ΔV=0 Answ. c)

Physics
KE₂-KE₁=Fs F= (KE₂-KE₁)/s=(10-8)/6 = 0.33 N

Physics
KE=W =Fs =0.8•0.5 = 0.4 J

Physics
W=mg=1768•9.8 = …N

Physics
KE=mv²/2

Physics Important please
E=kq₁/x²=kq₂/(3-x)² 3e/x²=12e/(3-x)² 9-6x+x²=4x² 3x²+6x-9=0 x²+2x-3=0 x=1 cm

Physics
KE=W(fr) mv₀²/2=F(fr)s=μmgs s= v₀²/2μg v=v₀-at v=0 => a= v₀/t s=v₀t-at²/2= = v₀t- v₀t²/2t= v₀t/2 t=2s/v₀=2v₀²/2μgv₀= =v₀/μg=6/0.1•9.8 =6.12 s

PHYSICS
KE=PE mv₀²/2=mgh=mgs/sinα s= v₀²sinα /2g= =5.5²sin23°/2•9.8 =… v=v₀-at v=0 => a= v₀/t s=v₀t-at²/2= = v₀t- v₀t²/2t= v₀t/2 t=2s/v₀=….

Physics
ΔV =V(∞)-V V(∞)=0 V=0 => ΔV = 0 Work of electric field = q₃ΔV=0 Answ. c)

PHYSICS
(a) The equations of the motion: - of the cylinder Iε =M Ia/R =TR T= Ia/R² - of the object m₂a=m₂g-T m₂a=m₂g- Ia/R² a(m₂+ I/R²) =m₂g a= m₂g/ (m₂+ I/R²) (b) T= Ia/R²=Im₂g/ R² (m₂+ I/...

phy
1/do+1/di=1/f 1/di= 1/0.21 – 1/1 = 3.76 di=0.26 m D=di+do =0.26+1 = 1.26 m (b) 1/do+1/di=1/f di =f•do/(do-f) D=do+di = =do+ f•do/(do-f) =do²/(do-f) For finding D(min) let differentiate D(do) D´={do²/(do-f)}´={2•do(do-f) -do²(1-f)}/(...

physics
Vector sum of two vectors at right angles p=sqrt{p₁²+p₂²} =sqrt2 =1.41 kg•m/s

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