Its kinda hard to tell, but something in your answer looks odd. There is nothing in your profit equation that would produce the term "-2bQ"
Do a little research, then take a shot. What do you think?
Ok, you have 5 cards showing, meaning 47 remain. You have 4 hearts showing, meaning 9 remain. There are 47-choose-2 ways of picking the next two cards. = 47!/2!(47-2)! =1081 possible ways. This will be the denominator. Now then, the number of ways of picking a heart and someth...
Both production runs of 300 and 400 produce the same profit and the maximized profit. Take it from here.
I believe I answered this in an earlier post. There are 9 possible values for the first digit and 9 for the second, and so on. So, there are 9^8 possible serial numbers, where no digits is a zero. Similarly, there are 8^8 possible values where no digit is a zero or a seven. So...
Do a little research, then take a shot, what do you think?
Do a little research, then take a shot, what do you think? Hint: Lots of firms today have a 10+ percent market share and a regulator knowing a firm's MC is quite a tall order. So there are two you can eliminate.
Take a shot, what do you think? Hint: think about economies of scale (if any) and how that affects a supply curve.
Always Always Always. Set MC=MR. MC is the first derivitive of the TC function. So, MC=4+4Q. Solve for Q.
With a fair coin the probability of a given 7-flip series is equal to ANY 7-flip series. That is, P(HHHHTTT) = P(TTTHHHH) = P(THTHTHT).... There are 2^7 = 128 possible 7-filp series. This is the denominator. There are 4-choose-7 ways to have a 4 heads in 7 filps. 4-choose-7 is...