If 30 degrees is the minimum angle that allows slipping to start, then the coefficient of static friction (mu_s) is given by M*g*sin30 = M*g*mu_s*cos30 mu_s = tan30 = 0.5774 The mass M does not matter. Angles greater than 30 degrees will also allow slipping.
I assume -37 is a temperature. What are the units? You have 35/71 = 0.493 moles of Cl2 Use the ideal gas law.
The velocity will immediately begin to accelerate upward, but it will begin at its original value (5 m/s)
math pre calc
Is the matrix a determinant? If so, 14 +0 +20x +30 -0 -6x = 2 14x +44 = 2 x = -3
"2 less than the product of 4 and 8" is 30. Subtract 9 from that.
I was wrong about the negative sign. Relative to zero voltage at infinity, the potential at nonzero distances will be positive. http://en.wikipedia.org/wiki/Electric_potential My brain isnt awake yet
V = -k Q/R k is the Coulomb's Law constant = 8.99*10^9 N*m^2/C^2 Q = 3.50*10^-6 C R = 0.17 m Solve for V, which will be in J/C units
4.00 m above the river surface, the bungee length is 32 m and it has stretched 7.0 m. The stored potential energy in the cord is then PEmax = (1/2)k*7^2 . This equals the gravitational potential energy loss, M*g*32. Kinetic energy at the top and bottom of the jump is zero. (49...
3 >or= 2x -1 > -11 4 >or= 2x > -10 2 >or= x > -5
Solve 3 = 15 e^(−0.051t) for t 0.2 = e^(−0.051t) ln (0.2) = -1.609 = -0.051 t t = 31.6 (days)
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