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Posts by damon

Total # Posts: 29,983

Science
v = Vi - 9.81 t at top v = 0 so t = 700/9.81 = 71.4 s now there are two ways to proceed one way: h = Vi t -4.9 t^2 h = 700(71.4) - 4.9(71.4)^2 h = 25,000 m other way; average speed up = (700+0)/2 = 350 m/s h = 350*71.4 = 25,000 m

math
each side of the big one is 4 times the one in the small triangle 4a+4b+4c = 4(a+b+c) the altitude of the big one is 4 timess the altitude of the small one (1/2)(4h)(4b) = (16) (1/2) a b

You mean e^kt not e^k/t
P = Po e^kt 400 = Po e^10k 1500 = Po e^35 t 1/Po = (1/400) e^10 k = (1/1500)e^35 k e^35 k / e^10k = 1500/400 = 15/4 e^25 k = 15/4 25 k = ln(15/4) = 1.322 k = .0529 so P = Po e^.0529 t 400 = Po e^.529 Po = 236 then P = 236 e^.0529 t I think you can take it from there

Physics
F = G M m /d^2 g = F/m = G M/d^2 on surface d is radius R so 9.81 = G Me /R^2 gv = GMv /R^2 = G (.8Me)/R^2 = .8* 9.81 them Wv = m gv = .8 We

MATH HELP ASAP PLEASE!!!!!
then divide both sides by 4 x > 0.3 now be careful, if you divide or multiply by a NEGATIVE number, you must change the direction of the arrow. However that is not the case here.

MATH HELP ASAP
well to make it easy 0.25 = 1/4 so (1/4) s = 50 s = 4 * 50 s = 200

Science
22.4 liters/mol calcium carbonate is 100 g/mol so we have 1/4 mol (1/4)(22.4) = 5.6 liters = .0056 m^3

physics
d = Vi t + .5 a t^2 runner 1 400 = 6 t and a = 0 t = 400/6 runner 2 400 = 10t - 0.9 t^2 .9 t^2 - 10 t + 400 = 0 solve quadratic t = complex number, never makes it :) The velocity turns negative before the runner reaches the finish Let's see when v = 0 v = 10 -1.8 t v = 0 ...

Mathematics
Jessica is correct.

superb
I am going to assume that you could not type = signs R = 0.30 meters Vt = 2t at t = 3 s Vt = 6 m/s dVt/dt = 2 m/s^2 so At = 2 m/s^2 Ar = Vt^2/R = 36/.3 = 360/3 = 120 m/s^2

By inspection - first one
many can be done faster by factoring though eg Solve. (-10x^3+30x-20) / (-5x+5) A) 2x^2-2x+4 B) -2x^2-2x-4 C) -2x^2+2x+4 D) 2x^2+2x-4*** =========================================== (2x^3-6x+4)/(x-1) (2x^2+2x-4) (x-1)/(x-1) so I agree By the way, where you type "where"...

Math
http://calc101.com/webMathematica/long-divide.jsp#topdoit

Physics 11
Yes, right idea. I did not check arithmetic.

physics-density
R = radius of cone height of cone = h draft of cone = x =distance below surface area of base = pi R^2 area of water plane = pi r^2 x/h = r/R geometry weight of cone = rho g(1/3)pi R^2 h weight of water displaced = 1000 g(1/3)pi r^2 x force up = weight of water displaced - ...

Time rates
The volume of anything pointy with straight sides is (1/3) base area * height so V = (1/3) pi r^2 h but h = 2 r so V = (2/3) pi r^3 find dr/dV, worry about dh/dV later (note h = 2 r) dV = (2/3) pi (3 r^2) dr = 2 pi r^2 dr dV/dt = 2 pi r^2 dr/dt = 10 m^3/min but r = h/2 and dr/...

algebra
5 n + 10 d + 25 q = 185 d = 2 q n = 2 d -2 = 4 q - 2 so 5 (4q-2) + 10(2q) + 25q = 185 ok from there?

Algebra 1
well first divide both sides by 5 1 x^2 + 1 x - 12 = 0 x = [ -1 +/- sqrt( 1 -4(1)(-12) ] / 2 x = [ -1 +/- sqrt(49)] /2 x = [ -1 +/- 7 ]/2 x = 3 or x = -4 CHECK 5*9 + 5*3 - 60 = ? 45 +15 - 60 = 0 sure enough

Chemistry
for electron lambda = h/mv = 6.63*10^-34 /[ 9.1*10^-31*6.68*10^5] = .109*10^-8 = 1.09 * 10-9 = 1.09 nm

Chemistry
A. ok I got 2.09*10^-19 J but used crude electron mass approx B. Ephoton = Eelectron + h * 5.5*10^15 Ephoton = 2.03*10^-19 + 6.63*10^-34*5.5*10^15 Ephoton = 2.03*10^-19 + 36.5*10^-19 Ephoton = 38.5 *10^-19 Joules now what wavelength is that E = h c/lambda so lambda = h c/E ...

Algebra 2
I agree.

Algebra 2
2 pi f x = x/4 so f = 1/(8pi) check when x = T , T/4 = 2 pi so T = 8 pi f = 1/T = 1/(8pi)

Math
What did you get ?

Math
4 x y z x = 2 y but x is <5 so y = 0, 1, or 2 4 + 2y + y + z = 12 so x + 3y + z = 8 if y = 0, then twice y is also 0 nope if y = 1, then twice y = 2, nope 421 three digits if y = 2 , then 4 4 2 z then if z = 2, the sum is 12 how about 4422 ???

Physics
rho water = 1000 kg/m^3 P1 + (1/2) rho V1^2 = P1 + (1/2) rho V2^2 and V1 A1 = V2 A2 so V2 = V1(100/25) = 4 V1 8*10^4 +(1/2)(10^3) V1^2 = 6*10^4 + (1/2)(10^3)(16 V1^2) solve for V1 then volume flow rate = pi R1^2 V1 or mass flow rate = 1000 pi R1^2 V1 note R1 = 0.10 meters

Physics
KE = (1/2) m v^2 dKE= (v^2/2)dm + mvdv dm = .02 m dv = .04 v dKE = (v^2/2) .02 m + m v .04 v = m v^2/2 (.02) + mv^2/2 (.08 ) = 0.10 KE = 10% because velocity is squared, it alone counts for 2*4 = 8%

Physics
They have the same mass. The force up on the wood block is m g the force up on the Al block is its volume * density of water * g but what is its volume? Al density = 2.7 * density water = 2700 kg/m^3 so volume = m/2700 so force up on Al is (m/2700)1000 g = m g/2.7 the force up...

Physics
A + B = 17 A - B = 7 2A=24 A = 12 B = 5 so sqrt(25+144)

physics
LOL try it with a mass on the spring as you compress it, U, the potential energy goes up when you release it the mass hits max velocity as it passes zero. then the kinetic energy dies and the potential climbs again U = (1/2) k x^2 x^2 is the same for + or - x A=B !!!!!

Physics
use dot product |A| |B| cos theta = A dot B = 36+64 -100 = 0 LOL, cos theta = 0 so theta = 90 degrees

Physics
Hmmm, how much work does the earth do on the moon?

Physics
probe mass = m probe speed = v = 5*10^4 ion mass = M ions/second = q ion speed = V = 2*10^4 ion momentum change/second = q M V = force force needed = mv^2/R so mv^2/R = q M V kinetic energy of ion = (1/2)MV^2 kinetic energy/second of ion flow = q(1/2)MV^2 Time to go 1/4 turn...

Calc
let z = 1/y dx = d/dz sec(z)dz dx = sec (z) tan (z) dz but dz = (-1/y^2)dy so dx = sec(1/y) tan(1/y) (-1/y^2) dy now dy/dx = -y^2/[ sec(1/y) tan(1/y]

Calc
f' = x d/dx(cos x) + cos x dx/dx +x^4d/dx(e^2x) + e^2x d/dx(x^4) = -x sin x + cos x + 2x^4(e^2x) + 4x^3 (e^2x)

Math
center at origin by symmetry x^2/a^2 - y^2/b^2 = 1 transverse axis = 2 a = 2-(-2) = 4 so a = 2 now x^2/4 -y^2/b^2 = 1 just find b from focus center to focus = sqrt(a^2+b^2) so 3 = sqrt(4+b^2) 9 = 4 + b^2 b = sqrt 5 so in the end x^2/4 - y^2/5 = 1

Algebra 2
I doubt if you mean f = 14 pi I bet you mean omega = 2 pi f = 14 pi then y = 2 sin (14 pi t - p) + 2 hen t = 0, y = 2 that works for p = 0 (the phase) so y = 2 sin (14 pi t) + 2 I used t, you can use x if you wish.

Algebra 2 TYPO I BET
y = a sin (2 pi f - p) + b y = 2 sin (2 pi f - p) + 2

maths
b = m/3 - 1 to solve you need another fact

Physics
(i) if the velocity is constant there is no acceleration so the force up from the floor = weight down = m g = 80*9.8 Newtons (i) If we accelerate UPWARDS at 2 m/s^2 then Fup-Fdown = m a Fup - m g = m a Fup = 80(9.8 + 2) Newtons

math
square root of any negative number

math
90 = 2.5 n n = 90/2.5 = ?

Multivariable calculus
(a + da)(b + db) = a b + b dz + a db + da db da db is higher order so to first order error in product is a db + b da error/product = db/b + da/a

Physics
first make it easier by dividing by 4 3 i + 6 j - 2 k is parallel but easier now divide all coefs by sqrt(9+36+4) = 7 :) 3/7 i + 6/7 j - 2/7 k

Algebra
Beats me but I notice that r is the only one that occurs toward the end of the alphabet.

Physics
A+B = P = (Ax+Bx)i +(Ay+By)j A-B = Q = (Ax-Bx)i +(Ay-By)j |P|^2 = (Ax+Bx)^2 + (Ay+By)^2 |Q|^2 = (Ax-Bx)^2 + (Ay-By)^2 those are equal? then Ax^2+2AxBx+Bx^2 + Ay^2+2AyBy+By^2 = Ax^2-2AxBx+Bx^2 + Ay^2-2AyBy+By^2 --------------------------------- subtract = 0 0 = 4AxBx +4AyBy SO ...

Math
I am not sure that I understand your question but here is the general method: http://people.richland.edu/james/lecture/m116/matrices/determinant.html

science
usually mol in chemistry about 6.022140857 * 10^23 of anything Just like a "dozen" eggs is 12 of them. 6.022140857 * 10^23 is called "Avagadro's number". Google that for history. The significance is that 6.022140857 * 10^23 atoms of anything has the ...

Geometry
(x-h)^2 + (y-k)^2 = r^2 center at (h,k) radius r so for example number 3 center at h = 0 and k = 3 radius is 2 sqrt 3 so r^2 = 4*3 = 12 then (x-0)^2 + (y-3)^2 = 12 or for number 5 (x-a)^2 +(y-b)^2 = c^2

Calculus
Angle G = pi/3 + pi t/90 (we know pi/3 = 60 deg) dG/dt = pi/90 for side g g^2 = 225 + 400 - 600 cos G 2 g dg/dt = +600 sin G dG/dt at G = pi/3 g^2 = 325 g = 18 at G = pi/3 2*18 dg/dt = 600 sin pi/3 * (pi/90) dg/dt = 14.4 * pi/90 = .16 pi now the area s = (1/2) sum of sides s...

Physics
change in y = -7 change in x = -17 magnitude of displacement = sqrt(7^2+17^2) tan of angle below -x axis = 7/17 because in third quadrant where x and y are negative

Lisa
horizontal distance (not displacement vector) hd= sqrt (330^2 + 320^2) vertical distance = 10 total distance = sqrt(hd^2+100)

Maths
B traveled on a HEADING of 150 (around SSE) Draw position of B, 10 from origin at 60 degrees south of east (heading of 150) With center at B, draw a circle of radius 12 A is 8 km from the origin (can draw another circle if you want) at the intersection of the 12 radius circle...

Physics 1st paper
or just take components up the middle 2 * 8 cos (120/2) = 16 cos 60 = 8

Math
149.99999999........ to one significant figure = 100

phisical science
Force = rate of change of momentum momentum is p = m * v so force is rate of change of m * v if m is constant which is generally the case until you get to relativity then force = m *(rate of change of velocity) rate of change of the velocity of the mass is the acceleration of ...

physics
sqrt (30^2+20^2) =sqrt(1300) = 10 sqrt(13) tan A = 2/3 where A is compass angle CLOCKWISE from north

Physics
Liter = .1^3 m^3 = .001 m^3 so .8*1000 = 800 kg/m^3 which is 80% density of water

physics
yes force of gravity = m g distance = D work done by gravity = m g D Remember the tension in the cord also does work, but that was not asked.

physics
v^2

History (1900ís)
Google: No Irish need apply

TYPOS ???
15.3 sin(pi*5*6) + 44.1 no way I think maybe you mean 15.3 sin (pi x/6) but I do not believe that either because it should be colder in January than in July when you have sin (pi) which is also 0. This has maximum temp in April, no way

math-precalculus
t = (y-4)/2 from second equation so x = 4 [ (y-4)/2 ]^2 x = (y-4)^2 x = y^2 -8 y + 16

Chemistry - Ionic Compounds
Br ion is -1 in general Sr ion is +2 Ca ion is +2 Ga ion is +3 O ion is - 2 so Br and O are our negative ions match them up with the positives (metals) Sr and Br = SrBr2 Sr and O = SrO Ca and Br = CaBr2 Ca and O = CaO Ga and Br = GaBr3 Ga and O = Ga2O3 2*3=6 and 3*2=6

maths
The publisher evidently makes 9-4 = 5 dollars per book. It evidently costs 50,000 to print any number of books (strange, typo maybe) 5 x = 50,000 x = 10,000

Statistics
Hey, now I have done 2. What is the probability that you can do it now? Same old binomial distribution.

Statistics
find P of 5 successes (100 %) then subtract that from 1 p of success = .92 P of 5 in a row = .92^5 = .659 so probability that not all 5 work = 1 - .659 = .341

Statistics
binomial distribution we want chance of exactly 5 of 6 making it p(grow) = .7 so p(not) = .3 P(6,5) =C(6,5) .7^6 * .3^1 = 6 (.7)^6 * .3 = .212

Physics
When in danger or in doubt, keep the units and make sure they come out right. meters = meters/second * seconds :) L = v T f = 1/seconds so f = v/L = (meters/ second) / meters = 1/seconds

typo
191 Hz

Physics
so A yes .335 B yes 1536 C well lambda = 1.8 meters all right but 1.8 = v T = v/f f = v/1.8 = 343/1.8 = 1.91 Hz keep that distance = speed *time in mind

Physics
http://hyperphysics.phy-astr.gsu.edu/hbase/Waves/opecol.html

Physics 11
The speed is slower, but the same number have to pass you in a minute if you are sitting there watching. There is no storage closet for the waves. In other words the same answer as for your earlier question. L = v T T is constant v, the speed, decrease so L decreases (it gets ...

Physics 11
the frequency (and period) do not change) distance = speed * time or wavelength = speed * period 1 = 30 T so T = 1/30 L = 15 T = 15(1/30) = 1/2 so I agree

Physics !! Help Needed UrGeNtLy!!
Force applied * distance in direction of force = 25 * 2.5 It is not clear what besides friction the force is overcoming, perhaps acclerating, but it does not matter. Work done by the force is still the force times the distance.

Math
8 x + 12 (x+y) = 20 x + 12 y

Physics
weight of stationary object there = m g = G m M/r^2 so g = 6.67*10^-11*9.6*10^25 /(86,700,000+8,610,000)^2 b) v^2/r = g c) T = 2 pi r/v

Math
plus the one at zero (one more fence posts than fence sections :)

Math
(23*21*21)a^2

Math
5 h - 3[4k-6m+2h-6k] 5 h - 12 k + 18 m -6 h +18 k - h + 6 k + 18 m

include data
You not only want us to do the problem for you, you want me to Google the specific heat of copper and water. LOL 20 Cc (200 - T) = 60 Cc(T-30)+50Cw(T-30)

Maths
a b^2 - a c^2 ??????? a(b+c)(b-c) 10(5.5+4.5)(5.5-4.5) 10(10)(1) =

Physics()
F = k Q/r^2 5 at 0 and -3.5 at 60 for 0 k (5)/x^2 + k(-3.5)/(x-60)^2=0 5(x-60)^2 - 3.5 x^2 = 0 5(x^2-120x+3600 ) - 3.5 x^2 = 0 1.5 x^2 - 600 x +18,000 = 0 x = 32.7 or 367 32.7 makes no sense (introduced by squaring) so 367 cm

physics
I checked the units but not the constants

physics
sorry, missed the 2

brakes for d meters
initial speed = V final speed = 0 length of skid = L assume constant road/tire friction coefficient = mu a = magnitude of deacceleration 0 = V - a t so t = V/a time to stop L = V t - (1/2) a t^2 L = V(V/a) - (1/2)a(V^2/a^2) so L = (1/2)(V^2/a) a = V^2/2L now physics F = m a = ...

Math
3 / sqrt 15 * (sqrt 15/sqrt 15) = 3 sqrt 15 /15 = sqrt 15 / 5 Hey , just keep your cool and do them step by step.

Math
which one is (-3,-4) and (2,6) ?????

Math
guess? No need to guess !!!!

Math
2x+2 = x^2 + 3x -4 x^2 + x - 6 = 0 (x-2)(x+3) = 0 x = +2 ---> y = 6 or (2,6) x = -3 ---> y = -4 or (-3,-4) so I disagree with you

physics
Component of thrust up = 400,000 sin 37 Newtons Lift = 756,000 N perpendicular to course made good so lift up component = 756,000 cos 37 Newtons so m g =9.81 m = 400,000sin37+756,000cos37

Chemistry
Yes, I could not understand what Kylee was doing so did it myself.

Chemistry
checking my way Al = 27 g/mol 3.17 g = .1174 mols of Al I need 3 mol O2 for 4 mol Al mol O2/mol Al = 3/4 = x/.1174 x = .0881 mols O2 required O2 = 32 grams/mol .0081*32 = 2.82 grams of O2 needed BUT I only have 2.55 grams O2 SO Al is limiting

maths
diagonals of rhombus are perpendicular so we have right triangle one leg = 11 half of 22 diag one leg = x/2 half of other diag hypotenuse = 15 so x^2/4 + 121 = 225

hyperbola I bet
means hyperbola probably http://www.mathwarehouse.com/hyperbola/graph-equation-of-a-hyperbola.php

steve reiny proportion help maths reiny!!!
i = k cp /d^2 k*8/150^5 = k*5/d^2 8 d^2 = 5*150^2 d^2 = (5/8)150^2 d = 150 sqrt(5/8) d = 150(.79) d = 118.5cm lower it 150-118.5 = 31.5 cm

hookle's law
stretches 5 with 50 N so stretches 10 with 100 N 20 + 10 = 30

math-probability
permutations of 16 taken 3 at a time (order matters so permutations) 16!/[(16-3)!] 16!/[ 13! ] 16*15*14 3360 possible groups of 3 out of those 16 1/3360 = .000297 forget it unless you know a lot about the particular horses :) !

math-probability
This link will not help with your listing task but does show how to do the calculation with repeating elements. http://www.mathwarehouse.com/probability/permutations-repeated-items.php

math-probability
permutations does not normally include identical elements abcd is ok as is abdc but using a twice is not part of it there is no fast way to do what you asked that I know of

Physics 11
the first antinode is 1/4 wavelength from the fixed end. the second one is half a wavelength further so at L/4 and 3L/4 = .6 and 1.8 the fixed end is a node x = 0 the ANTInode is 1/4 L away, x = L/4 the next node is at L/2 , x = L/2 next ANTInode is at 3L/4 x=(3/4)L the next ...

math
I think you can do them all as standard linear programming problems. I gave you a link below. I do not know any method OTHER than by corners.

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