Tuesday

July 28, 2015

July 28, 2015

Total # Posts: 21,555

**Math**

I would say that y = x - 8 then I would say -3x - 2(x-8) = 16 I would solve that for x and use that x to go back and find y
*July 28, 2015*

**Physics**

3.9/2 = 1.95 left of pivot --- right of pivot 50(1.95) = 27 x + 35(1.95) 27 x = 15(1.95) x = 15(1.95)/27 to the right of pivot
*July 28, 2015*

**Physics**

.28 F = 98
*July 28, 2015*

**Algebra**

maybe you mean 5^4 - (8x)^2 = 0 ?????? that would be 25^2 - (8x)^2 =0 (25 - 8x)(25+8x) = 0 8x = 25 or 8x = -25
*July 27, 2015*

**pre-calculus**

112.5 = 90 + 22.5 ah ha, 22.5 is half of 45 we will be able to do this with half angle formulas first: sin 122.5 = sin(90+22.5) = sin 90 cos 22.5 + cos 90 sin 22.5 = cos 22.5 + 0 so we want cos (45/2) cos 45/2 = sqrt[ (1+cos 45)/2] = sqrt [ (1 +1/sqrt2)/2 } = sqrt [ (1 + sqrt ...
*July 27, 2015*

**Integral calculus**

h^2 = 2 x^2 2 h dh/dx = 4 x dh/dx = 2 x/h dh/dt = dh/dx * dx/dt = 2 (x/h) dx/dt but x/h = 1/sqrt 2 so dh/dt = sqrt 2 * dx/dt ---------------------- but more simply h = x sqrt 2 dh/dx = sqrt 2
*July 25, 2015*

**Physics**

total contact area = 4 * .217 * .179 = .155 meters^2 total force = gage pressure * area = 176357*.155 = 27,401 Newtons weight It might be interesting to also find the mass in kilograms assuming this all happens on earth 27,401/9.81 = 2793 Kg mass (heavy car)
*July 24, 2015*

**Math**

whoops (x+5)(x-2) (y^3+5)(y^3-2)
*July 23, 2015*

**Math**

I personally would say x = y^3 then it is x^2 + 3 x - 10 (x-5)(x+2) now go back (x^3-5)(x^3+2)
*July 23, 2015*

**calculus**

obviously 2 r </= 12 volume = pi r^2 h =1000 then pi r^2 = 1000/h but h</= 11 so pi r^2 >/= 1000/11
*July 22, 2015*

**Physics**

http://www.mathpages.com/home/kmath114/kmath114.htm u + 2 U
*July 22, 2015*

**Math**

find how many minutes until one is left. That one leaves immediately if the first ones left at t = 0 a(n+1) = (1/2)A(n) a(1) = 256 a(N) = 1 an = a1 r^n-1 1 = 256 *.5^(n-1) .5^(n-1) = 1/256 (n-1) log .5 = log (1/256) n-1 = 8 n = 9 so 9 * 5 min = 45 min if the first ones left at...
*July 22, 2015*

**Physics**

suspect you mean 30 south of west momentum east 7900*5 - 1650*20 cos 30 momentum south 1650*20 sin 30 new mass = 7900 + 1650 new mass*speed east = old momentum east new mass* speed south = old momentum south
*July 22, 2015*

**Math Check**

x^2+ x(6)^1/2+3=x^2 +3 makes no sense at all. 6^(1/2) is not zero
*July 22, 2015*

**Physics**

T = our unknown angle theta angular acceleration = alpha = d omega/dt I = (1/2) M R^2 FF = friction force up slope FF * R = torque so FF * R = (1/2) M R^2 * alpha FF = (1/2)M R alpha R omega = no slip velocity R alpha = no slip acceleration = a so FF = (1/2) M a F = m a F = M ...
*July 21, 2015*

**Algebra1**

of course we could have short cut that by saying 9 (x-8)^2 = y-8 then (x-8)^2 = (1/9)(y-8) but best do the whole completing the square process.
*July 20, 2015*

**Algebra1**

If it is indeed y = 9 (x-8)^2 + 8 then y = 9 (x^2 - 16 x + 64) + 8 y = 9 x^2 - 144 x + 576 + 8 y = 9 x^2 - 144 x + 584 then x^2 - 16 x + 64 8/9 = y/9 x^2 - 16 x = y/9 -64 -8/9 x^2 - 16 x + 64 = y/9 -64 -8/9 + 64 (x-8)^2 = y/9 -8/9 = (1/9)(y-8) vertex at (8,8)
*July 20, 2015*

**not a parabola**

Need an x^2 somewhere perhaps y = 9 (x-8)^2 + 8 or something?
*July 20, 2015*

**math**

3^2 * 6 = 9*6 = 54
*July 20, 2015*

**math**

area is proportional to scale squared volume is proportional to scale cubed
*July 20, 2015*

**physics**

10 = (1/2)(.4) t^2 solve for t v = 0 + .4 t
*July 20, 2015*

**physics**

v = 30 - a (75) assume you mean 1.5 km or 1500 meters 1500 = 30 (75) - .5 a (75)^2 solve for a then go back and get v at 75 seconds
*July 20, 2015*

**physics(kinematics)**

You are welcome. Actually that was fun :)
*July 19, 2015*

**physics(kinematics)**

me too :)
*July 19, 2015*

**physics(kinematics)**

we agree !
*July 19, 2015*

**physics(kinematics)**

v = Vi - 8 t x = Xi + Vi t - 4 t^2 20 = Xi + Vi (4) - 4(16) 20 = Xi + 4 Vi - 64 Xi + 4 Vi = 84 so Vi = (84-Xi)/4 16 = Vi - 8 t 16 = (84-Xi)/4 - 8 t (eqn 1) 4 = Xi + [(84-Xi) /4] t - 4 t^2 (eqn 2) from eqn 1 64 = 84-Xi - 32 t so Xi + 32 t = 20 Xi = (20 - 32 t) substitute that ...
*July 19, 2015*

**college chem**

Na ---- 23 g/mol Cl ---- 35.5 g/mol so NaCl 58.5 g/mol so 42.6/58.5 = .728 mols .728/1.58 = .461 mol/Liter
*July 19, 2015*

**how exasperating !**

Oh my :(
*July 19, 2015*

**calculus**

sketch it of course where does y = 2x hit y=6/x? 2 x = 6/x x^2 = 3 x = sqrt 3 then y = 2 sqrt 3 so from x = 0 to x = sqrt 3 integrate y = (2 x-.5 x) = 1.5 x 1.5 x^2/2 .75 ( 3-0) = 2.25 then where does y = .5 x hit y = 6/x? .5 = 6/x^2 x^2 = 12 x = 2 sqrt 3 so integrate y = (6/x...
*July 19, 2015*

**Physics**

.... and if you have a physics question type PHYSICS, not Blue bells....,
*July 19, 2015*

**blue bells model school**

The momentum does not change but the balls are together during the collision so initial ke = (1/2) m V1^2 = total energy initial momentum = m V1 final momentum = (n+1)m V2 so V2 = V1/(n+1) so ke during collision = (1/2) (n+1)m V2^2 = (1/2) (n+1)m V1^2/(n+1)^2 = (1/2)m V1^2/(n+...
*July 19, 2015*

**Thokozwayo secondary school**

So I can talk to my neighbors.
*July 19, 2015*

**Physics**

Jai showed you how to do this type of problem below. All your problems are really the same and are solved the same way. In other words if you do what Jai said, you can do them all. We are not here to do them all for you. http://www.jiskha.com/display.cgi?id=1437267116
*July 19, 2015*

**math**

DRAW IT ON A GRAPH ! square in quadant 3 or 4 diagonals hit at (2,-2) or (-2,-2) that is a and d NOT B or C
*July 18, 2015*

**math**

+1 -2 +3 -4 +5 .....+99 -100 = +1 +3 +5...... +99 -2 -4 -6...... -100 --------------------- ADD -1 -1 -1 ..... -1 :) LOOKS LIKE AROUND -50
*July 18, 2015*

**math**

you left the lower limit out so I assume 0 sum of all integers from -9 to +9 looks like zero to me so 4 pm
*July 18, 2015*

**Algebra**

LOL - thanks
*July 18, 2015*

**Algebra**

The key is "rounded to 82" :)
*July 18, 2015*

**Algebra**

Well, try 49 :) 49 +4*90 = 409 409/5 = 81.8 rounds to 82 so ok try 48 48 +4*90 = 408 408/5 = 81.6 rounds to 82 so ok try 47 47 + 4*90 = 407 407/5 = 81.4 no good
*July 18, 2015*

**Algebra**

( a+b+c+d+e)/5 = 82 a+b+c+d+e = 410 but 90*4 = 360 so he got at least 50
*July 18, 2015*

**math**

500/9 = 55.5 so there are 55 from 9 to 495 j = 55 500/7 = 71.4 so there are 71 from 7 to 497 k = 71
*July 18, 2015*

**Math 115 Statistics**

draw a box or matrix with your 36 possibilities make an x for win, an o for lose(3,4,6) 0 1 2 3 4 5 6 1 x o o x o x 2 o o x o x x 3 o x o x x x 4 x o x x x x 5 o x the rest x 6 number of o s = 10 so 10/36
*July 18, 2015*

**Math URGENT!!!**

10/30 * 9/29 * 8/28
*July 18, 2015*

**calculus**

dM/dt = -k M separate variables, M left, t right dM/M = -k dt integrate ln M = -k t + c note e^log a = a ao e^ln M = M = e^(-kt+c) = e^-kt e^c or since e^c is some constant call it C M = C e^-kt note that when t = 0 e^-kt = 1 so C = initial amount so here M = 100 e^-kt
*July 17, 2015*

**physics**

good answer.
*July 17, 2015*

**maths**

f-5 = 3(s-5) f + 10 = 2(s+10) ---------------- -15 = 3(s-5) - 2(s+10) -15 = 3s - 15 -2s -20 20 = s then f-5 = 60 -15 f = 50
*July 16, 2015*

**geometry**

(8/6)(12+12+6)
*July 16, 2015*

**geometry**

Pure luck ! You are welcome :)
*July 16, 2015*

**geometry**

ah, I think 155 / C
*July 16, 2015*

**calculus**

dT/dt = -k (T-38) try dT/(T-38) = -k dt ln(T-38) = -k t T-38 = ce^-kt T = 38 + ce^-kt when t = 0, T =75 75 = 38 + c c = 37 so T = 38 + 37 e^-kt at t = 30 , T = 60 so 60 = 38 + 37 e^-30 k 22/37 = .595 = e^-30 k ln .595 = -.52 = -30 k so k = .0173 and T = 38 + 37 e^-.0173 t you ...
*July 16, 2015*

**Alebra 2**

law of cosines c^2 = a^2 + b^2 - 2 a b cos angle
*July 16, 2015*

**Stats**

first pick p anchovies = 1/12 p not anchovies = 11/12 second pick you now only have 11 toppings one of which is anchovies p anchovies = 1/11 p not anchovies = 10/11 11*10/(11*12) = 10/12 = 5/6 p neither anchovies =
*July 16, 2015*

**Math**

We want y = m x + b ? solve for y 3 y = 2 x - 6 so y = (2/3) x -2 so m = 2/3 , b = -2
*July 16, 2015*

**Math**

slope = 4162 but when t = 10, n = 45400 so n - 45400 = 4162 (t-10) ----------------------------- n at t = 19 n = 45400 + 4162(9)
*July 16, 2015*

**Math**

slope = slope (y-9)/(x-1) = (19-9)/(3-1) = 5 you can do the rest
*July 16, 2015*

**Math**

12 y = 15 x - 1 y = (15/12) x - 1/12 y = (5/4)x - 1/12
*July 16, 2015*

**Geometry**

180-45
*July 16, 2015*

**Physics**

If Fx is on a graph, you need the area under the curve from x = 0 to x = 3
*July 15, 2015*

**Physics**

work done = integral Fx dx from 0 to 3 calculate that then Ke final = Ke initial + work done
*July 15, 2015*

**Physics**

assume you mean dot or scalar product A dot B = |A| |B| cos theta so here cos theta = .5 cos^-1 0.5 = 60 degrees
*July 15, 2015*

**Calculus Partial Derivatives**

x y z = k sum = s = x + y + z ds = ds/dx dx + ds/dy dy + ds/dz dz = 0 for max or min but ds/dx = ds/dy = ds/dz = 1 so ds = dx + dy + dz = 0 so max when dx = -dy - dz but x = k/(yz) dx/dy = -kz /(yz)^2 dx/dz = -ky /(yz)^2 so dx = -[-kz/((yz)^2 ]dy - [-ky/(yz)^2]dz so k y = k z ...
*July 15, 2015*

**precalc**

well, if you are not allowed to use calculus you must complete the square to find the vertex of that parabola. 16 t^2 - 48 t -20 = -h t^2 - 3 t - 1.25 = -h/16 t^2 - 3 t = -h/16 + 1.25 t^2 - 3 t + 9/4 = -h/16 + 3.5 (t - 1.5)^2 = - 1/16 ( h - 56) so at peak t = 1.5 and h = 56...
*July 12, 2015*

**sjrkps**

By the way, if you post a physics question say physics, not sjrkps so you get a physicist.
*July 12, 2015*

**sjrkps**

v = Vi + a t v = 0 + .8 m/s^2 * 20 s = 16 m/s
*July 12, 2015*

**math**

but much more fun my way :)
*July 12, 2015*

**math**

x^2 = tan^2 +2 tan sin + sin^2 y^2 = tan^2 -2 tan sin + sin^2 x^2-y^2 = 4 tan sin = 4 sin^2/cos ____________________________________ x y = tan^2 -sin^2 = sin^2/cos^2 -sin^2 = sin^2/cos^2 - sin^2 cos^2/cos^2 = [sin^2 / cos^2] [1-cos^2] but 1 - cos^2 = sin^2 so = sin^4/cos^2 so ...
*July 12, 2015*

**physics**

weight = 320+ 4*15 + 500 + 750 + 1000 = total force up moments around one end Ff=force up from floor at far end Fn = force up at near end 320(1.2)-Fn*.3+30*.3+500*.4+750*1.2 +1000*2 +30*2.1-Ff*2.1 = 0 but Fn = (total force up - Ff)
*July 12, 2015*

**Physics**

V = Vi e^-(t/RC) .1 = e^-(10/10C) = e^-(1/C) ln .1 = -1/C
*July 11, 2015*

**Physics**

but the boat is also being pushed by the propeller m = 60 + 500 = 560 kg
*July 11, 2015*

**physics**

You are welcome.
*July 11, 2015*

**physics**

6000 Pascals is 6000 Newtons per square meter. Multiply that by the area of the wall in square meters to get the force in Newtons. The density of water is about 1000 kg /m^3 so the weight of a cubic meter of water is about m g = 1000 * 9.81 = 9810 Newtons so a column of water ...
*July 11, 2015*

**physics**

k Q1Q2/d^2 plug and chug
*July 11, 2015*

**physics**

Hey, have you bothered to try these yourself?
*July 11, 2015*

**physics**

You hear the difference frequency. You want it to be zero. So loosen it more :)
*July 11, 2015*

**physics**

find the frequency from the wavelength lambda = c T = c/f then energy = Lank constant * frequency
*July 11, 2015*

**math**

8 y = -5 x - 5 1.6 y = -x - 14 slope of first = -5/8 slope of second = -1/1.6 which is -5/8 therefore, no, they have the same slope and are either parallel or identical.
*July 11, 2015*

**Math**

2 L + 2 w = 80 or L + w = 40 L w = 300 so w = 300/L so L + 300/L = 40 L^2 - 40 L + 300 = 0 (L-30)(L-10) = 0 try L = 30 and w = 10
*July 11, 2015*

**math**

LOL - close enough, a short lunchtime walk.
*July 11, 2015*

**math**

MIT, Ocean Engineering. BSc in Physics but went back later for engineering doctorate and taught engineering.
*July 11, 2015*

**math**

Anyway, find the total time for the round trip by adding the time out and the time back. Then divide 240 miles by the time in hours
*July 11, 2015*

**math - typo?**

Well did he go 60 or 40 on the way back?
*July 11, 2015*

**physics**

constant horizontal speed = 22 cos 45 so time to fence = t = 100 /(22 cos 45) so how high is it at time t? h = initial height assume 0 + [ 22 sin 45] t - (1/2)(9.81) t^2 That gives you h in meters. Convert to feet to see if it is higher than five feet.
*July 11, 2015*

**Algebra?**

huh ? multiply the side length of a square by four to get the perimeter.
*July 11, 2015*

**Career choice advice needed**

I clicked on this only because the title was in Nederlands (of Afrikaans). It would be wise to put the subject in the title so that you get a teacher who knows something about the subject (I really do not, particularly in South Africa)
*July 11, 2015*

**physics**

every second a volume of .5 m * .01 m^2 = .005 m^3 comes out of the pipe. 2700 kg/m^3 * .005 m^3/second = 13.5 kg/s
*July 10, 2015*

**algebra**

x, x and (x+5) 3 x + 5 = 26 so 3x = 21 x = 7 x = 7 x+5 = 12
*July 10, 2015*

**st joan of arc**

tan 48 = height of building/60 tan 56 = height of top of antenna/60 if you want the height of the antenna itself, subtract.
*July 10, 2015*

**Physics**

7.9/2 = 3.95 so center of plank is 3.95 from outer end which is 3.95 - 3.5 = .45 inside the edge of the platform so for equilibrium 130 (.45) = 31 x x = 1.89 out from edge
*July 9, 2015*

**Physics**

k Q1 Q2 / r^2 note r^2 not r so 1. yes 2 no 3 no 4 yes if you mean 1/r^2 5 not necessarily, Like charges repel.
*July 9, 2015*

**Physics - what ?**

equation for what? Did you try to copy and paste something? That will not work here.
*July 8, 2015*

**math (algebra)**

r = 1/d r = 1/(2r) r^2 = 1/2 pi r^2 = area = pi/2
*July 8, 2015*

**Calculus**

f(x) = |x-2|
*July 8, 2015*

**Calculus**

divide top and bottom by x (5 x^2 + x - 1)/3
*July 8, 2015*

**david college**

I would not have noticed this if Ms. Sue had not said it was Physics. I never took David College.
*July 8, 2015*

**david college**

The charge is the same on each of them. Where else would the electrons on the low side of the top one come from but the high side of the low one :) C = Q/V for each and the voltages add so 100 volts = V1 + V2 100 = Q1/C1 + Q2/C2 but Q2=Q1 = Q so 100 = Q/C1 + Q/C2 = Q (C1+C2)/...
*July 8, 2015*

**Physics**

T is tension if the slope of the plane is 32 degrees component of weight down plane = 10 (9.81) sin 32 which is trying to accelerate the mass down the slope so if acceleration up slope is a then T - 98.1 sin 32 = 10 a now the hanging mass force down = mg - T 98.1 - T = 10 a ...
*July 8, 2015*

**No figure**

This is kind of challenging without the figure but all you really need is F = m a and weight = mass * local gravity
*July 8, 2015*

**physics**

force, direction, distance from A F , up (assumed) , x (unknown) 2500 , down , 0 4000, up , 8 10,000, down , 12.5 3000, up , 21 3500 , down , 25 sum of forces up = 0 so -2500+4000-10000+F+3000-3500 = 0 F -5500 = 0 so F = +5500 up sum of clockwise moment = 0 about A 2500*0 -...
*July 8, 2015*

**maths**

so those opposite angles are 130/2 = 65 sum of all the angles is 360 so 130 + 2 theta = 360 theta = 115 so two angles of 65 deg and two angles of 115 degrees
*July 8, 2015*

**maths**

90-32
*July 8, 2015*