Chemistry
What how can I calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l)->2 KAl(OH)4 (aq) + 3 H2 (g) Please show steps ..
Chemistry
If the percent yield was 81.5%, how many grams of aluminum were used to prepare 20.0 g of potassium alum?
Chemistry
Calculate the percent yield of alum if you obtained 75.0 g of potassium alum from 5.00 g Al.
Chemistry
How many moles and how many grams of potassium alum, KAl(SO4)2 · 12 H2O, can be prepared from 5.00 g of aluminum?
Chemistry
Which one ?
Chemistry
Calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l)->2 KAl(OH)4 (aq) + 3 H2 (g)
Chemistry
Calculate the volume (in mL) of 9.0M H2SO4 that you would need to convert 0.070 moles of KAl(OH)4 to K2SO4 and Al2(SO4)3 according to the following equation: 2 KAl(OH)4 + 4 H2SO4->K2SO4 + Al2(SO4)3 + 8 H2O
Chemistry
Calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l) ¨ 2 KAl(OH)4 (aq) + 3 H2 (g)
Calculus AP need help!
oops.. i thought 1/2 to -3/2. now i understand. thanks
Calculus AP need help!
1. f(x)=√5x+6, find f'(x) 2. f(x)=√4x^2+3x+4, find f'(x). i got stuck. f(x)=√5x+6=(5x+6)^1/2 f'(x)= 1/2(5x+6)^-3/2*(5).
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