Monday

April 21, 2014

April 21, 2014

Total # Posts: 15

**ckc**

Lotto result

**Math**

3X+7Y+5=0.,..,..,.,..(1) 4X-3Y-8=0..,,..,.,...,..(2) From (1) x=(-5-7y)/3..,..,..(3) put into equ (2) for x ; (-20-28y)/3-8=0 ; y=31/28=1.1 put into equ 3 for y x=(-5-7.7)/3=-4.2 -4.2p +1.1-1=0 ; p=-0.1/-4.2 p=0.024

**Math**

DUde 1 of u question has been solve check it out it is similiar

**math**

Speed=distance(km)/time(mins)

**Statistics**

Total =106 (Sample space) Women=23 p(w)=r/n=23/106

**MATH**

A+B=7, A=7-B---(1) A+C=12,---(2), frm 1 substitute the value of A into eq 2 :7-B+C=12, C=12-7+B---(3) also B+C=15---(4), also in the same way put C in eq3 into eq 4 ;B+12-7+B=15, B=5, now rem eq1 put B into it ;A=7-5=2 do the same thin 4 C by putin B in eq3 C=5

**algebra2 HELP PLEASE**

calculator still boothin

**Physics**

First of all convert 54cm to m 1m=100cm, therefore 54cm=0.54m=h. then using equation of a motion v^2=u^+2gh,since u =0 g=10 the equation bcoms v^2=2gh then substitute and solve for v ans=32.9

**Physics**

First of all convert 54cm to m 1m=100cm, therefore 54cm=0.54m=h. then using equation of a motion v^2=u^+2gh,since u =0 g=10 the equation bcoms v^2=2gh then substitute and solve for v ans=32.9

**Physics**

First of all convert 54cm to m 1m=100cm, therefore 54cm=0.54m=h. then using equation of a motion v^2=u^+2gh,since u =0 g=10 the equation bcoms v^2=2gh then substitute and solve for v ans=32.9

**Physics**

First of all convert 54cm to m 1m=100cm, therefore 54cm=0.54m=h. then using equation of a motion v^2=u^+2gh,since u =0 g=10 the equation bcoms v^2=2gh then substitute and solve for v ans=32.9

**Physics**

First of all convert 54cm to m 1m=100cm, therefore 54cm=0.54m=h. then using equation of a motion v^2=u^+2gh,since u =0 g=10 the equation bcoms v^2=2gh then substitute and solve for v ans=32.9

**Math**

A CIRCULAR PIECE OF CARDBOARD IS TRIMMEM IN SUCH A WAY THAT ITS CIRCUMFERENCE IS REDUCED IN THE RATIO 3:7. IN WHAT RATIO IS THE SURFACE AREA REDUCED?

**math**

ice forms on a refrigerator ice box at the rate of (4-06t)g per minute after t minutes. if initially there were2g of ice, find the mass of ice formed in 5 minutes.

**Maths Methods**

EXPLANATION:for example x^2 -5x+6 first of al the product =6*x^2=6x^2(first and last term) sum=-5x(2nd term) now find 2 terms dat when u add give -5x and product 6x^2 [(terms ar -3x&-2x)since -*-=+ &-+-=-] now it bcoms x^2-3x-2x+6, factorise=x(x-3)-2(x-3)=(x-2)(x-3) (collectin...

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