grade 9 polynomials
7r + 21s - 4r + 18S then combine like terms
chemistry
This was a multiple choice question, with possible answers of -13.1 KJ/mol; -6.26 KJ/mol; -27.8 KJ/mol; or -26.2 KJ/mol. I was confused as to how to set equation but now I'm confused because if I'm doing this right-none of these answers work. Thanks!
chemistry
The amount of 2.00 mol of a solid ionic compound was dissolved in 225 mL of water in an insulated container. The initial temp of water was 20 deg. C and the final temp. was 47.8 deg C. What is the delta heat Dissolution? Assume the heat absorbed by the container is negligible.
chemistry
substance X has a molar mass of 107.6 g/mol. When 2.50 g of substance x burns in an iron calorimeter, the temp. of the calorimeter and the water (2.000 Kg) increases from 25.8 deg. C to 38.7 deg. C. What is the molar heat of combustion of substance X in KJ/Mole. Heat capacity ...
chemistry
Thank You! You have answered a couple of my questions and I wish I had you for my Professor as mine seems to expect knowledge and not want to teach it! (haha but not really funny!) Thanks again!
chemistry
Okay, so this was a question on a quiz and I'm not sure if we were to just assume that it was dissolved? But the moles of CaCO3 is .4 correct?
chemistry
what is the molarity of 40g in 0.5L of solution. Molecular weight of substance is 100.09g/mole.
chemistry
if you have 1000g of a substance at -20 degrees celsius with a specific heat of .110 c/1 degree celsius and you add 12 kilojoules to it what is the resulting temperature?
Chemistry
8.1 x 10 to (-3)power has 2 sig fig. 910 has 2 sig fig zero doesn't count unless there is a decimal point after it. 175.0 has 4 decimal point is present and zero is to the left of the other sig figs. hope this helps!
Physics 102 (College)
I'm stuck on part B of this question: A system does 125 J of work on environment and gains 79 J of heat in the process. Find change in internal energy (delta U, abbreviated dU)of a. the system and b. the environment. A. Find dU of the system W = 125 J Q = 79 J dU = Q - W d...
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