chemistry
p=h/lambda(meters) , E= p^2/2m + 1.659*10^-18, LambdaMax=hc/E
chemistry
Jiskha is not part of the MITx platform!!! How the honor code of MITx could be applied to an user of other system?
chimistry
p=h/lambda(meters) , E= p^2/2m + 1.659*10^-18, LambdaMax=hc/E
Chemistry
-422.24
Chemistry
10.4
Chemistry
(Kg og Na)/ 23*4 =X X * 47.88 = in g convert to Kg
chemistry
p=h/lambda(meters) , E= p^2/2m + 1.659*10^-18, LambdaMax=hc/E
chemistry
Jiskha is not part of the MITx platform!!! How the honor code of MITx could be applied to an user of other system?
chemistry
-422.24
chemistry
p=h/lambda(meters) , E= p^2/2m + 1.659*10^-18, LambdaMax=hc/E
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