If 18.80 grams of hydrochloric acid are reacted with a large amount of aluminum metal, what volume of hydrogen gas would be produced at STP? (Hint: start by writing a balanced equation for the reaction.) 3HCl + Al -> 3H + AlCl3 18.80g moles= grams/mw 18.80/109.5 0.171689497...
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How many milliliters of 0.0850 M Na3PO4(aq) will react with 22.00 mL of 0.0800 M MgCl2(aq)? 3 MgCl2(aq) + 2 Na3PO4(aq) ==> Mg3(PO4)2(s) + 6 NaCl(aq) V x M = V x M (22.00mL)(0.0800M) = (0.0850M)(x) Is this the correct set-up? Does it have 4 sigfigs, or am I wrong?
4 P 8.28g m=g/mw x=8.28/124.0 x=0.067 + 502 15.65g x=15.65g/160 x= 0.0978 = P4O10
4 P + 5 O2 -> P4O10 8.28g 15.65g moles=g/mw x=15.65g/160.0 x=8.28/124.0 x= 0.0978 x=0.067 Which one would be limited? Please help if possible. Also, are my sigfigs correct?
Given the following two step reaction: 4 P + 5 O2 -> P4O10 P4O10 + 6 H2O -> 4H3PO4 If you have 8.28 g of P, 15.65 g of O2, and 19.95 g of H2O, how many grams of H3PO4 can be produced?
$2500 is invested in an account at interest rate r, compounded continuously. Find the time required for the amount to (a) double and (b) triple. r=0.085 I know you use the formula A=Pe^rt and you would start by setting it up as follows: A=(2500)e^(0.085)(t) I'm not sure wh...
What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of 1.5x10-3 if Km=2.9x10-4 and Ki=2x10-5?
You have found the following stock quote for RJW Enterprises, Inc., in the financial pages of today's newspaper. The closing price for this stock that appeared in yesterday's paper was $????. If the company currently has 17 million shares of stock outstanding, the net ...
Find required water pressure to supply water at h = 35.0 ft and P = 40.0 Lb/in^2. ----------------------------------- Working equation: P = hDw where P = pressure, h = height, Dw = weight density (Dw for water is 62.4 Lb/ft^2) ----------------------------------- P at bottom = ...