Thursday
December 5, 2013

Total # Posts: 73

Chemistry
If 18.80 grams of hydrochloric acid are reacted with a large amount of aluminum metal, what volume of hydrogen gas would be produced at STP? (Hint: start by writing a balanced equation for the reaction.) 3HCl + Al -> 3H + AlCl3 18.80g moles= grams/mw 18.80/109.5 0.171689497...

Chemistry
Thank you SO much. Not only did you help me get the correct answer, but you helped increase my understanding of these problems. Cheers to you.

Chemistry
How many milliliters of 0.0850 M Na3PO4(aq) will react with 22.00 mL of 0.0800 M MgCl2(aq)? 3 MgCl2(aq) + 2 Na3PO4(aq) ==> Mg3(PO4)2(s) + 6 NaCl(aq) V x M = V x M (22.00mL)(0.0800M) = (0.0850M)(x) Is this the correct set-up? Does it have 4 sigfigs, or am I wrong?

Chemistry
4 P 8.28g m=g/mw x=8.28/124.0 x=0.067 + 502 15.65g x=15.65g/160 x= 0.0978 = P4O10

Chemistry
4 P + 5 O2 -> P4O10 8.28g 15.65g moles=g/mw x=15.65g/160.0 x=8.28/124.0 x= 0.0978 x=0.067 Which one would be limited? Please help if possible. Also, are my sigfigs correct?

Chemistry
Given the following two step reaction: 4 P + 5 O2 -> P4O10 P4O10 + 6 H2O -> 4H3PO4 If you have 8.28 g of P, 15.65 g of O2, and 19.95 g of H2O, how many grams of H3PO4 can be produced?

Trig/Pre-Calc
\$2500 is invested in an account at interest rate r, compounded continuously. Find the time required for the amount to (a) double and (b) triple. r=0.085 I know you use the formula A=Pe^rt and you would start by setting it up as follows: A=(2500)e^(0.085)(t) I'm not sure wh...

Biochem
What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of 1.5x10-3 if Km=2.9x10-4 and Ki=2x10-5?

Finance
You have found the following stock quote for RJW Enterprises, Inc., in the financial pages of today's newspaper. The closing price for this stock that appeared in yesterday's paper was \$????. If the company currently has 17 million shares of stock outstanding, the net ...

physics
Find required water pressure to supply water at h = 35.0 ft and P = 40.0 Lb/in^2. ----------------------------------- Working equation: P = hDw where P = pressure, h = height, Dw = weight density (Dw for water is 62.4 Lb/ft^2) ----------------------------------- P at bottom = ...

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