Posts by berhana
Total # Posts: 2
more trig.... how fun!!!!
if you can't help me with my first question hopw you can help me with this one. sec(-x)/csc(-x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(-x)/csc(-x) = sin(-x)/cos(-x) = tan(-x) However, tan (x) does not...
how do you start this equation i've been tryng it for 20min. sec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x ec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x Factor out a sec^5 tan and divide thru. Left is sec^2 x = Tan^2 x Then this should reduce to sin^2 x = cos^4 x take the...