Monday

December 22, 2014

December 22, 2014

Total # Posts: 6

**calculus**

pleaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaasw help can you pleaaaaase help me find the area between y=cos(4x) and y=1-cos(4x) 0<=x<=pi/4 i tried to solve it, and i got like : 2*sqrt3+ pi/12 is it right? if not please tell me how can i solve it...i'm really confused i ...
*May 2, 2010*

**calculus**

i did all that, i found Pi/12 then , i took the integral from 0 to pi/12, and from pi/12 to pi/4 and i got: integr from 0 to pi/12 cos(4x)-(1-cos(4x) + integ from pi/12 to pi/4 1-cos(4x)-cos(4x) but i'm not sure if it was right or not...can u check with me please?
*May 1, 2010*

**calculus**

can you pleaaaaase help me find the area between y=cos(4x) and y=1-cos(4x) 0<=x<=pi/4 i tried to solve it, and i got like : 2*sqrt3+ pi/12 is it right? if not please tell me how can i solve it...i'm really confused
*May 1, 2010*

**Math**

Consider the equation below. (Give your answers correct to two decimal places.) f(x) = 8sin(x) + 8cos(x) 0 ≤ x ≤ 2 (a) Find the intervals on which f is increasing. (Enter the interval that contains smaller numbers first.) ( , ) union ( , ) Find the interval on ...
*March 10, 2010*

**chemistry**

thank you so much
*March 1, 2010*

**chemistry**

a student synthesized 6.895g of barium iodate monohydrate, Ba(IO3)2.H2O, by adding 30.00 mL of 5.912*10^-1M barium nitrate, Ba(NO3), to 50.00 mL of 9,004*10^-1 M sodium iodate, NaIO3 (1) write the chemical equation for the reaction of solutions of barium nitrate and sodium ...
*March 1, 2010*

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