Monday
July 28, 2014

Posts by atif


Total # Posts: 3

math
integral x/(x+5)^1/2 (u-5)/u^1/2 du giving u^1/2 du -5u^-1/2 du and integral will be now 2/3 u^3/2 -10u^1/2 +c =2/3(x+5)^3/2 -10(x+5)^1/2 +c =2/3(x+5)^1/2{(x+5) -30} +c =2/3(x+5)^1/2{(x -25} +c have i done something wrong??

math
integral from 5 to 0 1/(4+x^2)^1/2 this is what i have so far 1/(sq.root(4+x^2)) as (1/2) (1+y)^-(1/2) with y=(x/2)^2 The binomial series of (1+y)^a = sum_k (a,k) y^k where (a,k) is the binomial symbol. In this case a=-1/2. for some reason when i plug in the values i get the w...

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