Chemistry
4.00 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.20 M, where it remained constant. A(s) <-------> B(g)+C(g) Then, the container volume was doubled and e...
Chemistry
2.422 mols is wrong.
NEED HELP ASAP!
Kc = 1.2^2/3.8=0.379 The container volume is doubled A(s)<------>B(g)+C(g) (3.8/2)-----x----x--- 0.379 = (x^2)/(1.9 - x) x^2 + 0.379x - 0.7201 = 0 x=0.679 M A = 1.9 - 0.679 = 1.22 M But I got it wrong.
NEED HELP
I got it wrong. X doesn't equal .189. I really need help on solving this problem.
NEED HELP!
Is x=0.189? I used the quadratic equation to solve for x from Kc = 0.514 = (0.6+x)(0.6+x)/(1.4-x). How do you find the moles of A?
NEED HELP ASAP
How do I find x and the moles?
Chemistry Help
For the first Kc I got .514 For the second Kc I got .129. How do I find the mols afterwards?
Chemistry
4.00 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.20 M, where it remained constant. A(s) <-------> B(g)+C(g) Then, the container volume was doubled and e...
Chemistry HELP
It is wrong. It said Incorrect. You need to compare Qc to Kc, not Kp.
Grammar (Last one :) )
Thank you :)
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