NEED HELP!
So part a would be at equilibrium and part b would be goes to the left?
Chemistry
In which direction will the net reaction proceed X(g)+Y(g)<---->Z(g) Kp=1.00 at 300k for each of these sets of initial conditions? a) [X]=[Y]=[Z]=1.0 m net reaction goes to the left net reaction goes to the right reaction is at equilibrium I chose 3 for a. b) Px=Pz=1.0 a...
Chemistry
Kc = 1.2^2/3.8=0.379 The container volume is doubled A(s)<------>B(g)+C(g) (3.8/2)-----x----x--- 0.379 = (x^2)/(1.9 - x) x^2 + 0.379x - 0.7201 = 0 x=0.679 M A = 1.9 - 0.679 = 1.22 M But I got it wrong.
NEED HELP!
•NEED HELP ASAP - Anon, Tuesday, February 5, 2013 at 11:14pm How do I find x and the moles? •NEED HELP! - Anon, Tuesday, February 5, 2013 at 11:25pm Is x=0.189? I used the quadratic equation to solve for x from Kc = 0.514 = (0.6+x)(0.6+x)/(1.4-x). How do you find the...
Chemistry
4.00 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.20 M, where it remained constant. A(s) <-------> B(g)+C(g) Then, the container volume was doubled and e...
Chemistry
2.422 mols is wrong.
NEED HELP ASAP!
Kc = 1.2^2/3.8=0.379 The container volume is doubled A(s)<------>B(g)+C(g) (3.8/2)-----x----x--- 0.379 = (x^2)/(1.9 - x) x^2 + 0.379x - 0.7201 = 0 x=0.679 M A = 1.9 - 0.679 = 1.22 M But I got it wrong.
NEED HELP
I got it wrong. X doesn't equal .189. I really need help on solving this problem.
NEED HELP!
Is x=0.189? I used the quadratic equation to solve for x from Kc = 0.514 = (0.6+x)(0.6+x)/(1.4-x). How do you find the moles of A?
NEED HELP ASAP
How do I find x and the moles?
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