Thursday
May 23, 2013

# Posts by andrew

Total # Posts: 858

Chemistry
For 105ml of a buffer that is .40 M in HOCL and .36M in NaOCL what is the pH after 13.4 ml of 1.5M NaOH is added? Ka for HOCL is 3.5x10^-8

Chemistry
Alright, I got it thanks!

Chemistry
I'm messing up somewhere 1x10^30= [.011-x]/[x][.836+4x]^4 4.8x10^29(x)+2.56x10^32(x^5)=.011-x Factoring out an x and moving all terms x(4.8x10^29+2.56x10^32(x^4))-.011+x=0 Then because of the relative size I assumed -.011 and x are negligible x(4.8x10^29+2.56x10^32(x^4))=0...

Chemistry
What is the concentration of Hg^2+ in 500.0 mL of a solution that was originally 0.011 M Hg^2+ and had 73 g of KI added to it? Hg^2+(aq) + 4I^-(aq)<=> HgI4^2-(aq) The overall formation constant is 1x10^30

physics
A building has become accidentally contaminated with radioactivity. The longest-lived material in the building is strontium-90. (The atomic mass of Sr is 89.9077 u.) If the building initially contained 4.8 kg of this substance and the safe level is less than 10.0 counts/min, h...

physics
After 1.84 days, the activity of a sample of an unknown type radioactive material has decreased to 85.8% of the initial activity. What is the half-life of this material? (in days)

Chemistry
Alright, I was able to figure them all out. Thank you!

Chemistry
So for the first portion I came to Kb=1.5x10^-10 then x^2/.14-x= 1.56x10^-10 x^2-(2.2x10^-11)x - 1.56x10^-10=0 solving with the quadratic equation I came to x= 1.25x10^-5 (I'm disregarding i) So -log(1.25x10^-5)= 4.9 But somewhere I've done something wrong as the homew...

Chemistry
Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. (a) 100.0 mL of 0.14 M HC7H5O2 (Ka= 6.4 multiplied by 10-5) titrated by 0.14 M NaOH halfway point equivalence point (b) 100.0 mL of 0.29 M C2H5NH2 (Kb = 5.6 multiplied by 1...

science
Its C...Nodules of certain plants such as clover fix Nitrogen to the soil...thats the reason farmers grow cver ...then plow it back into the soil..Natural source of Nitrogen...dontknow about the others...

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