Sunday
May 19, 2013

Posts by ami


Total # Posts: 247

chm
Calculate the PH OF A SOLUTION prepared by mixing 15.0mL OF 0.50 M OF NaOH AND 30.0mL OF 0.50 M BENZOIC ACID SOLUTION?( Benzoicacid is monoprotic and its dissociation constant is 6.5*10^-5)

chm
What is the pH of the solution obtained by mixing 30.00mL OF 0.250M HCL AND 30.00mL OF 0.125M NaOH?

mat 172
solve the equation: arccosx+arccos2x=arccos1/2

Microbiology
64

CHM
Given the initial concentrations of 0.10 atm NO2 and 0.10 atm N2O4 in a 1.0 L flask, what will be the equilibrium partial pressure of NO2? N2O4(g)=2NO2 Kp=0.660at319K Choose one answer. a. 0.10 atm b. 0.31 atm c. 0.045 atm d. 0.72 atm e. 0.19 atm

chm152
At a particular temperature, Kc = 54 for the reaction H2(g) + I2 (g) <=> 2 HI(g). One mole of HI is placed in a 3.0-L container. What would be the equilibrium concentration of HI? Choose one answer. a. 0.035 b. 0.071 c. 0.29 d. 0.30 e. 0.33

chm152
PCL5(g)=PCL3(g)+CL2(g) 5.0 moles of PCL5 are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium. Choose one answer. a. 0 b. 1.0 c. 2.0 d. ...

chm152
PCL5(g)=PCL3(g)+CL2(g) 5.0 moles of are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium. Choose one answer. a. 0 b. 1.0 c. 2.0 d. 3.0 ...

chm152
Consider the following equilibrium: 5.0 moles of are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium. Choose one answer. a. 0 b. 1.0 c....

chm152
When solid NH4HS is placed in a closed flask at 28 C, the solid dissociates according to the equation: NH4HS(s) <=> NH3(g) + H2S(g) The total pressure of the equilibrium mixture is 0.766 atm. Determine Kp at this temperature. Choose one answer. a. 0.147 b. 0.766 c. 0.587...

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