Physics
Work required = Gain in PE = m*g*h = 1460*9.8*14Sin12.5 J (h-vertical height gained)
physics
Loss in KE = Gain in elastic PE of the spring. (1/2)mV^2 = (1/2)kx^2 find K from this equation. Remember to convert the units of V to m/s
Physics
consider a sytem comprising of Sunbather + raft. No external force on this system.Therefore thr Center of mass of the system will remain stationary. If she walks to the west, the raft will move to the east by a distance that will keep the CM at the original location. No extern...
Physics Angular displacement
Car's displacement= S = ut + at^2/2 = 25*6 + 2*6^2/2 = 150 + 36 = 186m One rev. of wheel covers = 2*pi*r No. of revolutions = 186/(2*pi*0.25) = 118.4 rev.
science
Do vector addition of the two velocities to obtain boat's velocity V w.r.t.river bank: V = sqrt(12^2+5^2) = 13 Km/hr and tan theta = 5/12; (theta - angle between V and north)
science
1) Speed of man w.r.t.escalator = L/t1 2) Speed of escalator w.r.t.ground = L/t2 3)Speed of man w.r.t.ground = (L/t1)+(L/t2) Time taken by man to cover distance(L) = L/(L/t1)+(L/t2) = t1*t2/(t1+t2)
science
1) change in speed: 12-5 = 7m/s 2) V1=5i & V2=12j Change in vel.= V2-V1 = 12j-5i its magnitude = sqrt(12^2+5^2) = 13m/s^2 3) x-dir.: 0=5+Ax*5 => Ax= -1m/s^2 y-dir.: 12=0+Ay*5 => Ay= +12/5=2.4m/s^2 So A = -1i+2.4j Mag. of av. acc.=sqrt(Ax^2+Ay^2)
science
Yes the bullet will hit the monkey as both fall with downward accleration of g m/s^2. Hint: The bullet will hit the monkey at a ht. S above the ground given by: S = V*Sin(theta)*t - (1/2)*g*t^2 {V-initial velocity at an angle theta with horizontal} During this time t, the monk...
Engineering Physics
Since the platform is 3m above ground(vertical height), the gravitational PE gained would be m*g*h - no need to multiply by Sin 30
physics
The truck is moving at constant velocity - means zero acceleration - that can happen only when the net force acting on the truck is zero.The frictional force opposes the motion and its magnitude is same as that produced by the engine for forward motion (under constant velocity...
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