Tuesday
May 21, 2013

# Posts by ajayb

Total # Posts: 117

Physics
Q=m*s*T I hope you can compute Q (heat required)

physics
use the formula: V^2=U^2-2*a*s where V is final velocity =0 U is initial velocity a is accn. = 12 m/s^2 s is height attained Compute s from the formula.

PHY: To AJAYB, follow up on previous response
I just answered your questions in the previous post. You are welome to ask again in case of any doubt.

PHysics
w^2 = k/m => k = m*w^2 =15*32^2 =15,360 n/m E =(1/2)k*A^2 =(1/2)*15360*(.20)^2 =307 J

Physics
You've to consider the motion in vertical and horizontal directions seperately. A)Vertical (y) dir.=> Vy^2 = Uy^2 + 2*(-g)*s = (10Sin45)^2 + 2*(-9.8)(-10) = 50 + 196 = 246 So, Vy= 15.68 m/s (Vy is the vertical component of the projectile when it hits the ground) B) Hori...

Physics
Remember Newton's third law of motion. The reactionary force on the car would be of the same magnitude i.e. 1580N.

Physics- Repost (Answer did not make sense)
My mistake - I wrongly considered the battery voltage to be 6V instead of 12V. B) The capacitor voltage will reach 6V (half of its final voltage) in 0.693*TC time. You can also use the equation: V = V0{1-e^(-t/RC)} where V=6 and V0=12. You'd get t= 8.316 ms C)Find q0 by us...

Physics- Repost (Answer did not make sense)
A) Your answer is correct - the time constant of the circuit is indeed 12ms. B) The time required to reach the final voltage by a capacitor is roughly 4*TC. In this case,the capacitors would charge up to full battery voltage(6V)in 48 ms. C) t=10 nano-seconds is such a short ti...

physics
T = 2*pi*sqrt(m/k) so k = 4*pi^2*m/T^2 = 444.5 N/m E = (1/2)*k*A^2 = (1/2)*444.5*0.155^2 = 5.34 J

Physics
You might have forgotten to include the latent heat - heat required to convert the state from ice to water w/o change in temp. Consider this factor and you could get the correct answer.

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