Math
What are you solving for? Are you solving for (y) or (x) or are you just combining "like" terms?
math
Or you could just do the Algebra. A=lw would be A=(cm)(cm) = cm^2 or A=(m)(m) = m^2 if you had the dimensions be 2 times the first one it would be 4 times as big, since it was squared. 3 would be 9 times, 4 would be 16 times, and so on.
math
let's take a rectangle for example. It has a width of 2 and a lengh of 3. You just take A=lw so the are is (2)(3)= 6 The one that is three times the other is 2(3) and 3(3) or 6 x 9 = 45. It is 9 times bigger. 45/6 = 9
math
yes that is correct. 1 m = 100cm so A = 100 cm x 100 xm A = 10000 cm^2 Good job!
College Algebra
Give the real solution set for each of the following: 42) log(6)(x^2+11) + log(6)x = 1 + log (6)(x^2+1)
College Algebra
I meant give the real solution set for the problem above
College Algebra
Write each of the following as a single logarithm (log (x+3))/(3) = 1
College Algebra
Write each of the following as a single logarithm: 8) ((5-log x)/4) + 4log y =
College Algebra
Give the rational number that is the exact value for each of the following: 14) Log(9)((∛(3)/(ã(27))=
Math
Meant you need to convert the percent into a decimal =P Lol
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