Thursday
May 5, 2016

# Posts by Venkatarama

Total # Posts: 8

physics
what about the initial 1v on capacitor c2. Since the source is at 5v ,this capacitor charge cannot get redistributed.Hence should it not add to the final value across c2? can somebody throw some light on this.?
September 10, 2012

physics
lets say two capacitors C1 and C2 1uF each are connected in series with a voltage source 5v. One of the capacitors C2 has an initial voltage of 1v and the other has no charge on it initially.What is the final voltages across the capacitor C2?
September 10, 2012

physics
September 10, 2012

physics
lets say two capacitors C1 and C2 1uF each are connected in series with a voltage source 5v. One of the capacitors C2 has an initial voltage of 1v and the other has no charge on it initially.What is the final voltages across the capacitor C2?
September 10, 2012

Physics
The first answer is correct...final voltage will be: Qtotal/(C1+C2)=0.347
February 14, 2012

Physics
Depending on which way they are wired:assume they are wired positive plate to negative plate of each other. Then Qeff=16*4-7*4=36uC.(If wired positive plate to positive plate then charges will add up) This charge will get redistributed. Applying conservation of charge: Qeff=(...
February 14, 2012

Physics
Ceq(c1,c2):3uF. This combination is in series with the 3uF capacitor and both are connected to the 15v battery. The voltage will get divided equally since they are both of the same value(7.5v). Hence energy would be. Both c1 and c2 have 7.5v across them since they are in ...
February 10, 2010

Physics
a.Ceq=8mf. b.16v since they are in parallel to the source. c.q=5*16 and q=3*16 respectively. d. 128mC is the total charge
May 31, 2007

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