Find the LCD: a) (12/55c^6) (4/11c^9) b) (9/4c+12) (5c/5c+10) c) (9x/x^2-4x+4) (5x/x^2-5x+6) d) (7/x) (3/42-7x) (x/x^2-36)
what is the ratio of 4 engines to 18 box cars....trying to help my son in math???
x=2 m=21 w=-12
A gardener has 72' of edging. She wants to use it to enclose a 125 square foot rectangular area; she does not have to use up all of the edging. What are the possible lengths that a side of the rectangle can have? Answer using interval notation. Hint: If the length of the r...
What is the total capacitance of capacitors connected in series, C1=444F, C2=621F
You simply factor out a 2x to get: 2x(3x+7)
When there is a negavtive exponent you need to flip the term to makee it positive so the problem should be written as: H(x)=(x^4-2x+7)[(1/x^3)+(2/x^4)] Then you simply multiply the two groups to get: H(x)=[(x^4-2x+7)/(x^3)]+[2(x^4-2x+7)/(x^4)] Then simplify the second fraction...
Possible derivation: d/dx(f(x)) = d/dx(log(x) csc(x)) The derivative of f(x) is f'(x): f'(x) = d/dx(log(x) csc(x)) Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u =csc(x) and v = log(x): f'(x) = log(x) (d/dx(csc(x)))+csc(x) (d/dx(log(x))) The...
I dont know if this is right because if you are using x for the distance the man is away from the light post then you cant set x equal to the rate at which the man is walking.
A man is 6ft tall and is walking at night straight toward a lighted street lamp at a rate of 5 ft/sec. If the lamp is 20 ft above the ground, find the rate at which the length of his shadow is changing.