Math- polynomial functions
State the number of complex roots of each equation then find the roots. I cant figure out these two! 1. 3x - 5 =0 2. c^2 + 2c + 1 = 0
pre- algebra
In a survery, students were asked whether they play basketball or tennis. Of 34 students, 24 play basketball and 13 students play tennis.4 students play neither. How many students play both sports? Is it 7 students?
pre- algebra
In a survery, students were asked whether they play basketball or tennis. Of 34 students, 24 play basketball and 13 students play tennis.4 students play neither. How many students play both sports? Is it 7 students?
physics-telescope
I tried to get help from a friend, but her email just said to use tan theta = x/D. I'm not sure why she said to use tan theta, and when I do that-> tan 0.00001165*2.4m=x I get x= 0.000000487 which is obviously not right.
physics-telescope
My prof says that the answer should be of magnitude 10^19. I'm not sure what he's doing differently. Is there another way to solve this?
physics-telescope
My prof says that the answer should be of magnitude 10^19. I'm not sure what he's doing differently. Is there another way to solve this?
physics-telescope
The Hubble Space Telescope (HST) can resolve objects that have a small angular separation because there is no atmospheric distortion of the light. (i.e. The HST has excellent resolving power.) Its 2.4-m-diameter primary mirror can collect light from distant galaxies that form...
physics, error calculation repost
sorry, edit, that would be (deltaM/M + deltaT/T)N
physics, error calculation repost
Hi Bob, I have to derive the error in the wavelength. I only know how to derive error equations from multiplication or addition/subtraction. For example, if I needed to derive an arror equation for N=MT it would be deltaN=(deltaM+deltaT)N So how do I do it for a division quest...
physics, error calculation repost
I need to derive an error equation for Bohr's model to use in my physics lab this week. I am really bad at calculus, so if anyone can help me that would be really great. the equation is (1/lambda)=R[(1/n^2final)-(1/n^2initial)] I've never had to derive anything like t...
Pages: 1 | 2 | 3 | 4 | 5 | 6 | Next>>
For Further Reading
