I have this integral that I don't know how to solve: ∫ (x-3)/sqrt(x) Would I multiply both parentheses first? or just turn it into (x-3)(x^-0.5)?
okay so there must be a mistake with the system, thanks for clearing that up Damon.
Using an upper-case "C" for any arbitrary constants, find the general indefinite integral ∫ (-2-t)(-9-t^2) dt Now I multiplied both parentheses to get: ∫ (18 + 2t^2 + 9t + t^3) dt now I integrated and got: 18t + 2t^3/3 + 9t^2/2 + t^4/4 + C but I'm tol...
2x-5=39 2x=39-5 2x=34 x=17
come on i waitied almost for 20 minutes and this is what i get. -_- not cool
A park ranger finds that 35% of the park visitors stay at the campground. Of 105 visitors stayed at the campground in one day, how many visitors did the park have that day? i got 36.75 people and then i rounded and got 37 people.
Thank Steve. But how do you get 60 or 70? or the -1?
it's integral, not interal, sorry for the mistake
find the derivative of: g(x) = interal(a=7x, b=6x) (u+5)/(u-5) du Hint: interal(a=7x, b=6x) (u+5)/(u-5) du = interal(a=0, b=6x) (u+5)/(u-5) du + interal(a=7x, b=0) (u+5)/(u-5) du
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