did I solve the problem correctly? c=$200+$50h c=$300+$25h is the answer c=$250 c=$325 Do all I have to do to this equation is to add them to get the total cost of labor with h=labor per hour and c=cost or do I have to solve it in a different way. I'm sorry for all the que...
For me to solve the system of equations for the total cost of lawn care using the tequnique substitution am I right to say: c=$200+$50h c=$300+$25h would be c=$250 c=$325
If my equation that I wrote does it matter how it is written. Does it matter if I write it' $200+$50h=c or c=$200+$50h or c=$50h+200
I have a problem with break even analysis? the question is I'm trying to find the cost between 2 businesses to care for my lawn. The one company has an initial fee of $200+$50an hour for labor cost and the second company has an initial cost of $300+$25an hour for labor cos...
It is easy to see a drop of water on the print of a glossy magazine but it is difficult to see it on the white area of the same page. Explain why.
y + x = -8 y - x = 4 Use substitution.
oh wait. no. the limiting reactant is CuSO4
So the limiting reactant is aluminum? Thank you so much!
2Al + 3CuSO4 --> + 3Cu + Al2(SO4)3 * copper(II) sulphate is a hydrate 1.2g of CuSo4 50mL of water 1.0 g of aluminum foil What is the limiting reactant?
Could a simple machine such as a lever, a pulley system or a hydraulic jack be considered a heat engine?
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