Monday

December 22, 2014

December 22, 2014

Total # Posts: 27,667

**math**

3:00 pm is 15 hours after midnight 6sin(pi/12 (15-11))+19 6sin(pi/12 * 4)+19 6sin(pi/3)+19 6*0.866+19 24.196 6+19=25 is the maximum possible temperature
*November 21, 2014*

**algebra**

x(2x+3) = 119
*November 21, 2014*

**math**

since the seat started at 60, it takes 1/2 turn to get back around to that height on the other side. That's 3.5 minutes
*November 21, 2014*

**Math**

√112 = ?
*November 21, 2014*

**math**

A B is an equation, not an expression C is too, and not even algebraic D is just a constant expression
*November 21, 2014*

**math**

Yes. In 1/4 turn, the wheel will be at the top.
*November 21, 2014*

**math**

any value between 64.8 and 65.4. For example, 65.0 64.800000000000000000000000000001 65.399999999999999999999999999999
*November 21, 2014*

**plz help. math**

Beckey! steven is mooching off your postings! Or, why not just use a single name, steven old buddy?
*November 21, 2014*

**plz help. math**

165 = 3*5*11 So, the table could seat 3,5,11,15,33,or 55 people The restriction on table size means that the only choices are 3,5,11,15
*November 21, 2014*

**algerbra**

If you mean √2, then the possibilities for a right triangle are 1 and 11, since 1^2 + √2^2 = 3 √2^2 + 3^2 = 11 If you meant 1/2, then the choices are √11/2 and √37/2 (1/2)^2 + 3^2 = √37/2 (1/2)^2 + (√11/2)^2 = 3
*November 21, 2014*

**algerbra**

try again. what is /2 ?
*November 21, 2014*

**algerbra - incomplete**

First, provide the length of the other side.
*November 21, 2014*

**algebra**

one way is to complete the square: x^2 + 5x + 3 = 0 x^2 + 5x = -3 x^2 + 5/x + (5/2)^2 = -3 + (5/2)^2 (x + 5/2)^2 = 13/4 x + 5/2 = ±√13/2 x = (-5±√13)/2 You get the same answer using the quadratic formula.
*November 21, 2014*

**geometry**

There are lots of sample constructions here: http://jwilson.coe.uga.edu/EMAT6680Fa08/Ruff/TriangleConstructions/TriangleConstructions.html
*November 21, 2014*

**math**

play around some at http://www.miniwebtool.com/hex-calculator/
*November 21, 2014*

**MATH**

Assuming hexadecimal, D5C
*November 21, 2014*

**math**

better check your text some more. With initial height h and initial velocity v, the height y at time t is y(t) = h + vt - 16t^2 So, you have y(t) = 20 + 5t - 16t^2 When working problems, don't forget what you know about parabolas -- their roots, vertex, etc.
*November 21, 2014*

**college algebra**

solve for t in 5300 * 1.077^t = 8000 * 1.056^t t = 20.9 years or, 21, since the interest is credited at year's end.
*November 21, 2014*

**math (fractions)**

mixed number
*November 21, 2014*

**DON VASCO PATNA**

you want 3/4 the concentration, so you must have 4/3 the volume.
*November 21, 2014*

**algebra 2**

just factor out the perfect squares: √25 = 5 √a^2 = a √b^5 = b^2 √b √(a^2/b^2) = a/b
*November 21, 2014*

**Algebra II**

you do have to remember to insert zeros for missing powers. Play around at http://www.mathportal.org/calculators/polynomials-solvers/synthetic-division-calculator.php
*November 21, 2014*

**algebra**

861bagels/3days = 287 bagels/day
*November 20, 2014*

**math**

father = 4y = brother+28 brother = father-28, so 4y-28
*November 20, 2014*

**Algebra**

31500(1+.068/365)^(365*30)
*November 20, 2014*

**math**

I'm sure you have a formula. For further reading, see wikipedia's article on Richter magnitude scale. It also has a table of sample values, so you can check your answer.
*November 20, 2014*

**Math**

2000(1+.05*18)
*November 20, 2014*

**Math**

Hmmm. Better make that Tn = n+3 if n is odd
*November 20, 2014*

**Math**

Looks to me like Tn = 2n+2 if n is odd Tn = 4*2^(n/2) if n is even
*November 20, 2014*

**Physics**

Vy = 7.4*1.7 = 12.58 m/s So, the final speed is √(8^2+12.58^2) = 14.91 m/s
*November 20, 2014*

**math**

Ah. missed the 5. So, yes, 5 3/2 = 13/2
*November 20, 2014*

**math**

12/8 = (3*4)/(2*4)= 3/2
*November 20, 2014*

**MTH001**

So, what are your truth tables?
*November 20, 2014*

**math**

If the original price is p, then the discounted price is 0.85p After the fee, the final price is 0.85p + 12 = 100 p = 103.53 That is not the greatest price; it is the only price which will cost exactly $100. It is the greatest price if she does not want to spend more than $100.
*November 20, 2014*

**Math Help**

#1. The figures are similar. Since 84/28=3, c/22 will also be 3. SO, c=66 #2. I believe you are correct. The 2nd triangle is 1/3 as big as the first. #3. No. Just double each coordinate.
*November 20, 2014*

**math ?**

no, but r=0, as a little synthetic division will show.
*November 20, 2014*

**Math**

s = 1/2 at^2 v = at, so t = v/a s = 1/2 a(v^2/a^2) = 1/2 v^2/a = 112^2/64 = 196 ft
*November 20, 2014*

**Math**

v(t) = 3/2 t^(1/2) s(t) = t^(3/2) + c 33 = 9^(3/2)+c, so c=6 s(t) = t^(3/2) + 6
*November 20, 2014*

**Calculus**

The slope at any point is y' = -7cosx The line through (0,0) and (x,-7sinx) has slope -7sinx/x. That means we need -7sinx/x = -7cosx x = tanx Solutions are x = 4.493409, 7.725252, 10.904122, ... The slopes of the lines are 1.521, -0.899, 0.639 See the first couple of lines...
*November 20, 2014*

**math, please help**

Looks to me like f(x) = (x-(-2))(x^2+4x+2)+0
*November 20, 2014*

**Math Help**

Looks good to me. Except "¢10 cents" is bogus notation. Try just 10¢
*November 20, 2014*

**Math (IB Calc)**

since cos(x) has it max at x=0, and you have a min there, A(x) = 50(1-cos(x)) now just plug in x = 2pi/3
*November 20, 2014*

**Math Help**

The scale factor of 2 means that (x,y) -> (2x,2y) So, you need to double the coordinates. Not sure what the heck you devised.
*November 20, 2014*

**Math help!!!**

First step: list the ordered pairs. (Mona,Kellie) ...
*November 20, 2014*

**Math**

You don't say whether these are courses from due North, or from the positive x-axis. I'll do the latter. the x- and y-components of the vectors are (450 cos65°, 450 sin65°) = (190.18,407.84) (35 cos20°, 35 sin20°) = (32.89, 11.97) Add them up to get (...
*November 20, 2014*

**english**

The current exchange rate is 1 yen = 0.0085 dollar So, a little less than 1 cent per yen. Or, a little more than 100 yen/$ 1/.0085 = 111.65
*November 20, 2014*

**English**

and you are correct.
*November 20, 2014*

**Pre Calculus**

P(0) = 160/(1+9) = 16 Just plug in t=6 for the population after 6 years. Note that as t->∞, e^-0.165t -> 0 So, the maximum possible population is 160 See http://www.wolframalpha.com/input/?i=160%2F+%281+%2B+9e^%28-0.165t%29%29+for+t+%3D+0..50
*November 20, 2014*

**Pre Calculus**

25*e^-5k = 18.4 So, k = ln(18.4/25)/-5 = 0.0613 So, now just solve for t in 25*e^-.0613t = 20.5
*November 20, 2014*

**Pre Calculus**

solve for m months in (1+.065/12)^m = 2
*November 20, 2014*

**Pre Calculus**

after t years, the population p is p = 127000 * 0.976^t Now just plug and chug
*November 20, 2014*

**algebra**

k = (h+j)+14 = x + x+4 + 14 = 2x+18
*November 20, 2014*

**Pre-Calculus**

The numbers are surely C:1 B:2 A:3
*November 20, 2014*

**math**

multiply or divide first, left to right. Then add or subtract, left to right. So, we have 5x5-5+5 25-5+5 20+5 25
*November 20, 2014*

**Math**

they are where y=0. If the product of two factors is zero, one of the factors must be zero. So, set them to zero and solve for x: x-6 = 0 means x = 6 and similarly for the other factor.
*November 20, 2014*

**Math**

(a) has three factors, so it will be a cubic, not a quadratic.
*November 20, 2014*

**Chemistry**

the volume has increased by a factor of 200, so the molarity has decreased by the same amount. 6.00/200 = 0.03
*November 20, 2014*

**math - I'm stumped**

So, now you know that d(t) = 5+b sin(ct) Now plug in the values you know: b sin(12c) = 0 b sin(1300c) = 2 b sin(1400c) = 3.46 we can see that 12c is a multiple of π. So, sin(1300c) = sin(1296c+4c) = sin(4c) sin(1400c) = sin(1392c+8c) = sin(8c) Hmmm. I'm stuck. 4c and ...
*November 20, 2014*

**Algebra**

yes, as you can easily verify with any of many online calculators...
*November 20, 2014*

**Algebra Help**

There is no easy analytic method. The best bet is a graphic or numeric method. You can see from http://www.wolframalpha.com/input/?i=solve+lnx+%3D+-4x that the solution is x = 0.3
*November 20, 2014*

**geometry**

if the sides are in the ratio of 3:4, the areas are in the ratio (3:4)^2 = 9:16
*November 20, 2014*

**Calculus Please check**

Looks good, except for the last one. It has no critical points, since Fx is never zero. Note that the critical points are where both Fx and Fy are zero.
*November 20, 2014*

**Math**

the circumference if the can is 2π. So, there are 10*36/2π labels per roll
*November 20, 2014*

**algebra**

http://www.wolframalpha.com/input/?i=y%3C-x-1%2C+y%3Ex%2B4&dataset=
*November 19, 2014*

**algebra2**

no idea. What's the connection between the BMW and the savings account?
*November 19, 2014*

**algebra2**

15000 * e^(30*0.0133)
*November 19, 2014*

**Math**

yep - it's there. Was there a question somewhere in there?
*November 19, 2014*

**Trig**

Draw a diagram. If the stations are labeled W and E, and the balloon is B, then angle WBE = 16° angle WEB = 106° So, the distance WB can be found using the law of sines: WB/sin106° = 161/sin16°
*November 19, 2014*

**math**

just do a little synthetic division. What do you get?
*November 19, 2014*

**Algebra**

Not quite (2^x)(2^x)(2^x)(2^x) = 2^(x+x+x+x) = 2^4x What you have is 2^x+2^x+2^x+2^x = 2^x(1+1+1+1) = 4*2^x = 2^2 * 2^x = 2^(x+2) So, now you have 2^(x+2) = 2^9 x+2 = 9 x = 7 128+128+128+128 = 512
*November 19, 2014*

**Algebra Two**

well, that would be (7x+4)(3x-9)
*November 19, 2014*

**algebra 1**

-4x-2y = -12 4x+8y = -24 add the two equations and you have 6y = -36 y = -6 now use that to get x
*November 19, 2014*

**Math**

First step: list the ordered pairs. (Mona,Kellie) ...
*November 19, 2014*

**Algebra**

solve for p in p(1+.12/2)^(2*7/2) = 45000
*November 19, 2014*

**Algebra 2**

x is x^1, so x*x^7 = x^(1+7) = x^8 the final answer is thus x^8/2
*November 19, 2014*

**math**

12/(12+6) = 12/18 is that at least 0.65?
*November 19, 2014*

**physics**

At the top of the toss, all the KE has been converted to PE, so 1/2 mv^2 = mgh or, v^2 = 2gh
*November 19, 2014*

**physics**

figure the distance each has traveled, and use the law of cosines to get the final separation. Start by drawing a diagram, so you know what's what.
*November 19, 2014*

**Algebra**

2000(1+.05)^18
*November 19, 2014*

**Algebra**

Assuming the coordinates are for the kite and the shadow, then the equation describing the line from the kite to the shadow is y = 4x Its slope is 4, so the slope of the string is -1/4. Its equation is y-12 = -1/4 (x-3) So, the x-intercept is (51,0) Thus, the distance is 51 ft
*November 19, 2014*

**MATH!!!**

b = 5a/11 c = 5b/11 d = 5c/11 what is the "agreed"? plug in your final result c+?+d=750 and then start substituting in to get a
*November 19, 2014*

**physics**

Ever heard of E=mc^2 ?
*November 19, 2014*

**math**

3/2 is more than 1 5/6 is just under 1 So, the only two that can cause trouble are 1/8 and 2/9 1/8 = 9/72 2/9 = 16/72 So, the order is clearly 1/8 2/9 5/6 3/2
*November 19, 2014*

**math**

area is proportional to the scale^2. So, 12cm^2 * (10^4)^2 = 12*10^8 cm^2 since 1m^2 = 10^4 cm^2, that means the area of the real lake is 12*10^4 m^2 = 12 ha
*November 19, 2014*

**Math**

#1 The first equation says y=6-4x. So, use that in the second equation and you have x-2(6-4x) = 15 Do #2 in like wise. Or, you can say that 2x = 10-y, so since 4x = 2(2x), 2(10-y)+2y = 5
*November 19, 2014*

**English**

Good idea. What do you have to say?
*November 19, 2014*

**math**

little kids
*November 18, 2014*

**math**

#1 We see that x = y-2, so 2(y-2)+5y = 9 Do the others in like wise.
*November 18, 2014*

**math**

You know you have at least 3 nickels, because only $5.75 can be made with just quarters. So, you have at most 47 quarters. 47 quarters = $11.75 plus 3 nickels = $11.90 That is $6.00 too much. Each quarter replaced by a nickel reduces the value by 20 cents. Since you have $6.00...
*November 18, 2014*

**3rd grade math**

all multiples of 2 are even every even row contains all evens every odd row contains multiples of 2 in the even columns. Similarly for the columns.
*November 18, 2014*

**trigometry**

Did you draw a diagram? If so, then it's easy to see that sinθ = 20/75
*November 18, 2014*

**Calculus**

yes, the product rule, and also the chain rule: y = (x)(e^-x^2) y' = (1)(e^-x^2) + (x)(e^-x^2)(-2x) = (1-2x^2)e^-x^2 If y = e^u, then y' = e^u u'
*November 18, 2014*

**Algebra 2**

recall that since i^2 = -1, 1/i = -i 1/(-1-i) * (-1+i)/(-1+i) = (-1+i)/2 1/(2i) = (1/2)(1/i) = (1/2)(-i) = -1/2 i
*November 18, 2014*

**CAL**

the tangent line has the same slope as the curve at the point of tangency. The slope at any x is y' = x^2-1 So, y'(1) = 0 Now you have a point and a slope, so the line is y + 2/3 = 0(x-1) or, y = -2/3 See the graphs at http://www.wolframalpha.com/input/?i=plot+y%3D+x^3...
*November 18, 2014*

**Algebra**

p = kv^2 so, if v is replaced by 2v, then p becomes k(2v)^2 = k*4v^2 = 4kv^2 = 4p So, p grows by a factor of 4. Makes sense, since p grows as v^2.
*November 18, 2014*

**algebra 1**

not quite ∛-64 = -4 (8 is √64) also, you need to divide both exponents by 3. 8=3*2+2 and 5=3+2 so, the answer is -4x^2y ∛(x^2y^2)
*November 18, 2014*

**algebra 1**

it's pretty, but it's not the answer ...
*November 18, 2014*

**Math**

eh? x <= 49 is "not more than" So, I'd pick (1)and(3)
*November 18, 2014*

**math**

multiply top and bottom by 2i: (-5+i)(2i)/-4 = ?
*November 18, 2014*

**math**

how about x^2+5x-3 = x+2 x^2+4x-5 = 0 Now it's a cinch, right?
*November 18, 2014*

Pages: <<Prev | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | **9** | 10 | 11 | 12 | 13 | 14 | 15 | Next>>