intro to computer
B - nothing is free
Math please help!!
just plug and chug, using the quotient rule (2^x ln2 - e^x)(2^x+e^x) - (2^x-e^x)(2^x ln2 + e^x) --------------------------------------------------------------- (2^x+e^x)^2 You can simplify that to 2^(x+1) e^x (ln2 - 1) / (2^x+e^x)^2
90ft * 7ft * (1/2 oz/ft^2) = 90*7*(1/2) oz Note how the ft^2 cancel out, just leaving oz in the result. Watch the units, and they will help you decide how to multiply or divide the ratios.
The sides are a b=a+12 c=b+24 d=c+36 So, a+b+c+d = 136 a+b+c+c+36 = 136 a+b+2c = 100 a+b+2(b+24) = 100 a+b+2b+48 = 100 a+3b = 52 a+3(a+12) = 52 4a+36 = 52 4a = 16 a = 4 So, the sides are 4,16,40,76
if the dept head makes x, then x + 3x = 290000 4x = 290000 x = 72500
learn to recognize common Pythagorean triples in right triangles. The simplest is 3-4-5. This is just double that, or 6-8-10. The rope is 10 feet long. Or, you can do the algebra, using r^2 = 6^2+8^2 and solve for r.
सर्वाधिक लोकप्रिय में से एक था बकवास कविता का ल...
C = 2πr, so r = C/2π A = πr^2 = π(C/2π)^2 = C^2/4π In this case, A = 16^2/12 = 21.3
evidently the volume of iron is 26.44-25.40 = 1.04 mL. So, the density is 8.2g/1.04mL = 7.88 g/mL
D/B = 27/16 for all strings. So, For the longer string, D/64 = 27/16 Now just solve for D
f = secx^cotx log f = cotx * log secx 1/f f' = (-csc^2 x * log secx) + (cotx * secx*tanx/secx) f' = secx^cotx (1 - csc^2(x) log secx)
While this might appear to be an exercise in half-angle or double-angle formulas, it is really just a check to see whether you remember your basic trig definitions: cscθ = 1/sinθ and secθ = 1/cosθ You happen to be using θ/2, but the principle holds. so...
You were right as far as you went. But, you didn't use the rest of the information they gave you. a+b+c = 22 But what else do we know? If a is the short side (assuming it is indeed an odd integer), then b=a+2 (next odd integer) c=2a (twice as big) So, substituting in the g...
Algebra/I hope this is the last time.
why all the embedded words and weird unbalanced parentheses? Just list the points: (0,4) (1,5) (2,6) How ever did you get (2,1)? (-10,-6) (-5,-1) (-4,0) and many more
You know that cosθ = x/r In QII, x < 0 and y > 0, so we know x = -2 r = 3 so, y = √5 Now you know that sinθ = √5/3 and you now can easily figure sinθ * tanθ
math (cant figure it out)
correct: C(7,2) = 7*6 / 2 = 21
We already went through f(3/2) and f(b) with f(x) = x^2+2. I answered early this morning, and you said thank you 4 hours ago. Why are you asking for those again? You got f(3/2) correct then. Why are you now not sure? At any rate, just substitute in the value wherever x appears...
Math (check answer plz)
I assume you mean 9C4 9C4! = 0 Anyway, 9C4 = 9!/(5!4!) = 9*8*7*6 / 4*2*3*1 = 126 9P4 = 9!/5! = 9*8*7*6 = 3024
since 84+16=100, it appears that 84 have taken politics 16 have taken history 0 have taken both 100 have taken at least one of the subjects.
algebra/Steve or Damon help
f(3/2) = (3/2)^2 + 2 = 9/4 + 2 = 4.25 f(b) = b^2+2 how did you get zero?
r^3 = 3375 r = 15 Now just use S4 = 32.5 to find the cheapest price. I suspect a typo, since $32.5 is such a small number.
after each step, there is 0.9 as much alcohol as before. So, after 7 steps, the amount of alcohol is 10*0.9^7 = 4.78 liters.
S3 = 1(1-r^3)/(1-r) = 157 1+r+r^2 = 157 r^2+r-156 = 0 (r-12)(r+13) = 0 r = 12 or -13 So, the GPs are 1,12,144,... 1,-13,169,...
high school algrebra 1
for p people, the cost c is c = 25 + 18p the cost per person is 25/p + 18
math (cant figure it out)
a cube has 6 faces, so the theoretical probability is 1/6, not 1/30! (B) Why would you divide 120 by the number of spots that show? Would P(5) be 1/24?
h/75 = tan 62
#1 ok #3 .701 = 0.7 to the nearest tenth. Your rounding doesn't have any tenths!
#1 you cannot divide by zero. So, when the denominator is zero, that value of x must be excluded. So, what is x when 3x-6=0? #2 ok #3 use the quadratic formula for this one. #4 Nope. 4^0 = 1 2^-3 = 1/2^3 = 1/8 So, 1 - 1/8 = 7/8 You calculated 4^0 - 2^3 #5 correct. So why did y...
Starting from February, after m months, he has 40m dollars. So, when does 40m = 320? m=8 So, what's 8 months after February?
20 cows 70 animals so, 20/70
Math - incomplete
Reiny went through this for you once. Now, maybe if you say which side of STU is b, we can make some headway.
You did not factor correctly. x^2-4x+4 = (x-2)(x-2) If that's what you got, then you clearly don't understand what it means. x-2 = 0 when x=2, not -2.
8(x+2) = 8x-24+y 8x+16 = 8x-24+y 40 = y It doesn't matter what the average age is. Replacing a 24-year-old by a 40-year-old adds 16 years to the total ages, raising the average by 2.
72t + 1/2 at^2 = 70 72 + at = 54 so, a = -16.2 m/s^2 applied for t=10/9 seconds
since g(3) = 2, g^-1(2) = 3 since h(-4) = 1, h^-1(1) = -4 (h*h^-1)(-7) = h(7)*h^-1(-7) = (-5)*(-8) = 40 If you meant (h◦h^-1)(-7) then that would be -7, since by definition (h◦h^-1)(x) = x.
y = 2cos(3x+135) cos(kx) has period 2pi/k, so y has period 2pi/3. The 135 is just a phase shift, and does not affect the period.
since area grows as r^2, the area grows by (1/2)^2 = 1/4
PQ has length √(2^2+15^2) = √229 P'Q' has length 4 times that.
math (check answer plz)
Repeating an experiment naturally gives rise to experimental probability. Since no experiment is described, the probability must be theoretical only. So, (C).
the clue is that (x+3) divides the volume. So, a little checking shows that the volume v = (x+3)(x-7)(x+9) so, if x+3=15, x=12 and the box is 15x5x21
surely you have the formula for the period of a pendulum of length L (and small amplitude): T = 2π √(L/g) Now just plug in your numbers.
-.05t + 300 = 182 Now just solve for t.
we just did one of these x(t) = 3t^2 - 18t + c Now just figure x(6)-x(0)
The max occurs when x = -b/2a = 5/4, and is indeed 65/8 wolframalpha.com confirms this: http://www.wolframalpha.com/input/?i=-2x^2%2B5x%2B5
done earlier, and you were correct.
m = miles g = gallons m = 20g
6 possible outcomes only 1 is a 5 So, theoretical P(5) = 1/6 You rolled 12 times, so that's B: experimentation. Evidently the die was heavily loaded.
Correct. Reiny missed the -2x^2. Even experts trip over the details sometimes.
Oops. Flipped a minus sign f(3) = 9-27+c = -18+c total change is thus -18
just solve for x in 2771x/(100-x) = 36000 x = 92.85%
Let the distance be d. If the kite is between the girls, d/sin75° = 20/sin40° But, if Kate is between the kite and Abigail, then d/sin25° = 20/sin40°
after m months, you have 10*3^(m/2)
0 < L <= 90 2L = 330-2W L = 115-W 0 < 115-W <= 90 90 >= W-115 > 0 205 >= W > 115
(f-h)(4) = f(4)-h(4) = (2*4+5) - (7-4/3) = ?
math foundations 20
you want x such that P(Z<x) = 0.025 That means that x must be more than 1.96 std below the mean. In this case, that's 3.128 years.
C(12,2)*2 assuming the scoops must be different flavors. If duplicate scoops are allowed, then it's just 12^2 * 2
You'll be covering rational functions, asymptotes, logarithms, inverse functions, and more. Go to your local used-book store, and buy a cheap text for Algebra II. Then, go for it -- with more tools at your disposal, the kinds of problems you can solve get much more interes...
If the marker is at distance x away from the spot just below the balloon, we have h/x = tan 27.8 (h+345)/x = tan 46.2 Eliminate x to get h/tan 27.8 = (h+345)/tan 46.2 Now just solve for h.
math help plz2!!!!
from the vertex, we know that y = a(x+3)^2+5 Now plug in the values to get a: 1 = a(-6+3)^2 + 5 9a = -4 a = -4/9 y = -4/9 (x+3)^2 + 5 See http://www.wolframalpha.com/input/?i=y+%3D+-4%2F9+%28x%2B3%29^2+%2B+5
we breathlessly await further developments.
as with all parabolas, the vertex (in this case a maximum) is at p = -b/2a = 150/.006
as with all parabolas, the vertex (in this case a maximum) is at x = -b/2a = 80/0.0002
the length is 270-x So, the area is length*width, or f(x) = x(270-x) As with all parabolas, the vertex is midway between the roots, so in this case, it's at x=135. Since the graph opens downward, the vertex represents the maximum possible area.
from the values of the roots, we know that the functions will be of the form y = ax(x+4) So, pick a positive to open upward, and a negative to open downward. Any nonzero value will do.
hit the ground == drop 400 ft. So, 16t^2 = 400 Now just solve for t.
7 filled 8 unfilled Choose 6 of each. So, C(7,6) * C(8,6) = ?
If two weigh 51, that's the minimum for two boys, leaving the maximum for the 3rd boy of 3*159-2*51 = 159-102 = 57
dv/dt = 0.6t cos(0.08t^2-1) v = 3/8 sin(0.08t^2-1) + c Since v(0) = 14, c = 14+3/8 sin(1) = 14.3 v(t) = .375 sin(.08t^2-1)+14.3 Now just evaluate v(10)
Algebra/could show me how to work this problem
I suspect a typo. Why not just say 2x^2+1? At any rate, assuming things are correct as written, for any input, just substitute it for all the x's and evaluate for the output. input: -2, output (-2)^2+(-2)^2+1 = 4+4+1 = 9
Physics-can someone please check this
(b) The horizontal speed is unaffected by gravity, so it remains 24.5 m/s. In 3 seconds, John travels 3*24.5 = 73.5 meters. (a) we know that the vertical position, starting at y0 is y(t) = y0 - 4.9t^2 Since y(3)=0, we can get the initial height by solving y0 - 4.9*9 = 0 y0 = 4...
wow. cubics are not generally easy to solve. Best bet is a graphical or numerical solution. wolframalpha gives http://www.wolframalpha.com/input/?i=4x^3-6.68E-7x^2%2B1.67E-8x-1.04E-10 The root is very close to zero, since the function is very nearly 4x^3=0 Blowing up the graph...
lose all the nonsense text. You have (x-1)^2 + (x-2)^2 + (x-3)^2 = 0 Now, you know that (x-1)^2 is a parabola, which is tangent to the x-axis at x=1, because of the double root. Similarly, the other two terms are never negative. So, since we are adding up three positive values...
you start out talking about two numbers, toss in some unknown quotient (maybe not even in lowest terms) then ask for "number"? The question is mighty unclear to me.
just add .145258x to both sides and you have 1.145258x = .145258 now divide by 1.145258 and you get x = 0.126834
for non-relativistic speeds, we can use the approximation. c/520 = (1+v/c) * c/590 520(1+v/c) = 590 1+v/c = 59/52 v/c = 7/52 v = 7/52 c Is that relativistic? Generally, less than 0.1c is considered non-relativistic, so we may be a bit off, but if that matters, use the exact fo...
The only possible choice assumes a typo where you meant to say that one quarter of x is 36. Then, x is 144. Hmm. Unless the question reads 4 quarters of x is 36. What is 1 quarter of x? Then the answer is 9.
Assuming you meant 0.400g/dm^3, that translates to 0.0004 g/cm^3 So, 500cm^3 of that means 0.2 g Or, in one step, that's 500 cm^3 * (1dm/10cm)^3 * 0.4 g/dm^3
The orbital period is given by T = 2π√(r^3/GM) We want M, which is thus M = r^3/G * (2π/T)^2 Now just plug in your numbers.
Looks to me like they could all be 8. Are there any restrictions on the values allowed? 2014 is not a multiple of 5, so there is no cycle of 5 numbers which repeats.
Algebra/not sure what to do
f(x) = x-8 for whatever value x has. So, if x=p, f(p) = p-8 Just replace x with the desired value throughout the entire line.
I'd say yes. That's what Accounts Receivable are for -- waiting for cash flow to be realized. That's assuming the invoice is not generated until a purchase is confirmed. But, what do I know? I may be off base here.
Since the n numbers are divided up in pairs, I'd say n/2 copies. Hence the formula for the sum: n(n+1)/2 Technically, that's [n+1]/2 where  is the greatest-integer function.
If P is x meters from the base of the pole of height h, then h/x = tan 53° h/(x+20) = tan 28° eliminate x and you have h cot 53° = h cot 28° - 20 h = 20/(cot28°-cot53°)
10(q+7) + 25q = 280
If there are x children, then .6x = 18 x = 30 78? 1? You just throwing darts at numbers? If not, show you r work, so we can help you get it right.
If we add up terms n through n+10, then we get (n+10)/2 (2a + (n+9)45) - (n-1)/2 (2a+(n-2)45) = 891 11a+495n = -1089 a+45n = -99 If we are adding up the first 11 terms, then a = -144 and T28 = -144+27*45 = 1071 T45 = -144+44*45 = 1836 But, if we add up terms T5 through T15, th...
Looks good to me.
x(t) = -cos t + c now you know that x(0) = 3, so plug in t=0 to find c. Then you can use t=2 to get x(2)
300 = 100 + 40*5 So, set things up as an arithmetic sequence, and find that S41 = 41/2 (100+300) = 8200
simple: 10000(1+.12*5) compound: 10000(1+.10)^5 evaluate and compare.
c(x) = 350 + .20 x
are there any pairs with the same 1st element? If not, it is a function.
or, using de Moivre's rule, 1+i = √2 cis π/4 so √(1+i) = ∜2 cis π/8 1-i = √2 cis -π/4 so √(1-i) = ∜2 cis -π/8 √(1+i)/√(1-i) = cis π/4 Now the angle doesn't matter, since cos^2+sin^2 = 1
√(1+i)/√(1-i) = √(1+i)√(1-i) / (1-i) = √(1-i^2) / (1-i) = √2/(1-i) = √2(1+i) / (1-i)(1+i) = √2(1+i)/2 = 1/√2 + 1/√2 i a = 1/√2 b = 1/√2 a^2+b^2 = 1/2 + 1/2 = 1
since the slopes are the same, the lines are parallel. Or, in this case, they are the exact same line.
Or, knowing that the general circle is (x-h)^2 + (y-k)^2 = r^2 plug in your points to get (-5-h)^2 + k^2 = r^2 h^2 + (4-k)^2 = r^2 (2-h)^2 + (4-k)^2 = r^2 h = 1 k = -19/8 r^2 = 2665/64 and we have the circle as derived above The brute-force way, of course, is to plug your poin...