Thursday

November 26, 2015
Total # Posts: 35,800

**Math**

in each case, multiply by the denominator, then add the numerators. For example -1 + 17/13 = (-13+17)/13 = 4/13
*September 23, 2015*

**Math**

go to wolframalpha.com and type in your expression
*September 23, 2015*

**geometry**

psq
*September 23, 2015*

**Math**

determine the slope of the line you want use point-slope form convert to slope-intercept #2 is thus slope of given line is -1/2 perp. line has slope 2 y-1 = 2(x-4) y = 2x-7 Luckily, that line also passes through (1,-5)
*September 23, 2015*

**W**

a very similar question was solved below: http://www.jiskha.com/display.cgi?id=1316469592
*September 23, 2015*

**Algebra**

If they lost x, then x + x+62 = 160
*September 23, 2015*

**MATHS**

cost = 12z-27s Now plug in whatever other quantities you want to use.
*September 23, 2015*

**calculus**

come on - this is Algebra I; no problem for a calculus student, right? 5(x^2+4)^4(2x)(x-2)^4+(x^2+4)^5(4)(x-2)^3 = 2(x^2+4)^4 (x-2)^3 (5(x-2)x + (x^2+4)2) = 2(x^2+4)^4 (x-2)^3 (7x^2-10x+8) now take a stab at the others. Look for common factors, one by one. Factor out the ...
*September 23, 2015*

**calculus**

f(x) is continuous, except where the denominator is zero. So, where is 1-cos(x) = 0?
*September 23, 2015*

**math**

g=18 j=2g+4 = 40 k=j-15 = 25 ...
*September 23, 2015*

**Math**

4 divided by 8 = 1/2 How did that help you come up with a=32?
*September 23, 2015*

**Physics**

Draw a velocity diagram. You will see that tanθ = horizontalspeed/verticalspeed
*September 23, 2015*

**Chemistry 151**

how many moles of AlCl3 is .2580g? Look at the formula for the compound. You will have 3 times that many moles of Cl ions.
*September 23, 2015*

**algebra I**

x/3 + x/2 >= x-3 2x + 3x >= 6x-18 -x >= -18 x <= 18
*September 23, 2015*

**Algebra 1**

A is correct D is (x+3)*8
*September 23, 2015*

**Math**

P(head) is 1/2 for any coin, no matter how many you have already seen.
*September 23, 2015*

**chemistry**

density is mass/volume, so mass = density*volume 2.5L*3g/cm^3 is 7.5, but the units are wrong 2.5L * 1000cm^3/L * 3g/cm^3 = 7500g or 7.5kg
*September 23, 2015*

**math**

All of your work is good. It seems your teacher is fixated on making sure you don't do anything in your head. If you set them up as I did, even the most OCD teacher should be satisfied. Good work
*September 23, 2015*

**math**

7. Anne is seven years younger than her brother, Brandon. Anne is 23. Let B represent Brandon’s age. A = B-7 so, B = A+7 A = 23 B = 23+7 = 30 Cougars lost to the Tigers in basketball by 15 points. The Tigers scored 72 points. Let C represent the Cougars' score. C = T...
*September 23, 2015*

**IPC**

((35.0-20.0) m/s) / (4.00 m/s^2) = 3.75s
*September 23, 2015*

**math**

as usual, draw a diagram and review your basic trig functions. L/50.0 = tan 59°30'
*September 23, 2015*

**Science**

If you say so...
*September 23, 2015*

**Science**

oh, please. If you plant bean seeds in several different environments, don't they all come up beans?
*September 23, 2015*

**green valley college**

First step: balance the equation
*September 23, 2015*

**MATH**

4x^2
*September 23, 2015*

**al 1**

x/3 + x/2 = 3/4 x(1/3 + 1/2) = 3/4 x(5/6) = 3/4 x = (3/4)(6/5) x = 18/20 = 9/10 Or, you could clear fractions by multiplying by 12: x/3 + x/2 = 3/4 4x + 6x = 9 10x = 9 x = 9/10
*September 23, 2015*

**math homework**

so, what does the band decide? That is the independent variable. The rest is dependent.
*September 23, 2015*

**math**

7^6 / 7^1 = 7^(6-1) = 7^5 What you have is just 7*7*7*7*7*7 ----------------- 7 one of the 7's cancels, leaving 5 more on top: 7^5
*September 23, 2015*

**MATH**

You want v=20, so, just solve 3t^2-6t-7 = 20 If you put in t=20, that will give you the velocity after 20 seconds. C'mon - think about what the variables mean...
*September 22, 2015*

**math**

multiply everything by 2 and you have 5d-3 = -1 Can you handle that?
*September 22, 2015*

**Calculus**

you need to review addition of vectors. AB starts at A and ends at B BC starts at B and ends at C So, AB+BC starts at A and ends at C. ABC form a triangle. google will provide lots of illustrations and examples of vector addition
*September 22, 2015*

**Calculus**

AB+BC = AC so, AB+BC+CD = AD BC-DC = BC+CD = BD See if you can use that idea to rearrange +/- terms so the ends line up in order
*September 22, 2015*

**Math**

c = 3p, so adding up all the feet, we have 2(3p)+4p = 2400 10p = 2400 so, there are 240 pigs c-p = 3p-p = 2p, so there are 480 more chickens than pigs.
*September 22, 2015*

**math**

well, 4+20 = 24
*September 22, 2015*

**Math**

what does Moran have to do with it?
*September 22, 2015*

**Calculus**

the left and right limits are the same at every point, and the function must be defined at every point. Intuitively, there are no holes in the graph.
*September 22, 2015*

**Math**

clearly, it is 18/40 Since I have no idea what part of the spinner is colored red, I cannot give a theoretical probability. If you pay attention to details (such as spelling) you can post a coherent problem...
*September 22, 2015*

**algebra**

since -x is just (-1)(x), and exponents are done first, -a^2 = -(a^2) = -(2^2) = -(4) = -4 on the other hand, if you want to do the minus first, you need to say (-2)^2 = (-2)(-2) = +4
*September 22, 2015*

**Math**

25.0m^3 * (3.28ft/m)^3 * $2.35/ft^3 = $2070.00
*September 22, 2015*

**Math**

if you multiply everything by 12, you have 4m + 3m - 12 = 30 Can you handle that?
*September 22, 2015*

**Math**

t(1/2 + 1/6) = 2 t(2/3) = 2 t = 2(3/2) t = 3 Or, you can multiply everything by 6 to get 3t + t = 12 t = 3
*September 22, 2015*

**Geometry**

how about just multiplying the section length (1.25m) by the number of sections (11)?
*September 22, 2015*

**Math**

8x^2+40x+32 = 8(x^2+5x+4) = 8(x+4)(x+1) So, (8x^2+40x+32)/(x+4) = 8(x+1) at every value of x except x = -4. So, the limit as you approach x = -4 is just 8(-4+1) = -24. The graph has a hole at x = -4, since 0/0 is not defined. But everywhere else, no matter how close, f(x) = 8(...
*September 22, 2015*

**maths**

Is 6 double 2? I think you want 64282
*September 22, 2015*

**math**

(1,2)(0,1)(8,9) Looks like there are eight of them. So, list them.
*September 22, 2015*

**Math**

well, 6+5 = 11 The rest is given
*September 22, 2015*

**precalculus**

For the point (-5,4) x = -5 y = 4 r = √41 cosθ = x/r = -5/√41 = -.781 cscθ = r/y = √41/4 = 1.601 Clearly the point is in QII ! How did you come up with your values?
*September 22, 2015*

**precalculus**

of course not. You know that cosθ is never greater than 1 or less than -1. Similarly, cscθ is never less than 1. Given a point (x,y), r^2 = x^2+y^2 cosθ = x/r cscθ = r/y Also, given that cosθ<0 and cscθ>0. tanθ cannot be positive.
*September 22, 2015*

**Precalc**

surely you have some ideas about these. #6 is cos,sec #1,#5 are the same functions
*September 22, 2015*

**Algebra**

If A and C are x, then B = x/5. So .02x + .10(x/5) + .16x = 1.00
*September 22, 2015*

**Algebra**

If x at 20%, then .20x + .05(10-x) = .14(10)
*September 22, 2015*

**Algebra**

well, set them equal: 40.74x + 742.65 = 47.93x + 725 Now just find x and add 1995.
*September 22, 2015*

**Math**

the area increases by a factor or (5/2)^2 So, just plug in the new numbers.
*September 22, 2015*

**physics**

v = √(2as) so, just plug in the numbers
*September 22, 2015*

**math**

(38 3/4)/(3 7/8) = 10
*September 22, 2015*

**Math**

hmmm. By this time you should certainly know how to plug in a number. x: -0.1 cos(3*(-0.1)-1)/(3*(-0.1)) = cos(-1.03)/(-.03) = -17.16 I assume you can use a calculator, or google, or wolframalpha.com
*September 22, 2015*

**Physics**

I'll assume you mean m/s, not s/m. Combined speed is 5.12 m/s, so they meet at 3.5 * 2.13/5.12 meters from where the red car started.
*September 22, 2015*

**Chem (HELP!!)**

visit http://www.onlineconversion.com/ Or use the conversion tables you surely have access to.
*September 22, 2015*

**Chem**

There are always several basic conversion units. For example, convert 1.745 * 10^-5 m^3 to pints. 1 gallon = 231 in^3 1 in = 2.54 cm so, just start converting, making sure the units cancel correctly: 1.745*10^-5 m^3 * (100cm/m)^3 * (1in/2.54cm)^3 * 1gal/231in^3 * 8pt/gal = 0....
*September 22, 2015*

**Chem**

google can do these, or visit http://www.onlineconversion.com/
*September 22, 2015*

**Algebra I**

an undefined slope means a vertical line, of the form x=h Since the line passes through (-2,5), the equation is x = -2 This is a trick question, since there is no y-intercept.
*September 22, 2015*

**Computer/Math**

do you mean you got syntax errors, or the results were wrong? If your typing was as good there as it is here, I'm not surprised.
*September 22, 2015*

**Math**

I say it's bogus. The two are not equivalent. Try plugging in some actual numbers. I suspect a typo. Or a garbled posting. associative would be like a(bc) = (ab)c
*September 22, 2015*

**MATH/GEOMETRY**

blah blah blah apparently <1 and <2 form a straight line, which is 180° so, m<1 = 180-34 = 146°
*September 22, 2015*

**Trigonometry**

recall that cosine = x/r And, r^2 = x^2+y^2
*September 22, 2015*

**MATH/GEOMETRY**

instead of repeating the cry for help, why not look at your previous post, where I ask for more data? You provide no information about the relationship between the angles, yet you expect us to guess a value for <1? Stop whining and read your useless post!
*September 22, 2015*

**Algebra**

Oddly enough, it is C It should technically be (-7)x(-7)x(-7)x(-7)x(-7) But if you change the sign on two of them, the answer is the same, because (-7)x(-7) = 7x7
*September 22, 2015*

**Algebra**

#10 .57 = 57/100
*September 22, 2015*

**Algebra**

#1 Nope. 5/6 + 2/3 = 5/6 + 4/6 = 9/6 #2 ok #3 Nope. 9 is a perfect square. #4 Nope. Suppose x = 1/6. You have 1x/2x #5 ok #6 ok #7 ok #8 Nope. A has too many -7's #9 What's the difficulty? Just use the values given: 2s³-4r² if r=1 and s=5 2*5³-4*1² ...
*September 22, 2015*

**Maths**

y^2 + 2.5^2 = 6^2
*September 22, 2015*

**MATH/GEOMETRY**

You need to provide a little more information about the diagram. Surely you can see that with just the measure of <2, there is no way to guess anything about <1.
*September 22, 2015*

**Programming**

sheesh. read name,cabin,years print name,cabin,years if years < 2, print "Newlywed Gift" if years >= 40, print "Deluxe Anniversary Package"
*September 22, 2015*

**Calculus 3**

since F is conservative, the work is independent of the path, so it is ∫[(1,-2,1),(0,-7,5)] 2dx-3dy-5dz = 2x-3y-5z [(1,-2,1),(0,-7,5)] = (0+21-25)-(2+6-5) = -4-3 = -7 You can work the other the same way, but it's easier since only y is involved.
*September 22, 2015*

**Algebra**

time = distance/speed. So, just use your numbers.
*September 22, 2015*

**Please help with this 1**

well, they need to get 26 1/3 yards just to get back to zero. Then another 10 for the 1st down. That's 36 1/3 yards. Or, 10-(-26 1/3) = 36 1/3
*September 22, 2015*

**math**

(42-7):7 = 35:7 = 5:1
*September 22, 2015*

**Algebra**

clearly the half-life is 8 years. So, after t years, the remaining fraction is 18*2^(-t/8) So, plug in t=20
*September 22, 2015*

**math**

You mean F=(9/5)(-62)+32 so, get out your calculator and run the numbers
*September 22, 2015*

**Calculus 1**

Just use the good old chain rule and product rule: f = 5√x sinx f' = 5(1/(2√x) sinx + √x cosx) = 5sinx/(2√x) + 5√x cosx
*September 22, 2015*

**Algebra**

time = distance/speed, so -315 / (-22.5) = ?
*September 21, 2015*

**Math**

eh? the last one you posted was 7 ? 14 31 Take a look at what I said there.
*September 21, 2015*

**Math**

9 9 = 7+(2^0+1) 14 = 9+(2^2+1) 31 = 14+(2^4+1) Then nth term is clearly 7 + 2^(2n-2)+1 That is only one of many ways to fill in the hole. You have so little to work with, you are free to pick almost any value you choose. I suspect that my solution is not the one intended, ...
*September 21, 2015*

**physics/algebra**

s(t) = 0t - 4.9t^2 Technically, s(t) indicates that the object is moving in a negative direction, as if falling from a height of 0m into a canyon. So, you equation should really be s(t) = -82.35 indicating it takes 4.1s to fall 82.35m. I'll let you worry about the +/- signs.
*September 21, 2015*

**physics/algebra**

You correct. t^2 = 82.35/4.9
*September 21, 2015*

**math**

1234*56 = 69104
*September 21, 2015*

**School**

4π+2
*September 21, 2015*

**Algebra**

y = 7 + (1/4)(18-x) for x <= 18 y = 7 for x > 18
*September 21, 2015*

**Math**

D: [0,12] R: [0,140]
*September 21, 2015*

**math**

1 1/2, -2, 2 1/2, -2 3/4
*September 21, 2015*

**Pre-Calculus**

I answered in http://www.jiskha.com/display.cgi?id=1442879979 You, of course, did not enlighten me on the difference between [x] and [[x]]
*September 21, 2015*

**Need HELP reall bad test tommorrow**

greatest integer is easy. Take any value, and use the greatest integer less than or equal to that value. [0] = 0 [0.4] = 0 [0.999] = 0 [1.11] = 1 [2.345] = 2 [1323.3423] = 1323 Watch out for negative values: [-0.5] = -1 [-1.01] = -2 [-14.43] = -15 Still no idea what you mean ...
*September 21, 2015*

**Need HELP reall bad test tommorrow**

just list some x values, and their corresponding function values. Not sure what [[x]] is I think [x] is the greatest integer function (floor) What is [[x]]? ceiling? absolute value?
*September 21, 2015*

**Math.**

600 mi/hr * 1hr/3600s * 1609m/mi = 268 m/s
*September 21, 2015*

**Algebra**

you want |200-18t| = 120 For 200-18t >= 0, you have 200-18t = 120 18t = 80 t = 4 4/9 For t>11.11, 200-18t < 0, so -(200-18t) = 120 -200+18t = 120 18t = 320 t = 17 7/9 So, 4 4/9 seconds after starting, he is 120 ft away. Then he passes you at 11 1/9 seconds, and at 17 ...
*September 21, 2015*

**Math**

start with the smallest possible factor. Divide by it as many times as possible, then move on to the next prime factor, and repeat until you have reached a prime number. 110 = 2 * 55 3 does not divide 55 55 = 5 * 11 There are no other prime factors, so 110 2*5*11 720 = 2*2*2*2...
*September 21, 2015*

**Geometry**

Its a straight line and angle bed is on the line with e = vertex aeb is 1 line of the angle & aed is the other ec shou.ld have been ec
*September 21, 2015*

**Geometry**

no way to tell. If b,c,d are consecutive points on a circle with center at e, where is a in relation to them?
*September 21, 2015*

**Geometry**

bc bisects <bed, m<aeb=11x-12 and m<ced=4x+1 find m<aec
*September 21, 2015*

**Geometry**

<2=<4, m<2= 110 degrees Given m∠2 = m∠4 Definition of congruent angles m∠4 = 110º Complete the 2 column proof
*September 21, 2015*