Monday

July 6, 2015

July 6, 2015

Total # Posts: 32,118

**Math**

I'd say 12/15, right?
*June 28, 2015*

**Calculus Partial Fraction**

note that x^3-8 = (x-2)(x^2+2x+4) So, your fraction is now x^2 -------------------- (x-2)^2 (x^2+2x+4) As partial fractions, that becomes A/(x-2) + B(x-2)^2 + (Cx+D)/(x^2+2x+4) Placing all that over the common denominator, we have A(x-2)(x^2+2x+4) + B(x^2+2x+4) + (Cx+D)(x-2)^2...
*June 28, 2015*

**math**

You need to know how the DJIA is calculated, to figure the effect of any one stock.
*June 28, 2015*

**Math**

Using the given formula, your expression is correct, but its value is 3110.50 (D) Expressed correctly, of course, it would be 15,000(0.986975)^(10*12) You must have pushed some buttons wrong if you got (A). Or just guessed...
*June 28, 2015*

**Finance**

3000(0.9744^20) = 1785.94
*June 28, 2015*

**Calculus Partial Fraction**

well, clearly you can cancel x^2 and you are left with 1 / x(x-2) = A/x + B/(x-2) Now if you place the right side over the common denominator, you have (A(x-2)+Bx)/(x(x-2)) In order for the two numerators to be identical, you need (A+B)x-2A = 0x+1 That is, A+B=0 -2A=1 A = -1/2...
*June 28, 2015*

**Math**

could be any of those, depending on the proportion of Microsoft stock in the DJIA.
*June 28, 2015*

**Math**

Hmmm. 518400 = (10*9*8)^2 Why did you use that?
*June 28, 2015*

**Math**

assuming the order of choice does not matter, 6C4 * 6C4 or, 6C2 * 6C2 = 15*15 = 225
*June 28, 2015*

**Math**

P(red,red) = 3/5 * 2/4 You don't really need to record the color, since the bean was not replaced. Unless you have eaten it, you can just look at the two beans drawn.
*June 28, 2015*

**trigonometry**

If A is the angle of elevation of the sun, then tanA = height/shadowlength So, height/5 = 5/6 Looks like you need to review the basic trig functions. And always draw a diagram!
*June 28, 2015*

**Math**

Looks suspiciously like 30000. Just sayin' ...
*June 28, 2015*

**Maths Problem**

Dan finishes in 70 minutes, so Ellen finishes in 75 minutes. If Dan's speed is d m/min Ellen's speed is e m/min So, d = (15/14)e 35e = 35d-300 35e = 35(15e/14)-300 35e = 75e/2-300 5e/2 = 300 e = 120 So, the distance is 120*75 = 9000m You can check to make sure that the...
*June 28, 2015*

**math**

16x^2-24x-13=0 16(x^2 - 3/2 x) = 13 16(x^2 - 3/2 x + (3/4)^2 = 13+16(3/4)^2 16(x-3/4)^2 = 22 (x-3/4)^2 = 11/8 x = 3/4 ±√(11/8) or, x = (3±√22)/4 or, eschewing fractions, 16x^2-24x-13 = 0 16x^2-24x+9 = 13+9 (4x-3)^2 = 22 ...
*June 28, 2015*

**maths**

I don't believe that one side is only 60cm. Fix that, and just find twice the perimeter, then subtract twice the gate width.
*June 28, 2015*

**Math**

recall that 3^4 = 81
*June 27, 2015*

**Finite Math**

If there are x Daybrite sets and y Noglare sets, then you want to maximize p=425x+700y subject to x+y <= 400 x >= 70 y >= 160 a good tool is at http://www.zweigmedia.com/RealWorld/LPGrapher/lpg.html it will solve and graph the solution
*June 27, 2015*

**Geometry**

the two bases of a parallelogram are equal the two bases of a trapezoid are different Bh vs (b+B)h/2 These can only be the same if b=B.
*June 27, 2015*

**Math**

well, did you actually try the values to see which are or are not? (0,-1): -1 = 0^2-1? yes now you try the others and we can check your answers.
*June 27, 2015*

**Math**

log3(3) = 1 so, 1+log3(x^2) = log3(3) + log3(x^2) = log3(3 * x^2)
*June 27, 2015*

**Math**

I'm not Carnak the Magnificent. What was the question, and how did you arrive at your answer? We're willing to provide help, and even answers, but don't make us come up with the questions, too!!
*June 27, 2015*

**calc**

so, what about the root test is causing difficulty?
*June 27, 2015*

**calc**

just take the integral from 0 to 2.
*June 27, 2015*

**calc**

using discs, we have integral[0,π] π sin^2(sin(x)) dx I don't think that can be evaluated with elementary functions. Do you have numeric methods available?
*June 27, 2015*

**math**

#1 600000*.9^4 = 393660 #2 16+32*9 = 304 #3 F12 = 89 #4 8*1/√2^5 = √2 #5 Assuming no one received more than one message 2+4+8+16+32 = 62 I suspect a typo in the problem.
*June 27, 2015*

**algebra**

variables are represented by letters: x and y numeric constants stand alone: -9 coefficients are numbers multiplying the variables: 4 and 15
*June 27, 2015*

**Math**

since the basic function is y=1, and that's not one of the choices, what do you think? Try the various choices to see which one works.
*June 26, 2015*

**math**

Since a = 1 r = 2 S4 = 1(2^4-1)/(2-1) = 15 S15 = 2^15-1 = 32768 So, the sum from S5 to S15 = S15-S4 = 32753
*June 26, 2015*

**math**

So far, 70% of your score is allocated as follows: .15*74 + .15*96 + .40*60.5 = 49.7 Since that is only 70% of your score, it's equivalent to 49.7/.70 = 70.1%
*June 26, 2015*

**physics**

since the sled is not accelerating, the net force acting on it must be zero. So, since the friction is .15*(30*9.8), that is equal to the force acting on the sled.
*June 26, 2015*

**algebra**

If there are x fill-in y multiple-choice z long-answer they have given us the following facts: x+y+z = 24 2x+6y+5z = 100 x+y = z Now you can solve for x,y,z
*June 26, 2015*

**math**

400$ * 3tickets/5$ = 1200/5 = 240 tickets
*June 26, 2015*

**math**

The curves intersect at (-2,2) and (1,-1) so, the area is the sum of all the little horizontal strips between the line and the parabola: ∫[-1,2] (2-y^2)-(-y) dy = ∫[-1,2] 2+y-y^2 dy = 9/2
*June 26, 2015*

**math**

x' = y√(y^2+2) so, the arc length s = ∫[0,1] √(1+x'^2) dy = ∫[0,1] √(1+(y^2)(y^2+2)) dy = ∫[0,1] √(y^4+2y^2+1) dy = ∫[0,1] √(y^2+1)^2 dy = ∫[0,1] y^2+1 dy = 4/3
*June 26, 2015*

**physics**

the mass of the rocket does not matter. Given a liftoff speed of v, the height h(t) = vt - 4.9t^2 The max height is reached when t = v/9.8, so we have v(v/9.8) - 4.9(v/9.8)^2 = 100 v = 44.27 m/s Or, you could just use the formula for max height h = v^2/2g and get v^2/19.6 = ...
*June 25, 2015*

**Probability**

Assuming a uniform population, the 1st person has a birthday. The 2nd has the same birthday with probability 1/365 same for the 3rd. So, ...
*June 25, 2015*

**DTM**

you never have said how many gallons (or liters) of gas (or petrol) have been used. Tough to figure mileage (or kmage) without that.
*June 25, 2015*

**DTM**

.50$/km * 100km/day = 50$/day not sure just what it is you want to know.
*June 25, 2015*

**Algebra**

If there were x more meets to go, and they won them all, then, since the wins = the losses 2+x = 10-2 take it from there. Note that the value of x is not the answer.
*June 25, 2015*

**Math**

I already see one error: gt = ln(v+1)
*June 25, 2015*

**Math**

dv/dt = g(1+v) dv/(1+v) = g dt ln(1+v) = gt 1+v = e^(gt) + c v = e^(gt) + c (diferent c) v(0) = 0, so c = -1 v = e^(gt)-1 now, v = ds/dt, so s = 1/g e^(gt) - t + c now, e^(gt) = v-1, so s = 1/g (v-1) - t + c since v = e^(gt)-1, ln(v)+1 = gt t = 1/g (ln(v)+1)) and so s = 1/g (v...
*June 25, 2015*

**Math**

.9*77 + .1*67 = 76 Look like it won't hurt too much. 1 point.
*June 25, 2015*

**Algebra**

revenue is price * quantity, so R(x) = x*p(x) = x(-.16x+320) = -.16x^2 + 320x Now just find the vertex of that parabola to locate maximum revenue.
*June 25, 2015*

**Algebra**

I think you are missing a minus sign on the x^2 term, since g = -32 ft/s^2 h(x) = 1/42 (-16/42 x^2 + 72.7x) = x/42 (-16/42 x + 72.7) h=0 when x=0 (ball is hit), and when x = 190.8 (ball lands) The symmetry of a parabola means that the ball is at its highest midway between the ...
*June 25, 2015*

**math gr. 10**

Two good solutions are provided by Reiny and MathMate in the related questions below.
*June 25, 2015*

**maths**

well, if y = sum(a_n x^n) y' = sum(n*a_n x^(n-1)) y" = sum(n(n-1)*a_n x^(n-2)) so, from the DE, we have sum(n(n-1)*a_n x^(n-2)) + 3x^2*sum(n*a_n x^(n-1)) - x*sum(a_n x^n) sum(n(n-1)*a_n x^(n-2)) + 3sum(n*a_n x^(n+1)) - sum(a_n x^(n+1)) sum(n(n-1)*a_n x^(n-2)) + sum((...
*June 25, 2015*

**Math**

polar can get kind of complicated, but this one's a piece of cake: y = t+4, so t = y-4 x = (y-4)^2 + 4(y-4) + 8 Now expand it out and note that it's just a parabola.
*June 25, 2015*

**Math: Compounded Interest**

just use your formula. For quarterly, that is 200(1+.05/4)^(4*1/4) = 202.5
*June 25, 2015*

**Math - thx Reiny**

Good catch. I felt vaguely uneasy with the way things worked out, but was in a hurry. No doubt Justine caught the slip on her own...
*June 25, 2015*

**Math**

r = 1/(3-4sinθ) (a) see http://www.wolframalpha.com/input/?i=r+%3D+1%2F%283-4sin%CE%B8%29 (b) r = 1/(3-4sinθ) r(3-4sinθ) = 1 3r - 4rsinθ = 1 3√(x^2+y^2) - 4y = 1 3√(x^2+y^2) = 4y+1 3(x^2+y^2) = 16y^2+8y+1 3x^2 - 13y^2 - 8y = 1 3x^2 - 13(y^2 - 8/...
*June 25, 2015*

**math**

maybe you should lie on the floor and kick your feet, too. Beats me what would come next. What kind of material are you studying, that they'd drop a sequence like that on you? Or are you just wasting everybody's time with lottery numbers?
*June 25, 2015*

**physics**

You know, when you log on here you see all these posts with subjects like math, science, psychology, English, etc. Why do you think that Cowdray Park will be interpreted as a school subject? work = force * distance So, just plug in your numbers.
*June 25, 2015*

**advanced algebra**

how about you provide the function, instead of naming a file we cannot see? Is it p(t) = a*e^(kt) with suitable values of a and k?
*June 24, 2015*

**Math**

the properties of logs are the same as those of exponents. √2 = 2^1/2 because √2 * √2 = 2 and 2^a * 2^b = 2^(a+b) 2^1/2 * 2^1/2 = 2^1 = 2 And, 2^-n = 1/2^n so, 1/√2 = 2^-1/2
*June 24, 2015*

**Math**

4x - e^(-(4x-y+3)) = -e^(-2) e^(-(4x-y+3))= 4x + e^(-2) -(4x-y+3) = ln(4x + e^-2) 4x-y+3 = -ln(4x + e^-2) y = 4x+3 + ln(4x + e^-2)
*June 24, 2015*

**Math**

since y(2) = 2, e^(2-2) = -2+c 1 = -2+c 3 = c So far, so good. e^(x-y) = -x+3 x-y = ln(-x+3) y = x-ln(-x+3) Somehow you got an extra "-" sign in there
*June 24, 2015*

**6TH GRADE MATH**

assuming in and out mean up and down, then I get -2-19+7 = -14 You have the bait 10 feet above the water!
*June 24, 2015*

**math**

θ=42°
*June 24, 2015*

**Math - oops**

Oops. I added, instead of subtracting. The final answer, of course, is -1/2, as shown above.
*June 24, 2015*

**Math**

log(√x) = 1/2 log(x) since log(x^n) = n log(x) So, what you have is √36 = 6, so √72 = 6√2 So, assuming by log2 you mean log2, log26 + log26 + log22 but log22 = 1, so that is = 2log26 + 1/2 Now, what is log26? You don't have a log2 button on your ...
*June 24, 2015*

**physics**

Unless the pilot can track a speeding bullet, I don't see how he can take any of those measurements. I guess he could turn the gun backwards and fire it when passing over an observer. If the observer sees the bullets come straight down, the speeds are ok.
*June 24, 2015*

**physic pls help**

how long does it take to fall 45m? 4.9t^2 = 45 t = 3.03 seconds So, how fast do they have to be moving to cover the 15m in 3 sec? 5m/s How fast is 5m/s in terms we can really relate to? That's 100m in 20 sec. Great athletes cover 100m in about 10 seconds, so it's only ...
*June 24, 2015*

**statistics**

ummm that would be .3 + .12 * 1.3 = ?
*June 24, 2015*

**physics**

just solve for t in 24 + 24.5t - 4.9t^2 = 0
*June 24, 2015*

**Physics**

the max height is (v sinθ)^2/19.6 the speed at time t is √(Vx^2+Vy^2) = √((v cosθ)^2 + (v sinθ - 9.8t)^2) The speed at max height is just Vx = v cosθ So, find t when h(t) is half the max height. That is, when vsinθ t - 4.9t^2 = (v sinθ...
*June 24, 2015*

**Algebra**

Suppose there are x price decreases. so, price is 400-x membership is 300+3x revenue is thus (400-x)(300+3x) = -3x^2+900x+120000 So, just find the vertex of the parabola to determine price and max revenue.
*June 24, 2015*

**math**

friction coefficients? mass of man? force of man's steps?
*June 23, 2015*

**English**

2 and 4 are the same 1 and 3 are almost self-contradictory. If he kept in touch, that means he got in touch on a regular, continuing basis. You can't do that every day. So, 1 and 3 are really not good English.
*June 23, 2015*

**algebra**

if x is at 5%, the rest (30000-x) is at 9%. So, you want x in .05x + .09(30000-x) = .08(30000)
*June 23, 2015*

**algebra**

x^4 + 2x^3 - x^2 - 2x x(x^3 + 2x^2 - x - 2) x(x^2(x+2)-(x+2)) x(x^2-1)(x+2) x(x-1)(x+1)(x+2) I expect you can take it from there, yeah?
*June 23, 2015*

**maths**

if cot x = 3/4 sec x = 5/3 csc x = 5/4 So, plug in the values and see whether it's true.
*June 23, 2015*

**maths**

So, is it ever true? tanθ/(1+tan^2θ) = sinθ/cscθ tanθ/sec^2θ = sin^2θ sinθ cosθ = sin^2θ sinθ(cosθ-sinθ) = 0 θ = π/4
*June 23, 2015*

**maths**

If you can't spell theta you might as well just use x. secθ = 5/4 so, sinθ = 3/5 cscθ = 5/3 tanθ = 3/4 tanθ/(1+tan^2θ) = sinθ/cscθ (3/4)/(1+9/16) = (3/5)/(5/3) (3/4)/(25/16) = 9/25 3/4 * 16/25 = 9/25 12/25 = 9/25 Hmmm. I suspect a ...
*June 23, 2015*

**Guru found Singh**

If I said A product of two integers is 10. If one number is 5, find the other number. could you find the other? Follow the same step here.
*June 23, 2015*

**Science**

a = v^2/r, so .18 = v^2/5 Now just find v.
*June 23, 2015*

**Differential Equation**

as you know, |ai+bj| is √(a^2+b^2) and ai+bj + ci+dj = (a+c)i+(b+d)j so what do you get?
*June 23, 2015*

**vectors**

two sides are <8,6,-4> and <9,10,14> The cross product is <124,-148,26> Its magnitude 194.823 is twice the area of the triangle.
*June 23, 2015*

**maths**

well, all four angles add up to 360, so 30+50+d+d = 360 . . .
*June 23, 2015*

**statiSTIcs**

52 is 2 std above the mean of 44. So, look up Z=2 in your table, and subtract that from 1. Or, mosey on over to http://davidmlane.com/hyperstat/z_table.html and enter 2 in the "Above" box and it will calculate the Z value and show the tail of the graph.
*June 22, 2015*

**Calculus**

well, recall what you were told: The price(in dollars) p,and the quantity sold x obey the demand equation p=-1/10x+150 You found that maximum revenue R occurs at x=750, so p = -75+150 = 75
*June 22, 2015*

**algebra**

c = k-4 c+2 = (k+2)/2 + 11 c = 24
*June 22, 2015*

**math**

AB = 12, BC = 4, CD = 7, and DA = 15 Start off my assuming that the largest number is the whole line. That might not be so, but it's a good place to start. B must be to the right of C, since BC < CD That means we have ACBD. Check: AC=8 CB=4 BD=3 You just have to play ...
*June 22, 2015*

**algebra**

just find t when 5422(1.037^t) = 29000000 (I dropped 3 zeros on each side) 1.037^t = 5348.57 t = log(5348.57)/log(1.037) It'll be a while
*June 22, 2015*

**algebra**

You don't say whether the dividing fence is to be parallel to the river or not. If not, then let x be the length of the side parallel to the river. Then you have x+3y = 4700 so, x = 4700-3y The area is a = xy = (4700-3y)y = 4700y - 3y^2 The vertex of this parabola is at (...
*June 22, 2015*

**algebra**

same as the others. Give it a try. period
*June 22, 2015*

**algebra**

this is just like the river field. Why do you insist on saying "comma" and then writing the number with the comma? question mark
*June 22, 2015*

**algebra**

if the side parallel to the river is x, and the other two sides are y, you have x+2y = 9000 the area a = xy = (9000-2y)(y) = 9000y-2y^2 The vertex of this parabola is where you have maximum area. That is at y = 9000/4 You have y, so you can get x, and can find the area.
*June 22, 2015*

**Algebra**

why all the words, when you have the symbols? demand quantity at price x is p(x) = 1/40 x + 19000 The cost is C(X) = 15450x + 20000 (a) So, the revenue (price * quantity) is R(X) = xp(x) = 1/40 x^2 + 19000x (b) P(x) = R(x)-C(x) = (1/40 x^2 + 19000x)-(15450x + 20000) = 1/40 x^2...
*June 22, 2015*

**Geometry**

42 u2004-42-42-42-00_files/i0060042.jpg
*June 22, 2015*

**Math**

see related questions below
*June 22, 2015*

**math**

your answer is correct. Why all the nonsense below it?
*June 22, 2015*

**Math**

If the number of 37,50,58-in tv's are x,y,z, then x = 2(y+z) y = z 1800x+2000y+4800z = 168000 Now just solve the three equations.
*June 22, 2015*

**physics**

F = ma = 1.2*10^3kg * (20m/s)/(5s) = 4.8*10^3 kg-m/s^2 = 4.8*10^3 N
*June 22, 2015*

**Algebra**

If the number of 37,50,58-in tv's are x,y,z, then x = 2(y+z) z = ? (which are equal?) 1800x+2000y+4800z = 168000 Fix the second condition, and then solve the three equations.
*June 22, 2015*

**algebra**

√42 By the way, your files cannot be seen anywhere except on your computer.
*June 22, 2015*

**programming ( qbasic)**

I did google searches for qbasic input to find how to do input and print qbasic math to see how math was done. It also showed the DIM statements and a FOR loop qbasic strings to find string functions like Val and CHR and ASC
*June 22, 2015*

**programming ( qbasic)**

DIM WORD AS STRING DIM SUM AS INTEGER INPUT "Enter a word: ", WORD$ SUM = 0 FOR N=1 to LEN(WORD$) SUM = SUM + ASC(MID$(WORD$,N,1)) NEXT N PRINT "Word value: ",SUM google is your friend. I have never used qbasic, but in about five minutes I found enough code...
*June 22, 2015*

**Physics**

you assumed g/min was gallon/minute Not so. It is grams/minute So, keeping track of the units, you want to convert volume to time: 196gal * 231 in^3/gal * (2.54cm/in)^3 * 1g/cm^3 * 1min/g = 741940 min = 1.41 yr Hmmm. check my math or your supposed answer
*June 22, 2015*

**Math - not**

I'm sure an acronym is not what you are after. An acronym is a word whose letters come from the words of a phrase represented, such as LASER - Light Amplification by Stimulated Emission of Radiation Maybe you are supposed to write a list using the letters of the word as in...
*June 22, 2015*

**mathematics**

type that into google or, what the heck -- use your calculator stop wasting time here with such nonsense.
*June 22, 2015*