# Posts by Steve

Total # Posts: 51,213

**English**

the literary device of foreshadowing is used in which of the following excerpts? They're spoiled and we're spoiled Those screams -- they sound familiar I have a feeling it'll be Africa again before then They're not old enough to do that alone, I explained My ...

**English**

thank you

**English**

my second choice was number 2

**English**

Which of the following is a way that imagery can be used? to present facts during debates to inspire audiences during speeches to entertain readers with a play on words to impress readers with facts and evidence My answer is the third one

**English**

Then it would have to be subjective

**English**

when doing research writing it is important to avoid being? timely, detailed, objectives, subjective My answer is detailed

**Mathematics for social science**

20P3 10C4

**English**

I agree with your comments. thank you

**English**

Absurdism is the attempt to show the ________ of the human condition. silliness seriousness uniqueness hopelessness my answer is the last one

**English**

thank you

**English**

Scientists report (1) that creatures living in the deep sea are in danger of starving to death. The underlined part of sentence 1 is what kind of clause? adverbial clause adjectival clause noun clause Independent clause My answer is independent because if you remove the word ...

**math**

75% = 3/4 He gave 42 to Joe

**math**

I'm assuming your asking how many did Keith get? 56*3/4=42 Leon gave to Joe 42*2/7=12 Joe gave to Keith 3/4= 75% 2/7=28.6%

**Calculus**

The weight of oil in the tank is w = (20*25? m^3) * (820 kg/m^3) * 9.8 = 4018000?N The center of gravity of the oil is 20m from the top of the tank, so the work required to empty the oil is 4018000? * 20 = 80360000? J Or, using calculus, the weight of oil in a thin layer of ...

**Physics**

Scroll down some here, and all is explained. http://www.insula.com.au/physics/1279/L14.html

**Math Functions Functions**

to shift right by h, replace x with (x-h) to shift up by k, replace y with (y-k) Thus, y-3 = (x-2)^2 shifts y=x^2 right 2 and up 3. Reflecting across an axis changes the sign of the other variable. Thus -y=x^2 reflects y=x^2 across the x-axis. Now see what you can do.

**math- factoring**

If two polynomials are identical, all the coefficients must match. So, a = 2 b = -13 c = 21

**Math**

(5?3,5)+(0,-4) = (5?3,1)

**Math**

in standard form, you have x^2+4x - 4(y^2-6y) = 28 x^2+4x+4 - 4(y^2-6y+9) = 28+4-4*9 (x+2)^2 - 4(y-3)^2 = -4 (y-3)^2 - (x+2)^2/4 = 1 Now use that with your standard properties of hyperbolas. check with this: http://www.wolframalpha.com/input/?i=hyperbola+(y-3)%5E2+-+(x%2B2)%...

**Math**

|p| = ?(42^2+35^2) = 7?(6^2+5^2) tan? = 35/42 = 5/6

**Math**

.075x + .12(5000-x) = 819

**Physics**

(10cos37,-10sin37)+(-14,0) = (-6,-6)

**Advanced Functions**

look at the differences. 1st: -0.2, -0.6, -1.0, -1.2, ... 2nd: -0.4, -0.4, -0.4, ... so, look for a linear relationship between y and x^2: y = 3-5x^2 fits pretty well, at least at first

**Math**

cos(2x) = 1 - 2sin^2(x) now just use your numbers.

**Math**

A. 32.65+(38.4-25) = ? B. 32.65+(x-25) = 50.15

**numerical methods in finance**

Just plug in your formula. If you have trouble with that, youtube has several videos showing examples.

**math**

small = 47/22 - 1/2 large = small + 40/11 small = 36/22 large = 116/22

**Geometry**

it is easy to show that ?NOD ? ?MOB check out vertical angles and recall that the diagonals bisect each other.

**Math**

y = 550 * 0.948^t

**Math**

recall that the sum of two adjacent angles is 180, so ...

**Math 120**

(3990-1890)/3990

**Maths**

clearly, P(3k) Q(2k)

**Math**

review the cot(x) function: h cot30 - h cot45 = 1

**Math**

tan? = 9/3 and try proofreading what you type. It's a mess.

**calculus**

what, you can't just plug in the 6 values of t? Even after the explicit example given? No calculus needed here, just basic algebra!

**Maths**

gotta be (d) since the point spread does not change

**Math**

o = 3s o+3 = 2+2(s+3) Olivia is 15

**Math**

construct a 60° angle AOB Bisect it. Measure out the hypotenuse and mark A. Construct the perpendicular to OB.

**College Algebra**

P(t) = 15.1*2.06^t

**Algebra**

This is just an extension of finding the line passing through two points. Plug in the points for Ax+By+Cz = 0 and solve for A,B,C.

**Physics**

F = ma constant velocity means a=0

**Calculus**

Huh, you can't figure the dimensions of s square of area A? The maximum area for a given perimeter is a square. The minimum perimeter for a given rectangular area is a square. So, the length and width would both be ?A But, since you seem to be taking calculus, look at the ...

**Calculus**

a square

**algebra**

hint: 24 = 5*5 - 1

**Linear algebra**

Clearly you did not continue reading to the section where it showed how to find Q1 and Q2.

**Algebra**

google is your friend: https://en.wikipedia.org/wiki/Skew_lines#Distance_between_two_skew_lines

**maths period help**

recall that the period of cos(kx) is 2?/k

**Math**

draw a diagram and review the tan(x) function

**Math**

Draw a diagram. It will be clear that if the pole has height p and the building has height h, then h/145 = tan34 (h-p)/145 = tan26

**Math**

draw a diagram and check on the cot(x) function.

**ALGEBRA**

I can't figure out your function. Usually these things are quadratics, so try writing it using x^2 for "x squared" and "*" for multiplication, since "x" is the variable name.

**calculs**

The distance from (3,-6,4) to a point (x,y,z) on the paraboloid is d^2 = (x-3)^2 + (y+6)^2 + (z-4)^2 = (x-3)^2 + (y+6)^2 + (x^2+y^2-4)^2 the partials of z are zero at (1,-2) and d^2 = 21 For centroids, just plug in to the formula. Should not be hard.

**Math**

If the three classes have debts of x,y,z then we know that y = x+458 z = x+1165 x+y+z = 6543 Now just crank it out.

**calculs**

B. Google volume of torus

**calculs**

A: The curves intersect at (-3,6) and (1,2) So, consider the volume as a set of nested cylinders of thickness dx. Then v = ?[-3,1] 2?rh dx where r=3-x and h=(-x^2-3x-6)-(3-x) v = ?[-3,1] 2?(3-x)((-x^2-3x-6)-(3-x)) dx = 2??[-3,1] (3-x)(-x^2-2x+3) dx = 256?/3

**Maths**

.42 If you still don't like the answer, take a look at what you asked, and think on how we could possibly know ... Then ask again, giving the information necessary.

**math**

Why repeat everything? 24+3r >= 100

**Pre calc**

It took 9 days to shrink to 1/4 its size. 40/640 = 1/16 = 1/4 * 1/4 So, it will take another 9 days to do that again.

**Trigonometry**

If you fix your typo: 2tan 23° / (1 - tan^2 23°) and recall your double-angle formula for tan(x) you will see what you need to do.

**Trigonometry**

#5 since trig functions are periodic, they have infinitely many solutions. #6 So the function and its inverse are 1-to-1. All the trig functions fail the horizontal-line test for inverses unless the domain is restricted, just like something simple like y=x^2.

**science**

5*2 N-m = 10 J work = force * distance

**Math**

a = 1.2b b = 1.25c a = c+58 Time to stop avoiding algebra! 1.2(1.25c) = c+58 1.5c = c+58 0.5c = 58 c = 116 Clara spent 116 Amy spent 174 Betty spent 174/1.2 = 145 so, add them all up.

**Maths**

The Lemma says that for any pair, a,b we can find q,r such that a = bq+r The above equation is just a ? r (mod 5) There is no unique value of a which will determine r.

**Maths**

0.42

**9th Math**

Draw one of the triangles formed by two radii. If the side length is s, then s/2 = 5 sin20° Find s, and p=9s

**science**

yes - the thrust is determined by the volume of liquid displaced.

**maths**

Assuming you meant (p+(pq^2)^1/3+(p^2q)^1/3)/p that term is 1 + (q/p)^1/3 + (q/p)^2/3 If you let u = (q/p)^1/3 then you just have (1+u+u^2)-q(1-u) But q = pu^3 Not sure just where you want to go with this. Your typos make things a bit murky.

**science**

h(t) = 20t - 5t^2 max height is at t=2 h(2) = 40-20 = 20

**math**

2+24 = 26

**Maths**

20/0.75 = ?

**Maths Trig**

Draw a diagram. You will see that sin? = 18/30 Extra credit: How wide a ship can pass through the opening?

**math**

Since all of 15,20,30 divide 300, the cube is 20x15x10 blocks in size. So, it can be cut into 3000 blocks. Or, using the idea above, divide the volume of the cube by the volume of a block: 300^3 / (30x20x15) = 27000000/9000 = 3000

**Algebra**

C appears to be a quadratic. As with any quadratic ax^2+bx+c the vertex lies at x = -b/2a So, find C(x) at that value.

**Algebra**

A^-1 exists if |A| is not zero. Here, |A| = 21-20 = 1 so, A has an inverse.

**English**

Which of the following lines from a&p illustrates updikes use of conflict A. the whole store was like a pinball and I didn't know which one they'd come out of. B. you could see the, when Queenie's white shoulders dawned on then, kind of move, or hop, or hiccup but ...

**algebra**

Peter's age now: x Paul's age now: y x-y years ago, Peter was y years old. x = 2(y-(x-y)) x+y = 56 Peter is 32 Paul is 24 8 years ago, Peter was 24 and Paul was 12.

**Algebra**

1/y - 1/(y+5) = 1/10 y = 5 check: 1/5 - 1/10 = 1/10

**Math**

Draw a diagram. You will see that h cot40° = (h+7) cot60°

**Basic Math**

If 13 is the slant height of a triangular face, then the area of the pyramid is just the base plus four triangles: 11*11 + 4*(11*13/2) = 407 I keep having trouble guessing what you mean by "side" especially of a cone.

**calculus**

lim x?? {(5x ? 4)/(5x + 3)}^5x lim x?? {(1 - 7/(5x+3))}^5x Let u=5x lim u?? {(1 - 7/u)}^u I assume you can now see that this is e^-7

**calculus**

using L'Hospital's rule we have lim x?0 (e^x ? e^?x ? 2x)/(x ? sin(x)) lim x?0 (e^x + e^?x ? 2)/(1 ? cosx) still 0/0, so do it again: lim x?0 (e^x - e^?x)/sinx and again: lim x?0 (e^x + e^?x)/cosx ? (1+1)/1 = 2

**Math - Trigonometry**

of course there is. I assume by "opposite" you mean at the same height on the opposite slanting face. If the base has side 2s, and the pyramid has height h, then If the point P is at height y, then it is at a distance x from the central axis of the pyramid. Using ...

**Linear Algebra**

#4 No, ?200 = 14.14

**Algebra**

well, father will be 36 in 4 years, so ...

**Math - Geometry!!!**

Well, it is certainly not a triangle. If you reorder the points a bit, it should be clear: (3,3),(7,3) (1,1),(5,1)

**Math**

(2/3)(3/4)-(1/6) = 1/3

**Math**

Square ABCD has side length 60. An ellipse E is circumscribed about the square and there is a point P on the ellipse such that PC = PD =50. What is the area of E? I got to the part with the point (30, 30). Now what next?

**Help Polynomial**

Start off with what you know. Substituting x = a,b you have Ra+S = P(a) Rb+S = P(b) Now just solve for R and S.

**Math, Induction**

test for n=1 3.7^2+1 = 14.69 BZZZZTT! But thanks for playing. I suspect a typo in your presentation.

**Math - Trigonometry**

I like 'em. People use decimals because of calculators. When I see °'" I run to my trig tables and do some interpolation!

**Science**

The resistance of each piece is still 25 ohms. Now, if a single 25-ohm wire had been cut into five pieces, then each piece would have had a 5-ohm resistance. That is not what we have here.

**Science**

think about it. The current has 5 different paths it can follow, so the resistance is 1/5 as great. So, 5 ohms 1/R = 1/25 + 1/25 + 1/25 + 1/25 + 1/25 = 5/25 = 1/5 So, R=5 Why would you think it is 1? Time to study some more.

**Integral Calculus**

1st step: go to your DE book and look it up, or go online. Google is your friend. order: highest derivative degree: highest power of highest derivative I can't believe you could not look that up for yourself. www.ul.ie/cemtl/pdf%20files/bm2/DegreeOrder.pdf

**Geometry proportions in triangles**

no diagram, so no way to answer here.

**algebra**

as with any quadratic, the vertex will be at t = -b/2a

**Maths**

180,600.00 (1+.0625)^6

**calculus**

arctan(2x^2y)=x+4xy^2 Using the good old product and chain rules, we get 1/(1+(2x^2y)^2) * (4xy + 2x^2y') = 1 + 4y^2 + 8xyy' Now just collect terms and solve for y': 16x^4y^4 + 4x^4y^2 + 4y^2 - 4xy + 1 - ------------------------------------------- 2x(16x^4y^3 - x...

**maths**

as with any parallelogram, the area A = bh base * height

**maths**

Well, the area of the rhombus is half the product of the diagonals. Draw a diagram and see where that takes you.

**Last math question of the night plz help quickly!**

these are both sloping straight lines. So, they extend forever in all directions. The domain and range are both (-?,?)