Friday

May 27, 2016
Total # Posts: 40,848

**physics**

google is your friend.
*March 27, 2016*

**math essentials**

well, whatever the factor, if it is x, then the area is reduced by a factor of x^2. xL * xW = x^2(LW)
*March 27, 2016*

**math**

?? Don't forget your basic Algebra I skills now that you're in trig. y = 2arcsin(x-5) y/2 = arcsin(x-5) sin(y/2) = x-5 x = sin(y/2)+5
*March 27, 2016*

**Algebra**

well, how far did she go altogether on the first 3 days?
*March 27, 2016*

**Math troubles**

Hmmm. I got .08789 + .01465 + .00097 = .10352 Looks like you have some problems. Make sure you are calculating your binomial coefficients correctly.
*March 27, 2016*

**Math troubles**

First off, no probability can be more than 1, so you calculations are off. P(x=3) = 5C3 .25^3 .75^2 P(x=4) = 5C4 .25^4 .75^1 P(x=5) = 5C5 .25^5 .75^0 Having gotten those, yes, you add them up.
*March 27, 2016*

**math**

google is your friend.
*March 27, 2016*

**maths**

well, shucks -- what are cos(pi/3) and cos(pi/4)?
*March 27, 2016*

**math @Reiny**

The problem as stated above does not mention draining. However, your answer is one of the choices, so I guess his posting today was garbled.
*March 27, 2016*

**math**

None of those. the 4 gal of 25% antifreeze contains 3 gal water 1 gal antifreeze So, you need 2 more gal of antifreeze to make the result 50% algebraically, .25*4 + 1.00 x = .50(4+x)
*March 27, 2016*

**math**

600 * .30 + 300 * .60 = (300+600)x
*March 27, 2016*

**math**

20% of 36, of course
*March 27, 2016*

**Math**

Review your basic trig functions: the vertical height is y/120 = tan10° the distance walked is z/120 = sec10°
*March 27, 2016*

**computer**

I'm holding my flowchart up to the screen. Take a look. the algorithm is for n = 2 to 20 step 2 print n next n or, if you don't like for loops, i=1 n=2 NEXTI: print n n = n+2 i = i+1 if i <= 10 go to NEXTI stop
*March 27, 2016*

**calculus2 - eh?**

you want to try that again in complete sentences? The fragment when the casting temperature 1200 o C is bogus If this is a linear heat increase, no calculus is needed. If not, what model are you using?
*March 27, 2016*

**Progression**

we know that since b-a = c-b, x^c/x^b = x^b/x^a and the same for y and z. Try starting with that.
*March 27, 2016*

**science**

recall that the height h is h(t) = (500 sin30°)t - 5t^2 Now just find the vertex of that parabola.
*March 27, 2016*

**math**

the nature is easily found from the discriminant, B^2-4AC.
*March 27, 2016*

**calculus**

you know that |t-1| has a minimum at t=1, so 1-|t-1| will have a max there. Now just find the values at -9 and 6 and select the max and min
*March 27, 2016*

**calculus**

draw a diagram. Here is where implicit differentiation comes in handy. at the moment in question, the boat's distance x from the dock is 8 ft. The length of rope z is found by z^2 = x^2+8^2 so x^2 = z^2-64 x = √(z^2-64) Now start taking derivatives. The velocity and ...
*March 27, 2016*

**calculas**

just use the chain rule to get 18x + 128y y' = 0 Now just solve for y' and that's implicit, not explicit.
*March 27, 2016*

**math**

64*13 + 28
*March 27, 2016*

**maths**

so, did you draw the graph? Font problems in my browser caused your function to be garbled. Try typing it in, rather than copy/paste.
*March 26, 2016*

**Math**

well, it's the same as the probability of NOT choosing a green ball.
*March 26, 2016*

**Pre Calculus**

well, since profit is revenue less cost, P(x) = R(x)-C(x) you just need to solve for x in 0.002x^2 + 38x - 150000 >= 1650000
*March 26, 2016*

**math**

Your Algebra I is missing 3cos(x+4) = 1 cos(x+4) = 1/3 x+4 = arccos(1/3) x = arccos(1/3) - 4 = 1.231 also, 2π-1.231 = 5.052 sin^2(t) = 1/2 sint = ±1/√2 since sin π/4 = 1/√2 t = all odd multiples of π/4
*March 26, 2016*

**contempory math**

not enough to go on. All we have is A, 4G's, A, 5G's no telling how many G's we are expecting between the A's. 4,5 ... is not much info.
*March 26, 2016*

**math**

the diagonal has length √(8^2+8^2) = 8√2 So, the sides have length 8. The total area is thus 6*8^2
*March 26, 2016*

**mathematics**

Let x be Jane's age now y be John's age now They have said x+y = 25 (x-8) = 2(y-8) So, just solve for x and y.
*March 26, 2016*

**TRIGONOMETRY**

Or, more directly, tan = 1/cot = 1/√(cot^2) = 1/√(csc^2-1)
*March 26, 2016*

**Math**

product means multiply: x(x+2) = 80 Note that 8*10 = 80
*March 26, 2016*

**calculas**

if it's a max at t=0, it is a cosine curve. So, y(t) = (2.7/2) cos((2π/18) t) the velocity is y', so v(t) = -(1.35)(π/9) sin(π/9 t)
*March 26, 2016*

**calculas**

first, find the slope of the tangent line anywhere: y' = -3sin(3x) so, at x=π/4, y = -3sin(3π/4) = -3/√2 Now you have a point and a slope, so the line is y + 1/√2 = -3/√2 (x - π/4)
*March 26, 2016*

**Math**

66/36 = 18/x 66x = 18*36 x = 18*36/66
*March 26, 2016*

**PRECALC**

f(3+h) = 2^(3+h) = 8*2^h f(3) = 2^3 = 8 ... (g◦f)(5) / (f◦f)(3) = √(f(5)-7) / 2^f(3) = √(32-7) / 2^8 = 5/64
*March 26, 2016*

**calc 2**

g(x) = (x + 5/2)^2 - 25/4 p = -25/4 there are Euler's method calculators online.
*March 26, 2016*

**Algebra 1**

What grade represents a C? Let's say it's a 75. Then just consider the total points he needs to have a 75 average: 68 + p >= 2*75 If a C is some other number, then just make the adjustment and solve for p, the number of points he needs.
*March 25, 2016*

**Probability**

well, of the 52 cards, how may are a 3 or a K?
*March 25, 2016*

**Math**

42.5 <= 90-19x <= 52 -47.5 <= -19x <= -38 2.5 >= x >= 2
*March 25, 2016*

**Probability**

well, of the 52 cards, how many are a heart or a king?
*March 25, 2016*

**mathematics-probability**

well, the probability of getting a 6 on just the 1st roll is (1/6)^1 * (5/6)^3 Since you are allowed a 6 on any of the rolls, what do you think?
*March 25, 2016*

**Math**

2*8*6 + 2*3*6 + 2*3*8 = 180 in^2 How much she needs to buy depends on the width of the roll and how much overlap she uses during the wrapping.
*March 25, 2016*

**Math**

well, such a reflection takes (x,y) -> (-x,y) Now just plug in your numbers.
*March 25, 2016*

**Math**

you have a square of side 18 and 4 triangles with base 18 and height 12. So, since you know how to find the area of squares and triangles, just add 'em up.
*March 25, 2016*

**math**

14C5 = ?
*March 25, 2016*

**Algebra**

27 x^(-1 - 2/3) y^(-1 - 3/3) = 27 x^(-4/3) y^(-2) = 27 / x^(4/3)y^2
*March 25, 2016*

**Algebra**

if the initial speed is x, then since time=distance/speed, 400/s + 160/s + 240/(s-20) = 11
*March 25, 2016*

**math**

clearly, if there are x stacks of green & blue, and y of red & yellow, then 20x+14y = 300 10x+7y = 150 y = (150-10x)/7 y = 10(15-x)/7 Since there must be an integer number of blocks, and 7 does not divide 10, it must divide 15-x So, 15-x = 7 or 14 and y = 10 or 20 So, there ...
*March 25, 2016*

**Maths**

if the z is a typo, then you just have 2(sinx+cosx) = 3/2 sinx+cosx = 3/4 If the z is for real, then sinz + cosx = 3/4 cosx = 3/4 - sinz sinx = sqrt(1 - cos^2(x)) = sqrt(1 - (3/4 - sinz)^2) now just add sinx+cosx
*March 25, 2016*

**geometry**

Since the area is 1/2 r^2 θ, the ratio is 1/2 r^2 m∠AOB --------------- = (m∠AOB)/(m∠COD) 1/2 r^2 m∠COD That is, since for a given circle, the area is directly proportional to the angle, the ratio of the areas is the same as the ratio of the angles...
*March 25, 2016*

**Calculus**

If you walk a distance x, then the time t to reach the opposite corner is t(x) = x/s + √((a-x)^2 + 10^2) Now, just find dt/dx. The fastest time is when dt/dx=0, so plug in the fact that it is when x=0. Then you will get an equation is a and s.
*March 25, 2016*

**Calculus**

since x+y+z = 10, we want the max of F(x,y) = xy + (x+y)(10-x-y) Fx = -2x-y+10 Fy = -x-2y+10 Fx = Fy = 0 at (10/3,10/3) So, max of F(x,y) = 100/3 That is, when x,y,z are all equal, at 10/3.
*March 25, 2016*

**math**

If there are x kg of 30% alloy, then consider the total amount of copper in each part. It must add up to the total in the final alloy. .30x + .55(50-x) = .50*50
*March 25, 2016*

**Math**

that would, of course, be 1/7 * 2/3 = 2/21 cups Good luck on finding a measuring set to help you. Extra credit: How many tbsp is that?
*March 25, 2016*

**Physics**

Looks about right, if you use g=10 m/s^2
*March 25, 2016*

**math**

In terms of bricks, the wall's dimensions are 3300/22 = 150 350/7 = 50 40/10 = 4 150*50*4 * .9 = 27000 bricks That's just using raw volumes. However, if we add 10% to each brick's volume, we only need 24545 bricks. A more detailed analysis would add 3.23% to each ...
*March 25, 2016*

**Physical**

clearly it is either A or D. So, is there a numeric factor in there somewhere, or not?
*March 25, 2016*

**Maths**

That's theta not tita For ease of typing, I'll just use x. 2sinx + 2cosx = 1.5 sinx + cosx = 3/4 Now, since sin 45° = cos 45° = 1/√2, sinx + cosx = √2 sin(x+45°) Now we have sin(x+45°) = 3/(4√2) = 0.53033 x+45° = 32° x = -13&...
*March 25, 2016*

**Science**

watch the units: mass (g) = volume (cm^3) * density (g/cm^3) I doubt that the density if 7.8 g/cm^3. Make sure the volume units are correct.
*March 25, 2016*

**Basic Arithematics**

6650 * 0.94 * 1.10
*March 25, 2016*

**Math**

well, c = πd so, d = c/π
*March 25, 2016*

**algebra 1 or pre algebra**

well, just plug in the point. It is on the line, so it must satisfy the equation: -3 = 3*7 + b Solve for b. Then, recall that y=mx+b is the slope-intercept form of a line...
*March 25, 2016*

**maths**

what do you have against fractions? 3/8 + 1/4 = 3/8 + 2/8 = 5/8
*March 25, 2016*

**physics**

P = EI = 240*5 = 1200 = 1.2kW
*March 24, 2016*

**Geometry**

for the flagpole, draw a diagram. Draw a line parallel to the ground at the level of the top of the flagpole. The two angles mentioned are alternate interior angles, so they are congruent. the slope is the tangent of the angle. So, what angle x has tan(x) = 1/12 ? Take a look ...
*March 24, 2016*

**Algebra**

Just as with the baker, let x = acres of wheat y = acres of barley You want to maximize p=450x+350y subject to x+y >= 15 x+y <= 20 200x + 150y <= 2400
*March 24, 2016*

**Algebra**

If there are x packs of waffles and y packs of muffins, you want to maximize p = 1.50x+2.00y subject to 3/4 x + y <= 250 6x + 3y <= 1200
*March 24, 2016*

**geometry**

Or, using the formula area = 1/2 * apothem * perimeter, that will give you the perimeter. 1/5 of that will be the side length.
*March 24, 2016*

**geometry**

a regular pentagon has an apothem of 3.2 and an area of 37.2 cm. What is the length of one side of the pentagon?
*March 24, 2016*

**english help please!!**

google is your friend. I searched for marilyn cross pilot and got a bunch of hits on The Cold Equations, and discussions of the story and characters. I'd think you'd try google first before running here and expecting someone else to do your work for you. I know, I know...
*March 24, 2016*

**algebra**

I assume, but cannot be sure, that you meant f(x) = (x^4-4x^3)/(3-4x^2) + 1 since 3-4x^2+1 is kind of pointless. The denominator is zero when x = ±√3/2, so that is where the vertical asymptotes are. Before going any further, it'd be nice to know whether my f(x...
*March 24, 2016*

**Calculus Applied Integrals**

Just as a check, ∫[12.1,22.1] 1000 π (12.2^2)*9.8 x dx = 7.83595*10^8 which agrees with Damon's number, as expected.
*March 24, 2016*

**@Engineers**

Nice work, Damon. I like how the engineers always cut to the heart of the problem. Reminds me of the engineer's way to measure the area of an irregular shape. He traced it onto paper, cut it out, and weighed it. Then he weighed 1 cm^2 of paper, and voila! The area was easy.
*March 24, 2016*

**Calculus Applied Integrals**

What similar triangles? The tank has a circular cross-section of πr^2 Work = force (weight)*distance, so figure the weight of a thin slice of water (thickness dy). Then the work done to lift it over the top from depth y is its weight times y. Add up all those work pieces ...
*March 24, 2016*

**Algebra**

As always, draw a diagram. You will see that x/25000 = tan2°
*March 24, 2016*

**mathematics-sequence**

I had a question about 3-tails. Since no one else has offered to help, maybe you should explain how that applies here, rather than just reposting your same question with no additional data.
*March 24, 2016*

**Trig Help**

(b)The period is T=2π/(3π/4) = 8/3 s, so the frequency is 3/8 Hz Now, use T=2π√(L/g) to find L (d) since cos(π/2)=0, you want 3π/4 t = π/2 t = 3π/4 * 2/π = 3/2
*March 24, 2016*

**Trig**

using what I showed you earlier, what do you get?
*March 24, 2016*

**Geometry**

um, what in the above solution, did you not understand?
*March 24, 2016*

**Geometry**

a 4x5 card does not have the same aspect ratio as the 8.5x11 paper enlarging 4 to 8.5 is a scale of 2.125 enlarging 5 to 11 is a scale of 2.2 So, using the smaller scale, 4x5 enlarges to 8.5x10.625 or, 8 1/2 by 10 5/8 trying to enlarge it more will cause the width to exceed ...
*March 24, 2016*

**Trig**

sin(-θ) = -sinθ sec(-θ) = secθ cot(-θ) = -cotθ So, you have (-sinθ)(secθ)(-cotθ) = 1
*March 24, 2016*

**Math**

p * .75 * 1.07 = 67.41 Now just find p.
*March 24, 2016*

**mathematics-sequence**

not sure what you mean by "3-tails" The sequence is clearly just an arithmetic sequence.
*March 24, 2016*

**math**

If there are x kg of the 7.50 nuts, the rest (3-x) are 9.50 So, add up the cost of the amounts used. It must equal the final cost. 7.50x + 9.50(3-x) = 25.00
*March 24, 2016*

**Calculus**

If the ends are x and the other side is y, xy = 25600 So, the cost c(x) = 3*2x + 3/2 y = 6x + 38400/x so, dc/dx = 6 - 38400/x^2 dc/dx=0 when x=80 So, plug that in and find the minimum cost
*March 24, 2016*

**physics**

use T = 2π√(L/g) to get L. Now using that L, replace g with 0.29g to get the new T. .90 = 2π√(L/9.8) L = 0.201 .29*9.8 = 2.842 So, the new T = 2π√(.201/2.842) = 1.671 s ================================== Or, noting that T varies inversely as ...
*March 24, 2016*

**Algebra**

two cases: -2w+7 > 5 -2w > -2 w < 1 -(-2w+7) > 5 2w-7 > 5 2w > 12 w > 6 http://www.wolframalpha.com/input/?i=|-2w%2B7|%3E5
*March 24, 2016*

**Math**

yes it is.
*March 24, 2016*

**MATH**

My bad. You are correct.
*March 24, 2016*

**MATH**

why 1/5? 5 of the 10 digits are even.
*March 24, 2016*

**Math**

h(t) = 3 + 40t - 16t^2 Now just find the vertex of the parabola.
*March 24, 2016*

**Algebra**

8w^2+(8w)(5) = 1102 w = 9.5
*March 24, 2016*

**math**

5000*(1+.07*13) + 5000(1+.03/2)^(2*13) = $16,913.55
*March 24, 2016*

**Algebra**

the integers are 2k and 2k+2 (2k)*2(2k+2) = 160 k(k+1) = 20 20=4*5, so k=4 The numbers are 8 and 10
*March 24, 2016*

**physics**

look at the units: .5 cal/g°C * 10g * 10°C = 50 cal
*March 24, 2016*

**algebra**

first, expand the parentheses, so all the exponents are collected: a^2(ab^3)^2 = a^2 a^2 b^6 = a^4 b^6 b^2(a^2b^2)^2 = b^2 a^4 b^4 = a^4 b^6 Since all the variables have the same exponents, the terms can be added, giving a simple a^4b^6 + a^4b^6 = 2a^4b^6
*March 24, 2016*

**Math**

Just take the fraction of 100 for the group you want: 9/20 * 100 = ?
*March 23, 2016*

**Math**

do you mean 40-4k^3 if so, then for k=2, 49-4*2^3 = 40-4*8 = 40-32 = 8
*March 23, 2016*

**MATHS GP**

ar + ar^3 = 30 ar^5 - ar = 90 I get a=3 and r=2 The GP is 3, 6, 12, 24, 48, 96, 192, 384, ... T2+T4 = 6+24 = 30 T6-T2 = 96-6 = 90 T8 = 384
*March 23, 2016*

**algebra**

Don't knock BASIC. I knew a girl in college who was using it to program a gyroscopically stable table in orbit in 1972.
*March 23, 2016*