Wednesday

January 28, 2015

January 28, 2015

Total # Posts: 28,440

**programming**

I assume you know C, so just code up rate = (amt < 10000) ? 0.03 : 0.05; interest = rate * amt * years; Better fix things, so that an exact amount of 10,000 is included somewhere in the condition.
*November 28, 2014*

**algebra**

if the supply pump can pump p gal/min, and the outlet pumps each draw q gal/min, 30(p-q) = 8450 45(p-2q) = 10950 (p,q) = (320,115/3) Now you can convert that to gal/hr.
*November 27, 2014*

**algebra**

boat=b, current=c 225/(b+c) = 5 225/(b-c) = 9 (b,c) = (35,10)
*November 27, 2014*

**Algebra 2 honor**

Just as a reminder, revenue is price * demand. That is, toe total income for all the items sold. recall that for y = ax^2+bx+c the vertex is at x = -b/2a. So, for this one, the vertex is at x = 112.5/22.5 = 5 Since the parabola opens downward, the vertex is a maximum. So, the ...
*November 27, 2014*

**Algebra 2 honor**

if there are x 75-cent increases, then there are 300-15x mugs sold. So, now we have the revenue as r(x) = (7.50 + 0.75x)(300-15x) = -11.25x^2 + 112.5 + 2250 Now just find the vertex of the parabola.
*November 27, 2014*

**Maths**

5x = 3x+24 x = 12 36 cattle, 60 sheep
*November 27, 2014*

**Integumentary System**

google is your friend.
*November 27, 2014*

**maths**

5x = 3x+24 x = 12 I'll let you decide which is which. You canto have a ratio cattle:sheep = 3:5 and yet have more cattle than sheep. There are 36 of one and 60 of the other.
*November 27, 2014*

**maths**

1/2 : 3/4 = 2/4 : 3/4 = 2:3 That should help, eh?
*November 27, 2014*

**math**

ar^2 = 9a so, r = ±3 Now we have a problem. We know that r=3, so the 5th term must be 27 times the 2nd term, regardless of the value of a. And, as you say, there is no way to determine a from the information given so far. You sure it's not 24 less than the 5th term?
*November 27, 2014*

**Math**

Since all the sides are equal, we have 3x 2 = 2y-x 2y-x = y 3 Fix your typos and then solve for x and y. If I assume that your "+" key is not working, then we have 3x+2 = 2y-x 2y-x = y+3 (x,y) = (2,5) So, the sides are 8 and p=24.
*November 27, 2014*

**math**

if N's digits are a,b,c, then we know that c>a, since reversing the digits increased the sum. cba - abc = 99(c-a) = 11(a+b+c) Since 99 is a multiple of both 9 and 11, a+b+c must be a multiple of 9. So, a+b+c is 9 or 18, since 7+8+9=24 is the maximum sum of digits. Now, ...
*November 27, 2014*

**IT**

Here's a nice little perl program. I'm sure you can modify it for the language of your choice. #pay off a loan in 10 equal payments, except for possibly the last, due to roundoff. print "Customer name: "; my $name = <STDIN>; chomp $name; print "...
*November 27, 2014*

**Math**

a + 6a + 2a = 180 a = 20 so now figure B and C
*November 27, 2014*

**Mathematics**

56/16
*November 27, 2014*

**Preamble to the Constitution**

Take a look at some of the recipients of the Liberty Medal. It is awarded to honor those deemed to have labored to secure the blessings of liberty. It will give you some idea of what might be considered to give meaning to the phrase. http://constitutioncenter.org/libertymedal/
*November 27, 2014*

**Algebra**

x+y = 156 x = y+28
*November 26, 2014*

**Math**

.09x + .11(x+400) = 117.00
*November 26, 2014*

**Math**

oops. That's (2±√32)/2 = 1±√8
*November 26, 2014*

**Math**

(b) t = -b/2a = 10/10 = 1 (a) find h(1) (c) solve for t when h=0 -5t^2+10t+35 = 0 or, t^2-2t-7 = 0 t = (2±√30)/2 (use quadratic formula) (d) correct
*November 26, 2014*

**Calculus**

dy/y^2 = 11x^2 dx -1/y = 11/3 x^3 + c Now plug in your initial condition to find c.
*November 26, 2014*

**math**

3/10 * 2/9
*November 26, 2014*

**English**

#2 is the most common Even it is not punctuated correctly. There should be a comma after "conditioner." Without the comma, it appears that one would "turn on the air conditioner to save electricity." #3 or #6 could also be used. The others are incorrect.
*November 25, 2014*

**TRIG!**

just replace t with 3t. They are the same curve. In either case, y = x^2+1
*November 25, 2014*

**physics**

the initial vertical speed is 47 sin 31° = 24.2 m/s So, the height y = 24.2t - 4.9t^2 Now use your algebra to find the vertex of that parabola. That will be the maximum height.
*November 25, 2014*

**Algebra**

v = k*pq/s^2 Now just plug in the numbers to find k.
*November 25, 2014*

**Math**

We need to keep the ratio 10:6 112 = 16*7, so we need to add 10*7 = 70 white balls 6*7 = 42 yellow balls
*November 25, 2014*

**trigonometry**

the circle is clearly the unit circle with center at (0,0) theta goes from 3pi/4 to 3pi/2
*November 25, 2014*

**trig**

2rcosθ + 3rsinθ = 5 r = 5/(2cosθ+3sinθ) rsinθ = 1/2 rcosθ tanθ = 1/2 θ = arctan(1/2) No r involved.
*November 25, 2014*

**Math Help!**

Correct .25 = n/350
*November 25, 2014*

**Math Help!**

820 = .20 n Looks like B to me when it starts out with "820 is" you need to start looking for "820 ="
*November 25, 2014*

**Math Help!**

Correct
*November 25, 2014*

**trigonometry**

θ = π/6 tanθ = 1/√3 y/x = 1/√3 y = 1/√3 x r = 8cosθ r^2 = 8r cosθ x^2+y^2 = 8x
*November 25, 2014*

**trig**

x = -2 + 12t y = 6 - 10t 0 <= t <= 1
*November 25, 2014*

**pre calc**

since v = kT/P, PV/T is a constant. So, 342*V/10 = 380*2.3/20
*November 25, 2014*

**Math**

oh. In that case, recall that N^0 = 1 for any value of N.
*November 25, 2014*

**Math**

none of those offered.
*November 25, 2014*

**easy math**

you are correct
*November 25, 2014*

**Calculus**

Let u = 1+lnx du = dx/x and the integrand is u du
*November 25, 2014*

**Calculus**

This is just the chain rule in disguise f'(x) = (x^3)^2 (2x) = 2x^5 Read up on the 2nd fundamental theorem of calculus.
*November 25, 2014*

**Calculus**

If you mean dx/x (lnx)^(1/2) then let u = lnx du = dx/x and the integrand becomes u^(1/2) du
*November 25, 2014*

**math**

c(t) = 420t where t is in hours
*November 25, 2014*

**Trigonometry**

csc^2 + sec^2 1/sin^2 + 1/cos^2 (sin^2 + cos^2)/(sin^2 cos^2) 1/(sin^2 cos^2) sec^2 csc^2 Not sure what the 2nd line is saying It's not an identity, just an expression.
*November 25, 2014*

**algebra**

7P3 = 7*6*5
*November 25, 2014*

**Problem Solving: Draw Picture**

draw a line 22.5 inches long mark a spot every 1.5 inches
*November 25, 2014*

**math**

just solve for y in: 1500 + (7500-1500)y = 7080
*November 25, 2014*

**English**

They all look good to me.
*November 25, 2014*

**English**

#1 is correct. Extra credit: what is bad about #2?
*November 25, 2014*

**Geometry**

the three medians intersect at the centroid, which is where the triangle will balance.
*November 25, 2014*

**Calculus**

the average value of f(t) over the interval [a,b] is ∫[a,b] f(t) dt ------------------ b-a So, for this problem, that would be (∫[0,5] .96t^2+25 dt)/(5-0) = (.32t^3 + 25t [0,5])/5 = 165/5 = 33
*November 25, 2014*

**Algebra math Question**

well, you have 2(w + 2.4w) = 20.4 Now just solve for w, and the length is 2.4 times that.
*November 24, 2014*

**math**

Oh, please. You provide no numeric details at all -- how do you expect an answer? Since 42 is the answer to the ultimate question of life, the universe, and everything, I thought surely it was the answer to your obfuscated question!
*November 24, 2014*

**math!!**

algebraically, you want 8m >= 3m+25 or, just note that Sam saves an extra $5/month. SO, it will take 5 months to gain $25.
*November 24, 2014*

**MATH**

P(1+0.01375/4)^(4*3) = 15000
*November 24, 2014*

**calculus**

So, looks like C to me.
*November 24, 2014*

**calculus**

since (arctan(u))' = 1/(1+u^2) u', we have d/dx arctan √(3x) = 1/(1+3x) (√3)/(2√(3x)) = √3 / (6x+2)√x
*November 24, 2014*

**Pre-Calc/Trig**

well, that would depend on n, don't you think? multiples of 2 are even; otherwise, odd
*November 24, 2014*

**Algebra**

the domain is all the values of x where f(x) is defined. f(x) = 4 if -6 <= x < -2 |x| if -2 <= x < 8 ∛x if 8 <= x <= 14 So, clearly the domain is [-8,14] since f(x) is defined everywhere inside the interval, and nowhere outside it. Doesn't matter ...
*November 24, 2014*

**Math**

Ya got me. I don't find any rational roots at all. Makes factoring kinda tricky. You sure it's not 2y^4-y^3-10y+5 ? That could be done by grouping y^2(2y-1) - 5(2y-1) (y^2-5)(2y-1) For your function as given, I don't see any way. Wolframalpha confirms this: http://...
*November 24, 2014*

**maths**

If you want the radius r of the circle, just draw a diagram and note that (4/2) = r sin(60°/2)
*November 24, 2014*

**math**

(7/2)mi / (221/4) min = 7/2 * 4/221 mi/min = 14/221 mi/min
*November 24, 2014*

**algebra**

Nope. As you state it, it makes no sense. One does not add and subtract denominators.
*November 24, 2014*

**algebra**

I'm guessing you meant y/(y-5)+5/(5-y) = y/(y-5) - 5/(y-5) = (y-5)/(y-5) = 1
*November 24, 2014*

**math - eh?**

1/a + 1/b = 1/60 12/a + 36/b = 1 You sure there's no typo? I get a negative value for a.
*November 24, 2014*

**Calculus**

Let u^2 = x+9 Then √(x+9) = u x = u^2-9 dx = 2u du Then the integral becomes ∫(u^2-9)/u (2u du) = ∫2(u^2-9) du = 2/3 u^3 - 18u = 2u/3 (u^2-27) = 2/3 √(x+9) (x-18) For other problems, you can check your results at http://www.wolframalpha.com/input/?i=%E2...
*November 24, 2014*

**Calculus**

u=5x du = 5dx and the integrand becomes 1/5 sec(u) tan(u) du That should look familiar
*November 24, 2014*

**Calculus**

let u = x^9 then du = 9x^8 dx and the integrand is now 1/9 e^u du
*November 24, 2014*

**math**

distance gone will be 45*4 = 180 km poles/km = 1000/50 = 20 So, 180*20 = 3600 poles
*November 24, 2014*

**Calculus**

let u = 7sinx+35 du = 7cosx and the integrand now becomes 1/7 du/u
*November 24, 2014*

**Math**

gee - why not follow the hints? Use cross products: if a/b = c/d, then ad = bc So, for the first, try each pair: 1. 24/96 , 27/108 ? 24*108 = 96*27 YES 2. 17/102 , 12/70 ? 17*70 = 102*12 NO 3. 21/51 , 35/85 ? 21*85 = 51*35 YES 4. 45/75 , 63/105 ? 45*105 = 75*63 YES Try the ...
*November 24, 2014*

**Math**

sinB/b = sinA/a sinB = 9(sin28)/15 = 0.2817 B = 16° or 164°
*November 24, 2014*

**Math**

since the distance s = rθ the object travels 8.1*10 = 81 cm/s Curious how you got 47
*November 24, 2014*

**Calculus**

or, 4 + 4/x^2 :-)
*November 24, 2014*

**Calculus**

just do a long division (4x^2+4)/x^2 = 4 + 2/x^2
*November 24, 2014*

**math,trigonometry**

well, you know that y/35 = cos 20° x/35 = sin 20° This problem is slightly sly, since most of the time they give you the angle with the ground!
*November 24, 2014*

**caculus**

let u = arcsin(x) du = 1/√(1-x^2) dx and the integrand is u^6 du
*November 24, 2014*

**math**

q = 2d 25q+10d = 360
*November 24, 2014*

**physics**

1W = 1J/s = 1N-m/s Just look at the units. You have 100,000N * 250m/s = 25,000,000N-m/s = 25MW
*November 24, 2014*

**math**

you asked it much better the first time. Why garble the question and post it again?!?!?
*November 24, 2014*

**math**

we are told that d = 2q 10d+25q = 135 now just solve for q 10(2q)+25q = 135 45q = 135 q = 3
*November 24, 2014*

**math**

2 A's out of 16 letters. P(A) = 2/16
*November 24, 2014*

**algebra**

If she started with d dollars, and bought y yards, then we are told 29.50y + 12.00 = d 19.75*2y = d+28.00 So, she started with $130 and bought 4 yards. check: 29.50*4 = 118, leaving 12 left over 19.75*8 = 158, $28 too much
*November 24, 2014*

**Trig**

Remember, it's sinA/a = sinB/b What you have is sinA = 5.74, not A=5.74 There is no angle with sine of 5.74. Clearly there will be no triangle here. Sin 88 is almost 1, so 23/4 that will be much more than 1.
*November 23, 2014*

**algebra**

c = 4b+1 .12b + .10c = 2.18 Now just solve for b and c
*November 23, 2014*

**Calculus**

v(t) = h'(t) = -32t + Vo Now just plug in t=5 and whatever Vo was.
*November 23, 2014*

**Trig- math**

how did you get sinA? Also, the area = (bc sinA)/2, not (ab sinA)/2 849^2 = 930^2 + 1301^2 - 2*930*1301 cosA A = 40.6° area = b*c*sinA/2 = 930*1301*0.651/2 = 393,879
*November 23, 2014*

**Trig**

-6u-3v = -6(2i-5j) - 3(-i+3j) = -12i+30j+3i-9j = -9i+21j |-6u-3v| = √(81+441) = √522 x = |v| cosθ and y = |v| sinθ Since cos60° = 1/2 and sin60° = √3/2 v = (4(1/2),4(√3/2)) = (2,2√3) I assume that (u)(v) means u•v If so, ...
*November 23, 2014*

**Calc**

See the first related question below. Just change the numbers as needed
*November 23, 2014*

**Basic Math (Check my answer)**

It is C width = area ÷ length
*November 23, 2014*

**algebra**

If the speed of the plane and the wind are p and w, then since distance = speed * time, 3(s+w) = 390 5(s-w) = 390 s = 104 w = 26
*November 23, 2014*

**Math**

do you know how to plot points? If so, just plot the four points above. Then you can measure the length and with of the rectangle. And surely you know how to wind the area of a rectangle, given its length and width ...
*November 23, 2014*

**Trigonometry**

since cos pi/6 = √3/2, sec pi/6 = 2/√3 Now just finish it up.
*November 23, 2014*

**math**

just solve for a: 14.7 e^(-0.21a) = 11.11 e^(-0.21a) = 0.7558 -0.21a = ln 07558 = -0.28 a = 4/3
*November 23, 2014*

**Algebra 2**

x^2 = 6y+10 (6y+10)^2 + y^2 = 2 37y^2 + 120y + 98 = 0 now just solve for y, then x. I hope you're looking for complex solutions... See http://www.wolframalpha.com/input/?i=solve+x^2%2By^2%3D2%2C+x^2-6y%3D10+
*November 23, 2014*

**Math**

4(x+2)+3x+2(x-y) 4x+8+3x+2x-2y 9x-2y+8 Not real sure just what you're asking for.
*November 23, 2014*

**Maths**

lots and lots. Clearly, 4 by 5 But also √20 by √20 1 by 20 7 by 3 (21 rounds to 10) Just pick any numbers that multiply to give a value between 19.5 and 20.5
*November 23, 2014*

**Math**

32(2)^2x-12(2)^x+1=0 Recall that 2^2x = (2^x)^2, so you have 32(2^x)^2 - 12(2^x) + 1 = 0 Now, just to make things easier to read, let u = 2^x and you have 32u^2 - 12u + 1 = 0 (8u-1)(4u-1) = 0 u = 1/8 or 1/4 So, that means we have 2^x = 1/8 ------> x = -3 2^x = 1/4 ------>...
*November 23, 2014*

Pages: <<Prev | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | **15** | 16 | 17 | 18 | 19 | 20 | 21 | Next>>