Posts by Steve
Total # Posts: 50,492
clearly, 1,3,5 are an AP 2,4,8 are a GP Now just plug in your formulas for partial sums.
0.95x = 4.75
I like your 25 stones.
I like Elsa's proof, using Heron's formula. Works for me.
The line containing (a,0),(0,b) has equation x/a + y/b = 1 This is called the intercept form of a line. Clearly, (1,1) lies on that line if 1/a + 1/b = 1
well, just plug and chug 1/(2y) - 1/(y-x) = 1/(y-z) - 1/(2y) (x+y)/(2xy-2y^2) = (y+z)/(2y^2-2yz) (x+y)/(x-y) = (y+z)/(y-z) (x+y)(y-z) = (y+z)(x-y) xy+y^2-xz-yz = xy+xz-y^2-yz y^2-xz = xz-y^2 y^2 = xz y/x = z/y Thus x,y,z form a geometric progression
Do you mean 1/(y-x), 1/(2y), and 1/(y-z) or 1/(y-x), (1/2)y, and (1/y)-z ??
Again, the curve is unbounded. If you mean y=(x^3/3)+x^2+x+1/(4x)+4 then here is the graph: http://www.wolframalpha.com/input/?i=(x%5E3%2F3)%2Bx%5E2%2Bx%2B1%2F(4x)%2B4 So, which part of the curve do you want?
Consider the interior of the bowl as a stack of thin circles. At height h, the circle has area ?r^2 = ?(16(h+1)) So integrate that from 0 to 2
If there are no correct answers, then the possible scores are 0,2,4,...,24 If 1, then 5,7,9,...,27 If 2, then 10,12,14,...,30 I think you can see the pattern here. Just make a 12x12 table and fill in the scores. Then cross them off a list of values from 1-60. Those remaining ...
If she travels x minutes at 70m/min, then the distance is 70x meters. It takes her 2 minutes longer at 60m/min. 70x = 60(x+2) x = 12 So, the distance is 840 meters. Her normal speed takes her 22 minutes, so she leaves at 7:38
http://formulas.tutorvista.com/math/orthocenter-formula.html This will give you the orthocenter, if you have the vertices of a triangle. If you set up your right triangle with the right angle at C=(0,0) then let the other two vertices be at A=(a,0) and B=(0,b). Then the right-...
I think that the ? is just a way of giving us the slope of the ladder. If the firefighter has climbed a distance z to a height h, then we have x^2+y^2 = 29^2 w^2+(y-h)^2 = (29-z)^2 when ?=?/3, x = 29/2 and y=29?3/2 w = (29-z)/2 and h = z?3/2 when z=6, then, w = 23/2 and h=3?3 ...
they are the same. 10/10, 5000/5000, ...
any plane intersection with a sphere is a circle.
What were you expecting it to "add up" to? -4b * (1-b)/b = -4b(1-b)/b = -4(1-b) = 4b-4
The n'th term is ar^(n-1) Sn = a(1-r^n)/(1-r) = 1/4 4a(1-r^n) = 1-r 4a - 4ar^n = 1-r 4a - 4ar^(n-1)*r = 1-r ar^(n-1) = (1-r-4a)/(4r) I can't see how you can solve for r and a. There are many possible solutions. n=1: a=1/4 n=2: a(1+r) = 1/4 a = 1, r = -3/4 a = -1/3, r...
12 is 3/7, so 4 is 1/7 Now how much would you pay?
sir damon steve damon damon help maths
That is correct. The average value of a function over an interval if ?[a,b] f(t) dt ------------------ b-a
You know the factors will be (3n-?)(n+?) or (3n+?)(n-?) where the ?? pairs are 1,4 or 2,2 So, just poke around a bit and you will soon find that (3n-4)(n+1) works
12/28 as much time, so 28/12 as many workers. 28/12 * 3 = 7
distance = speed * time Since their distances are the same, if Jim's speed is x, then x(1/4) = (12)(1/3) x = 16 mi/hr Or, you can consider it like this. Jim takes 3/4 as long, so his speed must be 4/3 as great. 4/3 * 12 = 16
8 - 10 paragraphs on The Odyssey part 1. PLEASE, I WONT TAKE THIS FOR GRANTED. god bless. i tried but i cant read it very well
The curve is unbounded. Also, there appears to be a typo. Why the +x+14x? As with any curve, its length over a given interval [a,b] is s = ?[a,b] ?(1+y'^2) dx
(a) do not know the formula (b) your text formatting sucks. try writing fractions as 3/4 and sequence terms as t7 or t20
Math! Help Hurry!
each small block has a volume of (1/4)^3 so the whole lot has a volume of 576 * (1/4)^3 = 9 ft^3
Math! Help Hurry!
I thought you said these problems were all different. They look exactly the same to me. Figure the volume of one of the small blocks, and use that to divide into the whole volume. 3 1/4 = 13/4 so the box has a volume of 13/4 * 3 * 1 = 39/4 ft^3 each small block has a volume of...
Math and Hurry Please!
2304 * (1/4)^3 = 36 cm^3
the new mix of 32+8=40 oz contains 4+8=12 oz of cream 12/40 = 30%
#1 I assume that x,y,z are integers, or there is no maximum sum. The minimum sum would be 3?500 ? 23.811 500 = 2^2 5^3 so its factors are 1,2,250 1,4,125 1,5,100 1,10,50 1,20,25 2,2,125 2,5,50 2,10,25 5,5,20 5,10,10 5,25,4 Now pick the largest and smallest sums. #2 v = ?r^2h...
Take a look at the distances for each stone, numbering them outward. I'm assuming that we only include the distances actually carrying stones. The actual distance walked would be twice that. # d 1 10 2 20 3 30 ... n 10n So, after collecting n stones on each side, the ...
In that case, you must have forgotten your Algebra I. Look at what you know: a+7d = 2(a+2d) 8/2 (2a+7d) = 39 or, massaged a bit, a = 3d 8a+28d = 39
-2x - 5 < -2 -5 < 2x-2 -3 < 2x -3/2 < x or, x > -3/2 do the others similarly.
add 3 to each part
your copy/paste skills are severely lacking. What's so hard about this? You have the function pieces and their domains. Just plug in your numbers for the proper part.
since ?WED ? ?FRI, ?R ? ?E So, solve for x.
consider the top of a large cone which has been cut off to leave the frustrum. Draw a side view. Using similar triangles, we know that the top of the bucket is 3/4 as high as the uncut cone. So, the piece that was cut off has an altitude of 15 cm. Subtract the small top of the...
This should help a lot. You can construct the vectors u and v for the two orthocenters, and then just get the magnitude of |u-v| http://mathforum.org/library/drmath/view/70440.html
maths sir damon reiny or steve help!steve see
surely you know about the chain rule. ?u/?r = ?u/?x ?x/?r + ?u/?y ?y/?r = 2x sin(t) + 2*0 = 2x sin(t) similarly for ?u/?t
f = (6-x)e^-x f' = (x-7)e^-x f" = (8-x)e^-x f"=0 at x=8 f(8) = -2e^-8 so (x,y) = (8,-0.00067) See http://www.wolframalpha.com/input/?i=(6-x)e%5E-x+for+6+%3C%3D+x+%3C%3D+11
(a) [?[0,?] (10 sin(x)-5sin(2x)) dx]/(?-0) = 20/? (b) 10sin(c)-5sin(2c) = 20/? c ? 1.238 or 2.808
well, the weight is 44-0.2t now integrate that over the required distance.
AC = AB+BC = a+b and so on. Of course they sum to zero, since that is a closed path.
so, think back to your Algebra II days and finish it up. What you have is correct, but make it look good: x^2-4x + y^2+4y = 0 x^2-4x+4 + y^2+4y+4 = 8 (x-2)^2 + (y+2)^2 = 8 http://www.wolframalpha.com/input/?i=r%3D4cos%CE%B8+-+4sin%CE%B8
F = ma
log2(2?3/5)) = log2(2) + 1/2 log2(3/5) = 1 + 1/2 (log2(3)-log2(5))
try n=5 1+4*5 < 2^5 -- true So, what about n+1? 1+4(n+1) = 1+4n + 4 Now just show that it is less than 2^(n+1)
surely by now you could have figured this out. Since ?ABC is isosceles, ?A = ?B = 30° Therefore, ?BMC is a 30-60-90 right triangle, with ?MCB = 90° So, BC = 12?3 Now drop an altitude from C to AB and use BC to find AB.
work = PE = mgh
Cool. Now where the heck is PR? Get with it, ok?
force is N = kg-m/s^2 work is J or N-m
I hope you are not the one who has already posted this several times, receiving an answer each time. It is (11+9)/2 * 6 * 16/12
multiplying by 10, we have -2x+25 = 22 ...
x = (6+y)/(2y) 2xy = 6+y y = 6/(2x-1)
Note that ?MQP = ?MPQ so ?QMP is isosceles. MQ = MP = 18 ?MRQ is 30-60-90, with a hypotenuse of 18 RQ = 9?3
and PR is where?
where is M?
well, the area is (11+9)/2 * 6 = 60 m^2 How many boxes is that? So, how much cost?
you cannot simplify the log of a sum. Since there are no common factors to remove, this is as simple as it gets. Unless you mean log 6(7m+3q) = log 6 + log (7m+3q)
Since 100 = 10^2 take the square root of both sides, and you have 10 = 100^(1/2) x = 1/2
PE is measured in J or N-m PE = mgh
V=kT/P so PV/T = k, a constant. You want T such that 10*74/T = 8*42/84 also, "cm to the 3" is written cm^3
3x+10 >= 4 3x >= -6 ...
(x+2)(x-3) --------------- (x+2) This is equal to (x-3) for every value of x except -2, where it is undefined.
recall that (a+b)^2 = a^2+2ab+b^2 so, take 1/2 of the middle coefficient and square it.
since the center is at y=5, and it is tangent to the x-axis, the radius is 5. Now, what is the standard equation for a circle?
well v increased by 3 m/s in 8 seconds. now, what is the definition of acceleration?
figure the lengths of the sides. Then use the law of cosines. c^2 = a^2 + b^2 - 2ab cosC
x^2?6x+9+y^2+2y+1 = 25 (x-3)^2 + (y+1)^2 = 5^2 Look familiar?
Draw a diagram, where a radius bisects the chord. You will see that the arc is subtended by the angle ?, where sin(?/2) = 9/14 The arc length is then s = r?
top is 14 left is 12 right is 10 bottom is 20 If the figure is a trapezoid, then 144-x^2 = 100-(6-x)^2 x = 20/3 The height h is h^2 = 144-(20/3)^2 h = 8/3 ?14 So, the area is a = (14+20)/2 * 8/3 ?14 = 136/3 ?14
what is the shape of the rope? straight lines? parabola? catenary?
1 and 2 are ok. On #3 you confuse frequency and wavelength. (and that's "greater")
conserve momentum: 5v = (8000+5)*0.50
(15 km/hr * 10^5 cm/km) * (49? cm^2) * x hr = (50m * 44m)(100cm/m)^2 * 21cm x = 2 hr
you don't say whether the values given are opposite or adjacent angles. So, you have one of two cases: x+40 = 3x-20 x+40 + 3x-20 = 180 Pick the one you want, solve for x, and then you can answer the questions.
pair them up 2,2n 4,2n-2 6,2n-4 ... What is the average of each pair? Or, consider their sum: 2+4+...+2n = 2(1+2+...+n) = 2*n(n+1)/2 = n(n+1) So, what is the average of that sum?
(a + b+10)/2 = (a+b)/2 + 5
N arctan(8/5)° E
remember the point-slope form of a line. The line with gradient m through (h,k) is y-k = m(x-h) Now just plug in your numbers.
y = -(x-3)(x-4) So, using discs of thickness dx, v = ?[3,4] ?r^2 dx where r=y v = ?[3,4] ?(x^2-7x+12)^2 dx = ?/30 Using shells of thickness dy, and taking advantage of the symmetry, v = 2?[0,1/4] 2?rh dy where r=y and h=?(1/4 - y) v = 2?[0,1/4] 2?y?(1/4 - y) dy = ?/30
well, there are 10 choices for each digit, so ...
first step: what is the probability of rolling a 7?
x^2-x-6 = (x-3)(x+2) x^2-5x+6 = (x-3)(x-2)
each shell has thickness dx, so v = ?[1,3] 2?rh dx where r=x-1 and h=y-3 v = ?[1,3] 2?(x-1)(4x-x^2-3) dx = 8?/3 as a check, using discs of thickness dy, v = ?[3,4] ?(R^2-r^2) dy where R=(2+?(4-y)-1) and r=(2-?(4-y)-1) v = ?[3,4] ?((1+?(4-y))^2-(1-?(4-y))^2) dy = 8?/3
Each shell has thickness dx, so v = ?[0,2] 2?rh dx where r = 9-x and h = 8-y v = ?[0,2] 2?(9-x)(8-x^3) dx = 984?/5 as a check, using discs (washers) of thickness dy, v = ?[0,8] ?(R^2-r^2) dy where R=9 and r = 9-x v = ?[0,8] ?(9^2-(9-?y)^2) dy = 984?/5
x/4 + 2 = -2 x/4 = -4 x = -16
Presumably, the same percentage of seals was tagged as was found in the later sample. So, 6982/x = 245/700
8th grade math asp help
as you can see, no pictures here.
Julia has served one year of her 10-year sentence in prison. She has behaved herself, work at the library, and has not acted out in any way. She is hoping that at her next hearing judge will reduce her sentence. What type of sentence is julia hoping that at her next hearing ...
well, a common right triangle is 5-12-13
because y is a function of x. You must use the chain rule. d/dx (3y^2) = d/dy (3y^2) * dy/dx
ln(x+y+3) = xy + y^3 (1+y')/(y+x+3) = y + xy' + 3y^2 y' Collect terms and solve for y': y' = 1-y(x+y+3) -------------------------- (x+y+3)(x+3y^2)-1 so, at (-4,2), y' = -1/7 So, now you have a point and a slope, and the ...
maths extrema need hlp
for extrema, you need ?f/?x and ?f/?y = 0 ?f/?x = cosx + cos(x+y) = 0 ?f/?y = cosy + cos(x+y) = 0 recall that cos ?/3 = -cos(2?/3) So that should get you started.
mathematics plz need help sir steve
Do you mean the Jacobian? F1x = 4x^3y^3 F1y = 3x^4y^2 F2x = 35x^6 F2y = 3cos(3y) So, the determinant of J(f1,f2,x,y) is (4x^3y^3)(3cos(3y))-(35x^6)(3x^4y^2) = 12x^3y^3 cos(3y) - 105x^10y^2 See http://www.wolframalpha.com/input/?i=jacobian+of+(x%5E4y%5E3,+5x%5E7%2Bsin(3y))