looks good to me. good work.
g(x) = (x-3)(x+3)(2x-1)/(x+3)(x-2) So, while the denominator is zero at x = -3, so is the numerator, so there is a hole there. The only vertical asymptote is at x=2. considering only the highest powers, as x gets huge, g(x) approaches 2x^3/x^2 = 2x, which is the slant asymptot...
there is a mark on the protractor at the center of the base. Place that mark on the angle, with the base of the protractor aligned with one ray of the angle. The other ray (maybe extended) will intersect the curve of the protractor, where you can read off the angle.
Pre Alg HELP
maybe 5" x 4" 20'x16' or any other 5:4 ratio, depending on the scale.
PE -> KE mgh = 1/2 mv^2 gh = 1/2 v^2 v = √2gh = √(2*9.8*7.63) = 12.23 m/s note that the mass doesn't matter. Only the height contributes to the speed.
I think you need to check out (c)
actually, that would be -1.96
AP Physics - correction
the diver's air speed is v = 9.8t make that correction and redo the board height.
the upward acceleration from the water is a=F/m = 1480/67 = 22.09 m/s^2 The diver's speed on entering the water is v = √(2as) = √(2*22.09*4.7) = 14.4 m/s In the air, the diver's speed is v = 4.9t^2, so he fell for t = √(14.4/4.9) = 1.71 seconds The di...