Monday

March 2, 2015

March 2, 2015

Total # Posts: 29,297

**Physics**

I'm having a hard time making out the figure. . .
*January 27, 2015*

**science**

the circumference of the frame is πd m The total length of wire is 5*50 = 250 m So, ignoring the slight difference of the length of a helix as opposed to stacked rings, the number of loops around the frame is 250/πd The height of each loop is 0.035 m, so (250/πd...
*January 27, 2015*

**algebra**

-49x^2-35x-6 -(49x^2+35x+6) -(7x+2)(7x+3)
*January 27, 2015*

**Math**

clearly, 12 does not divide either polynomial. 4x^2 + 13x + 3 = (4x+1)(x+3) 8x^2 + 22x - 6 = (4x-1)(x+3) Now can you see the common factor? How ever did you come up with 12?
*January 27, 2015*

**BOGUS!**

expect no help till you finish the question. Do you see what you actually wrote? No diagram, no description of what D and E are. BOGUS!
*January 27, 2015*

**math**

well, (2+4+6+...+200) = 2(1+2+3+...+100) 1+2+3+...n = n(n+1)/2 So, x = 200*201/2 and you have 200*201/2 - 2*100*101/2 = 200/2 (201-101) = 100*100 = 10,000 Or, you could note that (1+2+3+...+200)-(2+4+6+...+200) = (1+3+5+...+199) The sum of the first n odd numbers is n^2, so ...
*January 27, 2015*

**math**

divide each price by its area. The smallest quotient is the best buy in $/m^2. How you factor in the quality is not specified.
*January 27, 2015*

**math**

a+b = 12 1/a + 1/b = 3/8 4+8 = 12
*January 27, 2015*

**math**

I expect you meant to say (2,-√5) man, some of the weird notations folks come up with! The line passing through the origin with slope m is y = mx You have a point, so you can figure the slope, right? The tangent line to a circle at any point (x,y) is -x/y SO, you want to...
*January 27, 2015*

**math**

answered in the first related question below.
*January 27, 2015*

**MATH**

75(b-4) <= 450
*January 26, 2015*

**Math**

no grids here, but surely you can see that the dimensions must be among 1x7 2x6 3x5 4x4
*January 26, 2015*

**Physics - Vectors**

when you say A times B, is that the dot product, or the cross product?
*January 26, 2015*

**Physics - Vectors**

not sure what Upper B means
*January 26, 2015*

**Physics**

conserve momentum. So, 2.33*10^4 * 3.71 + 4.66*10^4 * 1.44 = 6.99*10^4 * v v = 2.20 m/s So, now just figure KE = 1/2 mv^2 for each car before, and the combo car after the collision.
*January 26, 2015*

**Geometry**

there are lots of possible probabilities. For each color, P(color) = #color/#total so P(red) = 5/(4+5+1+2) = 5/12 do the others similarly.
*January 26, 2015*

**Algebra**

2(w + w-1) = 106 4w-2 = 106 4w = 108 w = 27 so, the width is 27 and the length is 26. An odd way to assign the dimensions, I must say... You forgot that the perimeter is twice the sum of the length and width.
*January 26, 2015*

**Math**

r = s+6 in 4 years, r+4 + s+4 = 78 so, now we can see that (s+6)+4 + s+4 = 78 2s+14 = 78 2s = 64 s = 32 SO, Samantha is 32 and Russell is 38 In 4 years, they will be 36 and 42 (sum = 78)
*January 26, 2015*

**MATHS**

in 2 hours, they can fill 2(1/10 + 1/8) = 9/20 of the pool. So, at 1/10 pool/hr, A takes an additional (11/20) / (1/10) = 11/2 hours
*January 26, 2015*

**Math**

I understand the question to mean that the difference in attendance was at least 16,600, so I'd write it as x-809,300 >= 16,700 x >= 826,000 Note that "at least" means greater or equal, not just greater.
*January 26, 2015*

**Math**

how many times you gonna ignore Reiny's explanation below, or at least say why it is unsatisfactory?
*January 26, 2015*

**Geometry**

I suspect it makes a difference which direction each one turns.
*January 26, 2015*

**Math**

the period of cot(x) is pi. The amplitude and power make no difference. So, the general solutions are n*pi ± pi/3 for any integer n.
*January 26, 2015*

**math**

ummm... how about √(mx+b) ?? I suspect you have not posed the question completely.
*January 26, 2015*

**Math**

15 <= -k/4 + 9 6 <= -k/4 -24 >= k or, k <= -24 Just work it like an equation, remembering to switch directions whenever multiplying by a negative value.
*January 26, 2015*

**math**

since a square of side 10/√2 has half the area, each side needs to be shortened by at least by 10 - 10/√2
*January 26, 2015*

**math**

http://www.wolframalpha.com/input/?i=-16t^2+%2B+42t+%2B+3.75+%3E%3D+22
*January 26, 2015*

**algebra. help!**

No idea. I added the rows, but my results do not match any of the choices. Not even close. I'm missing something here.
*January 26, 2015*

**algebra. help!**

are these supposed to be vectors or matrices? In either case, I assume we are to add corresponding components. 3/4 - 5/3 = -11/12 2/3 + 4/2 = 8/3 So, I guess I'm not getting what it is you want.
*January 26, 2015*

**math**

Looks a lot like my work. But we'll let that go... Surely you can now solve the equation! If two numbers have a product of zero, one or the other must be zero. So, either x-12 = 0 --> x=12 x+1 = 0 --> x = -1 Clearly the solution is x=12. That is, the firework will ...
*January 26, 2015*

**pre-algebra**

clearly y cannot be 8.3. Multiply that by 6 and you get 50 6y+5 = 10 6y = 5 y = 5/6 y = 0.8333 4 = z/12-17 z/12 = 21 z = 21*12 = 252
*January 26, 2015*

**math**

first, do a google on special characters to find the ±√ symbols, which you can then copy and paste. All those words are just too ugly for words! You have y=2x^2-2x+1 and y=3x-5, so set them equal: 2x^2-2x+1 = 3x-5 2x^2-5x+6 = 0 The discriminant (b^2-4ac) is ...
*January 26, 2015*

**math**

use >= for greater than or equal <= for less than or equal
*January 26, 2015*

**Science**

h doesn't matter KE = 1/2 mv^2 = (1/2)(0.02)(2) = 0.02J all those words are just noise. v is 2 m/s, much easier to read.
*January 26, 2015*

**math**

if you mean sec^2 x - 1 = 3 then we can proceed to sec^2 x = 4 sec x = 2 or -2 sec pi/3 = 2, so using that as a reference angle in each quadrant, x = pi/3 or 2pi/3 or 4pi/3 or 5pi/3
*January 26, 2015*

**Math**

check the table. As x increases by 2, y increases by 7. So, the slope of the line is 7/2, making the only possible choices A and B. y = 7/2 x is 7 when x=2, but the table has y=8. So, we have to adjust things and get y = 7/2 x + 1 (A) If you check the other values, you will ...
*January 26, 2015*

**Math**

I can't quite parse your language. Do you mean y = √(bx)^-2 or some other arrangement? If that is what you meant, then b=0 will make the domain an empty set.
*January 26, 2015*

**Math**

Hmmm. y = 1 - 1/(2√(3x-6)) I get a horizontal asymptote at y=1, with the range (-∞,1)
*January 26, 2015*

**physics**

the height is y = 15t - 4.9t^2 So, solve for its vertex (max height), and t when y=0 and y=4 to answer the other questions.
*January 26, 2015*

**Math**

3.50 * 1.80 = 6.30
*January 26, 2015*

**math**

the slope of the line Ax+By+C=0 is -A/B so, check the pairs. #1 -3/4 vs -6/8 same, so parallel or identical since multiplying the 1st by 2 gives the 2nd exactly, they are in fact the same line. do the others in like wise.
*January 26, 2015*

**Math**

5(-11/5)^2 - 3(-11/5) + 9 5(121/25) + 33/5 + 9 605/25 + 165/25 + 225/25 995/25
*January 26, 2015*

**Chemistry**

Looks ok to me.
*January 26, 2015*

**Science**

#2B fission does not absorb light or heat. Gravity made the planets condense. The others look ok.
*January 26, 2015*

**maths**

write what you are given: p = h+7 4p+2h = 58 Now it's a cinch, right?
*January 26, 2015*

**Physics**

this is just practice converting to and from polar to rectangular coordinates. Convert each putt, add them up, and convert back: 3.32 @ N = <0,3.32> 1.63 @ SE = <1.153,-1.153> 0.703 @ SW = <-0.497,-0.497> add them up and you have <0.656,1.670> and that ...
*January 26, 2015*

**physical sciences**

if they act in the same direction, they add up to 12N if the act exactly opposite, the subtract to 2N in the direction of the original 7N force.
*January 26, 2015*

**Math**

#1 ok #2 ok #3 Almost x^2-9 = (x+3)(x-3) divide by (x-3) and you are left with (x+3) #4 ok
*January 26, 2015*

**physics**

well, the height y = 1000 - 10.0t - 4.9t^2 just find t when y=0.
*January 26, 2015*

**math**

what's the trouble? You have two functions and want to know where they are equal. -x^2+15x = 4x-12 x^2-11x-12 = 0 (x-12)(x+1) = 0 I think you can take it from there, right?
*January 26, 2015*

**Denumerator? :-)**

I know what an enumerator does, but I'm not sure what a denumerator does . . . eliminate stuff?
*January 26, 2015*

**math**

we know that A+B+C=180°, and we see that A = 36.86° B = 67.38° So, C=75.76° Now you can use the law of sines to find the other two sides.
*January 26, 2015*

**Math**

4012/44 = 91.1 4982/44 = 113.2 So we know that the multiple is between 92 and 113 Since 4*3=12 and 4*8=32 are the only multiples that end in 2, we know that the other number is one of 93 98 103 108 113 44*93 = 4092 44*98 = 4312 44*103 = 4532 44*108 = 4752 44*113 = 4972 So, ...
*January 26, 2015*

**College Algebra**

Hmm. It's clear that x=0 works, but is there anything else? (2^x+1)(3^x+1) = 2^x + 3^x + 6^x + 1 so, (2^x+1)(3^x+1) +1-4^x + 1-9^x = 4 (1+2^x)(1+3^x) + (1+2^x)(1-2^x) + (1+3^x)(1-3^x) = 4 (1+2^x)(1+3^x+1-2^x) + (1+3^x)(1-3^x) = 4 I don't see anything dropping out. If ...
*January 26, 2015*

**Mathematics**

a line has constant gradient. A curve does not. Also, the gradient of a curve might even be discontinuous.
*January 26, 2015*

**stats**

you can play around with Z table stuff here: http://davidmlane.com/hyperstat/z_table.html
*January 26, 2015*

**Statistics**

try playing around here: http://davidmlane.com/hyperstat/z_table.html
*January 26, 2015*

**Calc**

This is also easy to see since cos(1/x) never exceeds 1. So, e^cos(1/x) never exceeds e. So, |e^cos(1/x)| <= e x e^cos(1/x) <= e*x -> 0 as x->0
*January 25, 2015*

**Math**

What you should do is read the problem carefully. It states that there are more than 50 marbles in the bag. So, what is the smallest multiple of 7 that is greater than 50? Must be 56.
*January 25, 2015*

**phisics**

mass * distance must be equal, so 18x = 36*0.45
*January 25, 2015*

**Calculus**

Since |(sin 1/x)| <= 1 |e^(sin 1/x)| <= e so x e^sin(1/x) <= x * e -> 0 as x->0
*January 25, 2015*

**Physics (Classical)**

using vectors, John's velocity is <0,-6.7> Mary's velocity is <-6.43,-9.53> Mary's velocity with respect to John is the difference between their velocities: <-6.43,-9.53> - <0,-6.7> = <-6.43,-2.83> Now just get the magnitude and ...
*January 25, 2015*

**Math**

840 * 2/3 = 560 840-560 = 280 half of 280 = 140 560+140 = 700
*January 25, 2015*

**Algebra I**

it lands when the height (y) is zero. So, just solve for x in -0.02x2 + 2.3x + 6 = 0 just use the quadratic formula.
*January 25, 2015*

**math**

(1 - 1/4 - 1/2(3/4))x = 800
*January 25, 2015*

**algebra**

you are correct if you meant [2(-2)-4(-3)]/(5-8)
*January 25, 2015*

**Physics**

First unify the units. 55.4 mi/hr = 24.8 m/s you know that the distance is given by s = 24.8t - 1/2 at^2 So, to stop in exactly 116 meters, we need 24.8t - 1/2 at^2 = 116 Now, we know that during that time, the speed reduces from 24.8 m/s to zero, so a = 24.8/t m/s^2 t = 24.8/...
*January 25, 2015*

**Math**

li spent $840 on vacation, She spent 2/3 of the amount on a train ticket and 1/2 of the remaining amount on food. How much did she spend on ticket and food altogether?
*January 25, 2015*

**Math**

sam travelled 1/4 of a journey by bus. he jogged 1/2 of the remaining distance and walked the rest of the way. If he walked 800 feet, what was the total distance he traveled?
*January 25, 2015*

**Algebra 2 Applications**

If you want to include the travel time of the sound, you have to look up the speed of sound in air. Let's say that is 343.2 m/s. So now, if the falling time is t, then we have 4.9t^2 = 343.2(3-t) t = 2.88 So, the balloon fell for only 2.88 seconds, making the distance 4.9*...
*January 25, 2015*

**physics**

well, you know that the height is y = 45t - 4.9t^2 Now just use that parabola to answer the questions.
*January 25, 2015*

**math**

If the four got amounts a,b,c,d respectively, then a = 2b b = 3c c = d/2 a+b+c+d = 840 a-d = 280
*January 25, 2015*

**math**

1day/L * 1000L/kL * 1year/365day = 1000/365 years.
*January 25, 2015*

**math**

since the denominator is not zero at t=2, just plug in t=2 to get the limit. The function is continuous at t=2. (2^44-9)/9
*January 25, 2015*

**Algebra**

I assume you mean 1/(1-2x) + 6x/(1+2x) = 3 the common denominator is (1-2x)(1+2x), so we get (x ≠ ±1/2) (1+2x) + 6x(1-2x) = (1-2x)(1+2x) 8x^2 - 8x = 0 8x(x-8) = 0 I expect you can take it from there, right?
*January 25, 2015*

**Calculus**

as you figured, the time t is t = (300-x)/(160) + √(800^2 + x^2)/70 dt/dx = 160x - 70√(800^2 + x^2) ----------------------------- 70*160√(800^2 + x^2) dt/dx=0 when 160x = 70√(800^2 + x^2) 25600x^2 = 56000000 + 4900x^2 x = 389.23 Hmm. Not what I had ...
*January 25, 2015*

**Maths**

x(t) = 0 if the object is at rest where it started. Don't you think you need to specify a bit more abut the situation?
*January 25, 2015*

**maths**

I think you have left something out. An = An-1 + 96
*January 25, 2015*

**math**

No, it would be y >= x+3 You have to include the number of female birds. There are at least three more males than that.
*January 25, 2015*

**math**

these are just simple polynomial addition, subtraction and multiplication. (f*g)(x) = f(x)*g(x) = (x+4)(3x+2) and the same for the other operators.
*January 25, 2015*

**Math**

tan π/4 = 1, so 4x = π/4 (1/√2,1/√2) period = π/4 x = π/16 + n(π/4) for the second, you just have cscx =0 or secx = 2 and proceed as above
*January 25, 2015*

**maths**

you know that the difference between terms is constant, so (4x+5)-(x) = (10x-5)-(4x+5) now just solve for x.
*January 25, 2015*

**math function2**

A) 18-6 = 12 seconds B) no idea of the radius. You give no indication of the height of the wheel, or where the platform is in relation to the axle. C) no can do. All we know is that h(t) = A + Bsin(pi/6 t + C)
*January 25, 2015*

**Algebra Ques23**

I can't imagine the math class where you have exercises in trigonometry, algebra, calculus, and such a simple question as this. Also, I get tired of your homework dumps with no effort on your part.
*January 25, 2015*

**Trig 4**

no. They are just ratios in a right triangle. Review your text, where I'm sure it is explained clearly. Google is your friend.
*January 25, 2015*

**physics**

clearly, the resultant is max if they act in exactly the same direction. So, what do you think?
*January 25, 2015*

**Mathematics (Vector) (ENGG1410)**

they are just ellipses parallel to the xy plane.
*January 25, 2015*

**College Trigonometry**

You can also read the excellent article on "trajectory" in wikipedia, where these equations are derived.
*January 25, 2015*

**Math**

you don't need to sum the series. It doubles 8 times in 24 hours, so the population is 40*2^8. You'd only need the sum if a new population, double the old one, was added every 3 hours. The runner problem is just the same. Every day you multiply the distance by 1.1 So, ...
*January 24, 2015*

**math**

just use the quadratic formula.
*January 24, 2015*

**maths**

Think of the hexagon as six equilateral triangles. The altitude of each triangle is 24. So, the side of each triangle (equal to the sides of the hexagon are) 48/√3
*January 24, 2015*

**Trigonometry**

No idea which angle sigma is, but I'll assume it's C, since otherwise you'd probably have used alpha. sinA/a = sinC/c so, sinA/28.1 = .4617/52.8 sinA = .2457 A = 14.2° or 165.3° Now you can find B and b.
*January 24, 2015*

**Algebra Rearrangement**

it's a quadratic in x: rx^2-tx-h = 0 use the quadratic formula to find the value(s) of x.
*January 24, 2015*

**math**

(c ¢)/(1 lb) * (a oz) * (1 lb)/(16 oz) = ac/16 ¢
*January 24, 2015*

**math**

1/(9+3+1)
*January 24, 2015*

**Geometry**

Pick up a real cube and draw a 3x3 grid one each face. Fill in the grids on 3 faces with R and 3 with B. The very center cubelet has no painted faces. Now count the others and total up the various color combinations. Make sure that it makes no difference how the two colors are...
*January 24, 2015*

**Pre Calculus**

Review the idea of reference angles, which are always in QI. sin 0.0135 = 0.0135 That is the angle in QI. But sin is negative in QIII and QIV. So we have π+0.0135 and 2π-0.0135 cot 0.351 = 2.731 But, cot is negative in QII and QIV, so we have π-0.351 and 2π...
*January 24, 2015*

**Math**

It appears that the chopped piece fell 4 feet. So, the tree was 4+7=11 feet tall.
*January 24, 2015*

**physics**

the height of the falling stone is 6.82-8.8t-4.9t^2 the height of the stone thrown upward is 8.8t - 4.9t^2 So, when do they meet? At t=0.3875 Now plug that into either function to get the height at that time. http://www.wolframalpha.com/input/?i=solve+6.82-8.8t-4.9t^2++%3D++8....
*January 24, 2015*

**physical**

√((300+400/√2)^2+(400/√2)^2)
*January 24, 2015*

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