Posts by Steve
Total # Posts: 50,491
you are told that 1 mole of gas fills 22.4 Liters so, how many moles of H2 were produced?
well, 7/10 the mass of the wood is submerged, so ...
10/.092 = 108.69 so, ...
There are 36 possible outcomes. How many of these are even and not 2? Well, of the 36 outcomes, half are even and half are odd. But you want even?2, so throw out 1,1. That leaves just 17/36 Just to be sure, list all possible successes: 13 15 22 24 26 31 33 35 42 44 46 51 53 55...
(12x+6)(3x^2+3x+5)^7 dx = 2(3x^2+3x+5)^7 (6x+3) dx Let u = 3x^2+3x+5 du = 6x+3 dx so, now your integrand is just 2u^7 du not so hard now, eh?
the amplitude is (87-73)/2 = 7 the center line is (87+73)/2 = 80 y = 7sin(k(x-h))+80 since y(8) = 0, y = 7sin(k(x-8))+80 since the period is 24 hours, 2?/k=24, so k = ?/12 y = 7sin(?/12 (x-8))+80 so, when is y=77?
dr/dt = 3 r = 3t + c since r(0) = 0, r = 3t a = ?r^2 da/dt = 2?r dr/dt ...
Math, Algebra, Graphing Systems of Linear Equation
I'm confused by your impatience and reposting the same problem...
Math, Algebra, Graphing Systems of Linear Equation
try playing around here, where I have plotted the first pair... http://www.wolframalpha.com/input/?i=plot+3x%2B2y%3D-6,+x-4y%3D-16 since your lines have different slopes, the have to intersect. You must have plotted them wrong. 3x+2y = -6 x-4y = -16 2y = -3x-6 -4y = -x-16 You ...
6th Grade Math (Please Help It's Getting Late)
$60 is the discount, not the price.
starting when? 6 degrees each minute, however.
well, KE = 1/2 mv^2
each octave up doubles the frequency
sum=0 max=0 min=9999 for i=1,12 read amount month[i] = amount if amount < min then min = amount if amount > max then max = amount sum += amount end for avg = sum/12
looks good to me.
I'd say the one which is not showing two sets of data.
just add up the KE before and after the collision.
As long as we're dividing by zero, what about 0/0? Why is it undefined? Suppose there is a value x such that 0/0 = x Then, multiplying by zero, we get 0 = 0*x But that is true for any value of x. So there is no particular value we can say is equal to 0/0.
Please help with MATH
why not post your solution to the first part, and we can see why this change is important?
32 * 26? in * 1ft/12in = 217.817 ft
correct. a person can determine the miles walked. After that, the calories follow.
.03 * 27700
there are only 2 colors. 3 socks must have two of the same color...
Math - Calculus
Actually, the shape does not matter for this question because it asked about the rate of flow through the channel. I suspect there were other parts where we'd have to work with the volume or depth in the bay, but not here.
Math - Calculus
just find the derivative dd/dt the shape of the bay does not matter for this question.
just divide and you get x+4 + 9/(x-2) So, as x gets huge, the 9/(x-2) vanishes, and the graph approaches the line y = x+4
well, x^2-4 has a minimum at x=0, so e^(x^2-4) will as well. since x^2-4 has an absolute max at x=±2, so does e^(x^2-4) But, as long as this is calculus, dh/dx = 2x e^(x^2-4) dh/dx=0 at x=0 (minimum)
Since F=ma, a = 8x/m. So, we have a(x) = -8/m x v(x) = -4/m x^2 + c1 s(x) = -4/3 x^3 + c1*x + c2 v(0) = 0 and s(0) = 10, so s(x) = -4/3 x^3 + 10 For the damping, just work with v(x) = -4/m x^2 + 8v and follow through to get s(x)
Since the y-axis is also the axis of symmetry for the curves, we can just take one side and revolve it. This will be easiest using shells of thickness dx: v = ?[0,2] 2?rh dx where r=x and h=(8-x^2)-x^2=8-2x^2 v = ?[0,2] 2?x(8-2x^2) dx = 16?
x = 3+4cos? y = 2+4sin? since cos^2? + sin^2? = 1, (x-3)^2 + (y-2)^2 = 4^2
no way to tell all we know is that 15 students got above 74% and 15 got below 74%
x grows by 2 the slope is 2, so y grows by 4. so, y=2+4=6 or, more formally, (y-2)/(3-1) = 2
each term is calculated using the previous term, not the next one!
Calculus - Fundamental thm of Calc
that would be ((1/4)(x^2)^2?1)^15 * 2x = 2x(x^4/4 - 1)^15
Calculus - Related Rates
Let the distance on the road be x. Then the distance z to the house is z^2 = x^2+25 z dz/dt = x dx/dt z(1) = ?26 ?26 dz/dt = 1 * 65 ...
google hole in sphere. You will find many excellent discussions.
well, you have a base perimeter of 30. So, the base of each triangular lateral face is 30/4 = 7.5 Now you can see what the side edges of the pyramid are, and there are four of them. let 'er rip...
reimburses? Did the doctor pay the patient something?
L = km/h^2 So, Lh^2/m = k is constant You want L such that L*50^2 = 40*h^2/175 If you will supply the original height, then you can solve for L.
I don't see any graph ...
#1 The line of symmetry of y=x^2 is the y-axis (x=0). Similarly, for a translated parabola y=a(x-h)^2 + k the axis of symmetry is the line x=h. So, for y = -2x^2+3 the axis is x=0 #2 same for |x|. So, for y = 1/3 |x| - 2 the axis is x=0 #3 Huh? This stumps you? P(4,-4)-->(-...
I suspect there was meant to be a question in there somewhere, but I couldn't see it ...
not mixed numbers. As a fraction, 87.3/8.73 = 10*8.73/8.73 = 10/1 = 10 In case you wanted individual fractions, 87.3 = 873/10 8.73 = 873/100
I think Natavia is right. If P = 1/26 that is the theoretical probability. No mention is made of actually performing the experiment.
recall that alternate interior angles between parallel lines are congruent. Draw a line through one vertex parallel to the opposite base. the rest is easy.
4 * 1/4 = 1
6 * 2/3 = 4
4/12 = 2/6 = 1/3
(a) 12(1/2)^(t/5700) = 10 t = 1499.3 years (b) 12(1/2)^(1599.3/5700) = 9.879 grams
calculus please help!!
The region is a semi-circle of radius 6, so the area ranges from 0 to 18? The integral is the area moving from the left side to some point x in [-6,6].
set this up as a geometric series and then just apply the sum formula. a = 2 r = 0.9 allow for round trips up and down
to start out, there are 13 diamonds in 52 cards. As you draw the cards, the probabilities change, due to the makeup of the remaining cards. The result is 13/52 * 12/51 * 11/50 * 10/49 = (13*12*11*10)/(52*51*50*49) = 13P4/52P4
A,C,D are true. The Intermediate Value theorem says that there is a zero in (-2,1) and (1,4) Rolle's Theorem (or MVT) says that f'(x)=0 somewhere in (-2,4) Mean Value Theorem says D is true
I must say, these problems of yours are some cumbersome. I'm not sure they are teaching much about factoring, since most of them only have a single monomial common factor. Like this one: 48x^3 - 128x^2 -56x -16 8(6x^3-16x^2-7x-2)
392n^4 + 168n^3 + 168n^2 +72n 8n(49n^3+21n^2 + 21n+9) grouping gives 8n(7n^2(7n+3)+3(7n+3)) 8n(7n+3)(7n^2+3)
5x(16x^3-12x^2-12x-9) 5x(2x-3)(8x^2+6x+3) the discriminant of the quadratic is negative, so it has no real factors.
The x^2 is easy: 195x^5 + 168x^4 - 28x^3 - 24x^2 x^2(195x^3+168x^2-28x-24) Now things get tough. If there are any rational roots of the form p/q, then we know that p divides 24 q divides 195 Some time and effort should convince you that there are no other rational roots, so no...
Maths ( Higher Level) Simultaneous Equations.
the method is just to write the words as math: mother is x years old, her son is y years old and the sum of theirs ages together is 58 x+y = 58 Five years ago, the mother was five times as old as the son (x-5) = 5(y-5) Now it's easy! x+y=58 x-5y = -20 subtract and you get ...
algebra 2, check my answer plzzzzzz
x = 5y^3 x/5 = y^3 y = (x/5)^(1/3) Or, if you insist on rational denominators, y = (25x)^(1/3)/5 your notation would seem to indicate 3?(25x)/5 rather than cubrt(25x)/5 = ∛(25x)/5
well 45/3 = 15 = one-third of the bag. So, ...
well, each foot of rope has 3 pieces, right ? 1 foot = 3/3 So, how many in 8 feet?
If b is breaths, then 10^9 b * 1min/16b * 1day/1440min * 1yr/365day = 118.9 years This makes sense, since 1 billion seconds is about 30 years.
Draw the angle. It should be clear that y = -5 x = 2 r = ?29 Now just recall that sin? = y/r cos? = x/r tan? = y/x now let 'er rip
Note that ?STP is similar to ?RTS and angle SRT = angle TPQ (alternate interior angles)
dy/dt = k/y y dy = k dt 1/2 y^2 = kt + c y^2 = 2kt + c y = ?(2kt+c) E does not work, as you can easily see: y = ?(2kt)+4 dy/dt = 2k/(2?(2kt)) = k/?(2kt) but that is not k/y = k/(?(2kt)+4)
just plug and chug. The surface can be thought of as a stack of thin rings. A = ?2?r ds where r=y and ds=?(1+y'^2) dx so, y' = (9x^4-4)/(12x^2) A = 2??[1/2,1] (x^3/4+1/(3x))*((9x^4+4)/(12x^2)) dx = 1981?/3072
Calculus (trig derivatives)
Draw a diagram. It is clear that when the distance of the beam from the point P on shore nearest the lighthouse is x, tan? = x/2 sec^2? d?/dt = 1/2 dx/dt when x=4, we have (1+(4/2)^2)(2?/20) = 1/2 dx/dt dx/dt = ? mi/s
Since the bisector meets BC at a 45° angle, CB=PB = 15 so AP=25-15=10
on each trip, walk = 1/3 bus = 2 3/4 - 1/3 = 2 5/12
the hexagon has an apothem a=9. so, its sides are s=6?3 Now, you know how to find the area of a hexagon of side s. The area A of the pyramid is just A=6(sa/2) The volume is 1/3 (area of hexagon)*42
Let Ø = angle to bottom of picture ? = angle subtended by the picture x = distance from wall to observer tanØ = 4/x tan(?+Ø) = 9/x so (tan?+tanØ)/(1-tan?tanØ) = 9/x (tan?+(4/x))/(1-(4/x)tan?) = 9/x see what you can do with that. or, if y=...
g'(x) = ?((x^2)^3+2) * 2x now just plug in x=2
Alg II COT
cot ?/6 = ?3
Alg II COT
google radicals and examples
there are lots of sort routines you can find online. So, this will accept an arbitrary number of names: n=0 name="x" while name ? "" read name if name?"" then names[n++] = name end while snames = sort names,n while n>0 print names[n--]
(4cosx+1)(2cosx+1) = 0 now it's a cinch...
There are 11P4 ways to pick the pained boats.
well, all the 400's and all the 900's and all the 40's & 90's of the other 8 hundreds and all the other 8 numbers ending in 9 for the other 8 hundreds
a set of n elements has 2^n-1 non-empty subsets
The way you have written it is incorrect. It should be 4tanx(1-tan^2(x)) ----------------------- (1+tan^2(x))^2 = 4tanx/(1+tanx^2) * (1-tanx^2)/(1+tanx^2) = [4sinx/cosx * secx^2][(1-tanx^2)/(1+tanx^2)] = (4sinx cosx)(1-tanx^2)/secx^2 = 2sin2x (cosx^2-sinx^2) = 2sin2x cos2x = ...
take sin of both sides and use your sum and double-angle formulas to get a polynomial in x sin(2arcsin(x/?6)+arcsin(4x)) = 1 x = ?39 - 6 see http://www.wolframalpha.com/input/?i=sin(2arcsin(x%2F%E2%88%9A6)%2Barcsin(4x))+%3D+1
well, 22 tens is 220 ...
looks ok to me, aside from using "square of" to mean "square root of"
use a common denominator. Then you have 12/28 + 7/28 not so hard now, eh?
their areas are in the ratio 2:3:4
wrong in so many ways. First, 1.00 is 100% .609 = 60.9% so, 2.608 = 260.9% But you read the question wrong. You know that 2 is 50% of 4, right? So, you divide 2/4 = 0.5 = 50% But you divided 321 by 123. Surely you could see that 2.6% is a totally unreasonable answer. Actually...
380 They have no common factors LCM(x,y) = xy/GCD(x,y)
I guess he is then lost. Or, try the law of cosines.
A. usingsymmetry, the area is just ?[0,?/4] 2cosx - secx dx = ?2 - 2tanh-1 ?/8 Using discs of thickness dx for the volume, v = 2?[0,?/4] ?(R^2-r^2) dx where R=2cosx and r=secx v = 2?[0,?/4] ?((2cosx)^2-(secx)^2) dx = ?^2 Using shells of thickness dy, we have to split the ...
sides have shrunk by ?4 = 2
well, just add up the numbers!
(8/6) * 48 = 64
well, the sum of all 9 angles is 7*180 = 1260 (1260-462)/6 = ?