Tuesday

March 3, 2015

March 3, 2015

Total # Posts: 10

**Chemistry PLEASE HELP:(**

I really need someone to explain this stoichiometry problem. Directions: Outline how to determine the limiting agent. Determine the excess reactant and how much is left over. Determine the amount of each of the products produced. CaSO4 + AuF3 = CaF2 + Au2(SO4)3 Start with 15 ...
*January 11, 2013*

**Someone PLEASE HELP! (Chemistry)**

Use the following problem to: Outline how to determine the limiting agent. Determine the excess reactant and how much is left over. Determine the amount of each of the products produced. CaSO4 + AuF3 = CaF2 + Au2(SO4)3 Start with 15 grams of each reactant.
*January 9, 2013*

**Math**

Solve each inequality by using algebra. 8. x 2 + 10x + 1 ≥ 12 9. x 2 + 13x + 45 < 5 10. -2x 2 + 3x + 12 > 10 11. Business A consultant advises the owners of a beauty salon that their profit p each month can be modeled by p(x) = -50x 2 + 3500x - 2500, where x is the...
*January 7, 2013*

**chemistry**

Suppose that you have an unlimited supply of copper 2 chloride to react with iron. How many moles if copper would be produced by 34.0 grams of iron with the copper 2 chloride solution
*October 29, 2012*

**chemistry**

Suppose that you have an unlimited supply of copper 2 chloride to react with iron. How many moles if copper would be produced by 34.0 grams of iron with the copper 2 chloride solution
*October 29, 2012*

**math**

the problem is -9x+1=-80. At the end I cant figure out if it is a negative or positive?
*March 21, 2012*

**Pre-Algebra**

-My tens and units digits are consecutive integers whose product is 2/3 of my hundreds digit. -My units digit is 1/3 of my hundreds digit. -The sum of my digits id equal to the sum of the first five counting numbers. What year am I?
*April 27, 2011*

**science**

What is something in an experiment thst can change?
*October 19, 2010*

**math**

what does trigonometry mean?
*March 3, 2008*

**English**

yea go ahead, but i will prolly like it... im tellin you now!
*March 2, 2008*

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