Thursday

August 25, 2016
Total # Posts: 1,218

**Physics**

the average velocity (Va) during acceleration is __ 3000 m / (3.8 * 60) sec the final velocity (Vf) is related to the initial velocity (Vi) by: Vf = (2 * Va) - Vi
*September 25, 2012*

**statistics**

there are 10C3 ways of drawing 3 chips there are 7C3 ways of drawing 3 red chips there is one way to draw 3 blue chips p = 1 - [(7C3 + 1) / 10C3]
*September 25, 2012*

**math**

(8 * 6) + (½ * 5 * 4)
*September 25, 2012*

**math**

-8bc^4
*September 25, 2012*

**Precalc**

you seem to be finding the axis of symmetry okay when you plugged in to find the vertex in #1, there is an error (should be 2,-4) __ this also affects the range completing the square should be: f(x) = (x - 2)^2 - 4 (x - 2)^2 = x^2 - 4x + 4 so you need to subtract out the extra...
*September 25, 2012*

**physics**

gravity also opposes the motion with a force of __ g * 297 * sin(25.9º) sum the forces; then find the acceleration with __ f = m a
*September 25, 2012*

**physics**

h = -.5 g t^2 + 2.6 t + 1.3 the max height occurs at the value of t that lies on the axis of symmetry (t = -b / 2a) __ t = -2.6 / -9.8 find t and substitute back to find the max height
*September 25, 2012*

**math**

Py = Pz = (2 * 5) + ( 2 * 3) write the equation for the perimeter of y using the length and width (2 * Ly) + (2 * Wy) = Py = Pz write the equation for the area of y using the length and width Ly * Wy = Ay = Py = Pz you now have two equations with two unknowns that you can ...
*September 25, 2012*

**algebra**

subtract the two equations to ELIMINATE the x-term -5y = 9 __ y = -9/5 substitute back to find x 4x + 9/5 = 5
*September 25, 2012*

**science**

gas equation temperatures are in Kelvin (absolute) v = (100 cm^3)[(1 atm) / (2 atm)](263º / 293º)
*September 25, 2012*

**physics**

it appears that the mass of the block is not involved in your final calculation (it cancels out in the second line) your work seems to be correct
*September 25, 2012*

**Physics**

you seem to have forgotten gravity add g to your acceleration number and you should be okay
*September 25, 2012*

**physics**

the acceleration is the change in velocity over time in this case __ (12.0 - 7) / 2.0
*September 25, 2012*

**Math**

Yoko's speed is 9/10 of Yolanda's in the time it takes Yolanda to run 110 yd, Yoko runs 99 yd so Yolanda wins the second race by a yard for a tie, the 100 yd that Yoko runs must be 9/10 of the distance that Yolanda runs .9 x = 100 __ x = 1000/9 Yoko runs 100 yd (900/9...
*September 24, 2012*

**math 176**

(x - 3y + 2z)(x - 3y - 2z)
*September 24, 2012*

**MaTh**

the area of the base is a factor of 42 with a perimeter of 18, the possible block arrangements are __ 8 X 1 __ area 8 7 X 2 __ area 14 6 X 3 __ area 18 5 X 4 __ area 20 14 is the only factor of 42, so the height must be 3
*September 24, 2012*

**Pre-Ap Physics**

the initial vertical velocity is __ (2650 m/s) * cos(41.9º) the time of flight is the initial vertical velocity divided by the gravitational acceleration __ 2 * [(2650 m/s) * sin(41.9º)] / (9.8 m/s^2) the horizontal velocity is __ (2.65 km/s) * cos(41.9º) the ...
*September 24, 2012*

**Science chemistry**

if n is the number of half-lives (1/2)^n * 1.000 = 0.121 (1/2)^n = 0.121/1.000 n [log(1/2)] = log(0.121) n = [log(0.121)] / [log(1/2)] half life = [1h17m] / n
*September 24, 2012*

**chem**

both compounds have one Cu, so the moles should be the same to find grams, multiply by the molar mass of CuO
*September 24, 2012*

**chemistry**

density is measured in g/cm^3 d = 19.07 / (3.1 * 1.9 * 4.6)
*September 24, 2012*

**Physics(Please help, thank you)**

the force that was needed to balance out F1 and F2 is equal in magnitude to the resultant, but opposite in direction so the resultant would be 280g at 77º since F1 and F2 have equal magnitudes and are 90º apart; the expected resultant would be 283g at 75º __ so ...
*September 24, 2012*

**physics**

momentum is conserved the mass of the clay, times its velocity; is equal to the mass of the clay+block, times its velocity 0.5 * v = (6 + 0.5) * 3
*September 23, 2012*

**Physics**

at 4s, the speed is 24 + 4g at 5s, the speed is 24 + 5g so the average speed over the interval (for one second) is 24 + 4.5g the distance is the speed times the time
*September 23, 2012*

**Physics**

h = .5 * g * t^2 34 = .5 * 9.8 * t^2
*September 23, 2012*

**physics**

constant velocity means no acceleration, which means zero net force so the third force is equal in magnitude to the resultant of the given forces; but opposite in direction the magnitude of the resultant of the given forces is __ sqrt(61.9^2 + 52.0^2) the tangent of the angle ...
*September 23, 2012*

**physics**

the work done on the car is reflected by the change in kinetic energy w = [.5 * 2000 * 20^2] - [.5 * 2000 * 10^2] the units are joules
*September 21, 2012*

**Science**

the kinetic energy at the bottom is the kinetic energy at the top plus the gravitational potential across the circle .5 m (Vb)^2 = [.5 m (Vt)^2] + [m g h] dividing by .5 m (Vb)^2 = (Vt)^2 + 2 g h v^2 = 3^2 + [2 * 9.8 * (2 * .8)]
*September 21, 2012*

**precal help**

n = d - 4 [(d - 4) / d] + [d / (d - 4)] = 5/2 multiplying by [2 * d * (d - 4)] [2 (d - 4)^2] + (2 d^2) = 5 d (d - 4) 2d^2 - 16d + 32 + 2d^2 = 5d^2 - 20d 0 = d^2 - 4d - 32 factoring __ 0 = (d - 8)(d + 4) 0 = d - 8 __ 8 = d
*September 21, 2012*

**Physics**

this is like a projectile problem turned sideways 0 = -(.5 * 3.7 * t^2) + (30 * t) solve the quadratic for t (you want the non-zero solution)
*September 21, 2012*

**physics**

the crate is sliding, so μk (the kinetic coefficient) is the relevant one the direction of the frictional force is OPPOSITE to the direction of motion the magnitude of the force is: the normal force of the crate on the ramp [m * g * cos(30º)]; multiplied by the ...
*September 20, 2012*

**phsycis**

the force diagram reflects the physical setup the walker is 15.0 m from either end; and is displacing the wire 1.0 m this means that the vertical component of the tension is one-fifteenth the tension in the wire (on BOTH sides) so the force exerted by the walker is 3675/15 * 2...
*September 20, 2012*

**physics**

because it starts from rest and accelerates uniformly, the average velocity is 1/2 the final velocity convert the km/h into m/s [multiply by 1000/3600] the distance is the average velocity, multiplied by the time (8.5 s)
*September 20, 2012*

**Math**

looks good
*September 13, 2012*

**Physics**

horizontal velocity (Vh) is the velocity (V) times the cosine of 20.0º vertical velocity (Vv) is V times the sine of 20.0º or __ Vv = Vh * tan(20.0º) = (104/4.60) * tan(20.0º) = 8.23 when the stone hits the ground, H = 0 0 = (-.5 * g * 4.60^2) + (8.23 * 4....
*September 13, 2012*

**Physics**

a) vertical __ H = (-.5 * g * 2.00^2) + 20.60 __ g is gravitational acceleration horizontal __ d = 19.0 * 2.00 b) H = 0 when the ball hits the ground 0 = (-.5 * g * t^2) + 20.60 solve for t to find the flight time
*September 13, 2012*

**Physics**

the k.e. is equal to the initial k.e. plus the potential energy from the drop k.e. = (.5 * .100 * 5.00^2) + (.100 * g * 10.0) g is gravitational acceleration
*September 13, 2012*

**Math**

a) 128 = (5 * 25) + (3 * 1) = (5 * 5^2) + (0 * 5^1) + (3 * 5^0) in base 5 __ 503 b)128 = 2^7 = (1 * 2^7) + (0 * 2^6) + (0 * 2^5) + (0 * 2^4) + (0 * 2^3) + (0 * 2^2) + (0 * 2^1) + (0 * 2^0) in base 2 __ 10000000 c) 128 = (10 * 12) + (8 * 1) = (10 * 12^1) + (8 * 12^0) in base 12...
*September 13, 2012*

**Physics**

the vertical component of the velocity (Vv)is __ 20.0 * sin(32.0º) the horizontal component (Vh) is __ 20.0 * cos(32.0º) the time (T) to max height is __ Vv / g a) Hmax = (-.5 g T^2) + (Vv * T) + 1.1 b) at Hmax, the ball has no vertical velocity; only horizontal (Vh)
*September 13, 2012*

**PHYSICS**

the time to accelerate to takeoff speed is __ 35 / 3.8 the average speed during acceleration is __ (0 + 35) / 2 the distance (length of runway) is speed times time
*September 13, 2012*

**physics**

0 = (-.5 * g * 5^2) + (10 * 5) + h g is gravitational acceleration
*September 13, 2012*

**physics**

Ha = -.5 g t^2 + 75 Hm = -.5 g t^2 + 30 t 75 = 30 t __ this is when substitute t into either equation to find where
*September 13, 2012*

**Physics**

a) [(2.25 m/s * 4.98 min) + (1.58 m/s * 2.18 min)] * 60 s/min b) (answer from a) / (4.98 min + 2.18 min) / (60 s/min)
*September 13, 2012*

**physics**

5.20 m/s * cos(51.5º)
*September 12, 2012*

**PHYSICS**

the final velocity of the ball must be zero at the edge of the table (after 1.32 m of travel) the average velocity is initial plus final,divided by two v = (2.1 cm/s + 0 cm/s) / 2 = 1.05 cm/s the time to stop the ball is the distance divided by the velocity t = 132 cm / 1.05 ...
*September 12, 2012*

**Physics**

after 1st stage: final velocity __ Vf1 = 26.4 * 3.92 final height __ Hf1 = .5 * 26.4 * 3.92^2 after 2nd stage: final velocity __ Vf2 = (12.3 * 4.48) + Vf1 final height __ Hf2 = (.5 * 12.3 * 4.48^2) + (Vf1 * 4.48) + Hf1 free-fall time is __ 21.2 s - 3.92 s - 4.48 s , or 12.8 H...
*September 12, 2012*

**science**

the angular momentum of the system is constant, so the velocity is inversely proportional the the radius of the orbit Va = Vp * (Rp / Ra)
*September 12, 2012*

**physics**

f = m a __ the force (weight) is directly proportional to the acceleration (g) weight = 685 * (9.8 / 12)
*September 12, 2012*

**physics**

f = m a __ acceleration is inversely proportional to the mass a = 2.9 m/s^2 * (2.7 / 14.9)
*September 12, 2012*

**physics**

time up equals time down (still) initial vertical velocity is __ 1650 * sin(66.1º) flight time is __ 2 * 1650 * sin(66.1º) / 9.8
*September 12, 2012*

**Physics**

ignoring the height of contact time up equals time down h = .5 g t^2 = .5 * 9.8 * 2.1^2
*September 12, 2012*

**math**

1,000,000 = 10^6 = 2^6 * 5^6
*September 12, 2012*

**physics**

average velocity equals initial plus final, divided by two Va = (12 + 24) / 2 = 18 m/s distance equals velocity times time d = 18 * 6.5
*September 12, 2012*

**science**

y / x = tan(-47.5º) y = x * tan(-47.5º)
*September 12, 2012*

**math**

(0 * 2^0) + (1 * 2^1) + (0 * 2^2) + (1 * 2^3) + (0 * 2^4) + (1 * 2^5) 0 + 2 + 0 + 8 + 0 + 32 = 42 (2 * 12^0) + (1 * 12^1) + (9 * 12^2) 2 + 12 + 1296 = 1310
*September 12, 2012*

**10th Grade Math-Algebra 2**

5 * x^3 * 4 * x * y^2 20 x^4 y^2
*September 12, 2012*

**physics**

stone time (T) plus splash time (t) equals watch time minus reaction time T + t = 3.65 - .25 __ t = 3.4 - T d = .5 * g * T^2 __ g = 9.8 m/s^2 also, d = 340 * t __ d = 340(3.4 - T) 4.9 T^2 = 1156 - 340 T 4.9 T^2 + 340 T - 1156 = 0 use quadratic formula to find T, then plug in ...
*September 12, 2012*

**Physics**

average velocity is __ 40.0 m / 9.40 s average equals initial plus final, divided by two 40.0 / 9.40 = (i + 2.35) / 2 __ i = 6.16 acceleration equals final minus initial, divided by time a = (2.35 - 6.160 / 9.40
*September 12, 2012*

**Physics**

average velocity is __ 40.0 m / 9.40 s or __ 4.26
*September 12, 2012*

**Physics**

the height of a freely falling object is: H = .5g*t^2 + Vo*t + Ho Vo is the initial vertical velocity Ho is the initial height (height of building) the height is 0 when the brick hits the ground in 3.3 sec g is -9.8 m/s^2 H = .5gt^2 + [17 * sin(25º)]t + Ho 0 = -4.9(3.3^2...
*September 12, 2012*

**College Physics**

the potential energy at the top of the leap is equal to the (vertical) kinetic energy at the start m * g * h = .5 * m * [v * sin(45º)]^2 the m's cancel (2 * g * h) / [sin(45º)]^2 = v^2 g = 9.8 m/s^2 145 = v^2
*September 12, 2012*

**physics**

H = .5 g t^2 1.7x10^4 = .5 * 3.3 * t^2 1.03x10^4 = t^2 2) multiply the fall time (t) by the acceleration (3.3 m/s^2) to find the final velocity
*September 12, 2012*

**writing equations**

We did not find results for: Please help me do this problem: I need to write an expression for the cost of an ice cream cone and "t' number of toppings. The information is once scoop of ice cream for $3 and each topping is $1.
*September 11, 2012*

**Math**

A cone has a volume of 41 cubic meters. If cut the cone in half, what would be the volume of the cone?
*May 17, 2012*

**algebra 2**

factor 4a cubed+44a squared+120a
*May 2, 2012*

**english**

give me the passage its from or like write the paragraph its used in
*May 1, 2012*

**english**

what is the question?
*May 1, 2012*

**algebra 2**

find the product (2a+1) cubed
*April 27, 2012*

**english**

whats the question
*April 26, 2012*

**english**

i think the whole sentence is infinitive
*April 26, 2012*

**english**

:) By mistake I opened a package addressed to my sister. is the next one and would be infinitive phrase?
*April 26, 2012*

**english**

looking for unusual flowers
*April 26, 2012*

**english**

thank you and i have a few more to do the next one is:We walked along the mountain path looking for unusual flowers. so it would be nominative absolute?
*April 26, 2012*

**english**

yes, and i think if its the whole sentence then its just asking what is the structure of it
*April 26, 2012*

**english**

i think its about the whole thing or like the part that is,then what is the structure of it
*April 26, 2012*

**english**

What grammatical structure is the italicized portion of the sentence? My most valuable coin, one from Spain, is worth more than $100.00.
*April 26, 2012*

**algebra 2**

If a sum of money is deposited in a savings account that is paying x percent annual interest the this sum of money increases by a factor of(1+x) squared after 2 years. multiply this expression. evaluate the polnomial expression found in part A for an annual interest rate of 50...
*April 25, 2012*

**algebra 2**

Multiply (3a+1)cubed
*April 25, 2012*

**Math**

Is this the answer?? I know that the triangle formed is both right and isosceles because There will be a 90 degree angle and two 45 degree angles.
*April 22, 2012*

**Math**

How do I measure
*April 22, 2012*

**Math**

It's a right isosceles triangle
*April 22, 2012*

**Math**

Explain how you know that the triangle formed is BOTH right & isoceles?
*April 22, 2012*

**math**

Use a net to find the length and width of a single sheet of paper that could be used to wrap the entire gift box. l = 6 in w = 4 in h = 2 in
*April 16, 2012*

**calculus**

P2 has a mysterious inner product * for which {x+4, 3x-5} is an orthonormal basis. IS there enough information to tell what is the length of 1? If so, compute it. If not say why not.
*April 13, 2012*

**Math**

1. P5 is an innerproduct space with an inner product. We applied the Gram Schmidt process tot he basis {1,x,x^2,x^3,x^4} and obtained the following as the result {f1,f2,f3,f4,x^4+2}. a. What is the orthogonal complement of P3 in P5 with erspect to this inner product? b. What ...
*April 13, 2012*

**calculus**

P2 has a mysterious inner product * for which {x+4, 3x-5} is an orthonormal basis. IS there enough information to tell what is the length of 1? If so, compute it. If not say why not.
*April 13, 2012*

**math**

18 times 4 times 14
*April 11, 2012*

**algebra**

find volume of the figure. Type in exponential expression. 2 2x 4 3 4x 4x shape is a retangle
*April 4, 2012*

**algebra**

an investor invested a total of 1,600 in 2 mutual funds.One fund earned a 6% profit while the other earned a 2% profit. If the investors profit was $56, how much was invested in each mutual fund. amount invested in mutual fund that earned 6% was___ amount invested in fund that...
*March 30, 2012*

**algebra**

is the answer one solution
*March 30, 2012*

**algebra**

use elimination method to solve. A+6b=14 A+2b=2 does it have (a)one solution (b)Infin. many sol (c)no solution
*March 30, 2012*

**algebra**

not sure what you are saying
*March 30, 2012*

**algebra**

use method of substitution to solve the system of linear equations. 2x-y=3 9x-4y=14 is the solution an ordered pair(,)
*March 30, 2012*

**algebra**

tugboat goes 160 miles upstream in 10 hours. The return trip downstream takes 5 hours. Find the speed of the tugboat without a current and the speed of the current. speed of tugboat is speed of the current is
*March 30, 2012*

**algebra**

method of substitution the perimeter of some traffic sigh must be 126 inches. Also its length is 11 inches longer than its width. Find the dimensions
*March 29, 2012*

**algebra**

use method of substitution to solve the system of linear equation 3x+4y=3/2 y=2x-1
*March 29, 2012*

**healthcare accounting**

what is the entry when we get a gift of $100,000 for cancer research only with the investments earnings also limited to cancer research?
*March 20, 2012*

**Thermo**

Calculate the standard cahnge in enthalpy for the combusation of coal/ Show the balnaced reaction. How does one get the balanced reaction of coal? Coal has many substances that make up its compsistion
*March 18, 2012*

**physics**

you kind of just droped 1/di there. where did it go? I just dont get how you got to: 1/di - 1/2di and then you went from 1/di - 1/2di = 1/2di.....you just droped 1/di. That doesnt make any since.
*March 17, 2012*

**math**

area of triangle with base of 1 3/4 and height of 4/5
*March 9, 2012*