Tuesday
February 28, 2017

# Posts by Scott

Total # Posts: 1,866

physics
I got -29.43m\s but that's not taking air resistance Into consideration.
November 7, 2012

physics
A student moves a box of books down the hall by pulling on a rope attached to the box. The student pulls with a force of 173 N at an angle of 27.5 above the horizontal. The box has a mass of 27 kg, and μk between the box and the floor is 0.2. The acceleration of ...
November 6, 2012

physics
Consider the 57 N weight held by two cables shown below. The left-hand cable is horizon- tal. 57 N 52 a) What is the tension in the cable slanted at an angle of 52? Answer in units of N
November 6, 2012

physics
A 2.67 kg block starts from rest at the top of a 27.6 incline and accelerates uniformly down the incline, moving 2.89 m in 2.45 s. The acceleration of gravity is 9.81 m/s2 . a) What is the magnitude of the accelera- tion of the block? Answer in units of m/s2
November 5, 2012

physics
A 31 kg box slides down a 33.0 ramp with an acceleration of 1.30 m/s2. The acceleration of gravity is 9.81 m/s2 . Find the coefficient of kinetic friction between the box and the ramp.
November 5, 2012

math(please help)
Al + As + B = 124 Al + B = 102 subtracting equations ___ As = 22 Al + As = 86 subtracting equations ___ Al = 64 subtracting equations ___ B = 38
November 4, 2012

Physics
the vertical component of the brick's velocity is 13.9 * sin(27.6º) 0 = (-.5 g 3^2) + [13.9 * sin(27.6) * 3] + (building height)
November 4, 2012

Math
d/dx [cos(x)]^2 = 2 cos(x) * [-sin(x)]
November 4, 2012

Pre- AP Physics
the gravitational force between two objects is the same for both objects
November 4, 2012

Math
a. w = f * d = 150 * 4 = 600 Nm b. 600 / .5 = 1200 Nm
November 3, 2012

physics
A 1.6 kg otter starts from rest at the top of a muddy incline 95.9 cm long and slides down to the bottom in 0.50 s. What net external force acts on the otter along the incline? Answer in units of N
November 3, 2012

physics
A shopper in a supermarket pushes a loaded 32 kg cart with a horizontal force of 10 N. The acceleration of gravity is 9.81 m/s2 . a) Disregarding friction, how far will the cart move in 3.3 s, starting from rest?
November 3, 2012

physics
A freight train has a mass of 3.1 × 107 kg. If the locomotive can exert a constant pull of 4.9 × 105 N, how long would it take to increase the speed of the train from rest to 71.9 km/h? Disregard friction.
November 3, 2012

physics
f = m * a ___ a = f / m a = .052 N / 474 kg v = a * t ___ t = v / a t = 880 m/s / (.052 N / 474 kg) t will be in sec__convert to days
October 30, 2012

5th grade math word problems
You need to form two equations. Since Frank's ticket is 1/2 that of his wife's, I wrote the first equation as F = 1/2W or W = 2F. Then I wrote my second equation as wife's ticket plus Frank's ticket are equal to \$294. In other words W + F = \$294. Then I ...
October 24, 2012

physics
Salmon often jump waterfalls to reach their breeding grounds. Starting 1.77 m from a waterfall 0.253 m in height, at what minimum speed must a salmon jumping at an angle of 44.8 leave the water to continue upstream? The acceleration due to gravity is 9.81 m/s2 . Answer in...
October 16, 2012

physics
A basketball player 1.9 m tall wants to make a basket from a distance of 7.8 m. The hoop is at a height of 3.05 m.If he shoots the ball (from a height of 1.9 m) at a 23.5 angle, at what initial speed must he shoot the basketball so that it goes through the hoop without ...
October 16, 2012

math
if an airplane is traveling at 245 meters per second, how many kilometers per second does it travel?
October 10, 2012

Geometry
interior + exterior = 180º
October 3, 2012

7th grade Science help
1. a 2. b 3. d
September 26, 2012

math
divide 1st (multiply by inverse) (1/3 * 7/5) + (5/14 * 7/5) 7/15 + 1/2 = 14/30 + 15/30
September 26, 2012

Pre-Calculus
f(x) + g(x) = (x^2) + (3x + 9) = x^2 + 3x + 9 = h(x) you can break it into whatever pieces you like h(x) = (x + 5)(x + 3) = x^2 + 8x + 15 f(x) = x^2 + 9 ; g(x) = 8x + 6 h(x) = f(x) + g(x) a. f(x) = 3x - 1 ; g(x) = 3 - 2x __ (3x - 1) + (3 - 2x) = x + 2 = h(x) b. f(x) = 7x - 3...
September 26, 2012

physics
it takes 5 s to stop the car __ 55 / 11 the average speed (Va) is __ (55 + 0) / 2 the stopping distance is __ Va * 5 twice as fast means that the stopping time is doubled, along with the average speed __ this means that the car travels 4 times as far
September 26, 2012

math
(3 1/2) / (2 1/3) (7/2) / (7/3) = 3/2 = 1 1/2
September 26, 2012

science
1. a 2. d 3. a 4. c 5. b
September 26, 2012

Physical Science
you need 500 N to overcome the static friction as is frequently the case; once something starts, it is easier to keep it moving
September 26, 2012

physics
the frictional force is __ .29 g the time to stop is __ 5.6 / (.29 g) the average velocity is __ (5.6 + 0) / 2 the distance traveled is the average velocity divided by the time
September 26, 2012

Physics
t * 2.3 * 120 = (59/60) * 16 * 240
September 26, 2012

math grade 10
cuberoot(1280) cuberoot(64 * 20) 4 * cuberoot(20)
September 26, 2012

Geometry
if you double the length, you double the area to have an area of 55 and a perimeter of 32, the original garden was 5 X 11 so the increase in perimeter is 22 __ the percentage is __ (22/32) * 100
September 26, 2012

Physics
average speed (Va) is __ (23 + 0) / 2 time (t) is distance/speed __ 210 / Va acceleration is speed change/time __ (0 - 23) / t
September 26, 2012

Stats
74.2 * 85
September 26, 2012

Chemistry
if you over titrate, you should be able to correct with a titration of a standard acid if you think you may have added too much, the amount of the unknown acid will appear to be more than it actually is __ this would cause you to think you have more moles, so the equivalent ...
September 26, 2012

chemistry
1000 nm in a µm
September 26, 2012

chemistry
50C is halfway between the freezing and boiling points of water (0C and 100C) 50F is is slightly above the freezing point (32F) and well below the boiling point (212F)
September 26, 2012

physics
momentum is conserved 41 * 7 = v * (41 + 30)
September 26, 2012

Physics
the throwing angle has no effect the KE at impact is the initial KE plus the KE gained from the gravitational potential (m g h) KE = (.5 * .058 * 11.0^2) + (.058 * 9.8 * 12.3) v^2 = (2 * KE) / .058
September 26, 2012

Chem
the molecular weight of CS2 is 76.13 so the C in 67.1 g is: 67.1 * (12.01 / 76.13) the molecular weight of CCl4 is 153.81 so the C in 45.2 g is: 45.2 * (12.01 / 153.81) divide the CCl4 carbon by the CS2 carbon to find the percent yield
September 26, 2012

Physics
the frictional force (which must be overcome) is __ m * g * 0.200
September 26, 2012

Physic
(m v^2) / r = m g sinΘ v^2 = 6.00 m * g * sin(9.0º)
September 26, 2012

Physics
[2.00 * sin(37.0º)] + [1.785 * sin(153.5º)]
September 26, 2012

Math
look at 1000 items M1 produces 300 with 18 defects M2 produces 300 with 15 defects M3 produces 400 with 16 defects the probability that a defect is from M1: 18 / (18 + 15 + 16)
September 26, 2012

statistics
80 ≤ [(88 + 83 + 86 + 72 + 3x) / 7] ≤ 89
September 26, 2012

Physics
the centripetal force (gravity) is now 4 times as large f = m v^2 / r multiplying f by 4 (and keeping m and r constant) means that v is doubled doubling the velocity would halve the period
September 26, 2012

Calculus-math
using slope-intercept, the given slope is -1/2 the slope of the tangent to the function is the 1st derivative f(x) = 1 / sqrt(x) = x^(-1/2) f'(x) = (-1/2) x^(-3/2) substitute to find x and then y at the point of tangency use point-slope to write the equation of the new ...
September 26, 2012

math
16! / (7! * 1! * 8!)
September 26, 2012

Physics
the average velocity during deceleration is __ (76 km/h + 0) / 2 the time is the distance divided by the average velocity you will have to convert km/h to m/s to find the answer in s
September 25, 2012

Physics
the average velocity (Va) during acceleration is __ 3000 m / (3.8 * 60) sec the final velocity (Vf) is related to the initial velocity (Vi) by: Vf = (2 * Va) - Vi
September 25, 2012

statistics
there are 10C3 ways of drawing 3 chips there are 7C3 ways of drawing 3 red chips there is one way to draw 3 blue chips p = 1 - [(7C3 + 1) / 10C3]
September 25, 2012

math
(8 * 6) + (½ * 5 * 4)
September 25, 2012

math
-8bc^4
September 25, 2012

Precalc
you seem to be finding the axis of symmetry okay when you plugged in to find the vertex in #1, there is an error (should be 2,-4) __ this also affects the range completing the square should be: f(x) = (x - 2)^2 - 4 (x - 2)^2 = x^2 - 4x + 4 so you need to subtract out the extra...
September 25, 2012

physics
gravity also opposes the motion with a force of __ g * 297 * sin(25.9º) sum the forces; then find the acceleration with __ f = m a
September 25, 2012

physics
h = -.5 g t^2 + 2.6 t + 1.3 the max height occurs at the value of t that lies on the axis of symmetry (t = -b / 2a) __ t = -2.6 / -9.8 find t and substitute back to find the max height
September 25, 2012

math
Py = Pz = (2 * 5) + ( 2 * 3) write the equation for the perimeter of y using the length and width (2 * Ly) + (2 * Wy) = Py = Pz write the equation for the area of y using the length and width Ly * Wy = Ay = Py = Pz you now have two equations with two unknowns that you can ...
September 25, 2012

algebra
subtract the two equations to ELIMINATE the x-term -5y = 9 __ y = -9/5 substitute back to find x 4x + 9/5 = 5
September 25, 2012

science
gas equation temperatures are in Kelvin (absolute) v = (100 cm^3)[(1 atm) / (2 atm)](263º / 293º)
September 25, 2012

physics
it appears that the mass of the block is not involved in your final calculation (it cancels out in the second line) your work seems to be correct
September 25, 2012

Physics
you seem to have forgotten gravity add g to your acceleration number and you should be okay
September 25, 2012

physics
the acceleration is the change in velocity over time in this case __ (12.0 - 7) / 2.0
September 25, 2012

Math
Yoko's speed is 9/10 of Yolanda's in the time it takes Yolanda to run 110 yd, Yoko runs 99 yd so Yolanda wins the second race by a yard for a tie, the 100 yd that Yoko runs must be 9/10 of the distance that Yolanda runs .9 x = 100 __ x = 1000/9 Yoko runs 100 yd (900/9...
September 24, 2012

math 176
(x - 3y + 2z)(x - 3y - 2z)
September 24, 2012

MaTh
the area of the base is a factor of 42 with a perimeter of 18, the possible block arrangements are __ 8 X 1 __ area 8 7 X 2 __ area 14 6 X 3 __ area 18 5 X 4 __ area 20 14 is the only factor of 42, so the height must be 3
September 24, 2012

Pre-Ap Physics
the initial vertical velocity is __ (2650 m/s) * cos(41.9º) the time of flight is the initial vertical velocity divided by the gravitational acceleration __ 2 * [(2650 m/s) * sin(41.9º)] / (9.8 m/s^2) the horizontal velocity is __ (2.65 km/s) * cos(41.9º) the ...
September 24, 2012

Science chemistry
if n is the number of half-lives (1/2)^n * 1.000 = 0.121 (1/2)^n = 0.121/1.000 n [log(1/2)] = log(0.121) n = [log(0.121)] / [log(1/2)] half life = [1h17m] / n
September 24, 2012

chem
both compounds have one Cu, so the moles should be the same to find grams, multiply by the molar mass of CuO
September 24, 2012

chemistry
density is measured in g/cm^3 d = 19.07 / (3.1 * 1.9 * 4.6)
September 24, 2012

Physics(Please help, thank you)
the force that was needed to balance out F1 and F2 is equal in magnitude to the resultant, but opposite in direction so the resultant would be 280g at 77º since F1 and F2 have equal magnitudes and are 90º apart; the expected resultant would be 283g at 75º __ so ...
September 24, 2012

physics
momentum is conserved the mass of the clay, times its velocity; is equal to the mass of the clay+block, times its velocity 0.5 * v = (6 + 0.5) * 3
September 23, 2012

Physics
at 4s, the speed is 24 + 4g at 5s, the speed is 24 + 5g so the average speed over the interval (for one second) is 24 + 4.5g the distance is the speed times the time
September 23, 2012

Physics
h = .5 * g * t^2 34 = .5 * 9.8 * t^2
September 23, 2012

physics
constant velocity means no acceleration, which means zero net force so the third force is equal in magnitude to the resultant of the given forces; but opposite in direction the magnitude of the resultant of the given forces is __ sqrt(61.9^2 + 52.0^2) the tangent of the angle ...
September 23, 2012

physics
the work done on the car is reflected by the change in kinetic energy w = [.5 * 2000 * 20^2] - [.5 * 2000 * 10^2] the units are joules
September 21, 2012

Science
the kinetic energy at the bottom is the kinetic energy at the top plus the gravitational potential across the circle .5 m (Vb)^2 = [.5 m (Vt)^2] + [m g h] dividing by .5 m (Vb)^2 = (Vt)^2 + 2 g h v^2 = 3^2 + [2 * 9.8 * (2 * .8)]
September 21, 2012

precal help
n = d - 4 [(d - 4) / d] + [d / (d - 4)] = 5/2 multiplying by [2 * d * (d - 4)] [2 (d - 4)^2] + (2 d^2) = 5 d (d - 4) 2d^2 - 16d + 32 + 2d^2 = 5d^2 - 20d 0 = d^2 - 4d - 32 factoring __ 0 = (d - 8)(d + 4) 0 = d - 8 __ 8 = d
September 21, 2012

Physics
this is like a projectile problem turned sideways 0 = -(.5 * 3.7 * t^2) + (30 * t) solve the quadratic for t (you want the non-zero solution)
September 21, 2012

physics
the crate is sliding, so μk (the kinetic coefficient) is the relevant one the direction of the frictional force is OPPOSITE to the direction of motion the magnitude of the force is: the normal force of the crate on the ramp [m * g * cos(30º)]; multiplied by the ...
September 20, 2012

phsycis
the force diagram reflects the physical setup the walker is 15.0 m from either end; and is displacing the wire 1.0 m this means that the vertical component of the tension is one-fifteenth the tension in the wire (on BOTH sides) so the force exerted by the walker is 3675/15 * 2...
September 20, 2012

physics
because it starts from rest and accelerates uniformly, the average velocity is 1/2 the final velocity convert the km/h into m/s [multiply by 1000/3600] the distance is the average velocity, multiplied by the time (8.5 s)
September 20, 2012

Math
looks good
September 13, 2012

Physics
horizontal velocity (Vh) is the velocity (V) times the cosine of 20.0º vertical velocity (Vv) is V times the sine of 20.0º or __ Vv = Vh * tan(20.0º) = (104/4.60) * tan(20.0º) = 8.23 when the stone hits the ground, H = 0 0 = (-.5 * g * 4.60^2) + (8.23 * 4....
September 13, 2012

Physics
a) vertical __ H = (-.5 * g * 2.00^2) + 20.60 __ g is gravitational acceleration horizontal __ d = 19.0 * 2.00 b) H = 0 when the ball hits the ground 0 = (-.5 * g * t^2) + 20.60 solve for t to find the flight time
September 13, 2012

Physics
the k.e. is equal to the initial k.e. plus the potential energy from the drop k.e. = (.5 * .100 * 5.00^2) + (.100 * g * 10.0) g is gravitational acceleration
September 13, 2012

Math
a) 128 = (5 * 25) + (3 * 1) = (5 * 5^2) + (0 * 5^1) + (3 * 5^0) in base 5 __ 503 b)128 = 2^7 = (1 * 2^7) + (0 * 2^6) + (0 * 2^5) + (0 * 2^4) + (0 * 2^3) + (0 * 2^2) + (0 * 2^1) + (0 * 2^0) in base 2 __ 10000000 c) 128 = (10 * 12) + (8 * 1) = (10 * 12^1) + (8 * 12^0) in base 12...
September 13, 2012

Physics
the vertical component of the velocity (Vv)is __ 20.0 * sin(32.0º) the horizontal component (Vh) is __ 20.0 * cos(32.0º) the time (T) to max height is __ Vv / g a) Hmax = (-.5 g T^2) + (Vv * T) + 1.1 b) at Hmax, the ball has no vertical velocity; only horizontal (Vh)
September 13, 2012

PHYSICS
the time to accelerate to takeoff speed is __ 35 / 3.8 the average speed during acceleration is __ (0 + 35) / 2 the distance (length of runway) is speed times time
September 13, 2012

physics
0 = (-.5 * g * 5^2) + (10 * 5) + h g is gravitational acceleration
September 13, 2012

physics
Ha = -.5 g t^2 + 75 Hm = -.5 g t^2 + 30 t 75 = 30 t __ this is when substitute t into either equation to find where
September 13, 2012

Physics
a) [(2.25 m/s * 4.98 min) + (1.58 m/s * 2.18 min)] * 60 s/min b) (answer from a) / (4.98 min + 2.18 min) / (60 s/min)
September 13, 2012

physics
5.20 m/s * cos(51.5º)
September 12, 2012

PHYSICS
the final velocity of the ball must be zero at the edge of the table (after 1.32 m of travel) the average velocity is initial plus final,divided by two v = (2.1 cm/s + 0 cm/s) / 2 = 1.05 cm/s the time to stop the ball is the distance divided by the velocity t = 132 cm / 1.05 ...
September 12, 2012

Physics
after 1st stage: final velocity __ Vf1 = 26.4 * 3.92 final height __ Hf1 = .5 * 26.4 * 3.92^2 after 2nd stage: final velocity __ Vf2 = (12.3 * 4.48) + Vf1 final height __ Hf2 = (.5 * 12.3 * 4.48^2) + (Vf1 * 4.48) + Hf1 free-fall time is __ 21.2 s - 3.92 s - 4.48 s , or 12.8 H...
September 12, 2012

science
the angular momentum of the system is constant, so the velocity is inversely proportional the the radius of the orbit Va = Vp * (Rp / Ra)
September 12, 2012

physics
f = m a __ the force (weight) is directly proportional to the acceleration (g) weight = 685 * (9.8 / 12)
September 12, 2012

physics
f = m a __ acceleration is inversely proportional to the mass a = 2.9 m/s^2 * (2.7 / 14.9)
September 12, 2012

physics
time up equals time down (still) initial vertical velocity is __ 1650 * sin(66.1º) flight time is __ 2 * 1650 * sin(66.1º) / 9.8
September 12, 2012

Physics
ignoring the height of contact time up equals time down h = .5 g t^2 = .5 * 9.8 * 2.1^2
September 12, 2012

math
1,000,000 = 10^6 = 2^6 * 5^6
September 12, 2012

physics
average velocity equals initial plus final, divided by two Va = (12 + 24) / 2 = 18 m/s distance equals velocity times time d = 18 * 6.5
September 12, 2012