Physics
a) [(2.25 m/s * 4.98 min) + (1.58 m/s * 2.18 min)] * 60 s/min b) (answer from a) / (4.98 min + 2.18 min) / (60 s/min)
physics
5.20 m/s * cos(51.5º)
PHYSICS
the final velocity of the ball must be zero at the edge of the table (after 1.32 m of travel) the average velocity is initial plus final,divided by two v = (2.1 cm/s + 0 cm/s) / 2 = 1.05 cm/s the time to stop the ball is the distance divided by the velocity t = 132 cm / 1.05 c...
Physics
after 1st stage: final velocity __ Vf1 = 26.4 * 3.92 final height __ Hf1 = .5 * 26.4 * 3.92^2 after 2nd stage: final velocity __ Vf2 = (12.3 * 4.48) + Vf1 final height __ Hf2 = (.5 * 12.3 * 4.48^2) + (Vf1 * 4.48) + Hf1 free-fall time is __ 21.2 s - 3.92 s - 4.48 s , or 12.8 H ...
science
the angular momentum of the system is constant, so the velocity is inversely proportional the the radius of the orbit Va = Vp * (Rp / Ra)
physics
f = m a __ the force (weight) is directly proportional to the acceleration (g) weight = 685 * (9.8 / 12)
physics
f = m a __ acceleration is inversely proportional to the mass a = 2.9 m/s^2 * (2.7 / 14.9)
physics
time up equals time down (still) initial vertical velocity is __ 1650 * sin(66.1º) flight time is __ 2 * 1650 * sin(66.1º) / 9.8
Physics
ignoring the height of contact time up equals time down h = .5 g t^2 = .5 * 9.8 * 2.1^2
math
1,000,000 = 10^6 = 2^6 * 5^6
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